Colors of the nodes in a tree

Similar Questions

• How to change the icon of the node in a tree when the node collapse or expand?

  How to change the icon of the node in a tree when the node collapse or expand?

  Hello

  You may need to use the custom for this skin.

  Arun-

• Change the color of the nodes in the tree based on a regular expression

  Dear Experts,
  
  Given:
  Sample:
  http://Apex.Oracle.com/pls/Apex/f?p=53647:5
  Test/test
  
  Information from the workspace
  Workspace: ralab
  user: test
  password: test
  application: trees-samples
  page: 5
  
  Mandatory
  I can change the color of node using jQuery contains() selector based on a value, for example the project

  apex.jQuery("#eba_demo_tree").find("a:contains('Project')").css("color","red");

  Now, the question:
  How can I update the jQuery code to change the node based on a regular expression as

  ^[P]

  or in other words for all the nodes starts with P, the color needs to be changed in red?
  
  Best regards
  Mahmoud

  $("#eba_demo_tree a").filter(function(index){
     var lRegExp = /^m/i; //or new RegExp('^m', 'i');
     //trim to get rid of leading space due to space in encapsulated ins-element
     return lRegExp.test($(this).text().trim());
  });
  

  http://API.jQuery.com/filter/
  http://www.w3schools.com/jsref/jsref_obj_regexp.asp
  http://www.regular-expressions.info/JavaScript.html

• Find the node of a tree leaf in oracle apex 5

  Hello

  I use TREE in oracle apex 5.0. I created a tree and an IR.

  For example, when the user clicks on the evolution of the event tree leaf node will occur and data of the selected node will be displayed in IR (on the change event of DA).

  Right now I am able to show that one of the values of node root.

  SQL OF THE TREE:

  Select case when connect_by_isleaf = 1 then 0

  When level = 1 then 1

  else                           -1

  end the status,

  level,

  "PRODUCT_GROUP_NAME" as the title,

  NULL as an icon,

  "PRODUCT_GROUP_ID" as a value.

  NULL as ToolTip,

  ' javascript:nodefunction('''||) PRODUCT_GROUP_ID | " ') ; "as link

  of ' #OWNER # '. " OMS_PRODUCT_GROUP ".

  start with 'PRODUCT_GROUP_ID' = (select product_group_id from the OMS_product_group where parent_id = 0)

  connect prior "PRODUCT_GROUP_ID" = "PARENT_ID".

  siblings arrested by 'PARENT_ID '.

  IR SQL:

  SELECT

  op.product_id_dump,

  op.product_name,

  OPG.product_group_name "Prodcut group."

  op. Description,

  op.unit_price

  Op OMS_PRODUCT, OMS_PRODUCT_GROUP opg

  WHERE op.product_group_id = opg.product_group_id

  AND opg.product_group_id = TO_NUMBER(:P53_SELECTED_NODE)

  Hi Dominique,.

  Try this query in your report,

  SELECT

  op.product_id_dump,

  op.product_name,

  OPG.product_group_name "Prodcut group."

  op. Description,

  op.unit_price

  Op OMS_PRODUCT, OMS_PRODUCT_GROUP opg

  WHERE op.product_group_id = opg.product_group_id

  AND op.product_group_id = TO_NUMBER(:P53_SELECTED_NODE)

  Union

  SELECT

  op.product_id_dump,

  op.product_name,

  OPG.product_group_name "Prodcut group."

  op. Description,

  op.unit_price

  Op OMS_PRODUCT, OMS_PRODUCT_GROUP opg

  WHERE op.product_group_id = opg.product_group_id

  AND op.product_group_id in (select product_group_id from the OMS_PRODUCT_GROUP where parent_id = TO_NUMBER (:P53_SELECTED_NODE))

  hope it works for you,

  Kind regards

  Jitendra

• Expand all the nodes in a tree table

  Hello

  I have a tree table in my JSPX, which needs to expand all its nodes when the page is loaded. Also mis the data control is a POJO data contrl where I have a collection (ArrayList), which serves to make this table from the tree. Tree table is displayed as expected with it of the child nodes.

  
  

  I was referring rare item such as these... https://blogs.oracle.com/jdevotnharvest/entry/how_to_programmatically_disclose_a to expand all nodes. But I get an exception of cast of class on the piece of code following

  Code:

  CollectionModel model = (CollectionModel) your_af_tree_reference.getValue();
  

  Exception:

  javax.faces.el.EvaluationException: java.lang.ClassCastException: oracle.adfinternal.view.faces.model.binding.FacesCtrlHierBinding$FacesModel cannot be cast to oracle.adf.view.rich.model.CollectionModel
  at org.apache.myfaces.trinidad.component.MethodExpressionMethodBinding.invoke(MethodExpressionMethodBinding.java:51)
  

  ......................

  I use Jdev 11.1.1.4

  Let me know if you need more details to achieve this please.

  Refer to this:

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/78-man-expanding-trees-treetables-354775.PDF

  You can download the sample code from:

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/index-101235.html

  Search for number 078.

• Change the color of the links in a tree

  I need to change the default link colors (a: active, a: hover, a: visited...) in a tree.
  I tried to put css inline
  style type = "text/css" >
  a: active {color: black; make-weight: bold; text-decoration: underline}
  a: hover {color: red; make-weight: bold; text-decoration: underline}
  a: link {color: blue; make-weight: bold; text-decoration: underline}
  a: visited {color: magenta; make-weight: bold; text-decoration: underline}
  < / style
  
  in the page template between the head, but the only style tags the pudding is a: visited.
  
  Version 3.1.0 apex class model - two level, Southwest theme tabs.
  
  Is there a built-in style a tree uses as styles of line replacing in a report?
  
  If so, what are they?
  
  Thank you
  
  Bob

  Hi Bob,

  In styling Pseudo-classes on a tags, you must specify them in strict order:

  a: link
  a: visited
  a: hover
  a: active

  Try changing the order to correspond to this

  Andy

• How to remove the feature clickable af:tree text node

  Hello
  
  I want to remove clickable feature of the text box for the af:tree node. (always expandable with + icon).
  
  even if I use af:outputtext for the node, it is still clickable.
  
  single tree leaf shoud be clickable.
  
  can I do this?
  
  < af:tree id = value = "#{'sTree' MenuGenerator.treeModel} '"
  var = 'node' styleClass = 'stree '.
  rowDisclosureListener = "#{MenuGenerator.treeToggle} '"
  Binding = "#{MenuGenerator.richTree} '"
  rowSelection 'single' = >
  < f: facet name = "nodeStamp" >
  < af:group >
  "< af:image source="/resource/images/page.png ".
  visible = "#{node.action! = null}" / >
  < af:commandLink text = "#{node.name} '"
  action = "#{STARS21TaskFlow.goToAction} '"
  visible = "#{non-empty node.action}.
  partialSubmit = 'true' immediate = "true" >
  < f: param = name "module" value = "#{node.module}" > < / f: param >
  < f: param = name 'action' value = "#{node.action}" > < / f: param >
  < / af:commandLink >
  < af:outputText value = "#{node.name} '"
  rendering = "#{empty node.action}.
  inlineStyle = "text-decoration: none;" background-color: transparent; ">
  
  < / af:outputText >
  < / af:group >
  < / f: facet >
  
  < / af:tree >
  
  
  
  With respect,
  WP
  
  Published by: Watel on January 22, 2010 17:31

  Hello

  How about you, using a disabled instead of an output text input text?

  Something like

  Arun-

• How to select the node on the tree to redirect to a different page

  Hello everyone,

  

  I created a tree on page 0

  conditional for pages

  It is based on values in a tree table

  https://Apex.Oracle.com/pls/Apex/f?p=67108:1:101371508545299:

  WORKSPACE:-REEMATEST

  username:-test

  password:-test

  My requirement is

  If I click on the details of employee node, it goes to page 2

  If I click on the node details 2 employees it goes to page 3

  How can I specify the page for each node forwarding

  Reema,

  If you want your query to simpler tree, where, then add a column over in the tree as the "url" table, and specify the url to each table entry.

  as I stated in Page 1 and table 'Tree' in your workspace.

  Leave.

• How to set programmatically the current node in a tree view of the ADF.

  Hello
  

  I'm trying to understand how to set programmatically the current node in a tree view of the ADF.

  My use case example is quite simple; If we take the sample application ADF Summit where under Management Summit, we have a tree view on the left with a list of high level of the country which in turn contain a subset of customers; then, in the right pane, we the customer detail information.

  What I'm trying to achieve is a solution by which I can add a new customer, commit and then to the tree show the client newly created as the currently selected entry.

  I use a pop-up dialog box to create my new entry of the customer and everything works well in this area, and my newly created folder is saved in the database.

  I know how to force the tree to cool off, but what I can't understand is how to do so, it highlights the newly created folder.

  Any help would be much appreciated.

  Refer

  https://blogs.Oracle.com/jdevotnharvest/entry/how_to_programmatically_disclose_a

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/78-man-expanding-trees-treetables-354775.PDF

• How to add a tab to the node root tree of inventory?

  Is it possible to add a tab for the node root tree in the display of the inventory? Something like InventoryView.VCenter?

  Thanks in advance,

  Derek

  InventoryView.RootFolder is probably what you want.

• Operations on the nodes of the tree

  Hi everyone, it's me again, with another question =)
  
  I need to be able to rename any node under a specific node in a hierarchy. Take this table and the following data samples.
  

  CREATE TABLE organisations
  (
    organ_id NUMBER(10) PRIMARY KEY, 
    parent_id NUMBER(10), 
    NAME VARCHAR2(255), 
    CONSTRAINT fk_org_to_parent_org 
       FOREIGN KEY(parent_id) REFERENCES organisations(organ_id)
  );
  
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (1,null,'Organisation 1');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (2,null,'Organisation 2');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (21,2,'Organisation 21');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (22,2,'Organisation 22');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (221,22,'Organisation 221');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (2211,221,'Organisation 2211');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3,null,'Organisation 3');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (31,3,'Organisation 31');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (311,31,'Organisation 311');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3111,311,'Organisation 3111');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (32,3,'Organisation 32');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (321,32,'Organisatin 321');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3211,321,'Organisation 3211');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (3212,321,'Organisation 3212');
  Insert into ORGANISATIONS (ORGAN_ID,PARENT_ID,NAME) values (313212,3212,'Organisation with an id containing 31.');

  I would rename the tree nodes. For example, for example add the '-renamed "to all nodes under the node with the id of the organ = 31?
  
  I tried the following, but it is not good, because whenever I have another ID containing the number 31, I have an erroneous result.

  SELECT organ_id, lpad(' ', LEVEL * 2) || name, 
         -- sys_connect_by_path(organ_id, ','), 
          case when instr( sys_connect_by_path(organ_id, ','), '31') > 0 then 
             name || '- renamed' 
             else 
             name
          end
    FROM organisations
   START WITH parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;

  The following query performs the work:
  

  select organ_id, lpad(' ', level * 2) || name, 
         -- sys_connect_by_path(organ_id, ','), 
          case when organ_id IN (SELECT organ_id 
                                   from organisations 
                                  start with organ_id = 31
                                CONNECT BY prior organ_id =  parent_id) then 
                name || '- renamed' 
             else 
             name
          end
    from organisations
   start with parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;

  I wanted to know if it was possible without selecting sub?
  
  Thank you

  Hello

  user13117585 wrote:
  ... I tried the following, but it is not good, because whenever I have another ID containing the number 31, I have an erroneous result.

  SELECT organ_id, lpad(' ', LEVEL * 2) || name,
  -- sys_connect_by_path(organ_id, ','),
  case when instr( sys_connect_by_path(organ_id, ','), '31') > 0 then
  name || '- renamed'
  else
  name
  end
  FROM organisations
  START WITH parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;
  

  It is called the problem of 'Mother in chemotherapy', here's a way to solve it:

  SELECT organ_id, lpad(' ', LEVEL * 2) || name,
         -- sys_connect_by_path(organ_id, ','),
          case when instr( sys_connect_by_path(organ_id, ',') || ',', ',31,') > 0 then
             name || '- renamed'
             else
             name
          end
    FROM organisations
   START WITH parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;
  

  In other words, don't look for '31', look at ", 31,

  The following query performs the work:

  select organ_id, lpad(' ', level * 2) || name,
  -- sys_connect_by_path(organ_id, ','),
  case when organ_id IN (SELECT organ_id
  from organisations
  start with organ_id = 31
  CONNECT BY prior organ_id =  parent_id) then
  name || '- renamed'
  else
  name
  end
  from organisations
  start with parent_id is null
  CONNECT BY PRIOR organ_id = parent_id;
  

  I wanted to know if it was possible without selecting sub?

  Thank you

• How can I update the children after a node in a tree?

  Hello world.
  I am updating a subtree programmatically using a bean managed as data source.
  I can find all the topics are about the use of your and JUCtrlHierNodeBinding.updateValuesFromRows.
  Now, I need to find a way to directly update the nodes without any line. What should I do?
  
  Here is the code:
  
  Tags:

                                  <af:tree id="tframe" initiallyExpanded="true"
                                           selectionListener="#{backingBeanScope.systemDataFrameBB.onSelectNode}" var="n"
                                           binding="#{backingBeanScope.systemDataFrameBB.tframe}"
                                           value="#{systemDataFrameMB.treeData}" expandAllEnabled="true"
                                           rowSelection="single" fetchSize="-1" contentDelivery="immediate"
                                           immediate="true" summary="summary">
                                      <f:facet name="nodeStamp">
                                                    <af:group>
                                                    <af:outputText value="#{n.is_system?'[SYSTEM]':''}" />
                                                    <af:outputText value="#{n.is_use?'':'[X]'}" />
                                                                   <af:outputText value="#{n.data_frame_name}"/>
                                                    </af:group>
                                      </f:facet>
                                  </af:tree>

  (systemDataFrameMB) bean managed:

       private ChildPropertyTreeModel treeData;
       public ChildPropertyTreeModel getTreeData() throws SQLException
       {
            if (this.treeData == null)
            {
                 AuthAMImpl authAM = this.getAppModule();
                 List<DataFrameNode> subTrees = authAM.getDataFrameTrees();    // load with JDBC and POJO
  
                 DataFrameNode root = new DataFrameNode();      // insert all sub-trees into a new tree
                 root.setData_frame_id(0);
                 root.setData_frame_name("[ROOT]");
                 root.setParent_data_frame_id(Integer.MIN_VALUE);
                 root.setIs_system(true);
                 root.setIs_use(true);
                 if (subTrees != null && subTrees.size() > 0)
                 {
                      root.setChildren(subTrees);
                      for (DataFrameNode n : subTrees)
                           n.setParent(root);
                 }
                 this.treeData = new ChildPropertyTreeModel(root, "children");      // I guess this is the simplest way to show hierachical data...
            }
            return this.treeData;
       }

  model:

  public class DataFrameNode
  {
       private int data_frame_id;
       private String data_frame_name;
       private int parent_data_frame_id;
       private boolean is_use;
       private boolean is_system;
  
       private DataFrameNode parent;
       private List<DataFrameNode> children;
  
          // getters/setters are omitted....
  }

  support bean (systemDataFrameBB):

          // edit event handler
       public void onEditResult(DialogEvent de)
       {
            String name = (String)this.getItName().getValue();
            boolean isUse = this.getSbcIsUse().isSelected();
            SystemDataFrameMB dfMB = (SystemDataFrameMB)JSFUtils.resolveExpression("#{systemDataFrameMB}");
  
            try
            {
                 node.setData_frame_name(name);
                 node.setIs_use(isUse);
                 dfMB.updateNode(node);                   // persist changes, this method will change all the children's 'is_use' field to FALSE when isUse == FALSE
                 AdfFacesContext.getCurrentInstance().addPartialTarget(this.getTframe());      // refresh the tree, only the edited node will be updated, but I want the tree to update the whole sub-tree to reflect the change on all its children
            }
            catch (Exception e)
            {
                          // omitted...
            }
          }

  Yes, you must use JUCtrlHierNodeBinding to update entire tree.

• How to get the primary key of the node selected in af:tree

  Hi all
  
  I use JDeveloper 11.1.1.5.0.
  
  I want to get the primary key of the node selected in the af:tree element. I wrote the code below in SelectionListener:
  

      public void drzewkoRwaSelectionListener(SelectionEvent evt) {
          RichTree tree = (RichTree)evt.getSource();
          TreeModel model = (TreeModel)tree.getValue();
          RowKeySet rowKeySet = evt.getAddedSet();
          Object key = rowKeySet.iterator().next();
          
          model.setRowKey(key);
     
          System.out.println(rowKeySet);
          System.out.println(rowKeySet.size());

  The result looks like this:

  [[oracle.jbo.Key[5 ], oracle.jbo.Key[6 ], oracle.jbo.Key[12 ],oracle.jbo.Key[14 ]]]]
  1

  I need the values of the last 2 nodes:
  1: oracle.jbo.Key [14]
  2: oracle.jbo.Key [12]
  
  How can I get?
  
  Kind regards
  Wojtek.

  Hello

  Try this code:

  {} public void drzewkoRwaSelectionListener (evt SelectionEvent)
  RichTree tree = (RichTree) evt.getSource ();
  Model TreeModel (TreeModel) = tree.getValue ();
  RowKeySet rowKeySet = evt.getAddedSet ();
  Key of the object = rowKeySet.iterator () .next ();

  model.setRowKey (key);

  System.out.println (rowKeySet);
  System.out.println (rowKeySet.Size ());

  Object [] keys = rowKeySet.toArray ();
  List (list) = keys [0];
  Keys = list.toArray ();
  * //from the table keys, you can get according to the value you want using as: [2], [3] key *.

• How to create a report based on the selection of a node of a tree

  Hello
  
  I am new to Oracle Apex and tried to build a tree and also an interactive report based on column empno from emp table.
  
  I created a tree based on the emp table. Now, I want to see the records in the employee selected in the tree.
  
  This is the query of the tree:
  
  Select case when connect_by_isleaf = 1 then 0
  When level = 1 then 1
  of another-1
  end the status,
  level,
  'ENAME' as the title,
  NULL as an icon,
  'EMPNO' as value,
  NULL as ToolTip,
  NULL as link
  of ' #OWNER # '. " EMP.
  Start by "MGR" is nothing
  connect prior "EMPNO" = "MGR".
  siblings arrested by 'ENAME '.
  
  Can someone tell me step by step how to go from here?
  
  I tried to follow the thread Re: question of tree but could not understand a lot of it.

  The approach to reload the page and display the report is fairly simple.

• You start by creating a new page element that will be used to store the selected node ID, for example. P100_SELECTED_NODE (you can do atext element and change hidden once everything works as expected)
  
• Change the query of the tree and the link column in the SQL of tree definition to a link to the same
  for example if your page is 100, you'd do the tree node a link to the same page but the value of the P100SELECTED_NODE with id_ of the node selected
  This is done here
  {message: id = 4410987}
  In this case, it would be

  ' f ? p = & APP_ID.: 100 :'|| : APP_SESSION |': P100_SELECTED_NODE :'|| EMPNO as link

  Now when you click on a link to tree node, it would be back to the same page, but set the P100_SELECTED_NODE with the empno of the clicked node.

• All that's left to do, change your report so that it refers to the new point inorder to filter records for this employee empno i.e

  SELECT ...
    ..
  WHERE empno= :P100_SELECTED_NODE
  

• Expand the node of the tree dynamically

  I have try the XML for the filter and open the tree node.

  var point: XML = xml... node. (@BH is argument); point is not null.

  tree. openItems = item; did not work

  tree. expandItem (point); also not worked

  tree. expandChildrenOf (point); still didn't work

  var p: * = tree.getParentItem (item); p is always null! ~~~

  tree. expandChildrenOf (p);

  The code you posted is slightly different from the one I proposed, after a while range of instruction you must call expandItem for element nodes [0]:

  tree.expandItem (node [0], true)

  So, you should try to replace the two lines that are placed below the one that is placed above.

  tree.expandItem (parentNode.parent (), true);

  tree.expandChildrenOf (PNode [0], true); / / not work