Check the hours between 2 datetime value

Hi all

How can - I to select lines, where between 2 hours, doesn't bother me what date they have.

date2 date1

(1) 20/04/2015 08:30 20/04/2015 09:30

(2) 21/04/2015 10:00 21/04/2015 11:00

I have a varchar(HH24:MI) i.e. myhours = 09:15

I have to get the first row

SELECT count (*) of myhours between TO_CHAR (date1, 'HH24') and TO_CHAR (date2, 'HH24');

In this case, I have to get 1 (exists), instead, if I myhours = 12:00 I get 0 (does not exist)

Thanks in advance

select count(*)
  from my_table
 where to_date('01-01-1900' || my_hour, 'dd-mm-yyyyhh24:mi') between to_date('01-01-1900' || TO_CHAR(date1, 'HH24:MI'), 'dd-mm-yyyyhh24:mi')
                                                                 and to_date('01-01-1900' || TO_CHAR(date2, 'HH24:MI'), 'dd-mm-yyyyhh24:mi');

Tags: Database

Similar Questions

Calculate the hours between two dates
Hello

I have a requirement to count the hours with 2 given timestamps, something like:
```
SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;

         B
----------
        48
```
However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
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Count the hours between the times of the day

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It is a timesheet, calculation of payment:

I'm trying to find a way to calculate how many hours is between two specific times of the day.

I enter a start time and an end time (in 2 different items), I calculate the number of hours that is. What I can understand.

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Enter the full date and time in columns A and B (for example ' 12 Sep 2016 8:00 AM "or you like the what ever valid date time value):

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see this

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http://www.jobinesh.com/2011/05/checking-for-dirty-data.html

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Calculate the hours between 2 business days

Hi all

Do a complex calculation on the days I do not know how to achieve this.

Here is my case:

I have a week of work with hours of work.

Then there's this delivery time sheet for how long should be set an order ready to be delivered:

Order1: max 5 hours of work

Order2: max 8 working hours

Order3: max 16 hours of work

When an order is placed, the time of the order is recorded, and when an order has been set in ready to be delivered, this time is also registered.

How to calculate the time difference between the time where an order has been placed and the time where the order has been on loan. Thereby also taking into account the working days and hours of work.

Example: type order1 order was placed Tuesday at 15:00.

Order has been fixed loan Wednesday at 14:00

This means that to fix this ready order lasts 7 hours, which means that it is 2 hours time.

CREATE TABLE REF_WORKDAYS
  (
    
    "WERKDAG"       VARCHAR2(15 ) NOT NULL ENABLE,
    "SOORT_WERKDAG" VARCHAR2(15 ) NOT NULL ENABLE,
    "BEGIN_TIJD"    VARCHAR2(10 ) NOT NULL ENABLE,
    "EIND_TIJD"     VARCHAR2(10 B) NOT NULL ENABLE,
    
  )

Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Monday','WORKINGDAY','08:00','16:00');
Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Tuesday','WORKINGDAY','08:00','16:00');
Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Wednesday','WORKINGDAY','08:00','16:00');
Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Thursday','WORKINGDAY','08:00','16:00');
Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Friday','WORKINGDAY','08:00','16:00');
Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Satrurday','WORKINGDAY','08:00','14:00');
Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Sunday','NOT-WORKINGDAY','08:00','16:00');

COMMIT;

create table glas_order

(order_id number
, order_desc varchar2(100) not null
, order_type varchar2(10) not null
, order_date date not null
, order_ready date

);

Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (1,'order bla','Order1',to_date('07-APR-15 09:00','DD-MON-RR HH24:MI'),to_date('08-APR-15 12:00','DD-MON-RR HH24:MI'));
Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (2,'order nice','Order1',to_date('14-APR-15 10:00','DD-MON-RR HH24:MI'),to_date('16-APR-15 16:00','DD-MON-RR HH24:MI'));
Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (3,'order ugly','Order2',to_date('18-APR-15 13:00','DD-MON-RR HH24:MI'),to_date('21-APR-15 09:00','DD-MON-RR HH24:MI'));

COMMIT;

Thank you

Diana

Select

I like order_id

such as length d

order_type

d decode(order_type,'Order1',5,'Order2',8)

overtime

of glas_order o

model

Reference r on

(select

WERKDAG w

begin_tijd b

e eind_tijd

, (to_date (eind_tijd, 'HH24') - to_date (begin_tijd, 'HH24')) * 24 hard

of ref_workdays

where soort_werkdag = "WORKINGDAY")

dimension (w)

measures (b, e, hard)

main m

partition of (order_id I)

size of (0 n)

measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as wday, order_type)

iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

, d [0] = d [0] +.

case

When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

then presentv (r.b [wday [0]],)

less (largest (order_ready [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')), to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

-bigger (to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI'), least (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))))

0) * 24

When order_date [0] + iteration_number = order_date [0] - first day

then presentv (r.b [wday [0]],)

TO_DATE (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

-bigger (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]],'YYYYMMDDHH24:mi'))))

0) * 24

When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

then presentv (r.b [wday [0]],)

less (order_ready [0], to_date (to_char (order_ready [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

-to_date (to_char (order_ready [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

0) * 24

of another nvl (r.dur [wday [0]], 0)

end

)

ORDER_ID	DURATION	ORDER_TYPE	OVERTIME
1	11	Order1	6
2	22	Order1	17
3	10	Order2	2

Rewrittten party rules for readability purposes (more resources)

measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as to_date (null), (null) to_date, bd, order_type, wday ed)

iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

, comics [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

, ed [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

, d [0] = d [0] +.

case

When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

then presentv (r.b [wday [0]],)

less (largest (order_ready [0], [0] bd), ed [0])

-Greatest (BD [0], least(ORDER_DATE[0],ED[0]))

0) * 24

When order_date [0] + iteration_number = order_date [0] - first day

then presentv (r.b [wday [0]],)

ED [0]

-Greatest(ORDER_DATE[0],BD[0])

0) * 24

When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

then presentv (r.b [wday [0]],)

least(order_ready[0],ED[0])

-bd [0]

0) * 24

of another nvl (r.dur [wday [0]], 0)

end

)

Jubilee should be Saturday I guessed.

Excerpt from the hours between two dates

Hello
This is the value stored in the table of my database.
I want to extract betwwen hours two dates. How can I extract it.
I try to run like this
Select to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') double, but it gives the answer as the format 21:10:00.000000000 + 000000365
I want simple hours, minutes, and seconds
What is the format of this value as "dd-MON-yy."
27 JANUARY 14 01.30.00.000000 PM
26 JANUARY 14 06.22.32.170033 PM

Use the Extract function. Like this.

() AS T1 (C1)

Select to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') of double)

SELECT EXTRACT (DAY OF C1) | ' DAYS '.

EXTRACT (HOUR OF C1) | ' HOURS '.

EXTRACT (MINUTE OF C1) | ' MINUTES '.

EXTRACT (SECOND C1) | ' SECONDS

FROM T1;

OUTPUT:

365 DAYS 21 HOURS 10 MINUTES 0 SECONDS

If not try it.

SELECT EXTRACT (DAY OF to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) | ' DAYS '.

EXTRACT (HOUR FROM to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) | ' HOURS '.

EXTRACT (to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') MINUTE) | ' MINUTES '.

EXCERPT ((SECOND from to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) |) ' SECONDS

DOUBLE;

Post edited by: Parth272025

How to find the hours between two times

Hai All

I had a problem I need to calculate work time

For example

Respondent outtime

0815 1715

So I need to calculate a time between these two times

How can I do using function for 100 our

Concerning

Srikkanth.M

Hello

use the below the update statement.

update dail_att set wtime =  extract(hour from (to_date(outtime,'HH24:MI')-to_date(intime,'HH24MI')) day to second);

Solution of the sample...

PRAZY@11gR1> desc dte;
 Name            Null?    Type
 ------------------- -------- --------
 INTIME           VARCHAR2(4)
 OUTTIME        VARCHAR2(4)
 HRS                NUMBER

PRAZY@11gR1> select * from dte;

INTIME     OUTTIME           HRS
---------- ---------- ----------
0815       1715
0900       1800
0830       1630

Elapsed: 00:00:00.00
PRAZY@11gR1> update dte set hrs = extract(hour from(to_date(outtime,'HH24MI')-to_date(intime,'HH24MI')) day to second);

3 rows updated.

Elapsed: 00:00:00.01
PRAZY@11gR1> select * from dte;

INTIME     OUTTIME           HRS
---------- ---------- ----------
0815       1715                9
0900       1800                9
0830       1630                8

Elapsed: 00:00:00.00

Kind regards
Prazy

Published by: Prazy on March 24, 2010 12:43

Check the number of non zero values in each row

Hello
I have the following table
create the table attbon as
(
Select pryear 2014, 1 empid, to_date('21/11/2014','dd/mm/yyyy') prdate, 12 prmonth, 3 shortleave union double all the
Select double union all the 12 prmonth 2014 pryear, 1 empid, to_date('22/11/2014','dd/mm/yyyy') prdate shortleave 0
Select double union all the 12 prmonth 2014 pryear, 1 empid, to_date('23/11/2014','dd/mm/yyyy') prdate shortleave 0
Select double union all the 12 prmonth 2014 pryear, 1 empid, to_date('24/11/2014','dd/mm/yyyy') prdate shortleave 0
Select double union all the 12 prmonth 2014 pryear, 1 empid, to_date('25/11/2014','dd/mm/yyyy') prdate shortleave 0
Select pryear 2014, 2 empid, to_date('21/11/2014','dd/mm/yyyy') prdate, prmonth 12, 1 shortleave Union double all the
Select 2014 pryear, 2 empid, to_date('22/11/2014','dd/mm/yyyy') prdate, prmonth 12, 1 shortleave Union double all the
Select 2014 pryear, 2 empid, to_date('23/11/2014','dd/mm/yyyy') prdate, prmonth 12, 1 shortleave Union double all the
Select double union all 12 prmonth, 2014 pryear, 2 empid, to_date('24/11/2014','dd/mm/yyyy') prdate shortleave 0
Select double union all 12 prmonth, 2014 pryear, 2 empid, to_date('25/11/2014','dd/mm/yyyy') prdate shortleave 0
Select 3-shortleave, 3-empid, prmonth 12, to_date('21/11/2014','dd/mm/yyyy') prdate, 2014 pryear Union double all the
Select double union all 12 prmonth, 3 empid, to_date('22/11/2014','dd/mm/yyyy') prdate, 2014 pryear, 1 shortleave
Select double union all 12 prmonth, 3 empid, to_date('23/11/2014','dd/mm/yyyy') prdate, 2014 pryear, 0 shortleave
Select double union all 12 prmonth, 3 empid, to_date('24/11/2014','dd/mm/yyyy') prdate, 2014 pryear, 0 shortleave
Select double union all 12 prmonth, 3 empid, to_date('25/11/2014','dd/mm/yyyy') prdate, 2014 pryear, 0 shortleave
Select pryear 2014, empid 4, to_date (' 21/11/2014 ',' dd/mm/yyyy') prdate, prmonth 12, 1 shortleave Union double all the
Select 2014 pryear, 12 prmonth, 3 shortleave, 4 empid, to_date (' 22/11/2014 ',' dd/mm/yyyy') prdate of all the double union
Select double union all 12 prmonth, 2014 pryear, 4 empid, to_date('23/11/2014','dd/mm/yyyy') prdate shortleave 0
Select double union all 12 prmonth, 2014 pryear, 4 empid, to_date('24/11/2014','dd/mm/yyyy') prdate shortleave 0
Select pryear 2014, prmonth 12, shortleave 0, empid, to_date (' 25/11/2014 ',' dd/mm/yyyy') 4 prdate double
);
I want to find the eligibility of premium participation for each employee for each day
An employee is allowed to take the maximum of 3 hours as shortleave.
Normally if SHORTLEAVE is greater than 1 for a day, the employee is not eligible for the bonus of participation for this day
So if an employee DISP shortleave of one hour each, on three different days or more, it is eligible for the bonus of attendance for every day.
If it make use of all three hours on a stretch as he is eligible for the bonus of presence condition no other short-term leave availed for this month.
otherwise this day where it's not eligible for the bonus of presence
That is to say.
attboneligible of a day is 1
If shortleave < = 1
or
(shortleave = 3, and County of short leave zero for the month is 1)
Required result
=============================================
EMPID PRDATE ATTBONELIGIBILITY
=============================================
21/11/2014 1, 1
22/11/2014 1, 1
23/11/2014 1, 1
24/11/2014 1, 1
25/1/11/2014 1
21/11/2014 2, 1
22/11/2014 2, 1
23/11/2014 2, 1
24/11/2014 2, 1
25/2/11/2014 1
3 21/11/2014 0
22/11/2014 3, 1
23/11/2014 3, 1
3 24/11/2014 1
25/3/11/2014 1
21/11/2014 4, 1
22/11/2014 4, 0
23/11/2014 4, 1
24/11/2014 4, 1
25/4/11/2014 1
===============================================
I use oracle 10g
Help, please

Hello Krishna,

Try this in your test data:

Update attbon set shortleave = 2 where shortleave = 3;

And compare with your expectations.

I guess, Frank or your own modiifcation will do the job...

If I understand you right...

But try Indra!

Best regards

Karlheinz

How to check the account of a column value is less than the other value of column in a table with a single column

Hello
Please let me know how to query the table and get the records that are less than the other column.
ID item_id item_type
3 1 r1
2 4 r2
1 5 r3
6 5 r4
I need to get all the lines in which item_id < id
o/p
ID item_id item_type
3 1 r1
6 5 r4

SELECT ID, ITEM_ID, ITEM_TYPE

Of

WHERE ITEM_ID<>

Calculate business hours between two dates in a cursor

Hello, its me again (?).

Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

with t (start_date
       ,end_date
       )
as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                       to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
    from dual
   )
, hrs (dt) as
  (select start_date
   from   t
   union all
   select dt +1/24/60
   from   hrs
   where  hrs.dt < (select end_date-1/24/60 from t)
  )
select count(*)/60
from hrs
where to_char(dt,'dy') not in ('sat','sun')
and  to_number(to_char(dt,'hh24')) not between 18 and 23
and  to_number(to_char(dt,'hh24')) not between 0 and 8
/

The logic above, I'm up here:

FOR c_record IN c_1 LOOP
//For each record, check if the two dates meet the criteria and then raise the counters accordingly
select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;

IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
  vContOk :=vContOk + 0;
  vContBad := vContBad+1;
  vContOt   := vContOt+1;
ELSE 
  vContOk :=vContOk +1;
  vContBad := vContBad+0;
  vContOt   := vContOt+1;
END
    IF;

IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
  vContOk :=vContOk + 0;
  vContBad := vContBad+1;
  vContOt   := vContOt+1;
ELSE
  vContOk :=vContOk +1;
  vContBad := vContBad+0;
  vContOt   := vContOt+1;
END IF;

IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
  vContOk :=vContOk + 0;
  vContBad := vContBad+1;
  vContOt   := vContOt+1;
ELSE
  vContOk :=vContOk +1;
  vContBad := vContBad+0;
  vContOt   := vContOt+1;
END IF;

END LOOP;

I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
However, I can't find a way to use this connection even in this case

Could you help me?
Thank you!

Greetings,
NACEUR

N wrote:
I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,
                                   p_end_date DATE
                                  )
    RETURN NUMBER
    IS
        v_return NUMBER;
    BEGIN
        with t as (
                   select  case level
                             when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                             else trunc(p_start_date) + level - 15 / 24
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                             else trunc(p_start_date) + level - 8 / 24
                           end end_dt
                     from  dual
                     connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                  )
        select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
        RETURN v_return;
END;
/

For example:

SQL> select get_bus_minutes_between(
  2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
  3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
  4                                ) work_minutes
  5    from dual
  6  /

WORK_MINUTES
------------
         261

SQL>

SY.

Number of hours of the weekend between two timestamps

I'm trying to take two timestamps and the total number of hours weekend between them. For example:
Between October 23, 13 08.28.00.000000 AM and 28 October 13 04.48.25.424940 PM, there are two weekend days. I want the query to return the 48 hours.
Between October 24, 13 04.48.25.424940 PM and 01.00.00.000000 October 27, 13 h ago weekend day plus 13 hours Sunday, I would that this return to 37 hours.
Database version:
Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
PL/SQL Release 11.2.0.3.0 - Production
"CORE 11.2.0.3.0 Production."
AMT for Linux: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production
Create / Insert statements:
CREATE TABLE 'TDIFF.
(NUMBER OF 'ID',
"TS1' TIMESTAMP (6).
('TS2' TIMESTAMP (6));
Insert into TDIFF (ID, TS1 and TS2) values (1, to_timestamp (17 October 13 02.09.01.818304000 PM ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (30 October 13 09.16.00.000000000 PM ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (2, to_timestamp (21 October 13 01.23.58.258494000 PM ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (24 October 13 10.00.00.000000000 AM ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (3, to_timestamp (07.33.10.874721000 AM October 23, 13 ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (24 October 13 10.00.00.000000000 AM ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (4, to_timestamp (09.12.41.928313000 AM October 23, 13 ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (25 October 13 02.30.00.000000000 PM ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (5, to_timestamp (10.12.22.790736000 AM October 23, 13 ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (24 October 13 06.40.00.000000000 PM ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (6, to_timestamp (10.33.20.879307000 AM October 23, 13 ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (25 October 13 04.24.00.000000000 PM ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (7, to_timestamp (11.01.23.467642000 AM October 23, 13 ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (24 October 13 07.00.00.000000000 AM ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (8, to_timestamp (23 October 13 04.45.08.237177000 PM ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (07.00.00.000000000 AM October 25, 13 ',' DD-MON-RR HH.MI.) PSM AM FF '));
Insert into TDIFF (ID, TS1 and TS2) values (9, to_timestamp (23 October 13 04.48.25.424940000 PM ',' DD-MON-RR HH.MI.)) PSM AM FF'), to_timestamp (28 October 13 08.28.00.000000000 AM ',' DD-MON-RR HH.MI.) PSM AM FF '));
This is what I have so far, but his return the number of incorrect hours:
```
SELECT TS1,TS2,
  (SELECT COUNT(*)
   FROM DUAL
   WHERE TO_CHAR(TS2 + LEVEL - interval '1' hour, 'DY') IN ('SAT', 'SUN') 
CONNECT BY LEVEL <= 24*extract(DAY FROM TS2-TS1)+extract(hour FROM TS2-TS1) + 1 ) D1_WEEKEND_HOURS
FROM TDIFF
```
Any ideas are appreciated.
-Steve

Here is another way, assuming a definition of the weekend as strictly between midnight Friday and midnight Sunday:

The interval of D1 to D2 can be considered be allowed between the D1 and the next 00 Monday more time between Monday preceding the D2 and D2 as well as the weeks between the two Monday to 00:00.
```
select  id, ts1, ts2,
( least(7 + (trunc(CAST(ts1 as DATE), 'IW') - CAST(ts1 as DATE)), 2) /* ts1 to Monday */
+ greatest( (CAST(ts2 as DATE) - trunc(CAST(ts2 as DATE), 'IW')) -5, 0) /* Monday to ts2 */
+ 2/7 * (trunc(CAST(ts2 as DATE), 'IW') - trunc(CAST(ts1 as DATE), 'IW') -7 ) /* Weeks between Mondays */
) * 24
from TDIFF
```

The sound of Apple received email saying and tells me to check the password within 48 hours. Scam?

rreceived 'Apple' email, telling me to check the password within 48 hours. Is it a scam?

Yes, it's almost certainly a scam.

The only time where Apple will send you a letter about your password is if you click on the "Forgot password" link on one of their sites, and even in this case the email will tell you how change or reset, has not check.

Take the time between two values

Hi people,

I have a problem and I know idea how to solve... I need help.

The problem is I want to take the time between two values max as you can see in the chart.

For example, in the image that I have add

4.5 - 1 840 = 2.66

And enter this value in the 'time between mostra '.

It's that I want...

But what I think is very complicated, because I don't know how to take the time correctly and does remove...

Thank you very much

Any solution?

Hi jocuma,

I tried something and hope that helps u.

Just create two arrays of temperature and voltage. First of all, I'll get the value of the voltage when it is more of a certain value and that same index to get the value of time and store in the shift register.

When I get the second higher than the limit value, I'll get time and subtract the previous value.

Check the hours between 2 datetime value

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