Calculation of the time differences between several lines

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• calculate the time difference between several lines

  Hello

  I have a table as below:

  create table select TEST_CASETBL (ID, CASE_NUM, CASE_STATUS, CASE_SUB_STATUS, LAST_UPD_DTTM)

  112, 123-456', 'open', 'Work', TO_DATE (11 March 2015 13:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  113, 123-456', 'Open', 'pending on the admin', TO_DATE (10 January 2015 15:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  114, 123-456', 'Open', 'client expectation', TO_DATE (10 July 2015 09:00 ',' hh24:mi:ss' of dd/mm/yyyy) of the DUAL union all select them

  315, 123-456', 'open', 'Work', TO_DATE (September 15, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  219, 123-456', 'Open', 'pending on the admin', TO_DATE (January 9, 2015 08:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  651, 123-456', 'open', 'Work', TO_DATE (August 20, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') from DUAL;

  I would like to calculate the duration total (days ideally) to CASE_SUB_STATUS, so have a set of lines:

  CASE_NUM of work waiting on admin waiting on customer

  -------------------------------------------------------------------------------------------------------------------------------------------------------

  123-456 70days 6 hours

  Here is the explanation of the pattern:

  ex: for everyday business computing (timestamp timestamp of ID:651 - ID:219) +(timestamp of ID:315-timestamp of ID:114) + (ID:112 stamp - current_time) = 11 days + 21 days 22hrs 23hrs 36 days 9 hours

  still waiting on admin

  (ID:219 timestamp - timestamp of ID:315) + (ID:113 timestamp - timestamp of ID:112)

  still waiting on the client

  (ID:114 timestamp - timestamp of ID:113)

  I would appreciate any idea how to solve this, ideally as an SQL

  Thank you

  Should he not?...

  with test_casetbl (id, case_num, case_status, case_sub_status, last_upd_dttm) as)

  Select 112, 123-456', 'Open', 'Work', TO_DATE (11 March 2015 13:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 113, 123-456', 'Open', 'pending on the admin', TO_DATE (10 January 2015 15:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 114, 123-456', 'Open', 'client expectation', TO_DATE (10 July 2015 09:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 315, 123-456', 'Open', 'Work', TO_DATE (September 15, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 219, 123-456', 'Open', 'pending on the admin', TO_DATE (January 9, 2015 08:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 651, 123-456', 'Open', 'Work', TO_DATE (August 20, 2015 10:00 ',' the hh24: mi: ss' dd/mm/yyyy) double

  ),

  t like)

  Select case_num,

  case_sub_status,

  (last_upd_dttm, 1, sysdate) ahead of diff last_upd_dttm (partition by order of last_upd_dttm case_num).

  of test_casetbl

  )

  Select case_num,

  trunc (a) | "day (s). TO_CHAR (date ' 1-1-1' + a, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") "work."

  trunc (b) | "day (s). TO_CHAR (day 1-1-1' + b, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") 'Waiting on admin',

  trunc (c) | "day (s). TO_CHAR (day 1-1-1' + c, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") "waiting on customer."

  t

  pivot)

  Sum (diff)

  for case_sub_status in)

  'Work' is.

  B "waiting on admin',

  C "customer expectation."

  )

  )

  CASE_NUM	Working	Waiting on admin	Waiting on customer
  123-456	63 day (s) 22 hour (s) (s) 50 minute 49 second (s)	19 day (s) on 20 (s) hour 0 minute 0 second (s)	27 day (s) on 4 hour (s) 0 minute 0 second (s)

• How do the time difference between two dates?

  Hi all
  
  I use this query to get the time difference between two dates.
  
  Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;
  
  but do not get the correct result.
  
  Thank you

  Left KEY... Left Padding of tanks.

• How to set the time difference between each data when using keithley 2400 scanning

  Hello friends,

  I use scanning Keithley vi the extent of SCANNING and acquire vi. I want to measure the voltage for each step and a pause between each two data, so I need a delay between each I step.

  I'm a starter to use Labview, thank you very much for your answers.

  Perry

  As Dennis says, if you use the built-in scan function, you will need to consult the manual. See Section 10-16 (this is page 10 of article 16, only paragraphs not but 10, 16) for the manual Keithley 2400.

  The Keithley 24xx series has a speed of measurement in units called PLC (Power Line Cycles). The default speed is 1PLC, which means a measure is taken with each cycle of line 1 power supply or 1/60th of a second (16.67ms). 24XX can range from 0.01 PLC (all 0.16ms) 10 PLC (all 166.6ms). The faster you measure, the less accuracy you get.

  To programmatically set this value, the command is

  ENSe:CURRent:NPLCycles

  ENSe:VOLTage:NPLCycles

  Depending on what you are sensing and where is the number of controllers from 0.01 to 10.

  Another factor that will determine the time between data points is the cycle SDM. These are more complicated, look at your Keithley manual for more information. Look at article 6 and article 11 for more information.

  Note:

  PLC times are based on a cycle of 60 Hz US.

• Measure the time difference between a digital output and an analog input that responded to the questionnaire

  Hallo,

  I use the following system:

  • OR PXI-1044 with controller NI PXI-8109
  
  
  • OR PXI-2564 switch module to turn on the monitor of my test device
  
  
  • Data acquisition multifunction NI PXI-6259 to measure the signal that responded to the questionnaire jump

  The two cards are the same - PXI trigger bus. For both, PXI-2564 and PXI-6259 I use DAQmx to set the reading and writing of the channels.

  Now, I want to measure the time between the digital output, my unit turns and the analog input, which measures the response of my system.

  I can't do work by myself, please help me!

  I thank Ludwig.

  Hi Ludwig,.

  If you can't give us any VI we have difficulties with to help you.

  Because I Donat knowledge how your program is mounted it is not easy to know where you should enter signals.

  Here's a question similar to yours:

  http://forums.NI.com/T5/LabVIEW/best-way-to-measure-time/TD-p/178704

  and 2 external links:

  http://www.ehow.com/how_8698983_measure-time-LabVIEW.html

  http://objectmix.com/LabVIEW/385152-how-can-i-use-LabVIEW-measure-time-between-analog-pulses.html

• There is the time difference between I phone and Apple Watch

  Ythe time on my I phone is correct, but on my Apple Watch is not

  You have sync it and paired? in the same time zone?

• Is there an easy way to calculate the time difference?

  I am trying to find a way to calculate the time difference between

  here at a certain time

  var settime:Number = 02:35

  and

  now would be getDate();

  I tried something rediculus, but it does not work when I entered a date less than 24 hours, is there a class out there who can just this kind of things

  or y at - it something on the internet that could tell me the difference between different time

  Thank you

  My attempt

  var date: Date = new Date();

  Set timer to what would I like to call the function
  var lastcallH:Number = 22;
  var lastcallM:Number = 50;
  var lastcallS:Number = 0;

  Set up of the 24-hour clock
  var tHour:Number = 24;
  var tMinute:Number = 60;
  var tSecond:Number = 60;

  Get the current time
  var cHour:Number = date.getHours ();
  var cMinutes:Number = date.getMinutes ();
  var cSeconds:Number = date.getSeconds ();

  Set the first variable
  var fH:Number;
  var fM:Number;
  var fS: Number;

  A second set of Variable
  var sH: number;
  var sM:Number;
  var sS:Number;

  Final conversion for the Timer
  var finalMil:Number;

  Time variables that will need to be converted

  If (lastcallH < Thur)
  {
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  finalMil = (sH * 60) + (sM * 60) + (sM * 60);
  }
  ElseIf (cMinutes > 0 | cSeconds > 0) {}
  ++ Choir;
  ++ cMinutes;
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  }
  else {}
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  }

  sH = fH + lastcallH;
  sM = fM + lastcallM;
  sS = fS + lastcallM;

  If (< 0 sH: sM < 0 | sS < 0)
  {
  sH = sH * (-1);
  sM = sM * (-1);
  sS = sS * (-1);
  }
  finalMil = (sH * 60) + (sM * 60) + (sM * 60);

  Allows you to implement a timer
  var yahooTime:Timer = new Timer (finalMil, repeat);
  var repeat: Number = 1;

  yahooTime.start ();

  yahooTime.addEventListener (TimerEvent.TIMER, displayCall);

  function displayCall(event:TimerEvent):void
  {
  trace ("well let's success");
  }

  your first trace() statement is almost certainly not what you want.

  dtDate2 is 08/08/2009

  and it's probably not what you want.  Flash months are zero-based.  That is to say, January corresponding to month 0 and December is the month 11.

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  Unit 4.0.3

  Everything worked very well, and all of a sudden, I'm not able to connect to the server unit using any domain account. When I enter the domain/name username/password, I get this error message:

  ************************************************

  The system is unable to log on due to the following error:

  There is a time difference between the client and the server.

  Try again or contact your system administrator.

  **************************************************

  I can use the same domain account (unityinstall) and the journal in other machines. I can connect the machine to the unit using a local account. There is no time difference between the DC server and unity.

  Need help,

  Thank you

  Partha

  Log on to your LOCAL computer using an account that has privileges

  At the command prompt, type the following:

  NET TIME ancien_mot_passe/set

  Found this on the MS site:

  Cannot open a session if the Date and time are not synchronized

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  Thanks in advance
  
  RSG
  
  Published by: RSG on March 29, 2011 05:42

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