BlackBerry 10 select all option missing in blackberry 10OS

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  Hi all

  I have received_bills and send_bills of 2 tables.

  The SEND_BILLS table is the source table displaying all records in it.

  I need to compare two tables together and insert all the missing elements in received_items including duplicate records.

  There may be duplicate in 2 tables records.

  I wrote a query, but it does not select the duplicate records if it's all the 2 tables. When the same duplicate records are send_bills and received_bill without worrying because send_bills has 4 of them and received_bill 2, it does not select the other 2 duplicate records. And it's just what I need.

  the query is

  SELECT SEND. POINT OF REFERENCE,

  Send. PAYMENT,

  Send. CODE

  OF SEND_BILLS SEND

  WHERE THERE IS NOT (SELECT REC. DATUM, PAYMENT, REC. REC. CODE

  OF RECEIVED_BILLS REC

  WHERE REC. REFERENCE = SEND. SCRATCH CARDS

  AND REC. PAYMENT = SEND. PAYMENT

  AND REC. CODE = SEND. CODE)

  send_bills records

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	29	A3
  OCTOBER 10, 15	47	A4
  9 OCTOBER 15	19	A8
  OCTOBER 10, 15	20	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	25	A5

  received_bills records

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	29	A3
  OCTOBER 10, 15	47	A4
  OCTOBER 10, 15	19	A1

  the result of the query is:

  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	20	A1
  9 OCTOBER 15	19	A8

  So he selects all the records

  the result should be

  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	20	A1
  9 OCTOBER 15	19	A8
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1

  --------------------------------------------------------

  -The DOF for Table SEND_BILLS

  --------------------------------------------------------

  CREATE TABLE SEND_BILLS

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE)

  )  ;

  --------------------------------------------------------

  -The DOF for Table RECEIVED_BILLS

  --------------------------------------------------------

  CREATE TABLE 'RECEIVED_BILLS '.

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE)

  )  ;

  -Insert the script for send_bills

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 29, 'A3');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('09-OCT-15','DD-MON-RR'), 19, 'A8');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 20, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5')

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5')

  -Insert invoices received from script

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 29, 'A3');

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Can someone please help me with the query so that I can also select all the missing records, including duplicates.

  Thanks in advance.

  Best regards

  Caroline

  If you should by all means use loop and then (send_bills and received_bills contain the same data as your original post):

  Select the reference, payment, code

  of (with

  Duplicator (Datum, Payment, code, CNT) as

  (select the reference, code, payment, cnt - 1).

  from (select datum, payment, code, count (one) - cnt count (two)

  (select date, payment, code, 1 one, to_number (null) two)

  of send_bills

  Union of all the

  Select datum, payment, code, to_number (null), 2 two

  of received_bills

  )

  Reference group, code

  having count (one)! = count (two)

  )

  Union of all the

  Select the reference code, payment, cnt - 1

  The duplicator

  where cnt > 0

  )

  Select the reference, payment, code

  The duplicator

  )

  DATUM	PAYMENT	CODE
  10/09/2015	19	A8
  10/10/2015	19	A1
  10/10/2015	25	A5
  10/10/2015	20	A1
  10/10/2015	19	A1
  10/10/2015	25	A5

  Concerning

  Etbin

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