Cannot configure the firewall using vSphere client (access to ESX 4i)

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• How to change the IP address for the virtual using Vsphere Client computer?

  Hello

  I have Esxi 5.0.0 and using the client vsphere 5.0.0 and deployed a VM with Centos 5.6.

  Can I change Ipadress assigned to the virtual computer that is already installed?

  Could you please let me know in detail of the measures to be executed in order to change the IP address if it is authorized using Vsphere Client 5.0.0

  You can take a look at this blog sound to change IP on the Windows virtual machine, probably using the CLI of power it should be possible on linux VM

• You cannot use vSphere client to change the settings of the virtual machine v10 or more

  Hello

  I just downloaded new version of Kali Linux to do some tests with my free version of ESXi update 5.5 2, the problem is that I can't change the settings of the virtual machine in vSphere Client.

  It's so good because of the independence of Web OS Client vSphere but what about the free version? Everyone knows you need a vCenter running successfully and a license for the vSphere Web Client.

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  Nice day.

  http://www.vmwarearena.com/2014/09/vSphere-client-5-5-Update-2-edit-hardware-version-10-VMS-using-vSphere-client.html

• How to configure NTP between Virtual Machines without using Vsphere Client

  I have a group of 8 virtual servers of 5.5 ESXi without an Internet connection. There are virtual machines on each of these 8 virtual servers.

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  ip address of the client 10.108.190.15

  Server /etc/ntp.conf

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  > > server 127.127.1.0 maxpoll 4

  > > fondant 127.127.1.0 stratum 10

  | ntpq Pei

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  | ==============================================================
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  | ntpq Pei

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  | ==================================================================
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  Any help in this issue deeply appreciated!

  Thank you!

  You can configure the ntp server without using viclient.

  Take a look @ http://kb.vmware.com/selfservice/documentLinkInt.do?micrositeID=&popup=true&languageId=&externalID=1003063

  Hope this helps

  -Assane

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• Error - because of unidentified problem, Windows cannot display the firewall settings

  Original title: Firewall Windows are not accessible to stop?

  Recently installed MSE.  Now, I can't launch Samsung Allshare to view files on the Samsung TV.  Firewall Windows is not accessible to stop temporarily so that Allshare can run.  All that is shown is "Because of problem not identified, Windows cannot display the firewall settings."  It seems that MSE has hidden and I can't determine how to communicate with them without going through the process of uninstalling and re-installing.

  Hello

  1 Windows operating system you are using?

  2. when exactly you get the error message?

  Important: this section, method, or task contains steps that tell you how to modify the registry. However, serious problems can occur if you modify the registry incorrectly. Therefore, make sure that you proceed with caution. For added protection, back up the registry before you edit it. Then you can restore the registry if a problem occurs.

  For more information about how to back up the registry, see the link:

  Back up the registry

  http://support.Microsoft.com/kb/322756

  See the article and check if that helps:

  You cannot start the Windows Firewall service in Windows XP SP2

  http://support.Microsoft.com/kb/920074

  If the problem is not resolved, please provide more information to help you best.

• When I go to my list of wireless networks, or try to connect to a network it tells me that windows cannot configure the network.

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  Hello

  I suggest you to follow the steps in troubleshooting this article and check if it helps:

  Error message when you try to run the Network Setup Wizard update for Windows XP Service Pack 2, Service Pack 3, or Windows XP Tablet PC 2005 Edition wireless

  http://support.Microsoft.com/kb/871122

  Also read these articles and check:

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  http://support.Microsoft.com/kb/313242

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• When I try to turn on the Windows Firewall, I get a sign message that says "Due to a problem not identified, Windows cannot display the firewall settings."

  When I try to turn on the Windows Firewall, I get a sign message that says "Due to a problem not identified, Windows cannot display the firewall settings."

  I found another thread in Microsoft Answers relating to this problem, but who said to go into Services and see if the firewall is configured to automatically start.  However, I can't find a Windows Firewall item in the Services Menu.

  I have the PC Tools Spyware Doctor antivirus.

  I had to do a complete recovery system... which sets just need to make sure that you back up your files.

• Windows cannot start the firewall service.

  Original title: my firewall stopped working and it won't let me turn it back on.

  My computer has alerted my that my firewall was off this morning. The alert came with the possibility to reactivate after having used the option of tis, another box emerged stating that it cannot be turned on again and try to activate it manually. I tried to turn it on manually and it still doesn't work. He is said to be the first "Windows Firewall settings cannot be displayed because the associated service is not running. You want to start the Windows Firewall Service? "after you press 'Yes', it says"Windows cannot start the firewall service. No error message is given. Any ideas?

  Hey, bed,.

  File system (CFS) auditor scan and see if it finds a breach of integrity. If so, System File Checker will try to replace missing or damaged files.

  Information available at:

   

  How to use the System File Checker tool to fix the system files missing or corrupted on Windows Vista or Windows 7

  http://support.Microsoft.com/kb/929833

  Kind regards

  Shinmila H - Microsoft Support

  Visit our Microsoft answers feedback Forum and let us know what you think.

• Oracle of the MAF error ' cannot read the DataControl uses on loadDataControl for the id:

  Need help!

  I created a simple SOAP web service for a remote database that works very well in 12 c WebLogic Server and also in the Jdeveloper HTTP Analyzer. When I use the same web service in the attached code, I get the following error (I've included output System.out.println in Ref. to the flow of the code) I use Jdeveloper 12 c MAF 2.0.0.0.41 on Mac OSx 10.9.

  Chk #0

  Processing line # 1

  Chk #1

  Chk #2

  [SEVERE - oracle.adfmf.framework - AmxBindingContext - loadDataControlById] Cannot read the DataControl uses on loadDataControl for the id: WLFNewActWS. [SEVERE - oracle.adfmf.framework - SynchronizationDC - syncDataFromOfflineToOnline] [Ljava.lang.StackTraceElement;@467c53d3

  @

  


  Sorry about that, I think I'm wrong you.

  OK, I created an example to test what goes wrong.

  1. server side, create a project named Employee_ws

  a. Department_ws.java

  public interface {Department_ws}

  public boolean addDepartment (a Department);

  }

  b. Department.java

  public class {Department

  public Department() {}

  Super();

  }

  int departmentId.

  String departmentName;

  locationId int;

  managerId int;

  {} public void setDepartmentId (int departmentId)

  this.departmentId = departmentId;

  }

  public int getDepartmentId() {}

  return departmentId.

  }

  {} public void setDepartmentName (String departmentName)

  this.departmentName = departmentName;

  }

  public String getDepartmentName() {}

  return departmentName;

  }

  {} public void setLocationId (int locationId)

  this.locationId = locationId;

  }

  public int getLocationId() {}

  return locationId.

  }

  {} public void setManagerId (managerId int)

  this.managerId = managerId;

  }

  public int getManagerId() {}

  return managerId;

  }

  }

  c. Department_impl.java

  @WebService

  / public class Department_impl implements Department_ws {}

  public Department_impl() {}

  Super();

  }

  @Override

  @WebMethod

  {} public boolean addDepartment (@WebParam (name = "arg0") a Department)

  If (Department! = null) {}

  int departmentId = department.getDepartmentId ();

  String departmentName = department.getDepartmentName ();

  int locationId = department.getLocationId ();

  managerId int = department.getManagerId ();

  Connection Conn;

  try {}

  Conn = ConnectionFactory.getConnection ();

  conn.setAutoCommit (true);

  Statement šment = conn.createStatement ();

  String inset_sql =

  "INSERT INTO dept (department_name, location_id, department_id, manager_id) VALUES ('+ '.

  departmentId + "," "" + departmentName + "'," + locationId + "," + managerId + ")";

  šment. Execute (inset_sql);

  Returns true;

  } catch (Exception e) {}

  System.out.println (e);

  }

  }

  Returns false;

  }

  }

  d. ConnectionFactory.java

  import java.sql.Connection;

  to import java.sql.DriverManager;

  import java.sql.SQLException;

  Connect to the database

  public class {ConnectionFactory

  public ConnectionFactory() {}

  Super();

  }

  protected static connection conn = null;

  public static connection getConnection() bird Exception {}

  If (conn == null) {}

  try {}

  String driver = "oracle.jdbc.driver.OracleDriver";

  String url = "jdbc:oracle:thin:@localhost:1521:orcl";

  User String = "employee";

  String password = "employee";

  Class.forName (driver);

  Conn = DriverManager.getConnection (url, user, password);

  } catch (SQLException e) {}

  System.Err.println (e.getMessage ());

  }

  }

  return conn;

  }

  public static {} Sub closeConnection()

  try {}

  If (conn! = null) {}

  Conn.Close ();

  Conn = null;

  }

  } catch (Exception ex) {}

  throw new RuntimeException (ex);

  }

  }

  }

  You can run Department_impl.java to start the Web service. i.e. http://127.0.0.1:7001 / Employee_ws-Client-context-root/Department_implPort? WSDL

  Server side sql:

  CREATE USER employee IDENTIFIED BY employee DEFAULT TABLESPACE users

  Temp TEMPORARY TABLESPACE

  Users WE QUOTA UNLIMITED;

  GRANT create employee to logon.

  GRANT alter used to logon.

  GRANT create any employee at table;

  GRANT create trigger employee TO;

  GRANT create any employee to view;

  GRANT create sequence employee TO;

  GRANT create synonym employee TO;

  GRANT create type employee TO;

  GRANT create employee to procedure;

  CREATE TABLE (DEPT

  DEPARTMENT_ID NUMBER (7, 0) NOT NULL,

  DEPARTMENT_NAME VARCHAR2 (50).

  NUMBER OF LOCATION_ID (7, 0),

  MANAGER_ID NUMBER (7.0)

  );

  2 create a mobile application of CRG named Dept

  

  a. Department.java (even for the server)

  b. SynchronizationDC.java

  import java.util.ArrayList;

  import java.util.List;

  Import oracle.adfmf.framework.api.AdfmfJavaUtilities;

  Import oracle.adfmf.framework.exception.AdfInvocationException;

  public class SynchronizationDC {}

  public SynchronizationDC() {}

  Super();

  }

  public void syncDataFromOfflineToOnline() {}

  It's just for testing, so I build Department manually instead of mobile db data, please replace in your business logic

  A Department = new Department();

  department.setDepartmentId (1);

  department.setDepartmentName("1");

  department.setLocationId (1);

  department.setManagerId (1);

  NamesList list = new ArrayList (1);

  List ParamsList = new ArrayList (1);

  List TypesList = new ArrayList (1);

  namesList.add ("arg0");

  paramsList.add (department);

  typesList.add (Department.class);

  try {}

  AdfmfJavaUtilities.invokeDataControlMethod ("Dept_WS", null, "addDepartment", namesList, paramsList,

  typesList);

  } catch (AdfInvocationException e) {}

  System.out.println (e);

  }

  }

  }

  c. new an AMX pag called Dept.amx

  "http://www.w3.org/2001/XMLSchema-instance" xmlns:amx ="http://xmlns.oracle.com/adf/mf/amx"

  xmlns:dvtm ="http://xmlns.oracle.com/adf/mf/amx/dvt" >. "

  Text = "syncDataFromOfflineToOnline."

  Disabled = "#{!}" Bindings.syncDataFromOfflineToOnline.Enabled}"id ="cb3"/ >

  d. deploy on Android Simulator

  

  Click the button and a new record have been db insert through the webservice, search the remote db recording

  

  If above does not solve your problem, please let me know, thanks.

  Byron

• How to connect to the server ESXI vSphere Client side WAN?

  How to connect to the server ESXI vSphere Client side WAN?

  through firewall

  I tried to open the ports 902 903, 443... and so on...

  and I tried several sites to find the solution but...

  nothing works...

  connectivity works on local network

  Help, please...

  Source Destination Port

  ESXI 443/TCP client

  ESXi 902/TCP client

  ESXi 902/TCP Client

  ESXi 902/UDP Client

  ESXi 903/TCP client

  Edit: Also check if the firewall ESXi all IP addresses are allowed to connect:

  Example:

  See attachment...

• I can't connect to Vcenter using vsphere client

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  In vsphere version 5.5 I can connect to vCenter using vsphere client 5.5.

  I can't find any information on this subject on vmware.com.

  Do vsphere 6.0 support connecting to vCenter using vsphere client?

  I guess you are using Vsphere Client beta built which has only the features of client enabled host.

  Try GA build Client to connect to vCenter. However, the latest vsphere 5.1 leave are available only in the web client.

• Sample SDK error. Could not load the module on vsphere-client/globalview-ui/locales/globalview-ui-en_US.swf resources.

  I add the service global services and global services-user interface on the server of virgo and start the server.

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  Please read the FAQ and tutorial doc in the Directory SDK docs, it's a typical error when you forget to compile the resources in your project file.

• Cannot open the project file with write access.

  I saw that this problem has been reported before, but have yet to find a solution.

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  I don't want to register as because other projects refer to this file and also my file is still going to be ruined.

  FYI two computers use Windows 7.

  All solutions?

  Right-click on the folder in Question and select Properties. Select tab security make sure you that you then add everyone to the list of users. Do you this by selecting edit and then add. Type in all members of the section of the object, and click ok. Then select all the user and check full control. Press Apply and we'll adjust the permissions for the folder and subfolders and files.

  Eric

  ADK