Determine whether the instance of the object is of a specific object class.

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  Hello

  I'm developing an application that will provide a background thread that calls a UIApplication.

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  Bell

  Why do you not use DURATION for this store. Take a look at this article from BB that does something similar.

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  Hi K jtm,.

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  Hi Paul,.

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  itemRender.mxml

  http://www.Adobe.com/2006/mxml '.

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  //...........

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  ...

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• Whether the object is a table, view, or synonym

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• Test whether the object is Assigned() which means... not null

  In Delphi using the Windows SDK, I can use the Assigned() function to determine if an object has been instantiated... IOW, not null.  How this is done in ActionScript?  I've been going around in circles in the documentation.  I can find every keyword and the operator, but I can't find how to test a null object variable.

  If (MyDataGrid.selectedItem is not null) {.. my... code...}

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• Determine whether the application has permission to camera?

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• Statement of the object as the type

  Hello
  
  I just discovered a very basic thing on the statements of the subject and references after half a year of learning:
  It does not compile:
  

  Object o = new Dog(); 
  o.grrrr(); 

  Could someone point me to an article where it is explained in detail?
  
  I'm in the dark here, but I try a few questions:
  -What can and cannot be done with a typed object reference as an ancestor of the class of the object, it refers?
  -What are the advantages and disadvantages of do?
  -J' tried with an interface as type and I can't use the fields for the object being referenced there either, so this will only make good reference to all the?
  
  -I don't see why we can declare an object such as an interface type or ancestor if ultimately we cannot use this reference to reach the fields of the object.
  It is only in that way we can iterate over objects whose type can vary? But even in this case, we cannot use the fields throughout the iteration.
  
  Thank you very much in advance for any commments on this.

  lemonboston wrote:
  Hello

  I just discovered a very basic thing on the statements of the subject and references after half a year of learning:
  It does not compile:

  Object o = new Dog();
  o.grrrr(); 
  

  Could someone point me to an article where it is explained in detail?

  Varialbe o type is reference-object. Which is determined by the object o, at compile time. That's all the compiler cares when decide how o may be used.

  I'm in the dark here, but I try a few questions:
  -What can and cannot be done with a typed object reference as an ancestor of the class of the object, it refers?

  You can use a reference in a way that is consistent with its type of compilation. Note that you can get o the dog and then use the reference obtained as a reference-to-dog expression, but you generally won't go up if you don't have to.

  -What are the advantages and disadvantages of do?
  -J' tried with an interface as type and I can't use the fields for the object being referenced there either, so this will only make good reference to all the?

  Glasses for the coding of the interface. The general idea is, roughly speaking, 'all I care is that I have the list. I don't like which particular implementation of list is (ArrayList, LinkedList, etc.), so he does these things that promises to the interface of the to do list. The details of how it does are not important to me. "This gives you the flexibility and, for example, allows the provider from the list on the RIGHT side of the = to give you different implementations according to what is appropriate at this time here during execution.

  -I don't see why we can declare an object such as an interface type or ancestor if ultimately we cannot use this reference to reach the fields of the object.

  Each object of dog IS - YEAR and each ArrayList IS - A list and IS - AN object and Collection of IS - A, etc. Google for oriented object is a relationship and the liskov substitution principle

  This is really more general stuff OO Java stuff, even if of course Java, like other OO languages, has its own details as to how it supports these concepts.

• Call the method of the object, the view object entity

  Hi all
  I use jdeveloper 11.2.1.0, and I need to call the method in the object class to view object entity class.
  Someone knows how to do?
  
  Thank you.

  http://andrejusb.blogspot.in/2009/11/calling-custom-entity-method-from-view.html

• Superclass of the object

  Hello
  
  All java classes are a subclass of the object. Consider this scenario,

  class A {
  }
  class B extends A {
  }

  Now what of class B? Is also a subclass of the object?
  
  Thank you
  RAM

  RAM wrote:

  Kayaman wrote:

  RAM wrote:
  I mean

  Object     A
  \    /
  B
  

  Isn't multiple inheritance?

  No matter what it is, it is something that cannot be done in Java.

  Can you tell the difference between the two great classes?

  The difference is: this particular case can be done in Java.

  So, in this case, can we say class B is not a subclass of the Object class?

  It seems that you were not attentive at all.

  Once again:

  Multiple inheritance (of implementation):
  NOT supported by Java
  -----------------------------------------
  class A {}
  class B {}
  class C extends A, B {}
  
    A   B
     \ /
      C
  
  NOT Multiple inheritance
  Supported by Java
  -----------------------------------------
  class A{}
  class B extends A{}
  class C extends B{}
  
   A
   |
   B
   |
   C
  

  In both cases, C is a subclass of A, and C is also a subclass of B.

  In addition, in both cases, A, B, and C are all subclasses of object. As we have already said in the other thread, which prompted to create this thread (but still somehow apparently ignored by you), every class is a subclass of the object.

• Actual mechanism of object class as the superclass for all classes

  Hi all
  
  We know that all the classes of the java platform are the descendants of the object class. Even if we write a new class, in the absence of any explicit superclass, each class is implicitly a subclass of the object. As we expand it, not directly the object class, then how is the methods of the object are inherited from the class Sub that we wrote? How the java to maintain this hierarchy?
  
  Can you please explain this carefully?
  
  Thanks in advance,
  Uday

  Udaya Shankara Gandhi wrote:
  Hi all

  We know that all the classes of the java platform are the descendants of the object class. Even if we write a new class, in the absence of any explicit superclass, each class is implicitly a subclass of the object. As we expand it, not directly the object class, then how is the methods of the object are inherited from the class Sub that we wrote? How the java to maintain this hierarchy?

  Because the language is defined in this way. Compilers implement the language according to the rules of the DG JLS. Exactly how they do it is not defined. It is each compiler. As long as it respects the rules defined in the JLS to the code analysis and generate the .class file, that's all that matters. However, somewhere in the compiler's code which is about:

  if (class has an extends clause) {
    generate corresponding bytes for extends in .class file
  }
  else {
    generate bytes for extends java.lang.Object in .class file
  }
  

  No great mystery, or philosophical question.

• Why the method clone() in object class as a "protected"?

  Hello
  
  Why in the object class's clone() method declared as a 'protected access modifier '? What is a reason for this? Why not she declared as a 'public' as equals() and hashCode() method?
  
  Thanks in advance
  Rishi

  RishiM wrote:
  If it is declared public in the object class then what happens? is no difference?

  Read my previous post. If the object has a public clone() method, then each class has it, and it will be public for each of them.

  Winstoon