By default in "in order to" in the query select can be different in 11g 10g

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• How do the query select outer join to a report of the APEX

  Hi all
  
  I'm Ann.
  
  I have a select statement that is used to calculate statistics for a month (October 2012 in this example)
  Select ph.phase_number
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  THEN last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (' ' Oct 2012 ', ' MY YYYY' "))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  Rollup Group (phase_number)
  ;
  
  The result is as below
  Phase_Number AVG_DAYS
  Phase One 8.6666666666666667
  Phase two 14.6
  Phase three 12
  11.4615365
  
  I have another list of selection mainly the list of months between two date value.
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order of which_month)
  
  The query result is as below
  
  DISPLAY_MONTH
  
  AUGUST 2012
  SEP 2012
  OCT 2012
  
  Is it possible I can join these two select statement above to generate a comparable result:
  
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  Sep 2012 Phase One 7.66
  Oct 2012 Phase One 5,66
  August 2012 Phase two 8.666
  Sep 2012 Phase two 7.66
  Oct 2012 Phase two 5,66
  August 2012 Phase three 8.666
  Sep 2012 Phase three 7.66
  Oct 2012 Phase three 5,66
  
  Or
  Days of month Phase number Avg
  August 2012 Phase One 8.666
  August 2012 Phase two 7.66
  August 2012 Phase three 5,66
  Sep 2012 Phase One 8.666
  Sep 2012 Phase two 7.66
  Sep 2012 Phase three 5,66
  Oct 2012 Phase One 8.666
  Oct 2012 Phase two 7.66
  Oct 2012 Phase three 5,66
  
  And it can be controlled by Phase number or month.
  My other colleague suggested I should use a left outer join, but after having tried many ways, I'm still stuck.
  
  I tried select is
  Select a.display_month, b.* in)
  Select to_char (which_month, 'LUN YYYY') as display_month
  de)
  Select add_months (to_date (' ' August 2012 ', ' MY YYYY' "), rownum-1) which_month
  of object
  where
  rownum < = months_between (to_date (' ' Oct 2012 ', ' MY YYYY' "), add_months (to_date (' ' August 2012", "MY YYYY"), - 1))
  order which_month)) a left outer join
  
  (Select to_char (ph.date_finished, 'MY YYYY') as join_month, ph.phase_number)
  sum ((case
  WHEN ph.date_finished IS NULL or ph.date_finished > last_day (TO_DATE (a.display_month, 'MY YYYY'))
  THEN last_day (TO_DATE (a.display_month, 'MY YYYY'))
  Of OTHER ph.date_finished
  END)
  (-ph.date_started + 1) / count (def.def_id) as avg_days
  Ph phase_membership
  inner join court_engagement this on ph.mpm_eng_id = ce.engagement_id
  join in-house defendant def on ce.defendant_id = def.def_id
  where def.active = 1
  and ph.date_started < = last_day (TO_DATE (a.display_month, 'MY YYYY'))
  and ph.active = 1
  and UPPER (ce.court_name) LIKE '% '.
  To_char (ph.date_finished, 'MY YYYY'), group (phase_number) rollup) b
  On a.display_month = b.join_month
  
  but then I get an error
  SQL error: ORA-00904: "A." "" DISPLAY_MONTH ": invalid identifier
  
  I need to view a report on the APEX with option for people to download at least format CSV.
  Already 1 inteactive report in the page, so I don't think adds another interactive report without using the iframe trick.
  
  If any of you have any ideas, please help.
  
  Thank you very much.
  
  Ann

  Hello Ann,.

  Frank has done a very good job. I am also impressed.

  Is in regard to your correction to his question, the problem is on this replacement you did

  last_day(TO_DATE(am.which_month,'MON YYYY'))
  

  AM.which_month is already a date type, and you don't need to convert it to this day.
  Here is the correct way:

  last_day(am.which_month)
  

  There are also sometimes with the data you've posted have no line for this month. So I also added a function NVL to display 0 under avg_days for these cases.

  Here is my corrected query:

  DEFINE startmonth = "Aug 2012";
  DEFINE endmonth   = "Oct 2012";
  WITH  all_months  AS
  (
     SELECT ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM-1) AS which_month
     ,      ADD_MONTHS(to_date('&startmonth','MON YYYY'), ROWNUM  ) AS next_month
     from all_objects
     where
     rownum <= months_between(to_date('&endmonth','MON YYYY'), add_months(to_date('&startmonth','MON YYYY'), -1))
  )
  SELECT TO_CHAR (am.which_month, 'Mon YYYY')  AS month
       , ph.phase_number
       , NVL(sum ( (CASE
                   WHEN ph.date_finished IS NULL OR ph.date_finished > last_day(am.which_month)
                   THEN last_day(am.which_month)
                   ELSE ph.date_finished
                END
               ) - ph.date_started + 1
             ) / count(def.def_id), 0) as avg_days
    FROM all_months am
         LEFT OUTER JOIN  a_phase_membership  ph  PARTITION BY (ph.phase_number)
            ON  am.which_month <= ph.date_started
            AND am.next_month  >  ph.date_started
            AND ph.date_started <= last_day(am.which_month)  -- May not be needed
            AND ph.active = 1
         LEFT OUTER JOIN  a_engagement  ce
            ON  ph.mpm_eng_id = ce.engagement_id
            AND ce.court_name IS NOT NULL  -- or something involving LIKE
         LEFT OUTER join  a_defendant     def
            ON  ce.defendant_id = def.def_id
            AND def.active = 1
   GROUP BY ROLLUP(phase_number, am.which_month)
   ORDER BY  am.which_month
          ,  ph.phase_number
  ;
  
  The output is:
  MONTH    PHASE_NUMBER           AVG_DAYS
  -------- -------------------- ----------
  Aug 2012 PHASE ONE                     0
  Aug 2012 PHASE THREE                   0
  Aug 2012 PHASE TWO                     0
  Sep 2012 PHASE ONE                    12
  Sep 2012 PHASE THREE                   1
  Sep 2012 PHASE TWO                     9
  Oct 2012 PHASE ONE                     8
  Oct 2012 PHASE THREE                   0
  Oct 2012 PHASE TWO                    14
           PHASE ONE                    11
           PHASE THREE                   1
           PHASE TWO                  11.5
                                9.71428571
  

  I don't know if that's really what you want. In the case check it and let me know.

  Kind regards.
  Al

• Rewrite the query, select below or try to get the necessary O/P

  Hello..
  
  My example of data.,.
  
  Create table customer (name varchar2 (10), telephone1 telephone2 number (10), number of phone3 (10), (10) number, bitwisephone number (10));
  
  Insert into customer values('a',23456,67890,null,12345);
  
  Insert into customer values ('b', 67459,89760,null, 37689);
  
  create table do_not_call (dont_call number (10));
  
  insert into do_not_call values (67890);
  
  insert into do_not_call values (37689);
  
  Question: -.
  --------------
  
  Customer 'a' has value of numbers1 as 23456.check if telephone1 exists in the do_not_call table.
  In fact there is no, so set the bit for numbers1 as "o" like wise search telephone2
  & phone3.after update of the bitwisephone for each client should be as the output below.
  
  
  Need to O/P: -.
  -------------------
  
  name bitwisephone
  
  a 010
  b 001
  
  
  For that matter... I use "any" operator...
  
  
  
  SELECT name, case when numbers1 = all (SELECT dont_call FROM do_not_call) and then put an end to '1' other '0'.
  -case when telephone2 = all (SELECT dont_call FROM do_not_call) and then put an end to '1' other '0'.
  -case when phone3 = all (SELECT dont_call FROM do_not_call) then '1' other '0' end 'Bits '.
  OF THE customer;
  
  
  Is there any other way to get the necessary O/P?
  
  
  Thank you!!
  
  Kind regards
  VijayRajaram.

  Looks like one already answered Re: rewrite the query, select below or try to get the necessary O/P

  with
  customer(name,phone1,phone2,phone3,bitwisephone) as
  (select 'a',23456,67890,12345,null from dual union all
   select 'b',67459,89760,37689,null from dual
  ),
  do_not_call(dont_call) as
  (select 67890 from dual union all
   select 23456 from dual union all
   select 37689 from dual
  )
  select name,
         to_char(mod(trunc(sum(weight)/4),2))||
         to_char(mod(trunc(sum(weight)/2),2))||
         to_char(mod(sum(weight),2)) bitwisephone
    from (select name,phone1 phone,4 weight
            from customer
          union all
          select name,phone2,2
            from customer
          union all
          select name,phone3,1
            from customer
         ) c,
         do_not_call d
   where c.phone = d.dont_call(+)
     and d.dont_call is not null
   group by name
  

  Please do not duplicate messages

  Concerning

  Etbin

• Number of lines on the query and export are different?

  Hello
  
  I'm kinda new to SQL Developer, but so far it has been very well. I came across a problem, but with a certain query I count the lines and get about 11 000 (which is what I expected), and then export the data to a csv file to download on another system, and somehow the number of lines is increased to 30,000? I tried several times and still get the same results, and I know that the extra lines should not be returned to request bythe they fail when uploaded to the other system.
  
  Does anyone have any idea why this could be? The query is a union query, but it was fine before. Looks like a bug to me, but then again that I am a newbie.
  
  Thank you
  
  Steve

  The recordtypeextract r table is not related to any other table. Link with another table and avoid the Cartesian join.

• Trigger of the ISO (behavior?) behavior different in 11g (works of 10g, 11g not)

  We have a two master tables, A and B connected by an xref, AB, who has the key to A column and the column key of B... each help-offer combo can only happen once.
  
  A may have 0 to many Bs, B can be 0 to many as.
  
  (these tables describe a pool of 'work'... the work can start at different points... If there is flow and life is good, it starts with A, becomes B and so a bond between them, but sometimes has never progresses to B... sometimes there are emergencies, and so B is created... each pool has a Master ID to itself)
  
  We have a view V1...
  Outer join B AB where corresponds to the button B (one column).
  
  ... we want to see Group B, if there a records, and as that may be related.
  
  We have another opinion V2... that selects in V1 where A key is not null.
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  We have a trigger to ISO on V2 (V2 is used by a form, but the problem is the DB level).
  
  In SQL Developer... in DB10g, V2 shows insertable ACE / ID.
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  In SQL Developer... in DB11g, V2 DOES NOT SHOW UP insertable / suppressible.
  
  The same code in both places. We test 11g, in order to determine our "traps" before that we will occupy migrate.
  
  With the 10gDB behind the form, follows after a deletion.
  With the 11gDB behind the form, it gives a 'impossible to remove from the view' and begins to talk about keys preserved and row ID.
  
  Why?
  
  We know that the data is very good. We like the behavior of 10g.
  The V1 and V2 have good recordset and keys appropriate to AB, and B.
  
  Without re - write this and similarly built views, what do we do to make it work again?
  
  All the clues are welcome!
  
  SM

  SM_Work wrote:
  With the 11gDB behind the form, it gives a 'impossible to remove from the view' and begins to talk about keys preserved and row ID.

  Only one question here is you ;)

  And the facts of talking too much, too little hard.

  What is you get the exact error message?
  What do you do with her?
  ANSI joins is involved?
  Can error be reproduced using SQL * more?
  Looking for metalink? -A first guess could be Bug 14274321

  Could you post the view? -If possible, a version boiled down from it.

  Think I remember a similar discussion (without knowing what we are actually discussing)-finding something like 10g was too lenient and he failed, now 11g.

  Concerning
  Peter

• The query selected several hierarchies of dimension levels

  Hi all.
  
  I've created a dimension with two hierarchies as follows customer by AWM 11.
  
  SLM_HIER: All clients-> seller-> client
  GEO_HIER: All clients-> status-> City-> client
  
  I also have a SALES_CUBE (measures: aggregation of QUANTITY, VALUE,: SUM) which is sized with Sun customer.
  
  I use OBIEE to query the OLAP engine (through the relational views that AWM created automatically). I followed the OTN OBE tutorials.
  
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  Thank you very much.
  
  Chris

  I think that OBIEE would also give you your answer of OLAP.

  This query has two hierarchies defined filters and (therefore OBIEE would need) automatically fix this request of the highest common level b/w hierarchies (in this case: base/leaf level - customer). Accordingly, if the CUSTOMER is your Customer dimension, OBIEE (at least, the old style of obiee modeling with olap) would introduce the security CUST_LEVEL = "Customer" filter Granularity of the result set returned would be for each customer. 1 card for each client meets the criteria of the VENDOR = "S1" and the CITY ("Athens", "Rome").

  Ideally, you should include the Cust Id columns quantity in your report of obiee answers and use a view/object of internal responses as a Pivot point of view to hide the column customer Details and get a localized aggregation staggered in the result set returned by OLAP to get the consolidated amount. Table of responses given at the customer level, answers Pivot can show the required result.

  Note1: The Cube cannot have this pre calculated result since it is a contradictory combination of filters in all hierarchies. Values of specific calculated level (or pre calculated) aggregation in the cube for level seller (h1) contain customers in all cities (h2) and same city level (h2) aggregates contain clients from all sellers (h1).

  Note 2: I believe OBIEE with OLAP modeling suffers from certain issues related to multiple hierarchies (for example: If you have the filter hierarchy by default only CITY ("Athens", "Rome"), I think it would always go for the lowest common level customer instead of the City level directly results).

  HTH
  Shankar

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  If I have a 1010 value two fields in a table COL1 and COL2 have a value of 0001.
  
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• Change the query to a display object

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  Hello

  You can switch the VO query editor based on an EO to expert mode. This allows you to change the entire query. Unless you change the use of the attribute, the update through this VO work. Open the VO query and choose the Expert mode option of the query to see what I mean

  Frank

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