For loop does not

Similar Questions

• parallel for loops does not

  Hello.

  I'm learning the multi - thread programming. To start, I use "parallel for loops" and I was surprised that it does not work. One - thread loop work a few times faster (depending on settings) that multi - thread. I don't know why, and it is my request to correct my Vi to work properly.

  Lenovo, G580, Windows 7, 64-bit computer

  Intel Core i7 3632QM
  Ivy Bridge
  Specification Intel (r) Core i7-3632QM CPU @ 2.20 GHz
  Package (platform ID) Socket 988 B rPGA (0x4)
  Number of hearts 4
  Number of threads 8

  LabView 2011.

  Altenbach says:
  

  Gibbon wrote:

  What was 'strange' behavior?  In "linia dluga" when inside the loop is on '1' of the "spreed up' between one and multi-fil is about 3 times, when I put it in '20' this grow to 6.2. It was strange form me, becourse I expect a similar value.

  A parallel FOR loop has an overhead for parallelization (split the problem, then go back the results, etc.). If the code is very fast, the overhead is proportionally larger. If the Subvi takes a long time to complete, the overhead of parallelization is insignificant. It is often not worthwhile to parallelize the loops with a very simple and fast code.

  Gibbon wrote:

  Altenbach - I have another question if you can help me - how did you "seconds relative high resolution." VI "? -I want to say how did you know that there is this 'vi '. And thanks a lot for your modyfications.

  You can find it in vi.lib\utilities. It is well known.

  Maybe not well known enough!  the 'Hidden gems' package adds to your palattes.  It has also been considered by a nugget of the community

• For loop does not or will not stop according to the toggle switch

  This is the VI I work with joint. The VI is a bit long, but the two loops on the left side are loops that have problems. When the program works and I hit the switch 'START of CYCLE' rocking the loop simply does not work. However, when I toggle switch on before the start of the program, the loop will run the way it is supposed to, but never shuts off when the switch is turned OFF.  Any help is appreciated. Thank you.

  billko wrote:

  James.Morris wrote:

  Good, so as I was saying before the left of right data flow, so things on the right don't peut/don't do nothing until things on the left ends.

  I've seen you say this twice now, and it is not true.  Data flow from the output of a node to the input of another.  This means "from left to right" because it was designed that way.  If you had two subVIs, 'A' and 'B', no cable together and 'B' to the right of 'A', it does NOT follow that 'A' will run before 'B '.  If, for some silly reason, you had 'B' exits on the left and the 'A' entries on the right, you could connect the outputs 'B' to 'A' and the data would be sent to the right left.

  But I'm fairly certain that I have misunderstood the information you were trying to convey?  (It wouldn't be the first time, believe me!)

  Ah, point taken, I'll have to adjust the way in which I explain the data flow, stream of best practices not only. It is difficult to describe the flow of data to a beginner without using the directions. I was just trying to convey that the Boolean value that it has a cable upwards is providing data for both the first structure of matter and the main While, loop which means they expect both for the info of the Boolean value. If he makes the request to wait for the user to click on the Boolean value, then the loop will wait too long.

  I think that the data stream is one of the biggest problems new users seem to fight with and this thread is an example of this. EMART can make this code work, even if it's a mess, but I think it is obtained when the additions of code got on immediately to the point where he needs a little more experience help to understand how do to encorporate more functionality without messing up what already exists.

• FOR loop does not update the local Variable

  I am newer to labview, and I can't wrap the head around why not a habit of local variable to update in the code if it updates on the dashboard. Anything im missing?

  Assume that you are talking about the local variable of the 'State of the cell. The terminal updates every 500ms in the small top loop, the local variable indicates simply that the indicator and thus updates also.

  The problem is "dataflow" and you need to familiarize yourself with the concept!

  Once the while loop starts, the local variable is reading and inside the loop begins. Most likely, the local variable is read before it is updated in the small loop, so most likely returns the value of a fade on the first iteration of the while loop. Now the small loop continues to go twice per second for about five seconds. Only after the loop FOR (and everything else inside the while loop) completed, the while loop will go to the next iteration, date on which the local variable is read once more, this time with the last value of the last for loop iteration of the previous iteration of the while loop.

  In summary, the local variable updates very well, it's just that the code does not read the new value around most of the time.

  Your VI is full also potential competition conditions caused by the over-use of the local variable. You need to respect the proper execution order by eliminating local variables.

  So what is the solution? Hard to say without knowing what the VI is supposed to do. Most likely, you will need to remove the inside OF the loop and use it outside while loop for everything.

• For each does not properly in the XSLT file to two loops on a single node

  Hi all
  
  I'm transforming 2 inputs to a single target using XSLT. Both of the target entry of the same pattern and have the child element.
  In the XSLT, I gave this condition.
  "< xsl: for each select="$Variable1.payload/ns1:BookStore/ns1:Books ">
  < xsl: for-each select = "/ ns1:BookStore / ns1:Books" >
  "< xsl: if test="$Variable1.payload/ns1:BookStore/ns1:Books/ns3:BookId = ns3:Books / ns3:BookId ">
  
  My second for each does not work and in the target, I'm getting double elements. Help, please. Here are two xml source and xml desired target.
  1 XML source:
  
  < bookStore >
  < book >
  Name1 < name > < / name >
  author1 < author > < / author >
  < ID > 1 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < book >
  name2 < name > < / name >
  Author2 < author > < / author >
  < ID > 2 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < book >
  < name > NAME3 < / name >
  author of 3 < author > < / author >
  < ID > 3 < / BookId >
  < quantity > 2 < / quantity >
  < price > < price / >
  < status > < / status >
  < book >
  < / book >
  
  XML source 2:
  
  < bookStore >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 1 < / BookId >
  < price > 100 < / price >
  < status > < / status >
  < book >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 2 < / BookId >
  < price > 200 < / price >
  < status > NA < / status >
  < book >
  < book >
  < name > < / name >
  < author > < / author >
  < quantity > < / quantity >
  < ID > 3 < / BookId >
  < price > 300 < / price >
  < status > < / status >
  < book >
  < / book >
  
  Desired target XML:
  
  < bookStore >
  < book >
  Name1 < name > < / name >
  author1 < author > < / author >
  < ID > 1 < / BookId >
  < quantity > 2 < / quantity >
  < price > 100 < / price >
  < status > < / status >
  < book >
  < book >
  name2 < name > < / name >
  Author2 < author > < / author >
  < ID > 2 < / BookId >
  < quantity > 2 < / quantity >
  < price > 200 < / price >
  < status > NA < / status >
  < book >
  < book >
  < name > NAME3 < / name >
  author of 3 < author > < / author >
  < ID > 3 < / BookId >
  < quantity > 2 < / quantity >
  < price > 300 < / price >
  < status > < / status >
  < book >
  < / book >
  
  Thank you

  Hello

  It will not work like that... To do something like the following... Only one for each...

  
    
    
      ns1:Name
      ns1:Author
      ns1:BookId
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Quantity
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Price
      $Variable1.payload/ns1:BookStore/ns1:Books[ns1:BookId = $bookId]/Status
    
  
  

  I don't have to check the syntax, but you get the idea...

  I hope this helps...

  See you soon,.
  Vlad

• SR400 while the loop does not work

  Hello

  I'm using LabVIEW for control SR400 through a GPIB card.

  I use SR400 to count the number of signal in a second, wait 0.05 s, then again count the signal once, wait 0.05 s once again, and so on.

  However, the while loop didn't iterate. When I started the program, it is only once.

  In execution of highlight mode, when an iteration is finished, he waited a long period starting the next. In normal mode, it doesn't have to iterate.

  Also when I clicked the stop button, it's been clicked. However when I wrote a very simple program, the stop button worked normally.

  In any case the button issue is not very important. I don't care that the program iterates forever or not. I just want to iterate.

  I searched the jury and had not could not any related problem.

  Is it better to attach my VI? The VI is in my computer lab.

  Thank you very much!

  This code just feels bad.

  (No real management mistakes, deep, stacked sequences FOR lines that are wired to iterate through only once, controls on the right and right to left, wiring weird code on average the last 10 items (Hint: means ptbypt with a length of 10 sample he would!).) If you want to use the wire of the error, the sequences would not even necessary)

  If the stop button does not reset, it means that the iteration of the loop does not terminate. It can fill in only if the two structures of the sequence ends.

  Have you tried running in execution, emphasizing fashion while looking at the diagram? Probably one of the communications is at a standstill. For example, the instrument sends really 6 bytes at the end? When you set the overall timeout and what is it?

• Loop does not complete

  I have a simple loop in a function I use to remove all elements in the array:
  

  for (var i: int = 0;  I < tempArray.length;. i ++)

  {

  tempArray.pop ();

  trace ("pop:" + tempArray.length);

  }
  
  The probelem I'm having, it's that the loop does not terminate. It seems that to remove a single item, sometimes it will remove two. An event that is triggered in a separate function you may this prevents from running until the end?

  is there another method I could use to remove all items?

  use:

  for (var i: int = tempArray.length - 1; i > = 0; i--)

  {

  tempArray.pop ();

  trace ("pop:" + tempArray.length);

  }

• Conditional loop does not work correctly.

  Hello
  
  If you look at my code, its all about the analysis of a dictionary. IM check the dictionary for the word 'aardvark '. It gives me wrong all the time. When "aardvark" is the first word of the table, IE my_dictionary [0] is "aardvark". I wonder why the conditional loop does not work very well. IM checking if the user string aardvark is == my_dictionary ; he should give me the true value.
  
  Is there an error in the code? Can someone explain to me where im going wrong?
  
  PS-> put everywhere traces gives me the right output. Except for the result of the if() function.
  
  Best regards and many thanks in advance.
  Roshan Kolar

  Hi Raymond,

  Thanks for the reply. I had the problem, actually the conditional loop was perfect, the analysis was not. The reason is, a few words in the dictionary had a return of cart/jump of line/space to the index of the last after the word. It was randomly, so some words have been taken, but some were not as "vicious" == "vicious" - gives the INVALID WORD.

  So I was thinking about the parser, where I removed the unwanted last tank - now the condition has worked well. Thank God I worked even after the publication of the request.

  Thank you very much Raymond.

  Kind regards
  Roshan

• Firefox for Mac does not recognize a valid SSL certificate

  Firefox for Mac does not recognize the SSL certificate that is valid for this site, I got: https://www.georgeglazer.com. It gives a warning "not reliable." However, the Firefox for Windows does not give a warning. This happens even if I clear the cache and it happens in the Mavericks and OS of Yosemite. The certificate is up-to-date and with Comodo. Firefox for Mac is now the only browser producing these errors (v. 39, put updated) - Internet Explorer, Safari and Chrome are not. Our hosting provider has said it's probably a browser issue, perhaps having to do with intermediate certificates in Firefox being obsolete. I really hope you'll solve the problem, as it's annoying for us when we're going to do right by our customers and pay for the SSL certificate. I have attached a picture of the warning and the other from what you see on a PC: a pop-up that says it is a verified SSL certificate and gives details about the issuer, the period of validity, etc.

  COMODO should you sent a link to download the file 'bundle' containing the intermediate certificates. Who needs to go in the same directory as the certificate of your site. If you are using a control panel, your host can probably help with this process. And if you bought through them, shame on them for not taking care of this for you already!

• the update of firefox 28 for mac does not, the bar just rotates, I can't get the update

  the update of firefox 28 for mac does not, the bar just rotates, I can't get the update. Thank you

  Hello

  Try to get the full version here:

  • All versions

  Then just install it.

• I'm having a problem where Firefox keeps asking for my password to Amazon, even if I tell Firefox NOT to remember this password. In Firefox options, Amazon is clearly recognized as a site for which does not save passwords.

  I'm having a problem where Firefox keeps asking for my password to Amazon, even if I tell Firefox NOT to remember this password. In Firefox options, Amazon is clearly recognized as a site for which does not save passwords.

  Do not remove the navigation, search and download history on Firefox to clear the "Site preferences".

  Compensation of the "Site Preferences" clears all exceptions for cookies, images, windows pop up, installation of software and passwords.

• Serial number for lightroom does not work

  my serial number for lightroom does not work

  Maritah has made education institution give you an indication of the place where you need to download the installation files from?

  You can download Lightroom 5.6 from the following locations:

  • Adobe - Lightroom: For Windows: Adobe Photoshop Lightroom 5.6
  • Adobe - Lightroom: For Macintosh: Adobe Photoshop Lightroom 5.6

  The updates contain the complete installation files and should accept your serial number.

• Adobe Photoshop Elements 12 for Mac does not in Applications. Tutorial for editing in iPhoto shows by selecting the Adobe software in Applications. Am I missing a step in product registration?

  Adobe Photoshop Elements 12 for Mac does not in Applications. Tutorial for editing in iPhoto shows by selecting the Adobe software in Applications. Am I missing a step in product registration?

  I answered my own question: there is a difference between "Download"and 'install'." Hunting the 'install' (1.5 hrs in my case) and align your passwords, Adobe ID, etc., then install. 15 min. The right choice appears in the Applications. However it is to understand why photo selected for editing in iPhoto does not display in the elements.

• "1 MHz" for the name of the source on the time loop does not work on LabVIEW Real-time 9.0

  A Loopis Timed running as expected if a time source is manually chosen in the dialog box of configuration for "1 kHz" (first digit) and "1 MHz" (second digit). If the time Source name is set through the input of the channel "1 kHz", the loop is executed, too third figure). But if the input string is "1 MHz", the loop is not executed (last figure). The channel two are created by "create constant" on the entry of the loop to exclude typos. Is it possible to set the Source of a loop time timed through the input string to the real-time clock hard Mhz?

  

  

  

  

  OK, I was a bit confused by the difference between the behavior of error...

  Now, the question is quite clear. Aid for the timed loop provides the following regarding the Source of the calendar entry:

  Specifies the name of the synchronization source to use to control the structure. The source of synchronization must be created using the create synchronization Source VI on the block diagram or selected in the dialog box Configure the timed loop .

  So, I think that you have somewhere in your code a time Source.VI create if you pass "1 kHz" as the name. But you did not do this for your clock "MHz 1"...

  hope this helps,

  Norbert

• While the loop does not stop when the two values are equal using equal to comparitor

  Hello world

  I have a really, really strange bug. I have a LabVIEW VI that change a chain on a power supply. I have a start and a stop voltage and use a while loop to increment the device. For example if I want to scan from 1, 2V to 2.2 V in 0.2 V incremements, the program will end when "The current tension" = "stop the tension." And it works very well!

  However, when I start - 3 V and want to stop to say-0.8 (new in 0.2 V incremements) the program does not stop when "The current tension" = "stop the tension." I checked with the probe close to what should be the end of the race and - 0.8 V goes both of the entries ' equal to ' comaprison operator, but that his can't trigger a real result.

  It's very strange for me. Espeically as if I'm going - 0.8 V to-2 V but decrement of-0.2 V, the program stops correctly!

  I am very confused!

  See you soon!

  Search on: comparison of floating-point numbers

  The second thread is particularly relevant. This discussion was 2009, but you can find that the same "bug" being reported to enter the end of the 1980s.

  Mike...