Case statement is not spend.
Hello
I'm having a strange problem with a case statement. I'm passing is a Boolean value that is set to false, but the case statement never switches to the loop of "false". I have attached a word doc who did the screen has a step of this unique through being shot. The photo of the top has the case highlighted with the probe #8 beside him indicate 'False. ' In the lower screen shot is the very next step that highlights the outside circle while ' loop', but the case statement is always 'True '. Anyone seen this before?
Gary Tyrna
Hey Mello,
Well, I see what you're saying and you are right, the problem is the case statement works when highlight of execution. But I have a main case statement in the loop that either allows the state machine to execute a loop or hides them and that case is triggered for no steps to true or false. So that was the reason why I sent the first e-mail because I could see this case change, but not the smallest. But if this is the fix well I'll run with it and lets see case statement switch the highlight of the performance.
Thanks again.
Gary Tyrna
Tags: NI Software
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Hi Experts
I have this case statement:
BOX WHEN ' @{pvCalType} "="Cal1"THEN"Calendar Cal1"". "" Year. "
WHEN ' @{pvCalType} "="Cal2"THEN"Calendar Cal2"". "" Year
ANOTHER NULL
END
All the columns in the YEAR of different sizes have properties of the hierarchy.
When I view my results of this statement, there is no hierarchy.
I want the hierarchy in order to drill down of the YEAR > QUARTER > MONTHS
Help, please.
Hello
do you have other possible values for "pvCalType"?
If not try this formula: "@{pvCalType} schedule". " Year. "
(not sure this is the right syntax, if it does not work after the return of the error and I get the right thing...)
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Dear all,
We have the database oracle 11g r2 on windows.
I created under function: -.
SQL > CREATE OR REPLACE FUNCTION FUNC_TEST (P_TEST VARCHAR2)
2 RETURN VARCHAR2
3 AS
4 V_TEST VARCHAR2 (20);
5
6 BEGIN
7
8 V_TEST: = P_TEST;
9
10
11 CASES
12. WHEN V_TEST = UPPER ('%UU%') THEN V_TEST: = REPLACE (V_TEST, 'UU', 'U');
13. WHEN V_TEST = UPPER ('%OO%') THEN V_TEST: = REPLACE (V_TEST, 'OO', 'O');
14. WHAT V_TEST = UPPER ('%NN%') THEN V_TEST: = REPLACE(V_TEST,'NN','N');
15 ELSE V_TEST: = "CHANCHAL";
END 16 CASES;
17
18
19 V_TEST RETURN;
20 EXCEPTION SO THAT OTHERS THEN
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23.
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SQL > SHOW ERR
No errors.
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FUNC_TEST ('TOON')
--------------------------------------------------------------------------------
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above function should show 'YOUR' build 'Toon' but its display "CHANCHAL";
I train hard get the result OK but could not get it.
Any suggestions would be very helpful.
Kind regards
Chanchal wankhade.Hello
Chanchal Wankhade wrote:
Dear all,
We have the database oracle 11g r2 on windows.
I created under function: -.
SQL > CREATE OR REPLACE FUNCTION FUNC_TEST (P_TEST VARCHAR2)
2 RETURN VARCHAR2
3 AS
4 V_TEST VARCHAR2 (20);
5
6 BEGIN
7
8 V_TEST: = P_TEST;
9
10
11 CASES
12. WHEN V_TEST = UPPER ('%UU%') THEN V_TEST: = REPLACE (V_TEST, 'UU', 'U');
13. WHEN V_TEST = UPPER ('%OO%') THEN V_TEST: = REPLACE (V_TEST, 'OO', 'O');
14. WHAT V_TEST = UPPER ('%NN%') THEN V_TEST: = REPLACE(V_TEST,'NN','N');
15 ELSE V_TEST: = "CHANCHAL";
END 16 CASES;
17
18
19 V_TEST RETURN;
20 EXCEPTION SO THAT OTHERS THEN
21 DBMS_OUTPUT. PUT_LINE (' THERE IS AN ERROR ');
22 END;
23.
The function is created.
SQL > SHOW ERR
No errors.
SQL > SELECT FUNC_TEST('toon') FROM DUAL;
FUNC_TEST ('TOON')
--------------------------------------------------------------------------------
CHANCHAL
above function should show 'YOUR' build 'Toon' but its display "CHANCHAL";
I train hard get the result OK but could not get it.
Any suggestions would be very helpful.
Kind regards
Chanchal wankhade.I think you meant:
CASE
WHEN SUPERIOR (V_TEST) LIKE "% UU" THEN V_TEST: = REPLACE (UPPER (V_TEST), 'UU', 'U');
WHEN SUPERIOR (V_TEST) LIKE '% OO %' THEN V_TEST: = REPLACE (UPPER (V_TEST), 'OO', 'O');
...
'%' is a wildcard character only on the right-hand side of the LIKE operator. '%' has no particular meaning when you use the = operator.
You can also use a CASE expression, rather than a CASE statement to this:
v_test: = UPPER (p_test);
v_test: = BOX
WHEN v_test LIKE "% UU" THEN REPLACE (v_test, 'UU', 'U')
WHEN v_test LIKE "% UU" THEN REPLACE (v_test, 'OO', 'o')
...
END;
Whatever it is, if v_test contains different models (for example "HOOVER VACUUM"), only 1 of them will be changed. Is that what you want?
If this isn't the case, after a few examples of data (CREATE TABLE and INSERT statements) and the results desired from these sample data. Explain how you get these results from these data.
See the FAQ forum: https://forums.oracle.com/message/9362002#9362002
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NOT IN clause in State of the CASE statement does not
Dear friends,
I want to use on the condition in the WHERE clause of my SELECT statement.
WHERE <>...
<>...
AND eihf.exr_aip_asset_sid NOT IN
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SO (37874,37909,43424,55040,59513,59598,58570,76148,75885,75927)
ON THE OTHER
(0)
END
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Help, please.
Kind regards
JonathanYou can not write a list of values within the case statement.
try something like this,
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using nested case statement does not get the right result
Hello all;
I have a sample of data similar to below
create table t3 ( id varchar2(200), qty number(30), qty2 number(30) );
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etc.
I tried write something but can not make it work
any help is appreciated. Thank you.select case when sum(v.qty) is not null and sum(v.qty) = 0 then 'Pass' when sum(v.qty) is not null and sum(v.qty) != 0 then 'Fail' else case when sum(v.qty2) is not null and sum(v.qty2) = 0 then 'Pass' else when sum(v.qty2) is not null and sum(v.qty2) != 0 then 'Fail' end as status end as status from t3 v;
Try this,
SELECT ID, CASE WHEN NVL(SUM (qty2),1) !=0 THEN 'fail' WHEN NVL(SUM (qty),0) != 0 THEN 'fail' ELSE 'pass' END FROM t3 GROUP BY ID OUTPUT ------------- ID RESULT -- ------ A fail B fail C pass D fail Z fail
G.
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Why this CASE statement would not work?
If I use a CASE in my SELECT statement and met a strange thing and just need help to understand why he did it.
When I type this, it does not work:
CASE TRIM (Column1)
WHEN NULL THEN Column2
WHEN 'foo' THEN Column2
Of ANOTHER Column1
END AS NewColName
I use this query in an Oracle procedure to insert data into another table. The data inserted in the column of NewColName end up being 4 empty spaces, located in Column1. In the logic of this, TRIM must remove all the empty spaces, and he should get mapped to the first statement WHEN, who must insert the value of Column2, but that does not occur. I tried the following versions of the first line as well:
LTRIM (RTRIM (Column1)) CASE
CASE of REPLACE (Column1, ' ', ")
and they all produce the same result. I also tried to change WHEN NULL for WHEN " and it changed nothing. However, when I rewrite the statement in this way it works the way it should:
CASE
WHEN TRIM (Column1) IS NULL, Column2
WHEN TRIM (Column1) = 'foo' THEN Column2
Of ANOTHER Column1
END AS NewColName
In my mind, it seems that these two methods are trying the same thing, why we could work and the other not? Only, it has no sense to me.
Thank youHello
Welcome to the forum.
In your first statement, you have
WHEN NULL THEN.
This is the same as x = NULL.
Nothing is never equal to NULL, if you find yourself in your ELSE clause.
Concerning
Peter -
Why is this game of case statements do not parallel execution?
I have the following Subvi:
I had a similar version which had specific cases for specific devices, but I wanted to make it more generic. I tested their work in parallel before the Subvi to GET all THE DATA is re-entrant I wonder if the merge errors feature prevents cases work properly. Maybe having the error returned to the Subvi on the top of the terminal will make a difference? Just try to understand what is happening.
RavensFan wrote:
James,
Why the constant true connected to the conditional tunnel?
I was simulating a Subvi, which has a Boolean result. He did not share his code so I don't have the Subvi himself.
I see now why OP does without a loop For, if there are more devices there carrots. The loop For could save code duplication to a minimum the number of cores.
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ORA-06592: not found CASE when executing CASE statement
Hello
I have a table of application where I built a form master detail (table with 33 columns, 13 is not hidden items and rest are hidden).
When I run the page I get an error "error while rendering page, article. P10_TIME_SAVED_FREQUENCY, ORA-06592: not found when executing CASE statement CASE"
Error:
Error during rendering of the element on the page P8_MONEY_SAVED_FLAG.
ORA-06592: not found CASE when executing CASE statement
Technical information (only visible to developers)
is_internal_error: true
apex_error_code: WWV_FLOW_FORM. UNHANDLED_ERROR
ora_sqlcode:-6592
ora_sqlerrm: ORA-06592: not found CASE when executing CASE statement
Component.type: APEX_APPLICATION_PAGE_ITEMS
Component.ID: 13345536607188241
Component.Name: P8_MONEY_SAVED_FLAG
error_backtrace:
ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 1751
ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 4241
ORA-06512: at "APEX_040200.WWV_FLOW_PLUGIN", line 1251
ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 977
ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 1406
DEBUG:
Exploitation forest exception in final_exception_handler:
SQLERRM: ORA-20987: APEX - error during rendering of the element on the page P8_MONEY_SAVED_FLAG. -
ORA-06592: not found CASE during the execution of the instruction BOX Backtrace: ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"
line 853 ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"
line 888 ORA-06512: at "APEX_040200.WWV_FLOW_DISP_PAGE_PLUGS"
line of 3240 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"
line of 1780 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"
line of 1950 ORA-06512: at "APEX_040200.WWV_FLOW", line 6725
How to solve this problem. Please advice
Oracle Apex Vesion: 4.2.1
Thank you
BO123 wrote:
Hello
I have a table of application where I built a form master detail (table with 33 columns, 13 is not hidden items and rest are hidden).
When I run the page I get an error "error while rendering page, article. P10_TIME_SAVED_FREQUENCY, ORA-06592: not found when executing CASE statement CASE"
Error:
Error during rendering of the element on the page P8_MONEY_SAVED_FLAG.
ORA-06592: not found CASE when executing CASE statement
Technical information (only visible to developers)
is_internal_error: true
apex_error_code: WWV_FLOW_FORM. UNHANDLED_ERROR
ora_sqlcode:-6592
ora_sqlerrm: ORA-06592: not found CASE when executing CASE statement
Component.type: APEX_APPLICATION_PAGE_ITEMS
Component.ID: 13345536607188241
Component.Name: P8_MONEY_SAVED_FLAG
error_backtrace:
ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 1751
ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 4241
ORA-06512: at "APEX_040200.WWV_FLOW_PLUGIN", line 1251
ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 977
ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 1406
DEBUG:
Exploitation forest exception in final_exception_handler:
SQLERRM: ORA-20987: APEX - error during rendering of the element on the page P8_MONEY_SAVED_FLAG. -
ORA-06592: not found CASE during the execution of the instruction BOX Backtrace: ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"
line 853 ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"
line 888 ORA-06512: at "APEX_040200.WWV_FLOW_DISP_PAGE_PLUGS"
line of 3240 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"
line of 1780 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"
line of 1950 ORA-06512: at "APEX_040200.WWV_FLOW", line 6725
How to solve this problem. Please advice
Oracle Apex Vesion: 4.2.1
Post a backtrace of the page see the request and the item type properties and the source / default to the value of the P8_MONEY_SAVED_FLAG element.
Seems to be similar to ORA-06592 with the page only items appear, which also involved a master/detail form. Can you reproduce this on apex.oracle.com?
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ROWNUM does not work in the case statement
I have a form in which users would like to see the first 10 records as a certain color, 10 neighbor as a certain color, etc. I was hoping that I could accomplish this simply by using a case statement and by referencing the value of rownum. I've posted the rownum in the page and everything seems fine, but when I run the statement below all comes down to BLOCK 1 meaning it has a value of < = 10. I have an order by clause on the report to sort by the primary key of the table. If I remove the single quotes to number all about, I get an error invalid number during page execution.
(case when ' #ROWNUM # ' < = '10' and then ' < div align = "center" style = "background-color: #FFDAC1;") make-weight: bold; color: #ffffff; » > ' || "BLOCK 1' | ' < / div > '."
When ' #ROWNUM # ' > '10' and ' #ROWNUM # ' < = '20' and then ' < div align = "center" style = "background-color: #F0F0DA;" make-weight: bold; color: #ffffff; » > ' || "BLOCK 2' | ' < / div > '."
When ' #ROWNUM # ' > '20' and ' #ROWNUM # ' < = '30' and then ' < div align = "center" style = "background-color: #DDFFDD;" make-weight: bold; color: #ffffff; » > ' || "BLOCK 3' | ' < / div > '."
When ' #ROWNUM # ' > '30' and ' #ROWNUM # ' < = '40' then ' < div align = "center" style = "background-color: #FFCC0;" make-weight: bold; color: #ffffff; » > ' || «BLOCK 4 "| ' < / div > '"»
When ' #ROWNUM # ' > '100' then ' < div align = "center" style = "background-color: #e6e6e6;" make-weight: bold; color: #ffffff; » > ' || "BLOCK 11' | (< / div > ' END) row_1
Any help would be greatly appreciated. Thank you amberI don't think you need to # ROWNUM all about characters at all, because you treat it like a normal column.
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TDE is not "transparent" to the CASE statement
Hello
I have installed oracle (10) database with TDE. It works very well with almost all queries. But I have problems when I try to use the CASE statement.
He comes to the table, I created:
{color: #0000ff} create table t_test)
col1 varchar (128)); {color}
This query returns an empty result (as planned, because there is still no data in the table).
{color: #0000ff} to select)
When col1 = 'test' then 'test '.
end) as Carter
of t_test
{color}
I now encrypt the column with the following statement:
{color: #0000ff} change alter table t_test (col1 encrypt using "AES256" without salt); {color}
And try again the same statement:
{color: #0000ff} to select)
When col1 = 'test' then 'test '.
end) as Carter
of t_test
{color}
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But if I try:
{color: #0000ff} select *.
of t_test
{color}
There is no errors (returns empty result, as expected).
I tried even with data, with the same result.
Could someone please tell me what I'm doing wrong here?
Thank you.You touch the Bug 6262107 'ORA-932 of the CASE expression sought with encrypted column:
Description:
"ORA-932 incompatible data types: expected BINARY got TANK ' is triggered.
on a query with a case expression sought on a column with TDE.for example:
CREATE TABLE TDE_TEST (COL1 VARCHAR2 (1));
INSERT INTO TDE_TEST VALUES('1');
ALTER TABLE TDE_TEST CHANGE (COL1 ENCRYPT WITHOUT SALT);
SELECT CASE WHEN COL1 = '1', THEN 'A' OF ANOTHER END 'B' OF TDE_TEST;
^
ORA-00932: inconsistent data types: expected BINARY got TANKWorkaround solution:
Convert a simple case of the searched case expression expression.So, I updated the sql works:
SQL > select (case col1
2 when 'test' then 'test '.
3 end) as Carter
4 * of t_test
/
no selected lineI hope this helps.
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It does not in the current official version of Setpbember.
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Thank you
Dave
Hi Dave,.
Apologies - I consider that the error is from the data acquisition function? I forgot that she was using the sample entry mode.
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LVStudent wrote:
[...] I can't call the case statement without using a sequence structure
Yes you can. You just need to be smart.
LVStudent wrote:
I don't think I can use a state machine to fix this.
I think you probably can.
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Hello
I'm trying a table find vi. This VI will be an existing xml file and once the user has selected access to its equipment, input, output and frequency it put all of these options in a string and search the XML for this exact table name and post it on one screen of output. The problem I have is my entry and exit selection must be a little different depending on the chosen equipment. I thought I could use an instruction box to change the options of selectable input and output, but I ran into snags a lot with it. For whenever I have to put a new drop of entry and exit in the drop-down menu in the case statement, he wants to put a new one in the front (I only want to enter and exit not only three I have two inputs and outputs hidden right now). I think I'm using the wrong case statement... Can someone help change my input and output, selectable options depending on the chosen equipment. Attached is my xml file, Array Find.vi (the original) and table Find_Test.vi (that's what I'm trying to change).
Thank you
dlovell
Hi dlovell,
A few changes in the attached VI:
Requirements/possible Solutions
- When the value of the equipment, do something
- Add the cases to the value of equipment change event
- Do something = decide what channels to write, to change the input and output strings
- Read material value changed
- Decision (case structure)
- Channel (same method as the previous mod)
Hope this helps
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Can I use a hexadecimal string with a case statement?
Simple question:
Can I enter a hexadecimal string to a case statement and have the case statement see it as hex?
I understand that I could convert the hexadecimal string to a number and then enter the hexadecimal number to the case statement but I am curious to know if I could have the case see the string itself as hex without this added feature.
Would be nice to not have to convert all my numbers throughout my code strings
Thank you
-Eric
How long are the strings? Since you mention convert in numbers, they are probably short and all of same length.
Are there different possible channels how?
Case header includes \-codes in the case of a label deal selector As string, so that should be enough for your use. For example this code turns the LED (.. .so that a simple string of "\00\00" of wiring would not be!)
(See also the last sentence of the "enumerated values" section of the help).
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