Calculate a value for the years annually or monthly or quarterly
Hi gurus -.
I have a requirement to divide a given sum monthly/quarterly/annually in recent years, based on the date of departure. So I need the logic of pl/sql to achieve it. Please help me and let me know if the questions.
Here is my example:
Let's say amount = 240, date start = January 1, 2013, term = quarterly or annually / monthly, years = 5 years (so now I need to calculate the amount for five years from January 1, 2013 to 31 December 2017 and the output should like below)
Month | Monthly amount | Amount quarterly | Annually the amount |
January 1, 13 | 20 | 60 | 240 |
February 1, 13 | 20 | ||
March 1st, 13 | 20 | ||
April 1, 13 | 20 | 60 | |
May 1, 13 | 20 | ||
1 June 13 | 20 | ||
July 1, 13 | 20 | 60 | |
1 Aug 13 | 20 | ||
1-13-seven | 20 | ||
October 1, 13 | 20 | 60 | |
November 1, 13 | 20 | ||
1st December 13 | 20 | ||
1 January 14 | 20 | 60 | 240 |
February 1, 14 | 20 | ||
March 1, 14 | 20 | ||
1 April 14 | 20 | 60 | |
May 1, 14 | 20 | ||
June 1, 14 | 20 | ||
July 1, 14 | 20 | 60 | |
August 1, 14 | 20 | ||
1 sep-14 | 20 | ||
1st October 14 | 20 | 60 | |
November 1, 14 | 20 | ||
1 December 14 | 20 |
Thank you very much!!!
Hello
Maybe something like this:
WITH bs AS
(
SELECT 240 * 5 AS amt
, TO_DATE (JANUARY 1, 2013"
"LUN-DD-YYYY".
) AS special and differential treatment
12 * 5 AS total_payments
9 AS first_group
12 AS cycle_length
OF the double
)
SELECT TO_CHAR (ADD_MONTHS (special and differential treatment, level - 1)
"LUN-DD-YYYY".
) AS mnth
CASE
WHEN MOD (FLOOR - 1, cycle_length) = 0
THEN the LEAST (first_group
total_payments + 1 - LEVEL
) * amt / total_payments
WHEN MOD (FLOOR - 1, cycle_length) > = first_group
CAN amt / total_payments
Payment END AS
BS
CONNECT BY LEVEL<=>=>
;
Tags: Database
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