FROM SHAPED DATENREPORT (how on the same page)

Hello everyone

Yes, I know that it is built in a design of two pages where the first is the form and the second report, but I want it for both on the same page so that you can see what he has on the report and add his own line to the table. Well, I could make the creation of a form, then by changing the page and then add another region. Alright. But then I don't know how to link them together so that the data is passed to the form of the report.

Additionally, the form to fill the data must pass in two separate tables, because a table contains the details of the location and the other opinion about each store. Easy to do on PHP and mysql, but here I'm lost.

Second thing that drives me crazy it is that I created a table named location as well as street postal code for a store and another for assessment so that customers or workers add a suite evaluate services etc.

Well, I'm trying to create that shape, that I first talked about this would hold all fields and I do on a SQL query that contains the definitions of the two tables. My XE is completely empty from the remains of other applications, etc. I do the equijoin alright


Select l.loc_id, l.company, l.postcode, l.street, l.town, e.eval_id, e.loc_id, e.locum_reg, e.date_booked, e.items, e.addicts, e.number_staff, e.attitude_staff, e.organisation, e.stock_filing, e.agency
location, e-assessment
where l.loc_id = e.loc_id

and I get this annoying error all the time


ORA-20001: unable to create the form on equijoin. ORA-20001: Error Page = 2 item = 'P2_LOC_ID' id = '1324114494879878' ORA-20001: error page 2 item = = "P2_LOC_ID" id = "1324114494879878" a same name something like existing at the level of applications. ORA-0000: normal end successfully

Well, if this form consists of two tables, it must definitely something in common with them! How did the name of the element suppose to have another name? It is made with the wizzard so supposedly the wizzard you should know, but I tried two days 14 hours a day.

no indication of how this problem would be invaluable for me

Thank you

Alvaro

Alvaro:

This help if you supplied alias names to the "loc - id" of each table column in the SQL query? Something like

select l.loc_id location_loc_id, l.company, l.postcode, l.street,l.town, e.eval_id, e.loc_id evaluation_loc_id, e.locum_reg, e.date_booked, e.items, e.addicts, e.number_staff, e.attitude_staff, e.organisation, e.stock_filing, e.agency
from location l, evaluation e
where l.loc_id = e.loc_id

CITY

Tags: Database

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