Category of request HTTP AIC method

Similar Questions

• HTTP GET method with the body of the message

  Hi all

  I work with an API using HTTP to make calls to a server. I met an API call in the documetnation that uses the HTTP GET method with a message body. It seems that this is not supported by LV14 because I do not see an entry of message body for the LabVIEWHTTPClient.lvlib:GET.vi function. The POST methods and COULD appear to be banned for this API call, I a not found 405. I could be stuck with the help of GET.

  Certainly, this isn't recommended GET method - but it is not explicitly forbidden in the HTTP/1.1 specification. Is there a work around to submit an HTTP GET request to content? I have to use HTTP external DLL to achieve?

  All entries would be great.

  Thank you

  Richard

  Seems to be a problem on the server side?  Maybe I misunderstood what you were trying to get?

• How to encode the URL in the Http Get method.

  Hi, I need to encode a url in the Http get method, I found URLEncodedPostData but that is used send message request can someone help me with this?

  Hi RexDoug,

  private String encodeUrl(String hsURL) {
          URLEncodedPostData urlEncoder = new URLEncodedPostData("UTF-8" , false);
          urlEncoder.setData(hsURL);
          hsURL = urlEncoder.toString();
          System.out.println(hsURL);
          return hsURL;
  }
  

  I tried thisbut it don't work I need to encode the url http get method.

  I used this code where I mention rules in URLEncodedPostData it works for me in coded form url in the get method.

  public String encodeUrl(String s){
          if (s!=null) {
              StringBuffer tmp = new StringBuffer();
              int i=0;
              try {
                  while (true) {
                      int b = (int)s.charAt(i++);
                      if ((b>=0x30 && b<=0x39) || (b>=0x41 && b<=0x5A) || (b>=0x61 && b<=0x7A) ||(b == 0x2F) || (b == 0x3A) || (b == 0x2D )|| (b == 0x2E)|| (b == 0x2C)|| (b == 0x3F)|| (b == 0x3D) ||(b == 0x26) || (b == 0x5F) || (b == 0x2A)) {
                          tmp.append((char)b);
                      }
                      else {
                          tmp.append("%");
                          if (b <= 0xf) tmp.append("0");
                          tmp.append(Integer.toHexString(b));
                      }
                  }
              }
              catch (Exception e) {}
              return tmp.toString();
          }
          return null;
  }
  

• 400 bad Request HTTPS on FF 10.0.1, 1o.0.2 vital security Proxy

  I use Firefox on W7 in the office. Our company uses a Proxy of vital for Internet access security. After the upgrade from 9.0.1 to 10 FF FF (10.0.2 including), I have problems to access HTTPS sites. The proxy returns the following error message:

     HTTP Error Status: 400 Bad Request
     Error Reason: Malformed HTTP request
  

  It still works without any problem after downgrading of 9 FF or IE, so it's certainly a problem of FF 10.

  Update: the problem has disappeared without me changing anything (FF 10.0.2). Most likely, there was a problem with the proxy server itself rejecting valid requests for some reason, may have a problem with the user agent in the filtering rules. So it wasn't a problem in Firefox. Thank you for your support.

• How to pass the parameters in the http post method?

  Hello

  I want to download the mp3 file on server and I need to pass two parameters with the post method.

  Here is my code for this.

                        String userid="id_user=8379";
                String filename="trackName=sample.mp3";
                String params=userid+"&"+filename;            
  
                          httpcon=(HttpConnection)Connector.open("http://api.upload.com/gStorage/uploadSong?output=json",Connector.READ_WRITE);
              httpcon.setRequestMethod(HttpConnection.POST);
              httpcon.setRequestProperty("Content-type","application/x-www-form-urlencoded");
              httpcon.setRequestProperty("Content-type","audio/mpeg3");
              os=httpcon.openOutputStream();
              os.write(params.getBytes("UTF-8"));
              fc=(FileConnection)Connector.open("file:///E:/sample.mp3",Connector.READ_WRITE);
              fileis=fc.openInputStream();
              bos=new ByteArrayOutputStream();
              byte[] data=new byte[50000];
              int ch;
              while ((ch=fileis.read(data,0,data.length))!=-1) {
                  bos.write(data,0,ch);
              }
              os.write(bos.toByteArray());
              os.close();
              System.out.println("Response code From server"+httpcon.getResponseCode());
              if(httpcon.getResponseCode()!=HttpConnection.HTTP_OK)
              {
                  System.out.println("Failed to upload bytes");
              }
              else
              {
                  //is=httpcon.openInputStream();
                  DataInputStream dis=httpcon.openDataInputStream();
                  int ch1;
                  StringBuffer buffer1=new StringBuffer();
                  while ((ch1=dis.read())!=-1) {
                      buffer1.append((char)ch1);
                  }
                  System.out.println("Response From Server"+buffer1.toString());
              }
          } i am getting response code ok but fail to upload file.
  

  may I passing the parameter in the wrong way?

  thankx.

  Hello

  Nitin I currently do a midlet project.

  So I used multipart post method.

  I just read this article. http://MindTouch.firmstep.com/AchieveForms/Design_Guide/Integration_Actions/types/HTTP_POST#top

  package com.http.main;
  
  import java.io.ByteArrayOutputStream;
  import java.io.InputStream;
  import java.io.OutputStream;
  import java.util.Enumeration;
  import java.util.Hashtable;
  
  import javax.microedition.io.Connector;
  import javax.microedition.io.HttpConnection;
  
  import com.sun.midp.io.BufferedConnectionAdapter;
  
  public class HttpMultipartRequest
  {
      static final String BOUNDARY = "----------V2ymHFg03ehbqgZCaKO6jy";
  
      byte[] postBytes = null;
      String url = null;
  
      public HttpMultipartRequest(String url, Hashtable params, String fileField, String fileName, String fileType, byte[] fileBytes) throws Exception
      {
          this.url = url;
  
          String boundary = getBoundaryString();
  
          String boundaryMessage = getBoundaryMessage(boundary, params, fileField, fileName, fileType);
  
          String endBoundary = "\r\n--" + boundary + "--\r\n";
  
          ByteArrayOutputStream bos = new ByteArrayOutputStream();
  
          bos.write(boundaryMessage.getBytes());
  
          bos.write(fileBytes);
  
          bos.write(endBoundary.getBytes());
  
          this.postBytes = bos.toByteArray();
  
          bos.close();
      }
  
      String getBoundaryString()
      {
          return BOUNDARY;
      }
  
      String getBoundaryMessage(String boundary, Hashtable params, String fileField, String fileName, String fileType)
      {
          StringBuffer res = new StringBuffer("--").append(boundary).append("\r\n");
  
          Enumeration keys = params.keys();
  
          while(keys.hasMoreElements())
          {
              String key = (String)keys.nextElement();
              String value = (String)params.get(key);
  
              res.append("Content-Disposition: form-data; name=\"").append(key).append("\"\r\n")
                  .append("\r\n").append(value).append("\r\n")
                  .append("--").append(boundary).append("\r\n");
              System.out.println("****In while Loop:-****"+res);
          }
          res.append("Content-Disposition: form-data; name=\"").append(fileField).append("\"; filename=\"").append(fileName).append("\"\r\n")
              .append("Content-Type: ").append(fileType).append("\r\n\r\n");
          return res.toString();
      }
  
      public byte[] send() throws Exception
      {
          HttpConnection hc = null;
  
          InputStream is = null;
  
          ByteArrayOutputStream bos = new ByteArrayOutputStream();
  
          byte[] res = null;
  
          try
          {
              hc = (HttpConnection) Connector.open(url);
  
              hc.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + getBoundaryString());
              hc.setRequestProperty("Content-Length",postBytes+"");
  
              hc.setRequestMethod(HttpConnection.POST);
  
              OutputStream dout = hc.openOutputStream();
  
              dout.write(postBytes);
              dout.close();
  
              int ch;
  
              is = hc.openInputStream();
              StringBuffer buffer=new StringBuffer();
  
              while ((ch = is.read()) != -1)
              {
                  bos.write(ch);
                  buffer.append((char)ch);
              }
              res = bos.toByteArray();
              System.out.println(buffer.toString());
          }
          catch(Exception e)
          {
              e.printStackTrace();
          }
          finally
          {
              try
              {
                  if(bos != null)
                      bos.close();
  
                  if(is != null)
                      is.close();
  
                  if(hc != null)
                      hc.close();
              }
              catch(Exception e2)
              {
                  e2.printStackTrace();
              }
          }
          return res;
      }
  }
  

  and use it in this way

  public void getBytes()
      {
          ByteArrayOutputStream bos=null;
          try
          {
              bos=new ByteArrayOutputStream();
              InputStream fis=getClass().getResourceAsStream("/super.mp3");
              int ch;
              byte[] data=new byte[120];
              while((ch=fis.read(data,0,data.length))!=-1)
              {
                  bos.write(data,0,data.length);
              }
              Hashtable params=new Hashtable();
              //params.put("id_user","8474");
              params.put("id_user","8379");
              params.put("file1","audio.mp3");
              HttpMultipartRequest httpreq=new HttpMultipartRequest("http://api.upload.com/gStorage/uploadSong?", params,"file1","xpressMusic.mp3","audio/mpeg",bos.toByteArray());
              httpreq.send();
              bos.close();
              fis.close();
          }
          catch (Exception e) {
              System.out.println("Exception"+e);
          }
  

  Here, the key is contenttype, contentLength.you can get the info on it from the link above.

  thankx.

• Property request http

  Hello guys '

  I have a problem. My application creates the HTTP request.

  So I need to know how to get the value of some items of property. These products are used to set HTTP headers.

  These elements are:

  "x rim-bsm-id".

  'Profile '.

  "x-wap-profile".

  "Accept."

  "x-Rim-by default-charset".

  "Accept."

  "x-Rim-by default-charset".

  x rim-image-line.

  "Accept-Charset".

  "Accept-Language".

  "User-Agent".

  "x rim-transcode-content".

  "Host".

  "x rim-gw-properties".

  In other words:

  httpConn.setRequestProperty (' x-rim-bsm-id ","HOW GET?"" ");
  httpConn.setRequestProperty ("profile", "HOW GET?");
  httpConn.setRequestProperty ("x-wap-profile","HOW GET?" "");
  httpConn.setRequestProperty ("Accept", "HOW GET?");
  httpConn.setRequestProperty (' x-Rim-by default-charset "," ISO-8859-1 "" ");
  httpConn.setRequestProperty (' x-rim-image-threshold ","HOW GET?"" ");
  httpConn.setRequestProperty ("Accept-Charset", "ISO-8859-1,UTF-8,US-ASCII,UTF-16BE,windows-1252,UTF-16LE,windows-1250");
  httpConn.setRequestProperty ("Accept-Language", "en-GB, fr; q = 0.5 ");
  httpConn.setRequestProperty ("User-Agent","HOW GET?" ");
  httpConn.setRequestProperty (' x-rim-transcode-content ","HOW GET?"" ");
  httpConn.setRequestProperty ("Host", "HOSTNAME");
  httpConn.setRequestProperty (' x-rim-gw-properties ","HOW GET?"" ");

  HOW to GET? -I don't know those signed items.

  Please help me guys

  The only one of general interest, as far as I KNOW is the profile and I don't think I've ever found a place for everything

  read it - I had for his construction of the information platform and profile agent version information.

  I don't know if there is anyway to get x-wap-profile browser either.

  All others should be deducted from your goals - if you know what you are doing these generally

  fill themselves.  You can get some ideas from hunting around the site of the ietf, for example,

  http://www.google.com/search?hl=en&FKT=2904&fsdt=10685&q=site%3Aietf.org+mime+types+Accept&aq=f&OQ=

  Headers x draw probably specifications API such as RIM transcoding etc.

• Why a film F4V format won't work not but in a request HTTP and FLV format?

  Why won't run a film F4V format but and FLV format is in an HTTP request, although both work in a FILE request? (Pro, browser plugin version 11.7 CS6, and tested in IE, Firefox, Chrome and Safari)

  It is usually a problem with the mime type of the server.

• How to read the value of request Http of the filter of the UCM?

  We have an application web connect to the Complutense University of MADRID. I would add some values to the request sent to the Complutense University of MADRID by this application. This value will be read by a filter of the Complutense University of MADRID, I created.
  
  What is the value of HTTP servlet can be read the filter of the UCM? is it possible to do something like:
  request.setAttribute ("myAttribute", "theValue")
  
  and retrieve myAttribute UCM filter value?
  
  Thank you

  AACC,

  When you rexternal application makes the call to the Complutense University of MADRID, all URL parameters or attributes of the request transformed into data variables Local to the Complutense University of MADRID.

  When you create your filter (if all goes well we are talking about the same thing here that filters means something special to the University Complutense of MADRID) you write Java Code. In this Java Code, you can access 'the query' attributes/values with code like this:

  String myval = m_binder.getLocal ("MyKey");

  Your mileage may vary, but this is the Basic code for out, review and/or use the query parameters.

  -Jason
  http://www.corecontentonly.com
  http://www.redstonecontentsolutions.com

• [REQUEST] HTTP connection to analysis

  Hello.. I have the source code...

   public void run() {
          if (!isValidUrl(url) || listener == null) {
              String message = "Invalid parameters.";
              message += !isValidUrl(url) ? " Invalid url." : "";
              message += (listener == null) ? " Invalid HttpResponseListerner instance.": "";
              notifyFailure(message, url);
              return;
          }
  
          // update URL depending on connection type
          url += DeviceInfo.isSimulator() ? ";deviceside=true" : getConncetionDependentUrlSuffix();
  
          // Open the connection and retrieve the data
          try {
              HttpConnection httpConn = (HttpConnection) Connector.open(url);
              int status = httpConn.getResponseCode();
              if (status == HttpConnection.HTTP_OK) {
                  InputStream input = httpConn.openInputStream();
                  byte[] bytes = IOUtilities.streamToBytes(input);
                  input.close();
                  notifySuccess(bytes, url);
              } else {
                  notifyFailure("Failed to retrieve data, HTTP response code: " + status, url);
                  return;
              }
              httpConn.close();
          } catch (Exception e) {
              notifyFailure("Failed to retrieve data, Exception: ", e.toString());
              return;
          }
      }
  

  I get all this

  Link Source Code

  My problem is, the application uses the connection TCP, Imust APN setting on my camera...

  I want to make this application uses the connection Blackberry Internet Service (BIS)...

  I'm so confused.

  Help me please.

  private String getConncetionDependentUrlSuffix() {}
  Not implemented
  return '; deviceside = false; "ConnectionType = m * s - p * blic ';
  }

  FIX

  

• How to receive the http on the BlackBerry itself as a server request

  Hi all

  I make a request which I must do a http called through SOAP web services and wish to receive this request http to my Blackberry itself (suppose that, by default, port). that is, I use the BlackBerry device as a client and the server.

  Please suggest me if RIM provides APIs of java application server server or someone has an idea about this.

  I use devic BB: BB 8900 OS v5.0

  Thanks in advance!

  Hello ashutoshg,

  Unfortunately the best I can give is that localhost and 127.0.0.1 simply don't are not supported with regard to a BlackBerry network connection.

  The following forum thread discusses two methods of obtaining the IP address of your device when it is connected via WiFi and I saw the success of these approaches in the past:

  http://supportforums.BlackBerry.com/T5/Java-development/WiFi-IP-address/TD-p/374272

  The only thing to note is that this kind of HTTP communication will travel through the WiFi network and back to the equipment; rather than work around the network via the loopback address infrastructure.

  Erik Oros

  BlackBerry Development Advisor

• How to get AFExecuteThisScript to return the value of Net.HTTP.request (asynchronous)?

  I have an Acrobat only plugin, developed in 2005 VS.  Originally with Acrobat 7 SDK, now updated to use Acrobat 9 SDK.  The ultimate goal of this feature is to open a PDF file from a web server Agile: If a user string, a URL is created, a request sent to the URL, then pay back the answer.  The answer can be either the PDF itself or a string path to the PDF file.  I thought it would be easier to use the version of PDF path to simply open the new PDF of the http:// address.

  I created a folder level javascript with a call to Net.HTTP.request confidence.  I have a script that works when invoked from a menu item added by the folder level javascript file.  But when you use this same command in my C++ with AFExecuteThisScript code, I can't get the HTTP response to finish pending in the code for the result.

  The Net.HTTP.request and the asynchronous callbacks confuse me, so maybe that's my big problem.  I could not Net.HTTP.request to return a value in a service simple javascript right now, I'm trying to use a "global" variable in the JavaScript folder level and two calls.  The first call "sets" the global variable, the other "becomes" it.  But this seems to be the issue.  When I have my code debugging or stop execution, the part of the response of the Net.HTTP.request is never called.  But when I left to go beyond this step with error recovery, the answer appears later.

  So how kick off of the Net.HTTP.request and be notified when it's over?  either in JavaScript or VC ++?

  Any help is appreciated.  Even if the best option is to stream the file from the web server to a local file and then open the (this is the option that I take in another tool that runs outside of Acrobat).

  Here's the code.

  Javascript controls at the level of the files (urls truncated for the post)

  var THE_PATH = '';
  
  function setTHE_PATH ( gURL ) {
      console.println('setTHE_PATH Begin');
      var params =
      {
          cVerb: 'GET',
          cURL: gURL,
          oHandler: 
              {
                  response: function( msg, uri, e)
                  {
                      console.println('response method: Setting Path');
                      THE_PATH = SOAP.stringFromStream( msg );
                      console.println('<<' + THE_PATH + '>>');
                  }
              }
      };
      console.println('URL: ' + params.cURL + '\n  oHandler: ' + params.oHandler );
      console.println('Path: ' + THE_PATH );
      var netResult = trustedNetHTTPrequest(params);
      console.println('setTHE_PATH End');
      return THE_PATH;
  };
  
  trustedNetHTTPrequest = app.trustedFunction( 
      function ( params ) {
          console.println('trustedNetHTTPrequest begin');
          app.beginPriv();
          var netResult = Net.HTTP.request( params );
          app.endPriv();
          console.println('trustedNetHTTPrequest end');
          return netResult;
      }
  );
  

  Added MenuItems with JavaScript at the folder level

  app.addMenuItem( { 
      cName: "mysetTHE_PATH", 
      cUser: "set THE_PATH", cParent: "Tools", 
      cExec: "setTHE_PATH('http://......&getURL=true');",
      nPos: 0 
  } );    
  
  app.addMenuItem( { 
      cName: "mygetTHE_PATH", 
      cUser: "get THE_PATH", cParent: "Tools", 
      cExec: "console.println( THE_PATH );",
      nPos: 0 
  } );   
  

  Here's the JavaScript Console output when you run these two commands:

  setTHE_PATH Begin
  URL: http://......&getURL=true
    oHandler: [object Object]
  Path: 
  trustedNetHTTPrequest begin
  trustedNetHTTPrequest end
  setTHE_PATH End
  response method: Setting Path
  <<https://......DesiredFilename.pdf>>
  

  Here is the function in the plugin C++, with additional measures to prove AFExecuteThisScript works here

  sprintf(jsScript, "testVal='%s';event.value = testVal;", strURL.c_str() );
  AFExecuteThisScript( aPdDoc, jsScript, &pReturnValue );
  // After this, pReturnValue is the passed-in URL, as expected.
  sprintf(jsScript, "setTHE_PATH('%s');event.value = 'Step 1 Worked!!';", strURL.c_str() );
  AFExecuteThisScript( aPdDoc, jsScript, &pReturnValue );
  // After this, pReturnValue is 'Step 1 Worked!!', as expected.
  sprintf(jsScript, "event.value = THE_PATH;", strURL.c_str() );
  AFExecuteThisScript( aPdDoc, jsScript, &pReturnValue );
  // After this, pReturnValue is NULL
  

  This is the JavaScript Console output when you run the commands using the plugin (mode debugger, to wait after step 1)

  setTHE_PATH Begin
  URL: http://......&getURL=true
    oHandler: [object Object]
  Path: 
  trustedNetHTTPrequest begin
  trustedNetHTTPrequest end
  setTHE_PATH End
  

  Note that he never gets to the part of the "method of response.

  Thank you!

  Tim James

  You need not limit yourself to the plugin API. The requests HTTP from C/C++ is a fairly common condition, just observe the restrictions in my answer.

• No http request

  Hi guys, someone has encountered this problem before, in my application, I need to send the web request http not or not, but QNetworkRequest accepts the URL.

  If you have a preview, please drop a message here.

  Thank you

  Use QTcpSocket. or CURL.

• HTTP request at regular intervals

  Hello

  I have an application that update its database, create an http request and parsing the xml response (it dynamically build the query with xml content). I want to update my database at regular intervals, so I need to do http request at regular intervals, of power to the top of the device to power off. My autorun app at startup, but I would like to request http in the same interval, even if I enter the application and I close. I tried with the task of thread or a timer, but I have the same problem, it is if I enter the application and close the thread dies and I can't see http request. I don't know if I explain my problem... Can you tell me if there is a solution?

  Thanks in advance.

  Kind regards

  Gianni.

  Use a background application. You can use a different entry point (see the knowledge base) to enter your main application.

  a timer and timertask run a thread would be the best solution I think

• HTTPS post problem

  Hey guys I have problems to send data to a back-end server. I am trying to send the data using the http post method. Now, the connection works fine, her gives me a 200 OK response, after which I try to write data. But unfortunately the server receives all the data. My code is as follows:

  String toSend = "write it to the server";

  Byte [] postData = toSend.getBytes ();

  c = (HttpsConnection) Connector.open ("https://myurl;deviceside=true");

  c.setRequestProperty ("Content-Type", "application/x-www-formulaires-urlencoded");
  c.setRequestProperty ("Content-Language", "en-US");
  c.setRequestProperty ("Content-Length", String.valueOf (postData.length));
  c.setRequestMethod (HttpConnection.POST);
  int responseCode = c.getResponseCode ();

  dStr = new DataOutputStream (c.openOutputStream ());
  dStr.write (postData);

  dStr.flush ();
  dStr.close ();

  c.Close ();

  Am I missing something here? Help would be greatly appreciated.

  Thank you

  David

  Get rid of the flush.

  do the "getResponse" before closing the stream. This void anyway.

  Like this:

  Set the properties of the application
  setRequestProperties (m_httpConnection);
                         
  dataOutputStream = m_httpConnection.openDataOutputStream ();
  writeRequestPayload (dataOutputStream);
     
  get and store the response for this request code
  m_responseCode = m_httpConnection.getResponseCode ();

  Now you can close the stream

• Video MESSAGE by using HTTP connection

  Hi guys,.

  I develop an application only option to record a video and post video on the server for this I think that HTTP POST method is correct, but my question is how can I specify the video file

  for example, my file is stored in SDCard/videos/sample.3gp, how can I POST this?

  Can someone help me please

  Note: I have the path of the device using FileSystemJournal.

  Thank you

  PAPI

  public byte[] getByteArray() throws FileDoesNotExistException, Exception {
              try
              {
                  if (fc == null) {
                          fc = (FileConnection) Connector.open(getPath(),
                                          Connector.READ_WRITE);
                          if (!fc.exists())
                                  throw new FileDoesNotExistException("Can't Open requested file :");
                  }
  
                  _inputstream = fc.openInputStream();
                  int x;
                  BAOS = new ByteArrayOutputStream();
                  while ((x = _inputstream.read()) != -1) {
                          BAOS.write((byte) x);
                  }
          }
          catch(Exception e)
          {
              ExceptionHandler.handleAndShowAlert(e.toString());
          }
                  return BAOS.toByteArray();
          }
  
  ///////////////////////////
  

  Just write the byte array to the outputstream