Date (RR, RRRR, YYYY)
Hello
If I don't TO_DATE('01-01-98','DD-MM-YYYY') why it becomes 1st January 98
Why this 00 before 98?
What you trying to do? The second parameter of the TO_DATE should be the format of the first parameter. Always use 4-digit.
http://docs.Oracle.com/CD/B19306_01/server.102/b14200/functions183.htm
See also the thread below and the blog for some of the detailed explanations.
https://edstevensdba.WordPress.com/2011/04/07/NLS_DATE_FORMAT/
See you soon
AJ
Tags: Database
Similar Questions
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Step 1. I choose Chinese (PRC) in the list format (region and language) and set the format of 'YYYY-MM-dd' date, apply. It is ok.
Step 2. I choose English (United States) in the list format (region and language) and set the format of 'YYYY-MM-dd' date, apply. It is ok.
Step 3. I chose the back to Chinese (PRC) in the format list (region and language), format date is reset to "YYYY/M/d", it is not ok for me.
How can I set the format of a two language. ?
Because I use the siemens industry software, when to change language it will read the date format different from the language that is displayed. My client want to see the same format.
I tested under Win XP, it may set the format even in different languages
Hi Jerry,
Thanks for posting the request in Microsoft Community Forums.
It is normal that you can not set the same date format for both languages at the same time. You will need to use the drop-down list to choose a date format customized if necessary.
Hope this information helps.
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How to convert date in month, YYYY
Hi all
I have a date column that is in the format ex: (12/06/2013) the user wants it to appear like June 2013. Can you help me how I can achieve this?
Thank you
Ravi
GO to the column-> properties-> data format select custom data format
write the format MMMM, YYYY
Kind regards
Rémy Agarwal
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Analysis of Date with Mr. YYYY and in between
Hello
[Oracle 11g]
I got a table with a Date in it. Lets called him Testdate and something called startmonth and endmonth.
Looks like the element (varchar2)
MM YYYY 03.2012 te and is a
I want to see all the data between the departure and endmonth.
First, I tried to convert my orignial table date:
It works:SELECT distinct TO_CHAR(TESTDATE, 'MM'||'.'||'YYYY') FROM mv_auswertung;
But now, I'm trying to get all the data between the start and enddate:TO_CHAR(TESTDATE,'MM'||'.'||'YYYY') 02.2012 12.2012 01.2012
Select * from mv_auswertung where TO_CHAR(TESTDATE, 'MM'||'.'||'YYYY') between to_CHAR(:P7_startmonth) and to_char(:P7_endmonth)
Hello
Thorsten wrote:
Hello[Oracle 11g]
I got a table with a Date in it. Lets called him Testdate and something called startmonth and endmonth.
Looks like the element (varchar2)
MM YYYY 03.2012 te and is a
Soething is not found in the end of the line above.
I want to see all the data between the departure and endmonth.
First, I tried to convert my orignial table date:
SELECT distinct TO_CHAR(TESTDATE, 'MM'||'.'||'YYYY') FROM mv_auswertung;
It works:
TO_CHAR(TESTDATE,'MM'||'.'||'YYYY') 02.2012 12.2012 01.2012
But now, I'm trying to get all the data between the start and enddate:
Select * from mv_auswertung where TO_CHAR(TESTDATE, 'MM'||'.'||'YYYY') between to_CHAR(:P7_startmonth) and to_char(:P7_endmonth)
The string "04.1999' comes between the chains ' 01.2013' and ' 06.2013', because «04' comes from '01' year ' 06';»»» the rest of the channels are not relevant for this comparison.
But what is TESTDATE? The first argument of TO_CHAR is supposed to be a DATE. If TESTDATE is a DATE, then you can say:
testdate BETWEEN TO_DATE (:p7_startmonth, 'MM.YYYY') AND TO_DATE (:p7_endmonth, 'MM.YYYY')
Remember that the day of default of ringworm s 01, nd default schedules, minutes, and seconds are 00, so
TO_DATE ('04.2013', 'Mm.YYYY')
is midnight, April 1, 2013, i.e. the beginning of the month, you may need to l as a
WHERE testdate >= TO_DATE (:p7_startmonth, 'MM.YYYY') AND testdate < ADD_MONTHS ( TO_DATE (:p7_endmonth, 'MM.YYYY') , 1 )
According to your values and your needs.
I hope that answers your question.
If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
If you need parameters (like: p7_startmonth) in the problem, and then after a few sets of parameters, and the results you want for you same SAMPLES for each game.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}Published by: Frank Kulash on April 17, 2013 07:00
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I'm a long-time user elements (most of the versions since the first came out) and I got 10s of thousands of photos, for the most part stored by downloading my different cameras by elements.
Now I have "improved" to 10 items and discover that he will not continue with the sequence of names of files that have been generated by previous versions.
I've always downloaded my photos in subfolders generated by elements whose name yyyy mm dd format. It's the great comfort that these records sort in chronological order. I have them go back to 2002 01 24.
Now, I have 10 items, and when I downloaded some new photos it by default for subfolders names that do not store in the sequence-(mm dd yyyy). So I went to options / card reader or the camera to correct this stupid fault. I looked in the drop-down list and there are many of which seem stupid choices, (why would anyone want a folder name which does not store in date order?), but not the one I want.
It is a serious problem. Suppose I have disappear for two days and take pictures sur.30 Nov 2011 and December 1, 2011 (friends OK U.S., November 30, 2011 and December 1, 2011). 10 elements will store the first batch as one of the last records in 2022 (as well as the shots made on January 31, 2011, March 31, 2011, etc.). My second day shooting will be stored near the beginning of the year, as well as snapshots taken the day of the other months.
It's crazy! -a bug that is absurd. But it does not seem so far have been fixed.
Can someone tell me a way round? Or that there is a fix for this bug that I have not found? Or that it's not on someone else's machine (in this case, why he did not on my machine with Elements 9?)
It's going to be extremely painful to have to hand - edit all future folder names so that they sort in sequence (and are compatible with my hundreds of existing records). I can't believe that Adobe would have done this deliberately, so I'm stumped. Help!
Bought my copy of 10 items on Amazon UK - should be a matter of UK standard. My PC running Windows 7.
Hello
In the case where you are not aware about it, a fix is now available from Adobe.
The team of items posted fixes for these issues:
Mac: http://kb2.adobe.com/cps/930/cpsid_93...
Win: http://kb2.adobe.com/cps/930/cpsid_93...
Brian
(Edited to put in hard links)
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problem with the type of date dd/mm/yyyy
Hi all!
I want to do something simple.
to get a type of dd/mm/yyyy string and convert it ti date jj/mm/aaaa type.
I wrote simple code
String pattern = "dd/MM/yyyy";
SimpleDateFormat format = new SimpleDateFormat (pattern);
try {}
Date = format.parse("12/03/2006");
System.out.println (date);
} catch (ParseException exception) e {}
e.printStackTrace ();
}
but the problem that I get Sun Mar 12 00:00:00 GMT + 02:00 2006
and I want to get this format dd/mm/yyyy.
because I need to insert it in my db. Thank you allFirst thing: almost always if a SQL statement uses variable data, use a PreparedStatement. With the help of a simple statement can, at first, most obvious glance, but it will cause endless problems.
The constant strings in SQL are "single quotes" i.e. apostrophes. They must at least cannot escape string constants. One of the reasons for always using class PreparedStatement is that you concatenate in a string value may contain an apostrophe. In this case it will be, at best, give your SQL syntax error. Worse it can make your system vulnerable to hackers.
Use code publishing code tags. Put the word 'code' braces before and after. This makes your code readable.
The field attribute by DEFAULT when you create a table must be a real date, not a model. I have never know this is useful for a date, except if it set to pick up the current date.
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Insert the data; DD/MM/YYYY
Hello
Please can someone tell me a method that works in that I can enter the date in my table.
CREATE TABLE BookCopy)
BcId VARCHAR2 (5) NOT NULL,
BtId VARCHAR2 (5).
DateAcquired DATE,
DateDestroyed DATE,
(BcId) PRIMARY KEY,
FOREIGN KEY (BtId) REFERENCES BookTitle (BtId));
I tried several ways but can't output the date in the format DD/MM/YYYY simple. Thanks for any help.PUMA,
Something like that
INSERT INTO bookcopy ( bcid, btid, dateacquired, datedestroyed ) VALUES ( 'ABCD', 'EFGH', TO_DATE (TO_CHAR (SYSDATE - 10, 'MM/DD/YYYY'), 'MM/DD/YYYY'), TO_DATE (TO_CHAR (SYSDATE, 'MM/DD/YYYY'), 'MM/DD/YYYY') );
concerning
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How to add a date dd-mm-yyyy field type in a form of planning data
Hi John,.
PLS, I have a question about the possibility of adding a date field type for example 03/03/2009 in a cell of planning data request form.
for example, I created:
-2 members in period dimension: StartProject and EndProject and I need enter and follow the date for these fields;
-a member of account called project;
- and a simple form with these columns and rows;
Try different settings for members of my - seems I can't date entry in the cell and rcvd errror: "you have entered an invalid value.
Can PLS, you confirm whether it is possible to enter the date type in a form?
If Yes, what is the specific configuration for account properties and the period: data storage, time balance, data type, etc. account type
Thank you very much
RobertHello
Go to administration > dimensions > evaluation order > period go to the right window.
See you soon
John
http://John-Goodwin.blogspot.com/ -
Date of issue - conversion to date and the date of conversion in months
I have some data in a text file for SQLLDR from a SQL SERVER.
In date columns are YYYY-MM-DD format eg-2011-01-03 00:00:00
but in oracle, we use DD-MM-RRRR.
Don't know why the SD and MM are get interchanged. Help, please.
It's my for sqlldr control file:
LOAD DATA INFILE 'F:\NV\Permits\SQLLDR\permits.txt' REPLACE INTO TABLE lot.p_permit FIELDS Terminated by "~" TRAILING NULLCOLS ( CP_PermitID "TRIM (:CP_PermitID)", CP_SubmitDate "to_date(to_date(substr(:CP_SubmitDate, 1,19),'RRRR-MM-DD HH24:MI:SS'),'DD-MM-RRRR')", CP_IssueDate "to_date(to_date(substr(:CP_IssueDate, 1,19),'RRRR-MM-DD HH24:MI:SS'),'DD-MM-RRRR')")
You convert date to date. First TO_DATE
TO_DATE (substr (: CP_IssueDate, 1.19), "DD-MM-RRRR HH24:MI:SS")
Converts correctly 19 characters of the CP_IssueDate string to date. Now, look at what is happening with the other. To_date first argument is string. Since to_date (substr (: CP_IssueDate, 1.19), "DD-MM-RRRR HH24:MI:SS") are dates:
TO_DATE (to_date (substr (: CP_SubmitDate, 1.19), 'DD-MM-RRRR HH24:MI:SS'), "DD-MM-RRRR")
implicitly converts the to_date (substr (: CP_IssueDate, 1.19), "DD-MM-RRRR HH24:MI:SS") to a string using default date format, then converts it back to the date using the format "DD-MM-RRRR. Of course if the default date format is not "DD-MM-RRRR" you can either get an incorrect date or a mistake. In any case, use:
LOAD DATA INFILE 'F:\NV\Permits\SQLLDR\permits.txt' REPLACE INTO TABLE lot.p_permit FIELDS Terminated by "~" TRAILING NULLCOLS ( CP_PermitID "TRIM (:CP_PermitID)", CP_SubmitDate "to_date(substr(:CP_SubmitDate,1,10),'YYYY-MM-DD')", CP_IssueDate "to_date(substr(:CP_IssueDate,1,10),'YYYY-MM-DD')" )
SY.
Published by: Solomon Yakobson August 1, 2011 16:45
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Hello world
I have problem in the insertion of date format in a table where the Arab data as "data" | Arab TO_DATE(:date_field.date,'DD/mm/yyyy');
It's show 10-Mar-03 (year-month-day) instead of DD/MM/YYYY.
I would appreciate your help.
Thank you
Ahon[email protected] wrote:
Hello worldI have problem in the insertion of date format in a table where the Arab data as "data" | Arab TO_DATE(:date_field.date,'DD/mm/yyyy');
It's show 10-Mar-03 (year-month-day) instead of DD/MM/YYYY.
I would appreciate your help.
Thank you
AhonChange to this
'Arabic Data'||to_char(:date_field.date,'DD/MM/RRRR');
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Value of the argument of the Add method must be a date or UsiTimeDisp.
I am writing a code to allow users to define what to look for in the navigatro and then use the results for further analysis. But when I try to search by date of creation I get an error that says: "add the argument to the value of the method must be either a date or a USiTimeDisp. I have tried different methods to enter the dates (dd/mm/yyyy, mm.dd.yyyy etc) but none have worked.
What is this error and how can I fix?
The add method does not accept a string but only CDate or UsiTimeDisp.
Creation usiTimeDisp
protected cdateVal: cdateVal = now
protected timedispVal: set timedispVal = createTime (year (cdateVal), month (cdateVal), day (cdateVal), (cdateVal) hour, minute (cdateVal), second (cdateVal))
In this case, I started with a CDate I created using now.
How to get a CDate from a string. Here, we encounter the problem of the locale.
English: 22.08.1970 10:22:30
German: 22/08/1970 10:22:30
which is also reflected by converting a CDate chain.
Option Explicit
protected cdateVal: cdateVal = now
Dim strVal: strVal = CStr (cdateVal)
StrVal MsgBox
protected cDateVal2: cDateVal2 = CDate (strVal)
msgBox cDateVal2This code will work. It is capable of converting a CDate a CStr and then back into a CDate. This works if the string is formatted as expected by your locale.
CDate ("22.08.1970 10:22:30")
will work in Germany but fails in the United States.
protected diademtimeVal: TTR = diademtimeVal ("22.08.1970 22:30","dd.mm.yyyy HH" ")
protected timedispVal: set timedispVal = createTime (0, 0, 0, 0, 0, 0)
timedispVal.SecondsFrom0000 = diademtimeValyou create a usitimedisp object using a fixed format string. This should resolve your request.
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How to import Date into the text data file TDR box?
I have a report template that I use frequently for data tracing files. At the top of the TOR, I have a main title text box that says "Daily Operation" usually followed by the date (entered manually) of this file.
Q: How do I import/reference the value of the date of the file (photo #1 - black outline) in the text box (photo #2) I use to Date? I appreciate all help.
Hi man of laboratory.
Looks like you will need to use the RTT (-real time), which transforms the tiara time real number (fractions of a second from 0 AD) in a date/time string. There is also a TTR function that goes the other way.
@@RTT (ChD (1, "[1] / Date"), "" mm/dd/yyyy # hh:nn:ss.fff "') @.
Brad Turpin
Tiara Product Support Engineer
National Instruments
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How to get the numeric date on reviews, no positions.
Hello
Can someone tell me how can I get a digital date on my blog comments? date is currently like 'may 25, 2015', and I wish it were "25/05/2015".» I went into the code and saw that the use of this tag "{tag_usagedate}", I managed to fix this for the blog because there is this tag: "{tag_blogpostmonthnumeric}", how can I do the same thing for comments date? " I need to do this because my site is in Portuguese, and it's the only way I found the date of the translation. Unless someone can teach me what are these tags and how can it change directly in their table of months for something like {'February', 'Marco', 'Janeiro', 'April',..., 'December'}. Any help is appreciated.
Thank you
Alex.
To do this I use liquid, make sure it is enable on your site, something as it does the job, maybe someone should check the syntax.
{{date | date: ' %d-%m - yyyy "}} for all numeric values, but {{date | date:"%d - MMM-yyyy"}} should return the date with the month names in your culture.
Look here the Developer Reference for all filters.
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Hi all
I have question,
"If I get the data of an input parameter 10 December 2013 08:41:53.
How can I convert the format of date,-> "DD-MM-YYYY".
Thanks for the help of You ' r
Hello
If you have a string str = 10 December 2013 08:41:53 ', you can call TO_DATE to create a DATE from it:
To_date (str, "MM/DD/YYYY HH24:MI:SS")
(Assuming that "12" is the month and '10' is the day).
Once you have a DATE (let's call it dt), you can view it in any format you want using TO_CHAR:
To_char (dt, "DD-MM-YYYY")
If you wish, you can nest one of these functions inside each other, like this:
SELECT TO_CHAR (TO_DATE (' DECEMBER 10, 2013 08:41:53 '))
, "MM/DD/YYYY HH24:MI:SS.
)
'DD-MM-YYYY ".
), Exit
DOUBLE;
Output:
OUTPUT
----------
10/12/2013
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A date today can be added in a date field when you press the submit button?
I created a form with a "submit" button and the form is sent by e-mail. Then the date when the form is submitted to appear in a date with the key field is pressed?
Any help with this is appreciated. Thank you.Hello
There is a preSubmit event to form objects that you can use.
Select your date field, open the script editor and add this script (language is FormCalc) in the preSubmit event.
$ num2date = (date (), ' MM/DD/YYYY')
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