calculate the number of minutes

Hello citizens of oracle,

I have a situation where I have to calculate the number of minutes took to run the package. I've seen proc_log that will give me proc_name (give me the name of the proc), START_DT (which gives the time when the process began exactly) and EXEC_TIME (gives having plenty of time each process taken in minutes and seconds). So I need to make the sum of the column EXEC_TIME. Please help me how to do this.

Thanks for the help.

Sam

So, how do you intend to group on a varchar2 column? Can you change the view to the EXEC_TIME in an interval instead? Is even more logical design-wise.

Please post some examples of data so I can get an idea of the format for the varchar2 column.  Want to most likely to convert it to an interval to summarize time exec, or converting varchar2 int to exec_time in a few seconds, then convert minutes to maintain granularity.

NM, I see here the format, you are def going to need to set this view if you want to match the runtime.

You are with your format makes it incredibly hard perform such an easy task. Change this EXEC_TIME column in the view to an int of total of seconds or milliseconds of delay of performance or do this column, an INTERVAL DAY TO SECOND data type. Once you do this, you can do a 'SELECT sum (exec_time) FROM WHERE XX... »

Published by: TheDudeNJ on November 12, 2009 13:48

Published by: TheDudeNJ on November 12, 2009 13:49

Published by: TheDudeNJ on November 12, 2009 13:51

Tags: Database

Similar Questions

  • Calculate the number of days remaining until the next anniversary. Help, please!

    Hi guys,.

    I'm new to the forum and to the development of BB. So please do not judge harshly if the answer to my question seems obvious.

    I need to calculate the number of days until the next birthday (taking into account any valid birth date)

    After looking at the API and the forum search, I realized that I could

    calculate the difference between two dates in milliseconds and then divide the delta of the value of a day in milliseconds. That is to say:

    birthdayCalendar.set (Calendar.YEAR, those);

    Date1 = birthdayCalendar.getTime () .getTime ();

    date2 = System.currentTimeMillis ();

    Delta = date1 - date2

    numOfDays = delta\DateTimeUtilities.ONEDAY

    Here's my question. How do I create a valid date1 what about leap years?

    Maybe there's a better way to solve this problem?

    Any help is greatly appreciated.

    I agree that the determination of the number of days between today and Feb. 29 could be a little difficult, if it is not a leap year.  I suspect that the calendar has a certain built-in mechanism to compensate for this, but your solution to choose a date is better.

    DST has a role to play, and Yes, the calendar makes up for it.  Let us take two dates, for example (before DST) March 1 and June 1 (after the DST).  If you take a calendar and set the same hour, minute, etc., they are all the same except for dates, then subtract one from the other, and then divide by the number of milliseconds in 1 hour, you calculate the number of hours between the same time on two different days.  You will find that it is not a multiple of 24 hours - because there is actually an hour less than the number of days since the clocks move forward (in the northern hemisphere anyway...),

    In your case, you are not calculating the number of hours, you calculate the number of days.  But you will be dividing by [24 * (time in an hour)].  If you take [23 * (time in an hour)] and divide it by [24 * (time in an hour)], using arithmetic on integers, you will end up 0.  The easiest to get around this, who also works for the end of the DST too, is to simply add one hour to the date before the division.

    Hope that makes sense...

  • REQ: script to calculate the number of months

    Looking for a script that will calculate the number of months between 2 dates (to 2 decimal points)

    or if there is a way to make a calculation of the number of months

    for example: if I go to google and say 75 days - months, it returns a value of 2.46

    That's what I'm looking for

    If anyone can help?

    with a calculation of date or number calculation?

    I tried # days / 365 x 12 but there is no decimal places.  right guard rounded up/down

    As mentioned in a month, the days are not constant throughout the year and change formula 28-31 days. How are you calculating the decimal value of the month?

    A year has 365 days, if she did then there would be no need for leap years and centuries jump.

    Calculation of a variable with the result of a calculation method is set to decimal.

    cDateFormat = "d-mmm-yyyy";
    var cStartDate = "January 1, 2000;
    var oStartDate = util.scand (cDateFormat, cStartDate);
    oStartDate.setHours (0, 0, 0, 000);
    var cEndDate = "January 15, 2000;
    var oEndDate = util.scand (cDateFormat, cEndDate);
    oEndDate.setHours (0, 0, 0, 000);
    nDiff var = oEndDate.getTime () - oStartDate.getTime ();
    Console.println ("end date:" + cEndDate);
    Console.println ("start date:"+ cStartDate ");
    Console.println ("difference in milliseconds:" + nDiff);
    Console.println ("difference in seconds:" + nDiff/1000);
    Console.println ("difference in minutes:" + nDiff / (1000 * 60));
    Console.println ("difference in hours:" + nDiff / (1000 * 60 * 60));
    Console.println ("difference in days:" + nDiff / (1000 * 60 * 60 * 24));
    Console.println ("difference in weeks:" + nDiff / (1000 * 60 * 60 * 24 * 7));
    Console.println ("difference over the years:" + nDiff / (1000 * 60 * 60 * 24 * 365.2524));
    Console.println ("difference in months:" + nDiff / ((1000 * 60 * 60 * 24 * 365.2524) / 12));  12 months in a year;

    End date: January 15, 2000
    Start date: January 1, 2000
    Difference in milliseconds: 1209600000
    Difference in seconds: 1209600
    Difference in minutes: 20160
    Difference in hours: 336
    Difference in days: 14
    Difference of weeks: 2
    Difference in years: 0.0383296591617194
    Difference in months: 0.45995590994063273

    Several turncate the decimal values scirpts because keeping them may not meet the need of specific calculation. You know that there are methods to roud until the next iniger, round.5 to the top and turnacate to the lower intiger.

    According to the date of departure, the values may be different:

    For a start date of February 1, 2000, 75 days would be 1,810 months but for a start date of 1 February 2001 75 days becomes 1,838 since the number of days of changes of February 29 to 28 and the number of days for the month of fractions varies from 26 to 27.

  • How to change the number of minutes for the exercise of the activity of the application

    How to change the number of minutes for the exercise of the activity of the application

    Hello

    It is not currently possible to change the goal of daily exercise.

    If you want to suggest that Apple consider adding this option, you can submit a request here:

    https://www.Apple.com/feedback/watch.html

  • Calculate the number of fringes

    Is anyone know the feasibility of the use of the Machine Vision or LabView to calculate the number of fringes in each region? (Attached image). I want to count how many white line on each region. For example, on the attached picture, there are about 6 regions and each region will display the number of the white line in their own region. For information, I have V8.5 of LabView and NI Vision Assistant V8.5. Please, give me some ideas on how to solve it.

    Thank you.

    Farid

    Check this box

  • How to calculate the number of days/weeks/months between 2 dates?

    Hello

    I would like to know how to calculate the number of days/weeks/months between 2 dates in OBIEE 11 g, for example, I have 26/05/2013 and 19/05/2013, then I want to get 7 days.

    Thank you!
    Jamie

    Hi Jamie,

    Through this links...

    http://www.bravesoft.com/blog/?p=682
    http://twobiee.blogspot.in/2012/01/working-with-date-differences.html

    Mark as correct it allows u...
    Thank you...

  • Calculate the number of days between two dates

    Hello

    Can someone help please change my formcalc script to calculate the number of working days between two date fields.  My script currently calculates the total number of days between two dates, including the weekends which must be excluded from the total.

    If

    (HasValue (Start_Date1) & HasValue (End_Date1)) then

    $

    = Date2Num (End_Date1, "YYYY-MM-DD" "en_IE") - Date2Num (Start_Date1, "YYYY-MM-DD" "en_IE") + 1

    on the other

    ""

    endif

    Any help will be most appreciated.

    Thank you.

    Check...

    (1) you said that you put the script on the event «days1» calculate My sample imitates the variable names used in the original message, "Start_Date1" and "End_Date1". If the names of variables for the start and end dates are different, you will need to modify the script to account for these names.

    (2) the Date2Num functions in the calculation of the "totalDays" use the date format "YYYY-MM-DD". If your date habits differ from "YYYY-MM-DD" FormCalc will complain.

    Steve

  • HO to calculate the number of items in a ComboBox?

    HO to calculate the number of items in a ComboBox?

    I found a good solution
    I developed this method by myself and it my help all the people

    public void findComboIndex (criteria: String, combo: ComboBox): void
    {
    combo.selectedIndex = 0;
    var tempCriteria:String = ";
    While (combo.selectedLabel! = ")
    {
    If (combo.selectedLabel is criteria)
    {
    break;
    }
    If (combo.selectedLabel is chaineTemp)
    {
    combo.selectedIndex = - 1;
    break;
    }
    tempCriteria = combo.selectedLabel;
    combo.selectedIndex ++;
    }
    }

    Good luck

  • to calculate the number of days between 2 dates

    Hi all


    I need to calculate the number of days between 2 dates.
    Y at - it no oracle built on that basis.



    Thanks in advance
    Kind regards

    Nick

    user646786 wrote:
    Hello

    Thanks a lot its really useful, but I must make a correction, I just want weekdays rather working days

    As already said, there are many examples on the forum of the calculation of the working days or the days of the week or whatever you want between certain dates of restrictions. You will need to have a go at adapting what has already been given before and then when you get stuck, come here and your postcode, and someone will take a look for you.

  • How to calculate the number of Avg based on month

    Hi all

    I want to calculate Avg based on averages of the month

    Ex: i have made Total column
    current month like July Thn avg = total/7.
    then even report working in October than avg time = total/10.

    Any help.

    Thank you

    You must specify a digital for parameter 2. The Substring function takes the source from character string parameters and the length of the unit. In my example it will take the value of the variable current_month and returns the characters of the 8th position for 2 characters (so character 8 and 9). For example, instead of 'Time' happening. "" Month "you must pass the literal number 8. So I think the actual code you need is:

    SELECT "Applications and financial accounts. "" Value "/ CAST (SUBSTRING (VALUEOF ("CURRENT_MONTH") OF 8 TO 2) as INT)"financial accounts and Applications.

    NB I'm assuming that the value that you want to divide by the number of current month is called "Applications and financial accounts. "" Value ", please change it's column that you never use.

    Please mark it as useful to the answer

  • How to calculate the number of Out_flags for the PIPL?

    Hey everybody!

    I'm kinda new to After Effects of programming, so I hope I'm not asking an obvious question.

    I searched the web and this forum but just could not find a solution to this problem.

    Compilation of my plugin works fine, but as soon as I select it from the menu effects I am presented with an incompatibility error.

    My question (already in the title): how to calculate the correct number for the global_out_flags pipl?

    Thanks in advance,

    Markus

    If you want the easiest option, just start with the debugger and to break in the General preferences where is defined, or, if you find amusement in the bit and other Boolean arithmetic shift, please do not hesitate to look at the macro

  • How to calculate the number of bytes

    There is a general algorithm that calculates the total number of bytes in a pl/sql record?

    And dates may take up to 7 or 8 bytes (for data) with the data if they are a column on a table or not in function (this is to with internal C code date types)...

    SQL> select dt, dump(dt) from xx;
    
    DT
    --------------------
    DUMP(DT)
    ----------------------------------------------
    18-FEB-2011 15:00:35
    Typ=12 Len=7: 120,111,2,18,16,1,36
    
    SQL> select sysdate, dump(sysdate) from dual;
    
    SYSDATE
    --------------------
    DUMP(SYSDATE)
    ----------------------------------------------
    18-FEB-2011 15:01:04
    Typ=13 Len=8: 219,7,2,18,15,1,4,0
    
    SQL>
    
  • How do I get the number of minutes each

    Oracle DB 10

    Hi all


    I have using this query to get the number of records retrieved by the simultaneous min program,

    SELECT count (distinct b.attribute2)
    oe_order_headers_all a, oe_order_lines_all b
    where a.header_id = b.header_id
    and b.flow_status_code = 'AWAIT_QUINTIQ_BOOK. '
    and to_Char (b.last_update_date, 'DD-MON-YYYY HH24:MI:SS'), between January 19, 2011 02:00:01 ' AND
    JANUARY 19, 2011 02:00:02 '

    This allows to get the number of records retrieved in a min.

    How to find the count of the last 10 minutes, IE 1 mins County 2.00 to 2.10


    Thanks and greetings
    Srikkanth.M

    This South for minute work wise County:

    Select To_Char(b.last_update_date,'DD-MON-YYYY HH24:MI') DT, count (distinct b.attribute2)
    oe_order_headers_all a, oe_order_lines_all b
    where a.header_id = b.header_id
    and b.flow_status_code = 'AWAIT_QUINTIQ_BOOK. '
    and to_Char (b.last_update_date, 'DD-MON-YYYY HH24:MI:SS'), between January 19, 2011 02:00 ' AND
    "JANUARY 19, 2011 02:10.
    GROUP BY To_Char (b.last_update_date, 'DD-MON-YYYY HH24')

  • Dynamically calculate the number of days between two dates and amounts of split

    Hello

    I have searched for a solution for this, but had no success.
    I need to show the amounts broken down by days.

    I have a table that has an amount column and start and end dates.

    I need to write a query so that the amounts will be broken evenly based on the number of days between the start date and end date.

    For example, for this line.
    insert into my_test values (' 1, '' 3-mar-2010, ' 7 - mar - 2010 ", 1000);

    the query returns this (split $1,000 over 5 days)


    ID Date amount
    1 ' 3-mar-2010' 200,00
    1 ' 4-mar-2010' 200,00
    1 ' 5-mar-2010' 200,00
    1 ' 6-mar-2010' 200,00
    1 ' 7-mar-2010' 200,00



    create table my_test)
    ID number (10),
    start_date date,
    End_date date,
    amount number (10.2)
    );


    Select * from my_test

    insert into my_test values (' 1, '' 3-mar-2010, ' 7 - mar - 2010 ", 1000);
    insert into my_test values (2, 10-mar-2010 ", 19-mar-2010", 2000);
    insert into my_test values (3, 20-mar-2010 ',' 21-mar-2010, 5000);



    Thanks in advance.

    Hello

    One way is to join a Meter of Table , a table, or (more often) a set of results includes a line for eery number 1, 2, 3,... until the maximum number of times you need to divide a line.
    For example:

    WITH     cntr     AS
    (
         SELECT     LEVEL - 1     AS n
         FROM     (  SELECT  MAX (end_date - start_date)     AS max_day_cnt
                 FROM        my_test
              )
         CONNECT BY     LEVEL <= 1 + max_day_cnt
    )
    SELECT       t.id
    ,       t.start_date + c.n                    AS dt
    ,       t.amount / (t.end_date + 1 - t.start_date)     AS amt
    FROM       my_test      t
    JOIN       cntr            c     ON     c.n <= t.end_date - t.start_date
    ORDER BY  id
    ,            dt
    ;
    

    This assumes that all dates have the same number of hours, minutes, and seconds, as is the case in your sample data.
    If this isn't the case, then use TRUNC (start_date) and TRUNC (end_date) instead of start_date and end_date or post some sample data and results if some lines do not represent a whole number of days.

  • Calculate the number of days off weekends


    Hi all

    I have a requirement where I have to calculate the difference between two dates, excluding weekends and holidays. Is there a way I can do it in OBIEE analysis.

    Any help would be appreciated.

    Thanks in advance!

    Check it for weekends cool - bi.com

    For the holidays, you will need to customize you the size of the day

    check if help

Maybe you are looking for