Calculation for each 3 discs

Similar Questions

• Change the label after you check the sum of calculation for the column

  Hi all
  
  I have a crosstab report and I checked the 'sum of calculation' for each column and the total at the bottom. The label is 'full report '. How to change this label?
  
  Thanks in advance!

  On the attributes page of the report, in the region to break the formatting, you can put your text into the field "Display this text when printing of money to report".

• Calculation for table element, then replace in same table

  I have a 2D, c [j, i] table, and I want to perform calculations on each element of this array, c [j, I] = c [j, I] + d * one update [i], so that the same table with the new values.  I installed the structure using a loop and got back each new c [j, I] that I'm supposed to do, but I can't seem to get these new values into the table.  I tried to use the node 'Replace table subset' but I can't seem to connect the output to the same HP. array [j, I] table.

  Any help is greatly appreciated!

  Hi cmersit,

  Why do you need that for? You have not said before...

  Well, create a local to c [j, I], move it to the for loop and connect with the release of ReplaceArraySubset. It's going to hurt needs memory and processing speed and doesn't help here. Replace [result] with a local of c [j, I] for this example. Otherwise use a shift register in the outer loop!

• Calculated for absent complex the day of the week

  I need to find the number of days absent per employee according to the following criteria. I'll explain using test table as below.

  the table below contains the data for each employee per day in the pt_hrs column, if the hours = 0 means that it is not present for that particular day. Friday is a weekend for us.

  case 1,

  Normal case since it is present every day except Friday, there are no missing for him.

  Case 2,

  If the employee is absent from Thursday and he reported to duty Saturday, then Friday is considered to be absent.

  Case 3,

  If the employee comes back from vacation let tell it the spokesperson of service directly on Saturday, and then Friday is considered to be absent.

  Case 4

  If the employee is absent from Thursday and he reported to duty Sunday, then Friday is considered to be absent.

  [code]

  CREATE TABLE PT_ATTENDANCE_REG (PT_EMP_CODE VARCHAR2 (12), PT_DATE DATE, NUMBER OF PT_HRS);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('24/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('25/11/2015'), 7);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('26/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('27/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('28/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('29/11/2015'), 8);

  -case 2

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R002', TO_DATE('24/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R002', TO_DATE('25/11/2015'), 7);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R002', TO_DATE('26/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R002', TO_DATE('27/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R002', TO_DATE('28/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R002', TO_DATE('29/11/2015'), 8);

  -case3

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R003', TO_DATE('24/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R003', TO_DATE('25/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R003', TO_DATE('26/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R003', TO_DATE('27/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R003', TO_DATE('28/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R003', TO_DATE('29/11/2015'), 8);

  -CASE4

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R004', TO_DATE('24/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R004', TO_DATE('25/11/2015'), 7);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R004', TO_DATE('26/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R004', TO_DATE('27/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R004', TO_DATE('28/11/2015'), 0);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R004', TO_DATE('29/11/2015'), 8);

  -desired output will be as follows - R001 is not included because he was away for the weekend only.

  PT_EMP_CODE, NO_OF_DAYS_ABSENT

  'R002'                     2

  'R003'                     4

  'R004'                     3

  [/ code]

  Hello

  Arif75 wrote:

  ...

  CREATE TABLE PT_ATTENDANCE_REG (PT_EMP_CODE VARCHAR2 (12), PT_DATE DATE, NUMBER OF PT_HRS);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('24/11/2015'), 8);

  INSERT INTO PT_ATTENDANCE_REG (PT_EMP_CODE, PT_DATE, PT_HRS) VALUES ('R001', TO_DATE('25/11/2015'), 7);

  ,,,

  Thanks for posting of sample data, but always use 2 arguments when calling TO_DATE.  The TO_DATE call with 1 single argument has all the problems of an implicit conversion.

  Thus, a person is considered on Friday that if he was absent the day before or the day after, isn't it?

  Here's a way to do it:

  WITH got_absent AS

  (

  SELECT pt_emp_code

  pt_date - necessary only for date filtering

  CASE

  WHEN pt_hrs > 0

  THEN 0

  WHEN TO_CHAR (pt_date

  , "DY".

  'NLS_DATE_LANGUAGE = ENGLISH'

  ) <> 'FRI'

  THEN 1

  HOW much MONEY (SIGN (pt_hrs)) OVER (PARTITION BY pt_emp_code

  ORDER BY pt_date

  BETWEEN 1 PRECEDING

  AND 1 SUITE

  )<>

  THEN 1

  0 OTHERWISE

  END as absent

  OF pt_attendance_reg

  -WHERE... - most filtering can go here

  )

  SELECT pt_emp_code

  SUM (absent) AS no_of_days_absent

  OF got_absent

  WHERE the absent > 0

  - AND pt_date > = TRUNC (SYSDATE, 'MONTH') - Date of filtering goes here

  GROUP BY pt_emp_code

  ORDER BY pt_emp_code

  ;

  Output:

  PT_EMP_CODE NO_OF_DAYS_ABSENT

  ------------ -----------------

  R002                         2

  R003                         4

  R004                         3

  This assumes that there is exactly 1 row for each person, each day and that pt_hrs > = 0.

  If the first date to a person is be a Friday, then that person is not counted as present the day before.  Similarly, if the last day is a Friday, they will not be considered as present the next day, so they can be counted as absent on Friday, even though they were not really missing the Thursday or Saturday.  This can be important if you filter by dates.  Most filtering can be done in the subquery, but filtering dates must be done later, after the analytical function of the SUM is calculated.

• analyze two times for each run?

  Oracle 11.2.0.3 Std Ed One

  Oracle Linux 64-bit 5.6

  New guy was trying to use MS Data Integrator for 1.7 million lines of charge of MSSQL to Oracle.  Process took more than 4 hours.  I started an on the session 10046 trace, let it run for about 5 minutes, then produced the report tkprof.  As I expected, the process was slow-by-slow transformation, issuing an INSERT for each line.  But what I wasn't expecting, it is the count analysis was twice the number of execution.  I am at a loss to explain this.

  call

  County

  central processing unit

  elapsed

  disc

  query

  course

  lines

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  Parse 83226	1.21	1.21	0	0	0	0
  Run 41613	41,41	43.19	5	41732	282786	41613
  Go get 0	0.00	0.00	0	0	0	0

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  Total 124839

  42,62

  44,41

  5

  41732

  282786

  41613

  Chess in the library during parsing cache: 1

  Lack in the library during execution cache: 1

  Optimizer mode: ALL_ROWS

  I convinced the new guy to let me write a simple PL/SQL proc to do an INSERT... SELECT and it ran in under 4 minutes...  but I'm still curious about this count analysis.  In fact, I'm a bit puzzled by the results on my proc as well.  This time, 1 run (as expected) but ZERO parsed?

  call

  County

  central processing unit

  elapsed

  disc

  query

  course

  lines

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  Parse	0	0.00	0.00	0	0	0	0
  Run	1	106.03	193.34	14	484982	2433678	739292
  Fetch	0	0.00	0.00	0	0	0	0

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  total

  1

  106.03

  193.34

  14

  484982

  2433678

  739292

  Chess in the library during parsing cache: 0

  Lack in the library during execution cache: 1

  Optimizer mode: ALL_ROWS

  The analysis of the user id: 656

  (recursive depth: 1).

  Clearly it 'parse' without 'run '.

  I've seen this before.

  Here is an example how it occurs when:

  SQL statement with some analysis but no executions or extraction on the remote database SQL Distributed (Doc ID 580301.1)

  Analysis number is high, but no executions (Doc ID 1335913.1)

• What is a difference between 'Logical processors' and 'logical processors for each host?

  Hi all!

  In the official document VMware "vsphere-51-configuration-maxima" or "vsphere-55-configuration - maximums.pdf" in the section "ESXi host maximum rates------Maximums calculation" exists in the elements:

  "Maximum CPU------logical CPU for each host ' (vSphere 5.1: 160;)   vSphere 5.5: 320)

  and

  "Machine virtual maximums------virtual CPU by host ' (vSphere 5.1: 2048;)    vSphere 5.5: 4096)

  Question: what is the difference between the two?

  And a more complex thing to maximum rates:

  Virtual machines per host: 512

  Number of hosts per cluster: 32

  Therefore, the cluster may be Virtual Machines (maximum): 521 * 32 = 16384

  But in the document, we have only 4000 VMs in maximum.

  Why?

  Thank you

  Ramirez,

  I understand your question as difference between 1. logic virtual CPU vs / by the hosts and 2. cluster/host Max County VM.

  Consider the case below;

  2 servers ESXi - 20 mV

  ESXi taken 1-4, 2 cores / socket

  ESXi 2-8 Sockets, 2 cores / socket

  Now here number of CPU logic-(4 x 2) + (8 x 2) = 24

  20 virtual machines - 2 jacks, 2 core / socket

  Virtual CPU count - 20 x (2 * 2) = 80

  Hope your first confusion is clear now.

  And a more complex thing to maximum rates:

  Virtual machines per host: 512

  Number of hosts per cluster: 32

  Therefore, the cluster may be Virtual Machines (maximum): 521 * 32 = 16384

  But in the document, we have only 4000 VMs in maximum.

  Why?

  This means that even if you have 32 Guest and each host can accommodate 512 VMs each the maximum number of virtual machines per cluster may not exceed 4000. And it does not mean that you can have a maximum of VMS (512 * 32).

  ~ dGeorgey

• Why pre-rendered footage get a new one made once again for each play or preview?

  Dear Sir/Mdm,

  I'm a novice, please bear with me.

  I use an Asus laptop with:

  1 CPU: Intel i5-3337U @ 1.80 GHz (4 processors)

  2. operating system: 8.1 Windows 64-bit (6.3, build 9600)

  3 RAM: 8 GB

  4 DirectX: Version 11

  5 edge graphics: Intel HD 4000

  6 dedicated graphics card: GeForce GT 740 M

  7 memory dedicated video: 2048 MB DDR3

  8 Nvidia Driver version: 6.14.13.3523
  

  9 total available graphics memory: 4096 MB

  
  

  I was hoping to avoid made repeated segments of images during RAM glimpses, through scrub or proofreading.

  
  

  I wrote before the associated layers of segments filled and pre-rendered the pre-comp, who gave a sequence (in AVI format) to replace the demo.

  
  

  But when I scrub through, reading (space) or do we RAM previews, pre-rendered footage Gets a new rendering even once (for each scrub-via/preview/reading).

  Need advice.

  Thank you.

  
  

  You wrong understand how Premiere Pro handles transitions and reading. Transitions, if the codec of the original film supports, can be rendered in real time, if the source codec is not, they are rendered when you preview so that the program window, the place watch you your video edited, acts as an existing media for the video player. Through playback engine is capable of reading multiple streams of video at the same time by using the Mercury playback engine.

  After Effects is a software of compositing that pixels in layers and perform math on each pixel. If you have cache enabled and then rendered frames are not re-renderings when redo you the ram preview, but if you make any change in the scenario, everything from that point forward must be returned again because there is no easy way say which pixels will change in the layers after you make a change without the calculations.

  AE is a great tool to produce the plans and short sequences, but it was never intended to be used as an editing program to assemble movies. It is simply not the right tool for this. Editing and Compositing integration will improve as both AE are more closely integrated, but it's like that with all of the software used to create a movie. Compositing is a separate operation of the Assembly, and they are managed differently.

• How to maintain a sequence of number for each execution of the view

  Hi all
  
  I would like to implement a vision that returns the sequence number (say, at 1 and increment a (num = num + 1)) for each performance.
  
  for example, first, it should be 1 and then for the excution second it takes 2...
  
  What is the best way to implement this scenario?
  
  Please advice me...
  
  Thank you

  You cannot do it directly:

  SQL> create sequence s
    2  /
  
  Sequence created.
  
  SQL> create view s_view
    2    as
    3      select  s.nextval s_value
    4        from  dual
    5  /
      select  s.nextval s_value
                *
  ERROR at line 3:
  ORA-02287: sequence number not allowed here
  

  You could:

  SQL> create or replace
    2    function s_func
    3      return number
    4      is
    5          v_retval number;
    6      begin
    7          select  s.nextval
    8            into  v_retval
    9            from  dual;
   10          return v_retval;
   11  end;
   12  /
  
  Function created.
  
  SQL> create view s_view
    2    as
    3      select  s_func s_value
    4        from  dual
    5  /
  
  View created.
  
  SQL>  
  

  However, sequence will be calculated that whenever view column is referenced:

  SQL> select  ename,
    2          s_value
    3    from  emp,
    4          s_view
    5  /
  
  ENAME         S_VALUE
  ---------- ----------
  MILLER              1
  CLARK               2
  KING                3
  ADAMS               4
  SMITH               5
  JONES               6
  FORD                7
  SCOTT               8
  JAMES               9
  MARTIN             10
  WARD               11
  
  ENAME         S_VALUE
  ---------- ----------
  ALLEN              12
  BLAKE              13
  TURNER             14
  
  14 rows selected.
  
  SQL>  select  ename,
    2           s_value,
    3           s_value
    4    from  emp,
    5          s_view
    6  /
  
  ENAME         S_VALUE    S_VALUE
  ---------- ---------- ----------
  MILLER             15         16
  CLARK              17         18
  KING               19         20
  ADAMS              21         22
  SMITH              23         24
  JONES              25         26
  FORD               27         28
  SCOTT              29         30
  JAMES              31         32
  MARTIN             33         34
  WARD               35         36
  
  ENAME         S_VALUE    S_VALUE
  ---------- ---------- ----------
  ALLEN              37         38
  BLAKE              39         40
  TURNER             41         42
  
  14 rows selected.
  
  SQL> 
  

  You could create the deterministic function, but it does not guarantee still sequence value will be calculated once per request.

  SY.

• Where is 'Create a separate record for each volume' past? in VMware-converter - 4.0.1 - 161434.

  Where is 'Create a separate record for each volume' past? in VMware-converter - 4.0.1 - 161434 (independent). Option is not more than 4 converter?

  Hello.

  When you get to the third tab called "View/Edit Options", choose the Edit option for 'Data to copy.'  Then choose the option advanced at the end of the menu "data copy type" and then use the options on the page layout tab target to assign separate discs.

  Good luck!

• Use of user track in buckets of 48 hours for each month

  I have an obligation to follow the use by the user in buckets of 48 hours for each month. For example, from midnight on 1st Oct, create buckets of 48 hours thanks to 23:59 on 31 Oct. For each user, how many times they use the system in each bucket 48 hours? I try to avoid PL/SQL, if I can so right SQL is preferred. Thank you very much in advance for your help.
  
  Usage_Table (sample data)
  
  ID User_Name Create_DateTime
  
  This last 100 10/01/11 00:01:58
  This last 101 01/10/11 01:02:31
  102 user_B 02/10/11 14:44:32
  This last 103 04/10/11 08:21:11
  This last 104 04/10/11 03:10:20
  105 user_B 05/10/11 12:50:30
  106 and user_a 07/10/11 13:45:10
  107 and user_a 07/10/11 18:22:08
  
  
  Example of output
  
  User_name From_DateTime To_DateTime Number_Of_System_Uses
  This last 10/01/11 00:00:00 02/10/11 23:59:59 2
  user_A 03/10/11 00:00:00 04/10/11 23:59:59 2
  user_B 10/01/11 00:00:00 02/10/11 23:59:59 1
  user_B 10/04/11 00:00:00 05/10/11 23:59:59 1
  and user_a 10/06/11 00:00:00 07/10/11 23:59:59 2

  Hello

  JoeCO wrote:
  ... I tried the outer join, but did not see the number 0. I'll keep playing with it.

  Sorry, my mistake. It was not nearly as simple as I said earlier. JOIN EXTERNAL means that all ranks of the cntr will appear in the result set at least once, but we need every line of cntr appear joining each month and user_name at least once, we can do with a partitioned outer join:

  WITH     cntr     AS
  (
       SELECT     2 * (LEVEL - 1) AS low_val
       ,     2 *  LEVEL     AS high_val
       FROM     dual
  --     CONNECT BY     LEVEL     <= 16     -- Max buckets in any month
       CONNECT BY     LEVEL     <=  4     -- For testing only
  )
  ,     got_month_start     AS
  (
       SELECT     user_name
       ,     create_datetime
       ,     TRUNC (create_datetime, 'MONTH')     AS month_start
       FROM     t_usage
  )
  SELECT       u.user_name
  ,       u.month_start + c.low_val     AS bucket_start_date
  ,       u.month_start + c.low_val
                 + 2
                 - (1 / (24 * 60 * 60))
                           AS bucket_end_date
  ,       COUNT (u.create_datetime)     AS number_of_system_uses
  FROM             cntr            c
  LEFT OUTER JOIN      got_month_start  u  PARTITION BY ( u.user_name
                                  , u.month_start
                                  )
                           ON  ( u.create_datetime
                               - u.month_start
                               )     BETWEEN     c.low_val
                                AND     c.high_val
  GROUP BY  u.user_name
  ,       u.month_start
  ,       c.low_val
  ORDER BY  u.user_name
  ,       bucket_start_date
  ;
  

  As you can see, I also moved the calculation of TRUNC (create_datetime, 'MONTH') in a subquery.
  I only showed the frist 4 buckets, just to simplify somewhat the exit during the original trial. The result is:

  `                                              NUMBER
                                                   _OF_
                                                 SYSTEM
  USER_N BUCKET_START_DATE   BUCKET_END_DATE      _USES
  ------ ------------------- ------------------- ------
  user_A 10/01/2011 00:00:00 10/02/2011 23:59:59      2
  user_A 10/03/2011 00:00:00 10/04/2011 23:59:59      2
  user_A 10/05/2011 00:00:00 10/06/2011 23:59:59      0
  user_A 10/07/2011 00:00:00 10/08/2011 23:59:59      0
  
  user_B 10/01/2011 00:00:00 10/02/2011 23:59:59      1
  user_B 10/03/2011 00:00:00 10/04/2011 23:59:59      0
  user_B 10/05/2011 00:00:00 10/06/2011 23:59:59      1
  user_B 10/07/2011 00:00:00 10/08/2011 23:59:59      0
  
  user_C 10/01/2011 00:00:00 10/02/2011 23:59:59      0
  user_C 10/03/2011 00:00:00 10/04/2011 23:59:59      0
  user_C 10/05/2011 00:00:00 10/06/2011 23:59:59      0
  user_C 10/07/2011 00:00:00 10/08/2011 23:59:59      2
  

• Determine a value for each record for the whole group

  < < Sorry I pasted erroneous results earlier > >
  
  Hello
  
  I have a table (in production, join the many tables, but for simplicity, I created a table), which has a few related accounts grouped by ACCT_GRP_ID I have to write a SQL (not a PL/SQL), who should have all columns of this table and an extra column "FLAG". For GA_CD = BBC, FLAG must have a value of 'No Show', if the APP_DT of at least a recording with the group is less than the current year also all the records in the group will have a value of 'Show '. For the record no BBC FLAG must always be 'Show '.
  
  DDLS
  {code}
  CREATE TABLE ACCOUNTS
  (NUMBER OF ACCT_GRP_ID,
  GA_CD VARCHAR2 (10),
  AGNT_NAME VARCHAR2 (50).
  NUMBER OF CASE_NUM
  NUMBER OF FUND_AMT
  DATE OF APP_DT,
  STATUS VARCHAR2 (10));
  
  INSERT INTO ACCOUNT VALUES (1, 'BBC', 'SAMANTHA, JOSE, 12345, 234.33, 2 AUG 2008', ' PLACED');
  INSERT INTO ACCOUNT VALUES (1, 'BBC', 'SAMANTHA, JOSE, 12346, 331,13, 24 APR 2009', ' PLACED');
  INSERT INTO ACCOUNT VALUES (1, 'BBC', 'SAMANTHA, JOSE, 12347, 201,27, 13 FEB 2009', ' PLACED');
  INSERT INTO ACCOUNT VALUES (2, 'BBC', ' MARK, ROSS, 12348, 98.12, 31 MAY 2009', 'PLACE' ");
  INSERT INTO ACCOUNT VALUES (2, 'BBC', ' MARK, ROSS, 12349, 121.00, 25 JUNE 2009', 'PLACE' ");
  INSERT INTO ACCOUNT VALUES (2, 'BBC', 'BRAND, ROSS, 12350, 11.00, 27 JUNE 2009', 'CLOSED');
  INSERT INTO ACCOUNT VALUES (3, 'BBC', "RAJ MALIK", 12351, 89.00, 31 DEC 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (3, 'BBC', "RAJ MALIK", 12352, 22.00, 26 OCT 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (4, 'BBC', 'SHANE, WILLS', 12353, 443.00, 7 JUNE 2009', 'PLACE');
  INSERT INTO ACCOUNT VALUES (5, 'BBC', 'JANE, WALLACE, 12354, 74.00, 17 JAN 2009', ' PLACED');
  INSERT INTO ACCOUNT VALUES (NULL, 'BBC', 'ROSY, BETH', 12355, 124.00, 21 MAR 2009', 'PLACE');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'TINA, WZWICK', 22330, 89.00, 31 DEC 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'YANA, KORVIN', 27351, 22.00, 26 OCT 2008', 'PLACED');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'SARA, YUI', 22352, 443.00, 7 JUNE 2009', 'PLACE');
  INSERT INTO ACCOUNT VALUES (NULL, 'STAR', 'MIKE, TROY, 22453, 74.00, 17 JAN 2009', ' PLACED');
  
  COMMIT;
  {code}
  
  Required result:
  {code}
  APP_DT GA_CD AGNT_NAME STATE BOITE_ FUND_ ACCT_ INDICATOR
  AMT NUM GRP_ID
  1 SAMANTHA, JOSE PLACE 12347 201.27 BBC 13/02/2009 no show
  1 SAMANTHA, JOSE PLACE 12346 331.13 BBC 24/04/2009 no show
  1 SAMANTHA, JOSE PLACE 12345 234.33 BBC 08/02/2008 no show
  MD2 BBC BRAND, ROSS CLOSED 12350 11 6/27/2009 see the
  MD2 BBC BRAND, ROSS PLACED 12349 121 6/25/2009 see the
  2 BRAND of BBC, ROSS PLACE 12348 98.12 show of 31/05/2009
  3 BBC RAJ MALIK not PLACED 12352 22 10/26/2008 no show
  3 BBC RAJ MALIK not PLACED 12351 89 12/31/2008 no show
  4 BBC SHANE, WILLS PLACE 12353 443 6/7/2009 see the
  5 BBC JANE, WALLACE PLACE 12354 74 1/17/2009 see the
  STARS of MIKE, TROY PLACED 22453 74 1/17/2009 see the
  See the BBC ROSE, BETH PLACED 12355 124 3/21/2009
  STAR SARA, YUI PLACED 22352 443 6/7/2009 see the
  TINA, WZWICK STAR PLACED 22330 89 12/31/2008 see the
  YANA STAR, KORVIN PLACED 27351 22 10/26/2008 see the
  {code}
  
  As in the results Group 1 has a record with the date of 2008 for the whole group getting 'No Show'. Group 2 has all the records this year, so he gets the 'Show '.
  Help, please!
  
  Published by: Kuul13 on June 25, 2009 13:31
  
  Published by: Kuul13 on June 25, 2009 13:43
  I think I'm really having a BAD BAD day... Sorry again... I don't need the domain TOT_FUND_AMT...

  Hello

  Thanks for posting the DDL and DML statements. This helps a lot.

  I don't understand the output, however. Do you want to really two rows of output for each row in the table? The tot_fund_amt is copied from somewhere else? More important still, the results do not include the new flag column. Isn't the point of all of this question? It's good to describe how the indicator is calculated, but you have to show, too.

  I think you want analytical MIN function to find the first app_dt in each group, like this:

  SELECT  a.*
  ,     CASE
            WHEN  ga_cd = 'BBC'
            AND   MIN (app_dt) OVER ( PARTITION BY  ga_cd
                                        ,              acct_grp_id
                                      )  < TRUNC (SYSDATE, 'YYYY')
                  THEN  'No Show'
                  ELSE  'Show'
       END     AS flag
  FROM     accounts   a
  ;
  

  Output:

  . ACCT
    _GRP GA                     CASE     FUND
     _ID _CD  AGNT_NAME         _NUM     _AMT APP_DT     STATUS FLAG
  ------ ---- --------------- ------ -------- ---------- ------ -------
       1 BBC  SAMANTHA, JOSE   12345   234.33 08/02/2008 PLACED No Show
       1 BBC  SAMANTHA, JOSE   12346   331.13 04/24/2009 PLACED No Show
       1 BBC  SAMANTHA, JOSE   12347   201.27 02/13/2009 PLACED No Show
       2 BBC  MARK, ROSS       12348    98.12 05/31/2009 PLACED Show
       2 BBC  MARK, ROSS       12349   121.00 06/25/2009 PLACED Show
       2 BBC  MARK, ROSS       12350    11.00 06/27/2009 CLOSED Show
       3 BBC  RAJ, MALIK       12351    89.00 12/31/2008 PLACED No Show
       3 BBC  RAJ, MALIK       12352    22.00 10/26/2008 PLACED No Show
       4 BBC  SHANE, WILLS     12353   443.00 06/07/2009 PLACED Show
       5 BBC  JANE, WALLACE    12354    74.00 01/17/2009 PLACED Show
         BBC  ROSY, BETH       12355   124.00 03/21/2009 PLACED Show
         STAR TINA, WZWICK     22330    89.00 12/31/2008 PLACED Show
         STAR SARA, YUI        22352   443.00 06/07/2009 PLACED Show
         STAR MIKE, TROY       22453    74.00 01/17/2009 PLACED Show
         STAR YANA, KORVIN     27351    22.00 10/26/2008 PLACED Show
  

  Note that the NULL acct_grp_id is a group. PARTITION BY acct_grp_id is of course necessary, but we must also, PARTITION BY ga_cd all non-BBC lines will be included in this group. In other words, we are unwilling reported as 'No Show', all ROSY just because TINA or JANA had an early app_dt.

• Order a different number of prints for each image

  If there is a way to order prints of different images different number?

  Say I want to order a print of all my images in a collection of 4 x 6, simple enough.

  Then, I want to order some of them also in format 8 x 10, also quite simple.

  But what I can't find out how to order say;  3 copies of the #4 8 x 10 image, 2 copies of the #5 8 x 10 image and 10 copies of the image #14 in 8 x 10.

  Something I m missing?

  Any help is appreciated.

  Thanks in advance.

  • The options button lets you change the number of prints for each selected photo.
  • The 'add pictures and change print sizes' button allows you to add additional formats and you can even select different amounts for each size.

  See this help page: https://help.apple.com/photos/mac/1.0/?lang=en#/pht6e15ea68

  

• Why I have to return my password for each song I buy on iTunes

  At some point, iTunes began to requires me to enter my password for each song I buy.  Usually, I do the search and buy on my Windows 7 desktop.  I scoured my account looking for an explanation on why he has changed, but I think not all the controls that I maybe changed.  Always in the past, once that I registered on my account, I could buy all the pieces I want without another password to sign in.   This change took place a few months ago.

  Thank you

  Barb
  

  This article may help:

  Manage your iTunes Store and App Store - Apple Support password preferences

  Read very carefully to see what password of the options you can set (especially with the Touch ID).

• The sum of total revenue for each customer unique and graphic it!

  Sunny greetings from Athens!  I walked for 5 hours for an elegant solution to the following:

  I want to add the total amount of revenue for each customer unique and graphic to view what customers bring in most of the species.

  Example of this in it:

  Customers	Charged €
  A	100
  B	200
  C	250
  A	130
  A	120
  B	100

  Customers	Total €
  A	350
  B	300
  C	250

  How this can be implemented by the numbers? As elegantly as possible?

  Hi menick,.

  SUMIF () will do the job.

  

  the formula in table 2::B2 =.

  SUMIF (table 1::A, A2, table 1::B)

  It is filled down.

  Quinn

• I do my job to the computer on a MAC computer. I want to create a document using Pages and then convert the document to PDF and send a group email. I want to send the PDF using the pdf for each receiver icon must click the icon to open t

  I do my job to the computer on a MAC book PRO. I want to create a document using Pages and then convert the document to PDF and send a group email. I want to send the PDF using the pdf for each receiver icon must click the icon to open the document. My problem is the document does not show the icon, but rather the document is already open. I spoke with 2 Apple. 'Experts' care and can help me. Can someone tell me what to do?

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