Build & write to text with different column formatting

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• Transfer values of ROWTYPE in ROWTYPE with different COLUMN specifications. keeping the Default_Data values

  Hello

  I have a problem on dynamically the transfer values of different columns in two variables given rowtype type.

  My intention is to transfer values from table1 into table2.

  Basically, I stated to vars of v_table1 and v_table2% rowtype, each of them contains columns with the same, and also the individual column names.

  v_table2% rowtype must be initialized with default values.

  I would like to insert v_table2 values in table2 later by practice 'INSERT INTO TABLE2 VALUES v_table2'.

  Before inserting, I need to change several values of column by different rules, but these rules are not relevant for my actual demand.

  The point is, how can I transfer the values of v_table1 in v_table2 for the hanving of columns with the same column name, without hard-coding the names of columns, because these two tables contain many columns.

  In addition values initialized with v_table2 default_data values should not be overwritten by data does not exist in the same named column of v_table1.

  Example: If v_table1. D is NULL, it should not replace the default value initialized former "Monday".

  Conditions:

  Table 1 contains the following values:

  Column name	Value
  A	'1'
  B	'2'
  C	NULL VALUE
  D	'somedata '.
  E	NULL VALUE
  F	« 3 »

  After the transfer of the values of v_table1 in v_table2, I guess that the following data:

  Column name	Value	Source
  C	NULL VALUE	Table1.C
  D	'somedata '.	Table1.D
  E	"Tuesday".	DATA_DEFAULT from Table2
  F	« 3 »	Table1.F
  G	NULL VALUE
  H	NULL VALUE

  Right now I am already able to fill the v_table2 with the default values:

  declare
    lv_query varchar2(1000);
    
    type cur_typ is ref cursor;
    rcur_typ cur_typ;
    
    v_table2 table2%rowtype;
  
  begin
      for rec in (select *
                  from user_tab_columns
                  where table_name = 'TABLE2'
                  order by column_id
                  )
      loop
        if rec.data_default is null then
            lv_query := lv_query||', null';
          elsif rec.data_type = 'NUMBER' then
            lv_query := lv_query||', '||rec.data_default;
          elsif rec.data_type = 'DATE' then
            lv_query := lv_query||', '||rec.data_default;
          else
            lv_query := lv_query||', '||rec.data_default||'';
        end if;
      end loop;
      
      lv_query := 'SELECT'||substr(lv_query, 2)||' FROM DUAL';
      dbms_output.put_line(lv_query);
      
      open rcur_typ for lv_query;
      fetch rcur_typ into v_table2;
      close rcur_typ;
  end;
  

  I have no idea how to achieve the transfer of v_table1 to v_table2 without substitute default values of table2.

  
  

  As far as I know I can find these columns with column names by querying:

  select column_name from user_tab_cols where table_name='TABLE1' intersect select column_name from user_tab_cols where table_name='TABLE2'
  

  Maybe you can give me some advice.

  Thank you very much.

  Sample data:

  CREATE TABLE "TABLE1" 
     (    "A" VARCHAR2(20 BYTE), 
      "B" VARCHAR2(20 BYTE), 
      "C" VARCHAR2(20 BYTE), 
      "D" VARCHAR2(20 BYTE), 
      "E" VARCHAR2(20 BYTE), 
      "F" VARCHAR2(20 BYTE)
     );
  
    CREATE TABLE "TABLE2" 
     (    "C" VARCHAR2(20 BYTE), 
      "D" VARCHAR2(20 BYTE) DEFAULT 'Monday', 
      "E" VARCHAR2(20 BYTE) DEFAULT 'Tuesday', 
      "F" VARCHAR2(20 BYTE) DEFAULT 'Wednesday', 
      "G" VARCHAR2(20 BYTE) DEFAULT 'Thursday', 
      "H" VARCHAR2(20 BYTE)
     );
  
  INSERT INTO "TABLE1" (A, B, D, F) VALUES ('1', '2', 'somedata', '3');
  
  INSERT INTO "TABLE1" (A, B, D, F) VALUES ('1', '2', 'somedata', '3');
  

  Banner:

  Oracle Database 11 g Release 11.2.0.3.0 - 64 bit Production

  PL/SQL Release 11.2.0.3.0 - Production

  CORE Production 11.2.0.3.0

  AMT for Linux: Version 11.2.0.3.0 - Production

  NLSRTL Version 11.2.0.3.0 - Production

  You can build a dynamic query that checks the values of all columns in the table 1,

  and if a column contains null, then retrieves the default value of the column in table2,

  or null if this column doesn't have a default vallue.

  Something like this pseudocode

  SELECT
     if column A is not null then take A from table1, else take default for column A from table2
     .....
     if column X is not null then take A from table1, else take default for column X from table2
  FROM table1
  

  The default budget can be extracted from USER_TAB_COLUMNS

  select column_name, data_default from user_tab_columns
  where table_name = 'TABLE2'
  order by column_id
  ;
  

• regexp: how to deal with different date formats?

  the date comes as varchar2 with '-'and':' as separators for day part and part time respectively. but it may come with different formats such as
  
  1993-05-17
  1993-05-17 13:04:23
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  Thank you

  As others have said, the smartest way is to keep your input in a format method and store your data in a date column.
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  union all select '1993-05-17 13:04:23' from dual
  union all select '1993-05-17 13:04' from dual
  union all select '1993-05-17 13:4' from dual
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  union all select '1993-5-7 13:4:2' from dual
  union all select '1993-05-17 1:4 PM' from dual
  )
  select d
       , to_date( translate( d, 'xampAMP', 'x' )
                , 'yyyy-mm-dd hh24:mi:ss'
                )
       + case when instr( upper( d ), 'P' ) > 0 then 0.5 else 0 end cd
  from test
  

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  Gossweiler beat

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  Chicken in a curry sauce <-(8pt)

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  Found! Field of ActiveRichText!

  Code following (not mine)

  compensates for the int [] = new int [] {0, 5, 12};
  Police fonts1 [] = new make [] {Font.getDefault (), Font.getDefault ()};
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• How to make a NULL handle with different columns

  Hi gurus,
  
  I need the Oracle in the reports:
  
  For example:-J' have a Temp table with three columns A, B and C
  
  My requirement is IF the columns A, B and C are null in the report he should return C 0, B as none and none.
  If all values are there in columns A, B or C, then report output should return these values.
  
  All your contributions are much appreciated.
  
  Thank you

  When column c is null, column should return zero and column b return zero and column c 0.
  If column C is not null, then it must return the values that are present in their respective columns.

  select nvl2 (c, a, 'None') a, nvl2 (c, b, 'None') b, nvl (c, 0) c from temp
  

• Zeroes with different digital formats

  Hi all

  I'm new here, and although I found the basic means to achieve what I'm trying to, I do not get the result I want:

  Situation: I have a table that contains a column of 'length' named LAENGE. These fields to store the value of the length in meters. As a result, I want to display the length in kilometers, so I use the following line in my opinion:

  -- ...

  ("Strecke" |) S.STRECKE_NR | "< br > direction | S.RICHTUNG |

  "< br > km | S.VON_KM_L |

  "bis" | S.BIS_KM_L | '< br > Lange =' | LAENGE/1000 | 'km') as TOOLTIP;

  -- ...

  In the view that result, values less than 1000 are displayed as ', 123' (e.g., 4321 becomes 4 321, but becomes 123, 123 with zero missing. Usually, I use to_char() for formatting the values, for example to_char (LAENGE, ' 0.999 '). But this only works for values less than 10000, if I use to_char (LAENGE, ' 000,999', it works for all values less than 1000000 which is good, but then I get useless zeros to smaller values.)

  Confusing? What I try to achieve is the following:

  1234 > 1 234

  123 > 0.123

  12345 > 12 345

  123456 > 123 456

  but now, with my to_char (LAENGE, ' 000,999') that I want to say is:

  1234 > 001,234

  123. > 000,123

  12345 > 012,345

  123456 > 123 456

  I can imagine it's only something simple that I'm missing just here. Any ideas?

  Thanks in advance!

  See you soon,.

  Freddy

  Hi, Freddy.

  126778f5-5b00-4ab6-9ed8-1279e3c9af46 wrote:

  Hi all

  I'm new here, and although I found the basic means to achieve what I'm trying to, I do not get the result I want:

  Situation: I have a table that contains a column of 'length' named LAENGE. These fields to store the value of the length in meters. As a result, I want to display the length in kilometers, so I use the following line in my opinion:

  -- ...

  ("Strecke" |) S.STRECKE_NR | '
  Direction '. S.RICHTUNG |

  '
  km '. S.VON_KM_L |

  "bis" | S.BIS_KM_L | '
  Lange =' | LAENGE/1000 | 'km') as TOOLTIP;

  -- ...

  In the view that result, values less than 1000 are displayed as ', 123' (e.g., 4321 becomes 4 321, but becomes 123, 123 with zero missing. Usually, I use to_char() for formatting the values, for example to_char (LAENGE, ' 0.999 '). But this only works for values less than 10000, if I use to_char (LAENGE, ' 000,999', it works for all values less than 1000000 which is good, but then I get useless zeros to smaller values.)

  Confusing? What I try to achieve is the following:

  1234--> 1 234

  --> 0.123 123

  12345--> 12 345

  123456--> 123 456

  but now, with my to_char (LAENGE, ' 000,999') that I want to say is:

  1234--> 001,234

  123--> 000,123

  12345--> 012,345

  123456--> 123 456

  I can imagine it's only something simple that I'm missing just here. Any ideas?

  Thanks in advance!

  See you soon,.

  Freddy

  What is

  To_char (laenge / 1000)

  '990D 000'

  )

  assuming that ',' is the separator of decimal in your environment.

• Receive error message when calculating the two fields with different date format

  I'm more familiar with SQL Server and Oracle, then after a search online without success, I ask here.

  I use developer PL/SQL with DB Oracle 11g Release 11.2.0.2.0 Enterprise 64-bit

  MyTable:

  ID_Number VarChar2

  Date of Date_Received

  Select ID_Number,

  Date_Received,

  To_Date (substr (ID_Number, 1.6), "YYMMDD") SentDate,.

  Date_Received - NumDays To_Date (substr (ID_Number, 1.6), "YYMMDD")

  FROM MyTable

  Where substr (ID_Number, 7.3) in ('ABC', 'ABD')

  and length (Trim (translate ((substr (ID_Number, 1,6)), '0123456789',' '))) a null value

  ID_Number Date_Received SentDate NumDays

  131002ABC1654106 10/16/10/2013-2013 14 2

  131004ABD8813899 4/12/2013-4/8/2013 4

  131014ABD1844832 10/16/10/14 OF 2013-2013 2

  Sometimes the first 6 characters in the ID_Number aren't the numbers and length (Trim (translate deletes records))

  I want just the records where NumDays > 2

  I tried to put the request in a subquery and using where NumDays > 2 outside.  I also tried using the calculation directly in the Where clause.  Without it in Where clause it works very well, with him in a place, I get the following error:

  ORA-01931: Date format picture ends before converting all of the input string

  
  

  I don't know how to put the two dates in the same format.  I tried to declare the format without result.  I don't understand how I can calculate in the selection, but do not use the same calculation in Where clause.

  Thank you for your help.

  Hello

  SQL is a language to describe the desired results.  How the system gets these results belongs to you don't have much say about which conditions will be applied when.

  One place where you can control the order of things is a CASE expression.  When you say

  CASE

  WHEN condition_1

  THEN expression_1

  END

  You can be sure that expression_1 will be evaluated only when cond_1 is set to TRUE.

  Try something like this:

  WITH got_sent_date AS

  (

  SELECT id_number, date_received

  CASE

  WHEN the TRANSLATION (SUBSTR (id_number, 1, 6)

  , 'x' 0123456789 '.

  , 'x'

  ) IS NULL

  THEN TO_DATE (SUBSTR (id_number, 1-6)

  , "YYMMDD".

  )

  END AS sent_date

  FROM MyTable

  WHERE (id_number, 7, 3) SUBSTR ("ABC", "ABD")

  )

  SELECT id_number

  date_received

  sent_date

  , date_received - sent_date AS num_days

  OF got_sent_date

  WHERE date_received > sent_date + 2

  ;

  If you would care to post some sample data (CREATE TABLE and INSERT statements) and the results desired from this data, I was able to test this.

  Of course, you'll still errors of execution if id_number starts with 6 digits, but they do not have to be valid, for example '131100' or '130229'.  This is one of the reasons why the date information storage in VARCHAR2 columns are a bad idea.  To work around this problem, see

  https://forums.Oracle.com/message/4255051

• Search text with different appliedLanguage

  Then.

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  Thank you very much!

  ~ Trevor ~ wrote:

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  This is what it looks like:

  

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  Hello world!

  I have an invoice form that must be printed in triplicate, the first one with the 'Original' text in the lower right corner, the second with 'Copy' and the third with «*»

  I didn't ' t know how to get this...

  Thanks in advance

  Hello

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  I hope that the foregoing would be healpful for you.

  ARO

  Yasser

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  Hello

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  How to reproduce the problem:

  Draw a line with the tool "Feather".

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  Chronology of the measure

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  ---

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