Button makes visible subform, and then adds another instance

Hello

I have a button that makes a subform visible. Which works very well.

I would like the button when a user clicks a second time to add another instance of the same subform. Is this possible? I have no idea how start with the JavaScript for this and would appreciate help.

Thanks in advance,

MDawn

Rather than raise the subform, and then adding cases you can do simply by using the instances, then the button does the same thing.

To 'hide' the subform using the instances, make sure that under binding that the Min County click on and the initial count is set to 0 (zero) - your subform is now hidden by default.

Change the code you have showing the subform to use addInstance() instead of the presence, using the underscore for the Instance Manager shortcut (you must use the underscore method, because the instance does not yet exist):

_hiddenSubform.addInstance (true);

If you remove instances to zero then the subform will disappear again. Doing it this way also has the advantage of reset all data in the subform.

Tags: Adobe LiveCycle

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Group by query, and then add another dimension

Hello guys,.
I am facing problem while building a query. In this, I do group first, and then add a column with a condition more.
I have following data in the table or existing query.
create table tableA (key number (5), newspaper varchar2 (5), varchar2 (5) Blog, available1 number (10), disponibles2 number (1), Type varchar2 (5))
Insert into tableA values (100, ' 501 ', ' 1501', 10000, 8000, "T1")
Insert into tableA values (100, ' 501 ', ' 1501', 12000, 0, 'T2')
Insert into tableA values (200, ' 502 ', ' 1505', 15000, 9000, "T11")
Insert into tableA values (200, '502', '1505', 8000, 1000, "T12")
Insert into tableA values (200, '502', '1505', 5000, 1000, "T13")
Insert into tableA values (300, ' 503 ', ' 1510', 7000, 6000, "T21")
Insert into tableA values (400, '503', '1510', 6000, 1000, 'T31')
I created the 'Difference' on the fly using NVL (available1, 0)-NVL(Revenue2,0) as the difference
Type of difference key1 journal Blog available1 disponibles2
100 501 1501 10000 8000 2000 T1
100 501 1501 12000 12000 T2
200 502 1505 15000 9000 6000 T11
200 502 1505 8000 1000 7000 T12
200 502 1505 5000 1000 4000 T13
300 503 1510 7000 6000 1000 T21
400 503 1510 6000 1000 5000 T31
Desired output
We must show Type (Sun) only when the difference is high and have to group by (Key1, Journal, Blog) while the rank becomes a.
It is like showing the first 6 columns first and then add the columns of 'Type' later (probably using subqueries).
Type of difference key1 journal Blog available1 disponibles2
100 501 1501 22000 8000 14000 T2
200 502 1505 28000 11000 17000 T12
300 503 1510 7000 6000 1000 T21
400 503 1510 6000 1000 5000 T31
Any idea or detail will be appreciated.
Thank you

Use the DUNGEON:

Select the key,

Journal,

blog,

Sum (revenue1) available1,

Sum (revenue2) disponibles2,

NVL (Sum (revenue1), 0)-nvl (sum (revenue2), 0) difference.

Max (type) keep (dense_rank last order of nvl(revenue1,0) - type nvl(revenue2,0))

from tablea

Key, group

Journal,

blog

order by key,

Journal,

blog

/

TYPE OF KEY JOURNAL BLOG AVAILABLE1 DISPONIBLES2 DIFFERENCE
---------- ----- ----- ---------- ---------- ---------- -----
100 501 1501 22000 8000 14000 T2
200 502 1505 28000 11000 17000 T12
300 503 1510 7000 6000 1000 T21
400 503 1510 6000 1000 5000 T31

SQL >

SY.

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```

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XFA. Host.Print (1
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Better yet: y at - it a (not excessively complex) way to print a specific object only (in this case, the guidelines text field)?
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Hello

Your form is already dynamic (flowing), then for your second button print, you can hide the main pages in the click event, print the remaining pages and then finally show all pages.

If you are looking for the syntax change the presence and properties of an object (Text6) watch here: http://assure.ly/h7whb8.

This will allow for example the object is visible and printing:
```
Text6.presence = "visible";
Text6.relevant = "+print";
```
To change back to Visible (display only):
```
Text6.presence = "visible";
Text6.relevant = "-print";
```
Hope that helps,

Niall

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Rob Brown - Microsoft MVP<- profile="" -="" windows="" expert="" -="" consumer="" :="" bicycle=""><- mark="" twain="" said="" it="">

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____________________________________________________________________________

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How do to activate 'VAPP Options' on an existing virtual machine, and then add the properties that will be passed down through the OVF - ENV. XML

I'm trying to understand vSphere PowerCLI how to activate the "Options of VAPP" on an exsiting VM (in this case a model freshly cloned) then add properties and select cdrom of the FVO data access such as when the virtual machine is running the FVO - env.xml contains the properties in the CD-ROM drive.

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Mike

You can use the vSphere API to activate the 'Options of VAPP"on an existing virtual machine, and set properties. For example:

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$spec.vAppConfig = new-Object VMware.Vim.VmConfigSpec

$spec.vAppConfig.property = new-Object VMware.Vim.VAppPropertySpec [] (1)

$spec.vAppConfig.property [0] = new-Object VMware.Vim.VAppPropertySpec

$spec.vAppConfig.property [0] .operation = 'Add '.

$spec.vAppConfig.property [0] = new-Object VMware.Vim.VAppPropertyInfo .info

$spec.vAppConfig.property [0].info.key = 0

$spec.vAppConfig.property [0].info.classId = "Property1ClassID".

$spec.vAppConfig.property [0].info.instanceId = "Property1InstanceID".

$spec.vAppConfig.property [0].info.id = "Property_1.

$spec.vAppConfig.property [0].info.category = "Property1Category".

$spec.vAppConfig.property [0].info.label = "property 1.

$spec.vAppConfig.property [0].info.type = "string".

$spec.vAppConfig.property [0].info.userConfigurable = $true

$spec.vAppConfig.property [0].info.defaultValue = "Property1DefaultValue".

$spec.vAppConfig.property [0].info.value = «»

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E-mail address is removed from the privacy *.

Hello

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Solve the problems of Windows Media Player video and other media or library

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Let us know the result of the Fixit.

MAX value query and then add to existing querry

Hi all

Asked me to add some fields to add to an existing query.
I'm having a problem with the initial query, so let's start first, and then maybe I'll be able to figure out how to add it in.
Here is my sample data:

CREATE TABLE TASK
( 
    TASK_TYPE     VARCHAR2 (50 BYTE),
    TASK_SEQ      VARCHAR2 (50 BYTE),
    COMPL_DATE    DATE,
    REQUIRED_TASK VARCHAR2 (100 BYTE)
);

 
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('ABC',18, TO_DATE('12-MAR-12','DD-MON-YYYY'), 'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('DEF',16, TO_DATE('12-MAR-12','DD-MON-YYYY'),'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('HIJ',12, TO_DATE('09-MAR-12','DD-MON-YYYY'), 'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('KLM',15, TO_DATE('12-MAR-12','DD-MON-YYYY'), 'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('NOP',11, TO_DATE('11-MAR-12','DD-MON-YYYY'), 'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('QRS',20, TO_DATE('29-MAR-12','DD-MON-YYYY'), 'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('TUV',13, TO_DATE('11-MAR-12','DD-MON-YYYY'), 'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('WXY',19, TO_DATE('30-MAR-12','DD-MON-YYYY'), 'Y');
INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('Z',24,   TO_DATE('04-APR-12','DD-MON-YYYY'), 'Y');

My desired output is the MAX (TASK_SEQ) based on the data set, the TASK_SEQ and the COMPL_DATE should always be recording albums that I'm trying to capture,
such as:
{Europe}
TASK_TYPE TASK_SEQ COMPL_DATE REQUIRED_TASK RNK
Z 24 4 4 2012 Y (DO NOT WANT THIS)

I have this code that I thought would work, but not as of yet - it returns all rows and ranks eac as 1.
{code}
 WITH DST AS
 (
  SELECT  TASK_TYPE,
          TASK_SEQ,
          COMPL_DATE,
          REQUIRED_TASK,
          RANK () OVER (PARTITION BY TASK_TYPE ORDER BY COMPL_DATE) rnk
  FROM TASK
  )
  SELECT * FROM DST
  WHERE rnk = 1
{code}
And this yields basically the same results:
{code}
SELECT  TASK_TYPE,
        TASK_SEQ,
        COMPL_DATE,
        REQUIRED_TASK
FROM TASK
WHERE (TASK_TYPE, TASK_SEQ) IN (SELECT TASK_TYPE, MAX(TASK_SEQ)
                                                FROM TASK
                                                GROUP BY TASK_TYPE )
{code}

Thanks for taking the time to look.

G

Hello

GMoney says:
... Here is my sample data:

Thank you! It is very useful.

... My desired output is the MAX (TASK_SEQ) based on the data set, the TASK_SEQ and the COMPL_DATE should always be recording albums that I'm trying to capture,
such as:
{Europe}
TASK_TYPE TASK_SEQ COMPL_DATE REQUIRED_TASK RNK
Z 24 4 4 2012 Y (DO NOT WANT THIS)
Be careful. The keyword tiny must code. (It must be spelled correctly, too.)
What is the desired line or line that you don't want? If this is the desired line, so you were on the right track with your first attempt. Try this:
WITH DST AS
 (
  SELECT  TASK_TYPE,
          TASK_SEQ,
          COMPL_DATE,
          REQUIRED_TASK,
          RANK () OVER (ORDER BY COMPL_DATE DESC) rnk
  FROM TASK
  )
  SELECT * FROM DST
  WHERE rnk = 1
;
Exactly what you have published, with the exception of the analytical clause.
'PARTITION BY task_type' means a separate set of numbers (starting with 1) assign to each separate task_type. Since task_type is unique, this means that each line is #1 in his own little world. If I understand the problem, you want (except ties) only 1 rank for the entire result set. This means you don't at all want a PARTITION BY clause. PARTITION BY is never required in any analytic function.
"ORDER BY compl_date" means that the first compl_date gets rnk = 1. You want the latest comp_date to get #1, so you must specify descending order. Note that this has nothing to do with task_seq. It you want to display the line with the highest task_seq, then the rnk column would be defined as:
RANK () OVER (ORDER BY task_seq DESC) rnk
If you know that the line with the upper task_seqs is always compl_dates later, then it does not matter that you use. Remember to descending order.

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Hello
Please tell me...
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Hello world
Im currently trying to build a flash presentation that will have different buttons on the same stage and each button when clicked on will be particular to appear on the scene objects. Then once you click each button once again he'll disappear connected on particular objects from the scene. Each button and the objects he made appear / disappear is separated from all other buttons actions.
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MC.visible =! MC.visible;

}

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Button makes visible subform, and then adds another instance

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