Conversion of XML output SQL output

Hello

How to convert the result of the SQL query in XML format? Pl help.

Thank you
Mano

You use DBMS_XMLGEN, you can generate the output XML form.

SQL> SELECT * FROM CUSTOMER;

C  D1         D2
-- ---------- ----------
c1 01/04/2009 01/04/2009
c2 01/04/2009 02/04/2009
c3 01/04/2009 02/04/2009
c4 01/04/2009 02/04/2009

SQL> select dbms_xmlgen.getxml('select c,d1,d2 from customer') xml FROM DUAL;

XML
--------------------------------------------------------------------------------


 
  c1
  01/04/2009
  01

SQL> 

Other means, also refer
http://www.stylusstudio.com/sqlxml_tutorial.html

Tags: Database

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  • XML and SQL output

    Hi all

    Please find test data and results as XML and SQL output.

    Version : Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

    create table emp_xml (empno number, emp_name varchar2 (100), by e-mail to varchar2 (100));

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    insert into emp_xml values (101, 'ROBERT',' [email protected]');

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    CREATE table emp_dept_xml (empno number, dept_list varchar2 (4000));

    insert into emp_dept_xml values (' 100,'10, 20, 30, ");

    insert into emp_dept_xml values (' 101,'40, 20, 10, 30, 50, ");

    insert into emp_dept_xml values (102, ' 10'),

    Expected in SQL output

    -----------------------

    EMPNO EMP_NAME EMAIL DEPTNO

    DAVID 100 [email protected] 10

    DAVID 100 [email protected] 20

    DAVID 100 [email protected] 30

    ROBERT 101 [email protected] 10

    ROBERT 101 [email protected] 20

    ROBERT 101 [email protected] 30

    ROBERT 101 [email protected] 40

    ROBERT 101 [email protected] 50

    DANIEL 102 [email protected] 10

    Results in XML

    -----------------------

    < USERS_DETAILS >

    < USER >

    < EMPNO > 100 < / EMPNO >

    DAVID < NAME > < / NAME >

    < EMAIL > [email protected] < / EMAIL >

    < ASSIGNED_DEPT >

    < DEPT > 10 < / DEPT >

    < DEPT > 20 < / DEPT >

    < DEPT > 30 < / DEPT >

    < / ASSIGNED_DEPT >

    < / USER >

    < USER >

    101/EMPNO < EMPNO > >

    ROBERT < NAME > < / NAME >

    < EMAIL > [email protected] < / EMAIL >

    < ASSIGNED_DEPT >

    < DEPT > 10 < / DEPT >

    < DEPT > 20 < / DEPT >

    < DEPT > 30 < / DEPT >

    < DEPT > 40 < / DEPT >

    < DEPT > 50 < / DEPT >

    < / ASSIGNED_DEPT >

    < / USER >

    < USER >

    < > 102 EMPNO < / EMPNO >

    DANIEL < NAME > < / NAME >

    < EMAIL > [email protected] < / EMAIL >

    < ASSIGNED_DEPT >

    < DEPT > 10 < / DEPT >

    < / ASSIGNED_DEPT >

    < / USER >

    < / USERS_DETAILS >

    Thank you

    Rambeau

    SQL>   select e.empno
      2         , e.emp_name
      3         , e.email
      4         , regexp_substr(d.dept_list, '[^,]+', 1, level) deptno
      5      from emp_xml e
      6      join emp_dept_xml d
      7        on e.empno = d.empno
      8   connect
      9        by level <= length(d.dept_list) - length(replace(dept_list, ','))
     10       and prior e.empno = e.empno
     11       and prior dbms_random.value() is not null;
    
         EMPNO EMP_NAME             EMAIL                DEPTNO
    ---------- -------------------- -------------------- --------------------
           100 DAVID                [email protected]      10
           100 DAVID                [email protected]      20
           100 DAVID                [email protected]      30
           101 ROBERT               [email protected]     40
           101 ROBERT               [email protected]     20
           101 ROBERT               [email protected]     10
           101 ROBERT               [email protected]     30
           101 ROBERT               [email protected]     50
           102 DANIEL               [email protected]     10
    
    9 rows selected.
    
    SQL> select xmlelement
      2         (
      3              "USERS_DETAILS"
      4            , xmlagg(xmlelement
      5              (
      6                  "USER"
      7                , xmlelement("EMPNO", empno)
      8                , xmlelement("NAME", emp_name)
      9                , xmlelement("ASSIGNED_DEPT", xmlagg(xmlelement("DEPT", deptno)))
     10              ))
     11         ).extract('*') xml_output
     12    from (
     13            select e.empno
     14                 , e.emp_name
     15                 , e.email
     16                 , regexp_substr(d.dept_list, '[^,]+', 1, level) deptno
     17              from emp_xml e
     18              join emp_dept_xml d
     19                on e.empno = d.empno
     20           connect
     21                by level <= length(d.dept_list) - length(replace(dept_list, ','))
     22               and prior e.empno = e.empno
     23               and prior dbms_random.value() is not null
     24         )
     25   group
     26      by empno
     27       , emp_name;
    
    XML_OUTPUT
    --------------------------------------------------------------------------------
    
      
        100
        DAVID
        
          10
          20
          30
        
      
      
        101
        ROBERT
        
          40
          50
          30
          20
          10
        
      
      
        102
        DANIEL
        
          10
        
      
    
    
    SQL>
    
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