Ddeleting the second tag line in the XML output

Hi all

When I run the following query:

Select dbms_xmlgen.getxml ("select wo.work_order_no,
cursor (select regacc.work_order_no, regacc.work_order_task_no, regacc.regulatory_account_no
of sa_work_orde_reg regacc
where regacc.work_order_no = wo.work_order_no) Reg_Test
of sa_work_order wo') xml
Double;

I get the following result:

<? XML version = "1.0"? >
rowset <>
< ROW >
< WORK_ORDER_NO > 1000170 < / WORK_ORDER_NO >
< REG_TEST >
< REG_TEST_ROW >
< WORK_ORDER_NO > 1000170 < / WORK_ORDER_NO >
< WORK_ORDER_TASK_NO > 01 < / WORK_ORDER_TASK_NO >
< REGULATORY_ACCOUNT_NO > 100.2.1 < / REGULATORY_ACCOUNT_NO >
< / REG_TEST_ROW >
< / REG_TEST >
< / ROW >
< / LINES >

Now what I need, is remove the second line tag < REG_TEST_ROW >. Y at - it a function or other ways to handle this. I'll use this query in the API of DBMS_XMLGEN.newcontext inside my procedure.

Thank you for your help in advance.

Published by: user33333 on June 29, 2010 01:11

Published by: user33333 on June 29, 2010 01:19

Hello

Here are a few options...

(1) using a scalar subquery rather than the CURSOR constructor (as long as it's supposed to always return a single line):

SELECT dbms_xmlgen.getxml(
'SELECT wo.work_order_no,
        ( SELECT XMLForest( regacc.work_order_no,
                            regacc.work_order_task_no,
                            regacc.regulatory_account_no )
          FROM sa_work_orde_reg regacc
          WHERE regacc.work_order_no = wo.work_order_no ) reg_test
FROM sa_work_order wo'
) xml
FROM dual;

(2) incorporating a XSL transformation (Yes, still!) to copy all nodes except REG_TEST_ROW:




 
  
 





(3) with the help of a simple replacement out serialized.

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