Columns in the WHERE clause - order affect the output?
I work on some queries to feed a DWH and stumbled upon this question. Let's say I have this query:(SELECT ARTREGNROS FROM gx.artabo aa,gx.toccab tc1
where aa.artid=tc1.artid
and t.tocid=tc1.tocid
and aa.abocod=c.abocod
and aa.artconcod=c.concod
and aa.percod=a.percod
and aa.ArtAboFlgA='S'
) Tarjeta
The exit will happen anyway if I do like this:(SELECT ARTREGNROS FROM gx.artabo aa,gx.toccab tc1
where aa.artid=tc1.artid
and a.percod=aa.percod
and aa.ArtAboFlgA='S
and tc1.tocid=t.tocid
and c.abocod=aa.abocod
and aa.artconcod=c.concod
) Tarjeta
I guess what he used, or at least I him did not change with the data that I use, but I thought to check here once just to have peace of mind. Maybe it's not the happiest example, but I guess the question is clear
No difference.
Tags: Database
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Hi all
I have a question on the OBI EE meta data layer.
We have OBIEE sitting on a with a star schema data warehouse.
Our fact table contains the following fields...
EmployeeID
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So my table of facts in the presentation layer would look like this
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Thank youHello
I think that what you want to achieve must be done in the physical layer and not the business layer.
Instead of using your physical table directly from the DB, you must create a physical table based on an SQL statement.
GO to the physical layer you / create the new object table in Table type choose "Select" and then you write your select statement as you want.
Once this is done to create your physical joins and import your table into your business layer and create your complex joins
This should do the trick.
It may be usefulConcerning
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http://docs.Oracle.com/CD/B19306_01/RAC.102/b14197/crsref.htm
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Don't quite understand. So, if
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So, ifTARGET = ONLINE , then that means this particular resourse should be up mandatorily ? and if TARGET = OFFLINE , then that means this particular resourse does not have to be up ?
It's also the way I understand it.
>
>
>Question2.
Can someone tell me a scenario for a standard implementation of CARS, where you can find the TARGET = OFFLINESuch as in the 11.2 CARS:
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Details on the order of columns in a Where Clause
Thank youHi All My both Quarries are giving same record count . so can i say that the order of the columns("msib.inventory_item_id=pol.item_id" AND" pol.item_id=msib.inventory_item_id ") in the where clause doesn't effect the query result in any situation {code } select count(*) from po_headers_all poh ,po_vendors pv ,po_lines_all pol ,po_line_locations_all pll ,mtl_system_items_b msib where poh.vendor_id = pv.vendor_id and poh.po_header_id = pol.po_header_id and pol.po_line_id = pll.po_line_id and pll.ship_to_organization_id = msib.organization_id ----------------1 and msib.inventory_item_id=pol.item_id --------------------------2 and poh.type_lookup_code = 'STANDARD' and pv.vendor_name = 'Star Gate Ltd' group by 1 select count(*) from po_headers_all poh ,po_vendors pv ,po_lines_all pol ,po_line_locations_all pll ,mtl_system_items_b msib where poh.vendor_id = pv.vendor_id and poh.po_header_id = pol.po_header_id and pol.po_line_id = pll.po_line_id and pol.item_id = msib.inventory_item_id ----------------------------------2 and pll.ship_to_organization_id = msib.organization_id -----------------------------1 and poh.type_lookup_code = 'STANDARD' and pv.vendor_name = 'Star Gate Ltd'
Published by: vijay539 on November 20, 2009 09:17
Published by: vijay539 on November 20, 2009 09:18
Published by: vijay539 on November 20, 2009 09:19
Published by: vijay539 on November 20, 2009 09:19Hello
Right; the order in which the columns appear in the SELECT clause has nothing to do with the lines that are in the result set.
In fact, unless you say SELECT DISTINCT , I don't think there's anything (except to trigger an error) you can do in the SELECT clause, which would change the lines are selected.
Published by: Frank Kulash, November 20, 2009 12:45
Sorry, I misread the question. You may have about the order of the conditions in the WHERE clause, not the SELECT clause.
The answer in short is the same:
Right.Unless you mix ANDS and ORs (no one should ever do and that you are not), the order of the conditions will make no difference in the results.
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How to set a null column in a where clause clause involving a statement box
In oracle APEX, I a (selection list) element called: P32_STATUS. It contains two values of interest (for this discussion): 'Available' and 'checked '. In my report, I have a column called vc_status that contains two values: "Checkbox" and NULL. In my application I want to use a case statement in my where clause similar to the lines of
where
.
.
.
AND (vc_status = CASE WHEN: P32_STATUS = "Checkbox" THEN : P32_STATUS )
WHEN : P32_STATUS = 'Available' THEN NULL END)
The 'box' filtering works but the filtering to try to vc_status the NULL value does not work. Can someone help me? Thank you!
(P.S. My intuition says that there because I can not put vc_status = NULL, but I must say that vc_status IS NULL... However, I don't know how to do execution IS ZERO inside a CASE statement)
Hello
Your intuition is right...
In Oracle NULL is a bit special:
NULL = NULL is false
NULL <> NULL is false
Thus, instead of the parameter a NULL value in the CASE WHERE there is just set a value on the other side:
NVL (vc_statut, 'Available') =: P32_STATUS
That's all! Simple, clean and functional
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Can anyone help?
fixed term
trigger the echo;
Set feedback off;
game check
put in head
set of 99 pages;
set pagesize 50;
set linesize 80;
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coil/usr/IBM/WebSphere/AppServerCommunityEdition/repository/default/TTMSWeb/12
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Col format a15 SECTION staff "Staff" JUSTIFY RIGHT;
Select b.device_status Device_Status, rtrim (count (a.reporter)) Total, c.first_na
me | » '|| c.last_name |' ('| c.Guid |') ' Staff
of scanner_assignment a, scanner_inventory b, pwc_employee c
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and a.serial_num = b.serial_num
and a.modify_by = c.guid
and trunc (a.return_dt) = trunc(sysdate-1)
and a.modify_by = '& 1' '.
and b.device_status = '0'
and b.device_status in ('0 ','8 ')
Group of c.first_name |' '|| c.last_name |' ('| c.Guid |') ", b.device_status
order of c.first_name |' '|| c.last_name |' ('| c.Guid |') ', b.device_status;
spool off;
output
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Extend your style orders of sheet with the direction of alignment, for example
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SQL> set markup html on entmap off head "" spool on
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WHERE clause order ox performance question
I do not understand order of execution of a WHERE clause, the use of a complex database
I want to write a SELECT statement with the following condition
... WHERE (branch = 'main') AND (type = 1) OR (AND the costs-1 = 2).
My question is
< 1 > yoyu can use parentheses within a WHERE clause
< 2 > how you would write such a clause as above if you cannot use parenthesis
Thank youHello
Yes, you can have parentheses in a WHERE clause.
I highly recommend to use when you need to use both AND and or in the same WHERE clause, sinceWHERE ( x AND y ) OR z
is not the same as
WHERE x AND ( y OR z )
As others have said:
( charge -1 AND charge = 2 )
will cause a compilation error.
Here's the syntax valid and quite reasonable (although somewhat obscure):WHERE ( branch = 'main' AND type = 1 ) OR ( charge != -1 AND charge != 2 )
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Select simple lines that correspond to a column in the output of function group
Writing a query that will search through a set of data that returns the codes bar of the CompoundNames who have a quantity amount > 500.
Then if it ran against the sample table below the output would be
0005
0006
0007
0008
0009
0010
Code bars, CompoundName, BatchId, quantity
--------------------------------------------------------------
0001, XE 1000, 1000 100 XE, 100
0002, XE 1000, 101 1000 X 100
0003, 102 1000 XE, XE 1000, 100
0004, XE 1000, 1000 103 XE, 100
0005, 2000 XE, XE 2000 100, 100
0006, 2000 XE, XE 100, 2000 101
0007, 2000 XE, XE 2000 102, 100
0008, 2000 XE, XE 2000 103, 100
0009, 2000 XE, XE 2000 104, 100
0010, 2000 XE, XE 2000 105, 100
0011, XE 3000, 3000 100 XE, 100
I had this day
Select CompoundName, Sum (Quantity) OF Table
CompoundName GROUP
HAVING Sum (Quantity) > 500)
compoundname order;
But I need every barcode corresponding to each batchid, while the total amount of lots is > 500.
TIAWelcome to the Forum,
The following approach will work for you.select distinct * from ( Select Barcode, CompoundName, SUM(QUANTITY) over (partition by CompoundName) sumqty FROM Table ) where sumqty > 500 order by compoundname;
TRN
Sudhakar B. -
Update one column of the other
Hi guys,.
I have two columns in a table, FIRSTNAME and LASTNAME. Currently, the firstname and lastname appear in the column "Firstname". I would separate the name of this column and insert in the "LASTNAME" column
For example, here is what I currently have:
Line: -.
First name last name
Peter Andre
James Dean
Men watch
Jenna Klare
James Smith
Tina Adams
Blair Witch
Currently, my "Lastname" column is empty. I want to update the table to insert lastname in the "First NAME" field in the "LASTNAME" column, so the output will look like:
First name last name
Peter Andre
James Dean
Men watch
Jenna Klare
James Smith
Tina Adams
Blair Witch
Help, please.
Thanks in advance.Hello
Maybe this,.
SQL> with t As(Select 'Peter Andre' Name From Dual union all 2 Select 'James Dean' Name From Dual union all 3 Select 'Watch Man' Name From Dual union all 4 Select 'Jenna Klare' Name From Dual union all 5 Select 'James Smith' Name From Dual union all 6 Select 'Tina Adams' Name From Dual union all 7 Select 'Blair Witch' Name From Dual) 8 SELECT regexp_substr(Name,'[^ ,]+' ) First 9 , regexp_substr(Name,'[^ ,]+$') LastName 10 FROM t; FIRST LASTNAME -------------------------------------------- -------------------------------------------- Peter Andre James Dean Watch Man Jenna Klare James Smith Tina Adams Blair Witch 7 rows selected
or
SQL> with t As(Select 'Peter Andre' Name From Dual union all 2 Select 'James Dean' Name From Dual union all 3 Select 'Watch Man' Name From Dual union all 4 Select 'Jenna Klare' Name From Dual union all 5 Select 'James Smith' Name From Dual union all 6 Select 'Tina Adams' Name From Dual union all 7 Select 'Blair Witch' Name From Dual) 8 SELECT Substr(Name,1,Instr(Name,' ',1)-1) First 9 , Substr(Name, Instr(Name,' ',1)+1) LastName 10 FROM t; FIRST LASTNAME -------------------------------------------- -------------------------------------------- Peter Andre James Dean Watch Man Jenna Klare James Smith Tina Adams Blair Witch 7 rows selected
Kind regards
Christian BalzPublished by: Christian Balz on 2009-06-17 15:33
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Version of DB: database Oracle 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
I have a table my_table as below:
create table my_table
(
my_code varchar2 (6).
my_id varchar2 (24).
forced pk_1 primary key (my_code, my_id)
);
Primary_key here's a composite key that contains columns 1 (my_code) and 2 (my_id).
Is there that a difference in the way below queries is executed in terms of performance (use of indexing in the extraction).(a) select * from my_table where my_code = '123' and my_id = "456";
(b) select * from my_table where my_id = '456' and my_code = '123';
The understanding I have the order of the column in the where clause should be identical to the sequence in
What primary key draws for indexing to be used by oracle in oracle other DML queries ignores indexing
However when I used explain plain both show the same query cost with single scan with index rowid.
so I don't know if I'm wrong in the concept that I have. Kindly help.Thanks in advance,
GerardYour question is answered in the Performance Tuning Guide
14.1.4 choosing composite indexes
A composite index contains several key columns. Composite indexes can provide additional benefits compared to the index to single column:
- Improved selectivity
Sometimes the two or more columns or expressions, each with a low selectivity can be combined to form a composite with a high selectivity.
- Reduced IO
If all columns selected by a query are a composite index, then Oracle may return these values in the index without access to the table.
A SQL statement can use a path on a composite index if the statement contains constructions that use a main part of the index.
Note:
This is no longer the case with the skip index scans. See "Index Skip Scans".
A main part of an index is a set of one or more columns that have been specified first and consecutively in the list of columns in the
CREATE
INDEX
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Hello
Oracle version: 11.1.0.7.0 - 64 bit
I read the documentation online at joins. The page is avialable here: joins at
My question is about the join order of evaluation of the conditions in clause and the conditions of those
are not the join conditions and are placed in the WHERE clause.
Consider the following pseudocode
SELECT
T1. Col1,
T2.Col1
Of
Table1 t1 LEFT OUTER JOIN table2 t2
WE
(condition_expression1)
WHERE
(condition_expression2)
Is it correct to say that if there is no column on the status of join (condition_expression1) in condition_expression2, then condition_expression2 is executed before condition_expression1? In other words, oracle always trying to filter based on the WHERE clause individually each table as much as possible before joining them based on the conditions on the article?
Thanks in advance,
Hello
dariyoosh wrote:
Hello
Oracle version: 11.1.0.7.0 - 64 bit
I read the documentation online at joins. The page is avialable here: joins at
My question is about the join order of evaluation of the conditions in clause and the conditions of those
are not the join conditions and are placed in the WHERE clause.
Consider the following pseudocode
SELECT
T1. Col1,
T2.Col1
Of
Table1 t1 LEFT OUTER JOIN table2 t2
WE
(condition_expression1)
WHERE
(condition_expression2)
Is it correct to say that if there is no column on the status of join (condition_expression1) in condition_expression2, then condition_expression2 is executed before condition_expression1? In other words, oracle always trying to filter based on the WHERE clause individually each table as much as possible before joining them based on the conditions on the article? ...
The reverse is actually closer to the truth, but we can't really make general statements like that.
SQL is not a language of the proceedings. Looking at the code SQL, we could say that the code does, but we cannot say much about how that code it. In other words, SQL is a language that describes the results you get, not the way to get them.
The optimizer will do everything what he thinks is faster if it does not change the results. If any order in which they are applied (in outer joins or CONNECT BY queries, for example), then think of the join is done first, and the value of the WHERE clause is applied to the result of the join.
Here is a query looks very much like you posted:
SELECT d.deptno
e.ename, e.sal
OF scott.dept d
LEFT OUTER JOIN scott.emp e ON e.deptno = d.deptno
WHERE e.sal > = 3000
ORDER BY d.deptno
;
Output:
DEPTNO ENAME SAL
---------- ---------- ----------
10 KING 5000
20 FORD 3000
20 3000 SCOTT
The scott.dept table contains deptnos 30 and 40; Why are they not in the result set? The query behaves as if the outer join is made first (production 15 rows), then the WHERE clause has been applied. All lines with deptno = 30 had sals down han 3000 and all single line with deptno = 40 was NULL in the sal column, then these lines are excluded (as well as other lines of deptnos 10 and 20), and only 3 lines above are left.
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"Invalid column" on the place where several clauses with subqueries and cfqueryparam
I see a behavior in the cfquery coldfusion I would like to find an exmplanation for. I have a query that performs a subquery in the select part and if I have several where lines, I get a message 'invalid column name' to find out where my second article, but only when I'm with cfqueryparam
For example, on what follows, I get "invalid column name «position_id»»
SELECT department_staff_tbl.*,
(SELECT max (bookmark_id)
OF bookmarked_items_tbl
WHERE item_id = department_staff_tbl.staff_id) AS bookmark_id
OF department_staff_tbl
WHERE department_id = < cfqueryparam value = "" #arguments.deptid # "cfsqltype ="cf_sql_integer">"
AND position_id = < cfqueryparam value = "" #arguments.posid # "cfsqltype ="cf_sql_integer">"
AND staff_id = < cfqueryparam value = "" #arguments.staffid # "cfsqltype ="cf_sql_integer">"If I change the order of my where clause staff_id is first, and then he said "department_id" is an invalid column.
If I don't have a where clause, it works. (i.e. WHERE position_id = < cfqueryparam value = "" #arguments.posid # "cfsqltype =" cf_sql_integer">).
If I remove the where clause of my subquery (WHERE item_id = department_staff_tbl.staff_id) it works.
This also works if I remove the cfqueryparam where my article so that my query looks like this:
SELECT department_staff_tbl.*,
(SELECT max (bookmark_id)
OF bookmarked_items_tbl
WHERE item_id = department_staff_tbl.staff_id) AS bookmark_id
OF department_staff_tbl
WHERE department_id = #arguments.deptid #.
AND position_id = #arguments.posid #.
AND staff_id = #arguments.staffid #.Any thoughts?
A more conventional way to enter your data is without the subquery. Something like that
Select fields, the bookmarkid max (bookmark_id)
from bookmarked_items__tbl join department_staff_tbl on staff_id = bookmark_id
When etc.
Some field group
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Where is the installer for the Source column of the command in other tab of orders?
Hello!
I would like to ask where to find the installer for the Source column of the command in other tab of orders. I saw internal and online, I think it's always external.
Thank you.
Jon
Order header Source is the origin of the order-using the OM Super user responsibility, see Setup-> controls-> import Sources. I think that external is a Source Type on the command line that indicates if the line item will be provided by your org or bought.
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DB version: 10 gr 2
When you use the ORDER BY clause, the lines are always sorted by the first column in the ORDER BY clause. So, what's the point of having several columns in the ORDER BY clause (I always see this in production codes)?
For the below SQLs' schema SCOTT, result sets are always classified according to the first column ename. When I added use asc and desc of employment, does not change the result set.
SQL> select * from emp order by ename; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO ---------- ---------- --------- ---------- --------- ---------- ---------- ---------- 7876 ADAMS CLERK 7788 23-MAY-87 1100 20 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30 7698 BLAKE MANAGER 7839 01-MAY-81 2850 30 7782 CLARK MANAGER 7839 09-JUN-81 2450 20 7902 FORD ANALYST 7566 03-DEC-81 3000 20 7900 JAMES CLERK 7698 03-DEC-81 950 30 7566 JONES MANAGER 7839 02-APR-81 2975 20 7839 KING PRESIDENT 17-NOV-81 5000 20 7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30 7934 MILLER CLERK 7782 23-JAN-82 1300 20 7788 SCOTT ANALYST 7566 19-APR-87 3000 20 7369 SMITH CLERK 7902 17-DEC-80 800 20 7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30 7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30 14 rows selected. SQL> select * from emp order by ename, job; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO ---------- ---------- --------- ---------- --------- ---------- ---------- ---------- 7876 ADAMS CLERK 7788 23-MAY-87 1100 20 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30 7698 BLAKE MANAGER 7839 01-MAY-81 2850 30 7782 CLARK MANAGER 7839 09-JUN-81 2450 20 7902 FORD ANALYST 7566 03-DEC-81 3000 20 7900 JAMES CLERK 7698 03-DEC-81 950 30 7566 JONES MANAGER 7839 02-APR-81 2975 20 7839 KING PRESIDENT 17-NOV-81 5000 20 7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30 7934 MILLER CLERK 7782 23-JAN-82 1300 20 7788 SCOTT ANALYST 7566 19-APR-87 3000 20 7369 SMITH CLERK 7902 17-DEC-80 800 20 7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30 7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30 14 rows selected. SQL> select * from emp order by ename, job desc; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO ---------- ---------- --------- ---------- --------- ---------- ---------- ---------- 7876 ADAMS CLERK 7788 23-MAY-87 1100 20 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30 7698 BLAKE MANAGER 7839 01-MAY-81 2850 30 7782 CLARK MANAGER 7839 09-JUN-81 2450 20 7902 FORD ANALYST 7566 03-DEC-81 3000 20 7900 JAMES CLERK 7698 03-DEC-81 950 30 7566 JONES MANAGER 7839 02-APR-81 2975 20 7839 KING PRESIDENT 17-NOV-81 5000 20 7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30 7934 MILLER CLERK 7782 23-JAN-82 1300 20 7788 SCOTT ANALYST 7566 19-APR-87 3000 20 7369 SMITH CLERK 7902 17-DEC-80 800 20 7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30 7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30 14 rows selected.
Search in this example, you will see the difference
SQL> create table test_order (name varchar2(10), surname varchar2(10), age number); Table created. SQL> insert into test_order values('Kamran','Agayev',26); 1 row created. SQL> insert into test_order values('Kamran','Taghiyev',26); 1 row created. SQL> insert into test_order values('John','Kevin',23); 1 row created. SQL> select * from test_order; NAME SURNAME AGE ---------- ---------- ---------- Kamran Agayev 26 Kamran Taghiyev 26 John Kevin 23 SQL> select * from test_order 2 order by age; NAME SURNAME AGE ---------- ---------- ---------- John Kevin 23 Kamran Agayev 26 Kamran Taghiyev 26 SQL> select * from test_order 2 order by age asc, surname desc; NAME SURNAME AGE ---------- ---------- ---------- John Kevin 23 Kamran Taghiyev 26 Kamran Agayev 26 SQL>
When in the second query, I sorted out only for age, you saw it there two 26 years old Keita, there was first Agayev, then Taghiyev. But if I want to get the family names in descending order when there are two very old person, then I will add the second column in the order by clause
- - - - - - - - - - - - - - - - - - - - -
Kamran Agayev a. (10g OCP)
http://kamranagayev.WordPress.com
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