Display of items on the left side of the SQL Developer.

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  When I opened my laptop, go to the internet, then open the start menu, this alert rises; Unable to display some items in the start menu...

  What can I do? What the menu items start? This can be corrected?

  Thanks for the help

  Tim

  Hello

  Were there any changes (hardware or software) to the computer before the show?

  Perform the steps mentioned below and see if the problem persists.

  a: right click on the Start button, then click on Properties.

  b: now click on the Start Menu tab and click the Customize button.

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• Cannot query the SQL Developer apex_application_files

  Request Express 4.2.5

  SQL workshop

  I use a function table to analyze several files, delimited by tabs, that I downloaded and saved on the apex_application_files.  The strange thing is that when I run the following query in the SQL workshop and the schema that owns the function table, then it returns the correct results.  However, when I try to do the same on the SQL Developer as the user who owns the table function it returns no result.  A short, generic version of the base query is:

  SELECT * from apex_application_files

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  I was able to get the data I need questioning wwv_flow_file_objects$ of in SQL Developer.

• Bug in the SQL Developer report where?

  Where can I report a bug in the SQL Developer? It is possible at all?

  I use Ubuntu 14.04 (32 or 64 bit) with Oracle VM 1.7.55 and get a SIGSEGV vm.

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  Diogo Sant

  If you have database support through MyOracleSupport, you can report a bug there.

  If this isn't the case, then this is the place, although nothing is guaranteed.

• How to create insert statements in the SQL Developer client

  Hi all
  
  A toad, we can create instructions for insertion of data in the table by clicking with the right button on the table and selecting create insert Stmts. But I am new customer SQL Developer. Could you please let me know how to do that in SQL Developer. I would be grateful if someone posts a link to the manual of the SQL Developer (how to use SQL Developer).
  
  Thank you.

  SQL> create table staging(x int, y varchar2(3));
  
  Table created.
  
  SQL> create table base(x int, y varchar2(3));
  
  Table created.
  
  SQL>
  SQL> insert into staging values(1,'ABC');
  
  1 row created.
  
  SQL> insert into staging values (2,'DEF');
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> select * from staging;
  
           X Y
  ---------- ---
           1 ABC
           2 DEF
  
  SQL> select * from base;
  
  no rows selected
  
  SQL>
  SQL> insert into base
    2  select * from staging;
  
  2 rows created.
  
  SQL> commit;
  
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  SQL> truncate table staging;
  
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  SQL>
  SQL> select * from staging;
  
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• Table of misinterpretation of the SQL Developer Reference

  I use SQL Developer with Oracle 11 g DBMS 2.1.1.64.
  I've noticed recently that even if the DBMS allows you to create a table and a function with the same name, if I try to type a variable % TYPE by using the table, that I have just mentioned, there is a compilation error. For example, there are cancel_tag_range and cancel_tag_range of the table function. Then I do this variable declaration:
  v_current_tag cancel_tag_range.start_tag%TYPE;
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  that is, SQL Developer interprets as a reference to the function, not the table.
  It seems to me that the SQL Developer should know how to handle this. After all, the DBMS let me name 2 objects the same - which I think should be a problem because they are different object types - one is an array and the other a function. In addition, the context of the statement should specify that the table is referenced.
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  SQLDeveloper use the PL/SQL compiler in the DBMS so the error comes from the DBMS. You'll have to rename it, I suspect.

• Question about the use of wildcards to the left side LIKE in SQL

  First of all, let me apologize because I posted this question earlier here and the question has been moved to the SQL forum.  Unfortunately, I do not have the possibility to answer or post a question in this forum, so I find myself in need to repost it here:

  If I use the select statement of the suite I get a double line:

  SELECT * FROM DUAL WHERE '%' LIKE '% ';

  But if I use the suite I get no line:

  SELECT * FROM DUAL WHERE '%' LIKE 'A % ';

  I guess that this % on the left acts as the '%' character and no comparison of character models.

  Is it possible to make it act as the wild-card operator, when it is placed on the left side of this TYPE?

  Then someone asked me what was my goal and if I could use REGEX.  Here's what I'm trying to do in general:

  I need to create a query similar to the following:

  WITH Constraint_Search_Input AS

  (

  Some_Id SELECT 'ABC', '%' Some_Other_Id OF the DOUBLE

  )

  SELECT *.

  OF Constraint_Search_Input

  WHERE Some_Id = 'ABC' AND Some_Other_Id LIKE 'a % '.

  ;

  Where the ID in the WITH are an entry from our processes and clause ID WHERE are stored as a set of constraints stored in a record in the database.

  The query is constructed dynamically, so a possible scenario represented in above the simplistic example, is that I received a single ABC for Some_Id entry and number of entry whether for Some_Other_Id but it the constraint (= 'ABC' AND Some_Other_Id LIKE 'A %' Some_Id) stored in the DB.  I then generate the query then because Some_Other_Id is part of the constraint that I need to add it to the entry that I build in the WITH of the query clause.

  I know that I can find ways more developed and complex execution of this match up of entry constraints, but I'm just trying to take advantage of the database to make it in the simplest.

  Thank you

  Thomas

  https://docs.Oracle.com/database/121/SQLRF/conditions007.htm#SQLRF52142 the model is on the right and the value you want is on the left, you cannot use wildcards to the left.

  What is the requirement of real business here? You have presented how you want to solve it, but find it does not work, there may be a more appropriate method.

• Cannot display the results in the SQL Developer tool

  Hello Experts - I installed Oracle SQL Developer (version 1.5.5), just run a simple query. Nothing appears in the results window. Can you please let me know why?

  Select * of the double

  You have an error message in the message area.

  White spaces are important in SQL!

  Good bye

  DPT

• Unable to connect the SQL Developer PDB

  Hello

  I am unable to connect to my pdb1 for SQL Developer.

  Oracle@Solaris:~$ lsnrctl status

  LSNRCTL for Solaris: Version 12.1.0.2.0 - Production on 4 January 2016 13:50:37

  Copyright (c) 1991, 2014, Oracle.  All rights reserved.

  Connection to (ADDRESS = (PROTOCOL = tcp)(HOST=) (PORT = 1521))

  STATUS of the LISTENER

  ------------------------

  Alias LISTENER

  For Solaris TNSLSNR version: Version 12.1.0.2.0 - Production

  Start date 4 January 2016 10:57:08

  Uptime 0 days 2 h 53 min 29 s

  Draw level off

  Security ON: OS Local Authentication

  SNMP OFF

  Parameter Listener of the /u01/12.1.0/grid/network/admin/listener.ora file

  The listener log file /U01/app/grid/diag/tnslsnr/Solaris/listener/alert/log.XML

  Summary of endpoints listening...

  (DESCRIPTION = (ADDRESS = (PROTOCOL = tcp)(HOST=solaris) (PORT = 1521)))

  (DESCRIPTION = (ADDRESS = (PROTOCOL = ipc) (KEY = EXTPROC1521)))

  Summary of services...

  Service '+ ASM' a 1 instance (s).

  Instance '+ ASM' READY State, has 1 operation for this service...

  Service 'cdb01' has 1 instance (s).

  'Cdb01' instance, State LOAN, has 1 operation for this service...

  Service 'cdb01XDB' has 1 instance (s).

  'Cdb01' instance, State LOAN, has 1 operation for this service...

  Service "Pdb1" has 1 instance (s).

  'Cdb01' instance, State LOAN, has 1 operation for this service...

  The command completed successfully

  Oracle@Solaris:~$

  SQL Developer:

  Status: Failure-Test failed: listener refused the connection with the following error:

  ORA-12505, TNS:listener is not currently of SID given in connect descriptor

  Type of connection is that fundamental role is SYSDBA

  But I can connect to my CBD01 of SQL Developer.

  //

  Thank you

  Christophe

  SQL Developer:

  Status: Failure-Test failed: listener refused the connection with the following error:

  ORA-12505, TNS:listener is not currently of SID given in connect descriptor

  As another reviewer said Oracle 12 c requires SERVICE_NAME and no SID to connect to the PDB files.

  http://www.Oracle.com/technetwork/articles/database/multitenant-part1-PDBs-2193987.html

  What is a database of the container

  So, what is the big advantage in this configuration, you may ask? Couldn't we have just created several ordinary vanilla instead of several PDB databases? Yes, we could have; but each of these 'plain vanilla' databases would have then his own load of instance (process and memory). PDB do not have an instance associated with them, eliminating this overload. Let's look at the installer with an example. Suppose you have a CBD (database container - the real database that hosts the other PDB files) called CONA, who has a calledPDB1 of the PDB. If you check the Oracle instance, you will see that there is one - that of the CBD. First, let's check the ORACLE_SID:

  [oracle@prosrv1 ~]$ echo $ORACLE_SID CONA
  

  That's all. There is only a single SID; not one for each PDB. Then we will check the process, especially very important that known as 'pmon ":

  See this last sentence above? See this line in the status of listening port you have posted?

  Service "Pdb1" has 1 instance (s).

  Pdb1 has a 'service' - a SERVICE_NAME allows to connect to him and all other PDB files.

• Not able to show tables/views to the SQL Developer

  I am a new user of SQL Developer with a new facility. When, in the nav of connections window, I see my db name and a list of items below - tables, views, indexes, etc. Problem is that when I click on "tables", for example, it does not show me a list of tables, even if she acts like he is looking for them. Also, when I use the "Search the database object" function on the Connections tab, nothing is returned, even though I know that I'm looking for a table that exists.
  
  I thought that perhaps it was not conclusive tnsnames, so I put its location in preferences/base data/advanced.
  
  I'm sure its something simple...?
  
  Thank you very much
  
  EWB

  Is the user, the owner of the tables? If not look under the node other users.

  Hope that helps,
  K.

• The SQL Developer memory usage is very high + session monitor work not

  Hello
  I'm facing 2 problems with SQL developer tool.
  
  (1) high memory usage (about 160 MB).
  (2) when I click on tools-> monitor sessions, session related window opens upward.
  
  I use 1.5.4 version. Please let me know if there are fixes for these issues.
  
  
  Thanks

  Hello

  (1) not much help for you, but for me, 160 MB is not excessive use of memory for SQL Developer (mine is currently sitting at around 150 MB). And then, I have been using the tool for a while and have a lot of memory on my computer.
  (2) tools > Sessions of the monitor works fine for me (DB 10.2.0.3). Do you get an error message when it "does not open upward? Which version of DB are you using? If you go through the browser reports (see > reports if it is not already displayed) and select Data Dictionary reports > Database Administration > Sessions > Sessions, does it report?

  theFurryOne

• Availability of the SQL Developer with embedded JDK

  SQL Developer 4.1 was released a month ago.

  As I can't install Java 8 on my system without maximum pain, I forward the release of the version with embedded Java.

  Does anyone know when this will happen?

  Concerning

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  Soon

• Bug? : cannot execute predefined "last awr" report with the latest version of the SQL Developer

  Using sql developer before 4.x... report works fine

  Using SQL developer 4.0.0.13... report fails with ORA-01422

  using the actual query to generate awr against the same range of component snap works perfectly

  I opened a SR on the question

  Thank you

  It's always a good idea to open a SR when you are able.  I assume that you have already received a response from support.  For others I wondered about this, the question is likely related to running the report against a CCR environment, as indicated in the following bug:

  Bug 18132564 - LAST AWR REPORT FAILS WITH ORA-01422 IN CCR ENVIRONMENTS
  

  The call of the AWR report requires parameters for a DB and an ID of Instance, so that the report should run, as in earlier versions, for only the current instance, or be modified to run all instances in the cluster.

  Kind regards

  Gary

  SQL development team

  P.S.: And, in fact, a discussion prior forum - ai2 4.0-AWR and ASH giving ora-01427

  lead following bugs are connected and supposed to be fixed for SQL Developer 4.0...

  
  

  Bug 17481944 - PERFORMANCE PANELS NEED AWR/ASH/ADDM FOR RAC ENVIRONMENTS SUPPORT

  
  

  ... with the developer commenting

  I've added a number instance selection control to the various reports: ASH,.
  AWR, difference and SQL. The control is supposed to be visible when the
  connection is a RAC system, tests should a RAC.

  So if you are not on a RAC system, or are on CARS but do not see the selection number instance control, please let us know.

  Post edited by: Gary Graham

• Question about how the SQL Developer to connect to DB

  I'm testing the recovery WORK and client connection, for a db 3 cluster node by rigging the first entry in my tnsnames.ora file and connecting with SQL Developer.

  In theory, Developer SQL should fail over to the second node listed in my tnsnames.ora file.

  The problem is that no matter what I put in my tnsnames.ora file, Developer SQL still connects to the first database listed, proddb1, EVEN if I have 1) remove this entry from the TNS and 2) when I mistyped the entry so it is not resolve in DNS.

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  You specify the TNSnames directory in preferences? It is possible, it uses the evil tns file to make the connection. It is even possible he finds several TNS files in that directory, and it does not use the one you intend to let him. You can see if you follow this 'thing'.

• Unusual behavior with the debugger of the SQL Developer

  Hello everyone,
  
  I've recently updated to Developer SQL 3.2.10.09 and I noticed unusual behavior during debugging. I can't confirm that this behavior started because of the update, but that's just a guess at the moment. I'll explain what's going on...
  
  I have a package and spec (both compiled for debugging) I want to scroll. I make a point to stop where I want to put an end to the execution and everything stops as expected at this time there... or what it looks like. The performance indicator is actually the line after where the process stopped in fact. Here is an example.

  ndxEmpl           PLS_INTEGER := 1;
  ndxNewFac        PLS_INTEGER := 1;
  ndxAdid           PLS_INTEGER := 1;
  ndxStdn           PLS_INTEGER := 1;
  ndxNonComp       PLS_INTEGER := 1;

  Say I put the breakpoint on line 3 of the code above. The execution point watch line three has been highlighted to indicate that it is the next line should be run, but when I mouse over ndxNewFac in both, he line shows its value to null. Then I switch to line 4 and ndxNewFac is now list 1, but ndxAdid is null.
  
  It is really interesting when you arrive if statements or many transport returns in the code, because the execution point will actually bring out a blank line when execution is still a stingray above.
  
  I reinstalled the JDK from my office and used previous versions of SQL Developer all with the same results in the end. I also used the computers of some colleagues on the same package and their debugging behaves normally. I have not tried the debugger on an anonymous block or another package yet, but I thought I'd throw this question here. I will reply with my findings.
  
  Everyone has experienced identical to this behavior? I'll capture some screenshots if the scenario above is not clear.
  
  Published by: gort_industries on Sep 28, 2012 08:28
  
  Published by: gort_industries on Sep 28, 2012 10:44

  There was an old problem where the debug line numbers didn't explain correctly additional "create or replace" added to the top. I thought that this had been fixed some time ago.