Calculating pivot table problem

Similar Questions

• pivot table problem

  create the table mytable
  (
  name varchar2 (50).
  name varchar2 (50)
  )
  
  Insert the table mytable values ('mary', 'john')
  Insert the table mytable values ('mary', 'baby')
  Insert the table mytable values ('mary', 'lady')
  Insert the table mytable values ('sean', 'kate')
  Insert the table mytable values ('sean', 'terry')
  Insert the table mytable values ('kate', 'tom')
  Insert the table mytable values ('kate', 'lary')
  .
  .
  .
  
  my result of the query is
  
  last name first name
  Jean-Marie
  baby Marie
  Lady Mary
  Sean kate
  Sean Terry
  Tom Kate
  Kate lary
  
  I want to like this
  
  Mary kate sean
  
  John tom kate
  baby terry lary
  Lady
  
  
  It's not all data.
  the data are changeable.there are 3 name as name like sean John 2 2 lik kate and it will be 5 name like paul... I want as column name and surname as the data...
  Thanks for your help...
  
  

  Hello

  Try this:

  WITH     number_rows     AS
  (
       SELECT     name
       ,     surname
       ,     ROW_NUMBER () OVER
                 (     PARTITION BY     name
                      ORDER BY     surname
                 )     AS r_num
       FROM     mytable
  )
  SELECT     r_num
  ,     MAX (CASE WHEN name = 'mary'     THEN surname END)     AS mary
  ,     MAX (CASE WHEN name = 'sean'     THEN surname END)     AS sean
  ,     MAX (CASE WHEN name = 'kate'     THEN surname END)     AS kate
  FROM     number_rows
  GROUP BY     r_num
  ORDER BY     r_num;
  

  The output is not quite what you asked:

  .    R_NUM MARY       SEAN       KATE
  ---------- ---------- ---------- ----------
           1 baby       kate       lary
           2 jon        terry      tom
           3 lady
  

  You do not have to display r_num: I showed just to make things easier to understand.
  If the output should really include "Jean" rather than "jon", or if it should appear above 'baby', rather than below, so please explain.

  If the names in columns ("Mary", "sean" and "kate" in your sample data) should be determined at run time, you need dynamic SQL statements to generate a statement like the one above.
  The script below shows one way to do this in SQL * more.

  /*
  How to Pivot a Table with a Dynamic Number of Columns
  
  This works in any version of Oracle
  The "SELECT ... PIVOT" feature introduced in Oracle 11
  is much better for producing XML output.
  
  Say you want to make a cross-tab output of
  the scott.emp table.
  Each row will represent a department.
  There will be a separate column for each job.
  Each cell will contain the number of employees in
       a specific department having a specific job.
  The exact same solution must work with any number
  of departments and columns.
  (Within reason: there's no guarantee this will work if you
  want 2000 columns.)
  
  Case 0 "Basic Pivot" shows how you might hard-code three
  job types, which is exactly what you DON'T want to do.
  Case 1 "Dynamic Pivot" shows how get the right results
  dynamically, using SQL*Plus.
  (This can be easily adapted to PL/SQL or other tools.)
  */
  
  PROMPT     ==========  0. Basic Pivot  ==========
  
  SELECT     deptno
  ,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
  ,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
  ,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
  FROM     scott.emp
  WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
  GROUP BY     deptno
  ORDER BY     deptno
  ;
  
  PROMPT     ==========  1. Dynamic Pivot  ==========
  
  --     *****  Start of dynamic_pivot.sql  *****
  
  -- Suppress SQL*Plus features that interfere with raw output
  SET     FEEDBACK     OFF
  SET     PAGESIZE     0
  
  SPOOL     p:\sql\cookbook\dynamic_pivot_subscript.sql
  
  SELECT     DISTINCT
       ',     COUNT (CASE WHEN job = '''
  ||     job
  ||     ''' '     AS txt1
  ,     'THEN 1 END)     AS '
  ||     job
  ||     '_CNT'     AS txt2
  FROM     scott.emp
  ORDER BY     txt1;
  
  SPOOL     OFF
  
  -- Restore SQL*Plus features suppressed earlier
  SET     FEEDBACK     ON
  SET     PAGESIZE     50
  
  SPOOL     p:\sql\cookbook\dynamic_pivot.lst
  
  SELECT     deptno
  @@dynamic_pivot_subscript
  FROM     scott.emp
  GROUP BY     deptno
  ORDER BY     deptno
  ;
  
  SPOOL     OFF
  
  --     *****  End of dynamic_pivot.sql  *****
  
  /*
  EXPLANATION:
  The basic pivot assumes you know the number of distinct jobs,
  and the name of each one.  If you do, then writing a pivot query
  is simply a matter of writing the correct number of ", COUNT ... AS ..."\
  lines, with the name entered in two places on each one.  That is easily
  done by a preliminary query, which uses SPOOL to write a sub-script
  (called dynamic_pivot_subscript.sql in this example).
  
  The main script invokes this sub-script at the proper point.
  In practice, .SQL scripts usually contain one or more complete
  statements, but there's nothing that says they have to.
  This one contains just a fragment from the middle of a SELECT statement.
  
  Before creating the sub-script, turn off SQL*Plus features that are
  designed to help humans read the output (such as headings and
  feedback messages like "7 rows selected.", since we do not want these
  to appear in the sub-script.
  Turn these features on again before running the main query.
  
  */
  

• Running sum and Pivot Table graphics

  Hello Experts,
  I've shown measures execution of amounts in pivot table problem is when I try to pivotted results graphic I get the original values and not the running sum values. Is there a way to get around this or another way to do?
  
  Thank you
  
  Published by: ZaidN on June 29, 2010 07:20

  Do the following things.

  (1) to restart all services

  (2) use the resume function it shows the cumulative graph also

  (3) accumulation of usage view on measure it in pivot does ' t shows resume graphic because the sum of runnung dynamically apply in pivot table, but the table takes the column.

  ...................
  Vincent V

• reg: pivot table calculation

  Hello
  
  
  
  is there a way to get the average and total calculated in the pivot table based on a column?
  
  
  example,
  
  in the time of country state id
  
  in pivot, I want to calculate total and average for the country / state of time according to the number of id of country / state
  
  
  Thank you

  Yes, you can. Make use of elements calculated to reach.

• Problem with pivot table

  Hello.
  
  I have a pivot table, and it should update that I change the value of selectOneChoice. I can only view some data in a PivotTable when I choose a value for the first time in selectOneChoice. If I select another value in the SelectOneChoice the PivotTable that is not updated.
  
  Here is my PivotTable:
  

   
   <dvt:pivotTable id="pivotTable1"
                              value="#{bindings.TValoresMatrizEnViewUp1.pivotTableModel}"
                              binding="#{backingBeanScope.backing_valoresMatriz.pivotTable1}"
                              contentDelivery="immediate" var="matrix"
                              visible="false" partialTriggers="::socCodigo"
                              rendered="true" 
                             >
                <dvt:dataCell>
                  <af:inputText value="#{matrix.dataValue}"
                              valueChangeListener="#{backingBeanScope.backing_valoresMatriz.alteraPivot}"
                              autoSubmit="true"
                              partialTriggers="it5"
                              id="it5"/>
                              
                </dvt:dataCell>
              </dvt:pivotTable>

  Can someone help me?
  
  My JDeveloper is 11.1.1.4.0
  
  Thank you

  Hi Marcos,

  Open your page definition and together in the iterator tag refresh properties = 'always' and cacheResults = "false"...

  That that it will solve your problem.

  Kind regards

  Renan

• Calculation of pivot Table

  Hello
  
  I need to create a named calculation in a pivot table similar in total general on columns. However, I need to customize the calculation to perform on some lines and average amount on some lines.
  
  How can it be reached, the calculations will be appear in the same column for each row.
  
  Can anyone help?
  
  Thank you

  I don't know or force to try any time, but stuck in mind.

  Contribution - ID no
  9147.29 - 1
  1043.16 - 1
  Total 10190.45 - 2

  create a new column and write f (x) case when 1 = column_name 0 another amount (contribution) / sum (ID no.) end

  see you soon,
  KK

• For Timo: Dynamically create pivot table binding

  Hi Timo,

  Long time ago you have this announcement on a thread:

  "The solution for your use a 2013 DOAG case, I presented was to create binding table pivot out user defined attributes in the table."

  For the defined attributes, VO is created dynamically and the pivot link.

  The pivot link is exchanged during execution as well as the activation of the adequate VO Dynamics to get only the

  necessary data for the pivot table in particular.

  ......

  I can't give you a working example because it is too complex. I can make available slides, but they are in German. "

  We have the same problem.

  Can you please send me this presentation on: email address removed by the moderator - there is no private through this public forum consultation >

  I can't find this Presentation on the Internet.

  Maybe, if you have some examples of simple work, too.

  Kind regards

  Diana

  Diana, you can get the DOAG2013_DynamicPivotTable_virtual7 blades | JDev & ADF Goodies

  The sample is too complex to be made available through my blog.

  Timo

• Remove sorting in a Pivot table view

  Hi people,

  How to remove the column header sort options in the pivot table view?

  Thank you

  AJ

  You want to remove the small arrows on the column header in a pivot view?

  If so, the options are available in the analysis criteria tab. The problem is it cannot be set to a point of view, they perform the whole analysis

  In the criteria-> Properties tab right next to the filters and the stages of selection analysis-> Interactions tab.

  Mark, if this can help

• How to get the QDR of ADF Pivot table datacell

  JDeveloper 11.1.1.5 version
  Java 1.6
  The ADF faces
  
  I want to click commandlink in a data cell that sends the value of the header cells to a bean of support. I think that we must get the QDR of a clicked data cell, but how?
  
  I created the PivotTable: column headers consist of a variable number of dates; row headers consist of the names of the units. The data that cross are a percentage of variance using energy over time. (There is no calculation in the PivotTable, just displaying data from the view).
  
  ........ 11 Jan 12 13 Jan Jan jan 14. .etc
  Module-1 2.00 5, 25 - 9.30-11.15
  Unit-2 - 554.22 497.00 7.70 2.00
  Unit-3 10.00 - 5, 00 5.00 1.00
  
  To the cell above it with 497.00 value, the user must click this value (commandlink) and the bean 1) calculate the values of the unit and the date to use as parameter values for ExecuteWithParams under another iterator and 2) navigate to another page using this another iterator.
  
  It seems that the QDR (reference data) is involved, but can't find enough information about how to implement the same.
  
  Here are the PivotTable on the jspx:
  
  < dvt:pivotTable id = "pivotTable1".
  Summary = "reading analytical pivot table.
  value = "#{bindings." CdsaReadingsItfVwView1.pivotTableModel}.
  var = 'cellData.
  varStatus = "cellStatus" >
  < dvt:dataCell >
  < af:commandLink id = "cl".
  Text = "#{cellData.DataValue} '"
  action = "#{pivot_bean.commandlink_action}" / >
  < / dvt:dataCell >
  < / dvt:pivotTable >
  
  
  
  In the bean, we try to getPivotTable(), but it is always null.
  
  Any direction is welcome.
  
  David K

  Check how the PivotTable selection demo was created:
  http://jdevadf.Oracle.com/ADF-richclient-demo/faces/feature/PivotTable/pivotTableSelection.JSPX
  Code for this demo here:
  http://www.Oracle.com/technetwork/developer-tools/ADF/documentation/ADF-faces-RC-demo-083799.html

• Pivot Table guest issue

  Hello
  
  I can place the Pivot Table guest column does not display values section in the menu drop-down showing only a single value.
  
  Version is 11.1.1.6.4 OBIEE and Mozilla Firefox 19.0.2
  
  How to overcome this problem.
  
  THX,

  If the column contains more than 1 value then browser. Check in IE or Chrome.

• Calculate the % with the pivot table columns

  I created an application with these columns:

  Metric       Study          Fast          Slow       On-Target     Total
  ---------------------------------------------------------------------------------
  Metric1     Study1           1             0              0             1
  Metric1     Study2           1             0              0             1
  Metric1     Study3           0             0              1             1
  Metric1     Study4           0             0              1             1
  Metric1     Study5           0             1              0             1
  Metric1     Study6           0             1              0             1
  Metric1     Study7           0             0              1             1
  Metric1     Study8           0             0              1             1
  Metric1     Study9           1             0              0             1
  Metric1     Study10          1             0              0             1

  I want to create a pivot table looks like this.

  Metric          Fast     Slow      On-Target     Total      % Fast     % Slow   % On Target
  ------------------------------------------------------------------------------------------------------
  Metric1         4           2        4            10           40        20       40

  The fast, slow, on the target and Total columns are calculated fields. Picky, I'm having is to get the % columns to work. I also tried create columns % in the form of columns of the table, but at each level of study, the % is 100% or 0%.
  
  I tried with duplicate columns, all different options to display the value as. None of them worked.
  
  Could someone help me? The version of the OBI is 10.1.3.4
  
  Thank you
  
  Shi-ning
  
  Published by: SPUD on November 21, 2011 23:09

  Sounds like it. You will need the account of studies as a measure in the criteria. You could do something in the repository, but the fastest way is:

  Criteria:
  Add the study in (it will not go into the PivotTable)
  create new measure based on any existing measure that has the background you need with the formula:
  cases where [existing] is not null then 1 else 0 end

  This will give you 1 for each line that your measure in effect is valid. Add this new measure in the PivotTable and treat it as a normal amount.

• White column in responses: Pivot table see

  Hello
  
  Greetings to all here...
  
  I use Oracle Business Intelligence Suite Enterprise Edition 10.1.3.4.
  I have created a report, the problem is that it shows some columns as empty when I display the result in responses, Pivot table view, the technical details:
  Column name: sales - MTD
  The column formula: IFNULL ('-common measures ".") Business-MTD sales", 0.00)
  Aggregation rule: default
  
  sample data:
  JAN Feb customer account number
  7053 < white > 22.00
  
  Data for Jan present in the database, infact for January, the column is not non-existent in databased, Feb is present and is displayed correctly.
  
  The column is of type DOUBLE, I want to display 0.00 instead of white, asking for your help.
  
  I did a search in the forum, but could not get a solution.

  Try this,
  Go to your report, the column - common measures. "' Turnover - BAT" in data marker select custom format
  and put it in #, # 0;-#, # 0; 0
  I hope it will work.

  Concerning
  Blackburn

• Pivot table column alignment

  Hi all

  I use the Oracle 11 g database to develop my application.

  I've created a generic column report.

  For this I used the concept of PIVOT table.

  My example query is

  with pivot_data like)

  SELECT DEPTNO, JOB, SAL, BISHOP

  WCP

  )

  SELECT *.

  OF pivot_data

  PIVOT)

  SUM (SAL)

  FOR DEPTNO

  IN (& P90009000_LIST.)

  )

  This output is

  WORK BISHOP 10 20 30

  --------- ---------- ---------- ---------- ----------

  PRESIDENT 5000

  7902 800 CLERK

  7698 950 CLERK

  7788 1100 CLERK

  7782 1300 CLERK

  7698 5600 SELLER

  MANAGER 7839 2450 2975 2850

  7566 6000 ANALYST

  8 selected lines.

  but I need the output as below

  BISHOP OF WORK 10 20 30

  --------- ---------- ---------- ---------- ----------

  PRESIDENT 5000

  THE 800 7902 CLERK

  THE 950 7698 CLERK

  1100 7788 CLERK

  1300 7782 CLERK

  5600 7698 SELLER

  MANAGER OF 2450 2975 2850 7839

  6000 7566 ANALYST

  8 selected lines.

  Come 10,20,30 pivot columns

  How to do this in my application?

  Thank you

  Su.GI

  Thanks Solomon.

  I used the code below.

  His job very well.

  with pivot_data like)

  SELECT DEPTNO, JOB, SAL, & P90009000_LIST., BISHOP

  WCP

  )

  SELECT *.

  OF pivot_data

  PIVOT)

  SUM (SAL)

  FOR DEPTNO

  IN (& P90009000_LIST.)

  )

  Thank you

  Su.GI

• Sort data in pivot table

  Hi Experts,

  Here's the requirement I need to sort the text Text_field field say to sort this column, I called another field. Sort_Text_field.

  I have the pivot table as follows

  Can I sort Text_field even if Sort_Text_field is not in the PivotTable on the side.

  Thank you!

  	Month1-(Jan)	Month2-(Feb)
  Text_field	MetricValue1	MetricValue2

  
  Thank you!!

  Just in case if helps others. Tim Dexter tanks

  Follow this link: https://blogs.oracle.com/xmlpublisher/entry/new_skool_crosstabbing

  Customization

  One new feature that I discovered this week is the ability to show a single column and sort by another. I got a data set which was extracting the month abbreviations, we wanted to show for months through the top and headers of lines on the side. As you know XSL is not very good with dates, in particular recognizing the names of months. He just wants to sort them alphabetically, so, after comes before Jan, etc..
  A way around this is to generate a number of months to the sides of the month and which allows to sort. We can do that in the crosstab, unfortunately it is not exposed in the user interface still but its doable.

  Go back and take a look at the initial crosstab command. especially the line inputs and columns. There, you will find the sort criteria.

  "ProductsBrand {, o = a, t = t}, PeriodYear {, o = a, t = t}.

  Note these key commas inside the braces? Because there is no field that precedes them, this means that the crosstab should sort on the column before the brace that is PeriodYear. But you can insert another column in the data set to be sorted. For myself how I needed to work.

  <>" _Fund_Type_._Fund_Type_Sort_, o = a, t = n} ';' _Fiscal_Period__Amount__._Amt_Fm_Disp_Abbr_ {_Fiscal_Period__Amount__._Amt_Fiscal_Month_Sort_, o = a, t = n} ';' _Execution_Facts_._Amt_ ';' amount '? >

  Excuse the horribly verbose XML tags, good ol' BIEE: 0) emboldened columns are not in the table, but in the data set. I just open the field, dropped and changed the value type (t) is 'n', number, instead of the default 'a' and my crosstab started sorting how I wanted that it.

  If you find other tips and tricks, please share in the comments.

• Pivot table result without aggregate function

  Hi all

  We have the following two tables:

  SQL > select * from class;

  CLASS_ID COURSES

  ---------- ----------

  1          1

  2          1

  3          1

  2          2

  3          2

  5          2

  6 selected lines.

  SQL > select * of course.

  COURSE_ID

  ----------

  1

  2

  The customer needs the output in the following format:

  class class class class

  1                    1               2               3

  2                    2               3               5

  I considered using the operator pivot tables however they require the use of an aggregate function, but there is no aggregation only required in the result here - we demand that the output as would a PivotTable?

  Try this.

  WITH class(CLASS_ID,COURSE) AS)

  1.1 DOUBLE UNION ALL SELECT

  SELECT 2.1 DUAL UNION ALL

  SELECT 3.1 FROM DUAL UNION ALL

  SELECT 2.2 DUAL UNION ALL

  3.2 DUAL UNION ALL SELECT

  SELECT DOUBLE 5.2)

  SELECT * FROM)

  SELECT THE COURSE

  CLASS_ID,

  ROW_NUMBER () OVER(PARTITION BY COURSE ORDER BY COURSE) RN

  CLASS)

  PIVOT (MAX (CLASS_ID) for (RN) IN (1 as CLASS1, 2 AS CLASS2, CLASS3 AS 3));

  OUTPUT:

  CLASS CLASS1 CLASS2 CLASS3

  -------- ---------- ---------- ----------

  1          1          2          3

  2          2          3          5