Appeal of the report form
Hi allI have a calendar.fmx (fmb also) and I want to open it in my Report (report 6i) when I pass the parameter date on a form of parameter.
How can I do this
Help, please
Mohan
By this code, you can call form of oracle in oracle report.
AppID PLS_INTEGER;
Begin
AppID: = DDE. App_Begin ("IFRUN60 module=e:\fahed\Run_Multiple_Reports.fmx userid=scott/tiger@host', DDE.") App_Mode_Maximized);
End;
Tags: Oracle Development
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now I have an interview tomorrow, and of course it will be included in the task I have to do.
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Best Of luck, first of all, go with confidence and come back with good news.
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Hello
Today, I have another problem :)
I fix this text and it's simpler
I have run reports of froms and I use RUN_REPORTS_OBJECT_PROC
If I use standard report_id in this procedure, then I get
WEB. SHOW_DOCUMENT ('http://oracle:8889 /'| reports_servlet |) ' /getjobid' | vjob_id |'? Server =' | report_server_name, "_blank");
If the report is not any parameter is ok and this work but if I put some then I get page with witch element, I set value (parameter witch I want) then when I put send query I get error REP-50134
But
If I use
WEB. SHOW_DOCUMENT ('http://oracle:8889 /'| reports_servlet |'? server = raportserv & report=c%3A\raporty\mod.jsp & destype = CACHE & desformat = HTMLCSS & userid = SCOTT % 2FTIGER % 40SZD & paramform = "Yes);
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concerning
Published by: user515960 on 2010-07-06 08:00Hello
If you want to use parameters, then you need to create the report with parameters and your query owes me something like that.
example: -.select ename,empno,sal.....from emp where empno=:p_no.............so here :p_no is parameter.now how you will use this in form with that code which is provide you in u r previos thread.
something like that.
DECLARE repid REPORT_OBJECT; v_rep VARCHAR2(100); rep_status VARCHAR2(20); plid ParamList; vParamValue number; BEGIN plid := Get_parameter_List('tmp'); IF NOT Id_Null(plid) THEN Destroy_parameter_List( plid ); END IF; plid := Create_parameter_List('tmp'); add_parameter(plid,'p_no',text_parameter,to_char(:emp.empno));---------------here you have to add your block name and item name and also we add parameter(P_no) which is created in report builder with the above query. Add_parameter(plid, 'PARAMFORM', TEXT_parameter, 'NO'); repid := FIND_REPORT_OBJECT('REPORT6');-----------------when you create report by using report nodes in form builder so you hav to Presss F4 to go to Property and there you have to set the report server name,desformat which is PDF and report name which is Report6 and also there in property u have to give the report path. SET_REPORT_OBJECT_PROPERTY(repid,REPORT_COMM_MODE,SYNCHRONOUS); SET_REPORT_OBJECT_PROPERTY(repid,REPORT_DESTYPE,cache); SET_REPORT_OBJECT_PROPERTY(repid,REPORT_DESFORMAT,'PDF'); SET_REPORT_OBJECT_PROPERTY(repid,REPORT_OTHER, 'paramform=no'); v_rep := RUN_REPORT_OBJECT(repid,plid); rep_status := REPORT_OBJECT_STATUS(v_rep); WHILE rep_status in ('RUNNING','OPENING_REPORT','ENQUEUED') LOOP rep_status := report_object_status(v_rep); END LOOP; /*Display report in the browser*/ WEB.SHOW_DOCUMENT('http://computer name/IP:8889/reports/rwservlet/getjobid'||substr(v_rep,instr(v_rep,'_',-1)+1)||'? '||'server=report_server_name' || '¶mform=no','_blank'); END;
Note:-you need to start the report server before displaying the report.
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Hi experts,
How can I make a report using the form. Just what I want my form will be input from the user and it will look related data of the emp table and it will produce a report using the oracle Report Builder.
Could you please tell me that how I can do this.
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RajatForm button when press shutter button of coding as below:
declare
pl_id paramlist;
Start
pl_id: = Get_Parameter_List ('PLIST');
IF this is ID_NULL (pl_id) then
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end if;
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call report 12 c of form 12 c by RUN_REPORT_OBJECT (the output format is pdf), but get error REP-56133 - an attempt to write to the folder failed due to a lack of permissions , can someone give me some advice. Thank you!
the solution is:
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REP-51002 link to the report server has failed 12 c forms
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I call report forms 12 c but my error report server name is rep_wls_reports_kalpataru started successfully see image.
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Run the code in the report button
----------------------
DECLARE
PARALIST paramlist;
n number;
p_file_name varchar2 (200);
BEGIN
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ON THE OTHER
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How to print report
-----------------------
PROCEDURE Report_Print (p_file_name varchar2, varchar2, varchar2, p_paramlist paramlist p_report_filename p_desformat) IS
rep_id report_object;
v_rep varchar2 (100);
v_report_server varchar2 (100);
v_report_path varchar2 (100);
v_servlet_url varchar2 (500);
v_job_id varchar2 (100);
BEGIN
v_report_server: = 'rep_wls_reports_kalpataru ';
v_report_path: = 'C:\Oracle\Middleware\Oracle_Home\reports ';
v_servlet_url: = '127.0.0.1:7779/reports/rwservlet ';
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END;
Please someone guide me to solve this problem.
Solved the problem by adding a COMPONENT_CONFIG_PATH in the default.env file.
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I have installed Oracle Forms 12 c:
There are a few questions (problems) in the configuration after the installation:
1. I need NLS_LANG value CROATIAN_CROATIA. EE8MSWIN1250. Text and the fields displayed are displayed correctly (all that is displayed from database), but their guests and the menu is displayed incorrectly (wrong characterset).
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3. I don't know how to define a subset of PDF (in the previous version, just edit uifont.ali and put the subset inside).
4. how to start Report Builder?
For me, after you apply this hotfix, pdf subsetting works very well. (Linux x 64 environment).
Concerning
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Developer Environment:
Windows 7 64 BIT
Oracle Fusion Middleware 11.1.2.2
WLS 10.3.6
All reports run correctly from the report generator.
I tried the following report server name, and do not know, I use a wrong name of report server, if the server not property began or if this is a problem in configuration of the environment.
Name of report server:
Rep_computer_name: Rep_xxxT5600.
(1) as a result URL will return the error:
http://localhost:7001 / reports/rwservlet/showenv? Server = Rep_xxxT5600
Returns the following error message:
REP-51002: link to rep_xxxt5600 for report server has failed.
(2) from the report server in a DOS window
C:\Oracle\Middleware\asinst_1\config > rwserver Server = Rep_xxxt5600
Returns the following error:
REP - 50125:java.lang.NullPointerExcpetion
Any help or advice would be very happy.
I apologize in advance - I posted this in the forum reports, but don't get all the answers. This information is needed for call forms reports, so I'm confident that someone from the Forum forms can help guide me.
Thanks yo in advance.
Mika
I was able to solve the problem by the following text:
- Implement the steps found in how you create and start up A Standalone Server reports in 11g R1 & R2 (Doc ID 961174.1)
- To solve the REP-52262: output diagnostic is disabled.
Change $DOMAIN_HOME/config/fmwconfig/servers/WLS_REPORTS/applications/reports_11.1.2/configuration/rwservlet.properties
#FROM
Yes #TO
Yes L2 -
Hello
I have a region of report which lists the data of revenue. First column is an 'Edit' button which, to the click, presents the edit form. Similarly, I would like to have a button, which, to the click, should give this reception report. Please let me know how to achieve this. When I click, it must pass the number of receipt as a parameter so that the report shows that this special reception.
Thank you
-Anand
anand_gp wrote:
Hope I am able to put the better question...
Not really. You have added any of the requested information.
Here's the form screen that accepts input of receipts. What I need to know, like the first box that is for the record "Edit", I expect a single key, which takes me to that particular record report (image following scree).
Why are you describing that as a' form '? The area shown in the image is clearly an interactive report region. Do not use standard Oracle APEX terminology makes it very difficult to understand your problem. Perhaps this interactive report was created as a form on a Table by report using the form wizard. If so, refer to him as such. The screen 'form' in these cases will be universally understood to be the form page, not the page of report.
To add a link to an interactive report, create a link to the column that passes the key value of the row of interactive report page of report received.
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Calculations in APEX 4.2 on the interactive report and the update form
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I know that people have asked similar questions, but I was not able to do this work. I'm doing some fairly simple math (addition, multiplication) in an application. I have 2 fields (VALUE_A, VALUE_B). I can get the addition and multiplication work in the interactive report, but I also need that it works correctly in the form of update. I also need update form to work dynamically so that if the values are changed, the correction calculated response is shown immediately on the update form and then reflected in the interactive report. I tried the dynamic action, with and without javascript without result. Any help would be appreciated.
Request Express 4.2.6.00.03
model application:
https://Apex.Oracle.com/pls/Apex/f?p=82162:
username: guest
password: Peanut123
Thank you
Rachel
ADD dynamic action
After refresh of region
Set value
ELEMENT the VALUE to change
check the fire on the load
To source, use expression JavaScript
If ($v ("P2_TEST_1")! = null & $v ("P2_TEST_2")! = null)
{
parseInt ($v ("P2_TEST_1")) + parseInt ($v ("P2_TEST_2"));
}
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{
parseInt ($v ("P2_TEST_1"));
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{
parseInt ($v ("P2_TEST_2"));
}
on the other
{ 0; }
That add another dynamic action on change POINT P2_TEST_1 and set even with the same expression JavaScrit action. but NOT fire on the load
Do the same for the ARTICLE P2_TEST_2And the same for A times B but change + to *.
Here, I did samples for you with this code.
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report form, where certain elements of the form received values.
Hi, Hello:
I have a question that maybe stupid, but boring for me. I need to provide a report form, where certain elements of the form have been given values automatically, and these elements (display only) are supposed to show some values in the form automatically.
I used the shape of the APEX with report. The update and delete worked well. But I can't display the automatic values when inserting. By default, APEX insert form makes each null element. I tried to give the value of two items: P5212_USERKEY, P5212_DAILY_VER_DATE with the process before header, after the header, after regions and footer and of calculation or in values of these two elements of the branch if user hit create button (submit). It never worked the two elements always display null value and when I load, I got "ORA-01400: cannot insert NULL into ("TBSBI".» "" "DAILYVERPRODNOTE '." " TAKE') ", because I put in place the constraint in the database that these two columns should not be null.
Could anyone help on this? any suggestion would be appreciated.
SamIf you have performed these 'Display' values only they can by default does not save session state. To access the elements of the page always returns null. Have you changed the "Save Session State" option to "Yes"?
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Hi all
Are there new version of Apex 4.2 or 5.0 already?
Currently I have 4.0
I created a page of type applications 'report with the formula '. I noticed that the 'create' and 'Edit' page share the same form. How to make a field (for example, PROJECT_NAME) in one be 'disabled' or 'hidden' when the form editing option?
I want to only activate the option 'create '.
Thank you much in advance.
KinsKins,
You have been close to answering your own question right along but access to your workspace and making the fix will not help you to learn this valuable concept.
You said
I want to show the column in 'create', but not in "update".
Now take this statement and apply it to your form. What happens in "Create" "Update" mode, versus mode? A create button usually against an apply changes button. So go back to early solution of Gus; apply a condition to the item you want to hide based on how you want this condition to be taken into account. In other words, your buttons are already conditioned; all you have to do is to apply the same State to your item.
Jeff
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