Get a value of gray of the pipette?

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• How to get 2 values of occurrence of the string?

  Hello

  I have given as below, so I need to get only 2nd value (between - value) and also give me simple ways

  Select 112181-3769-3687 double

  Select 11495-3677-3653 double

  Select 1128-7608-7328 double

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  994122 wrote:

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• Getting a value record according to the existence or not...

  Hello
  Assume that the famous 'emp' table and another table called 'taste '.

  create table sample(empno number(4), dates1 date, dates2 date)

  and some sample data:

  SQL> insert into sample values(7788,null,null);
  
   
  
  1 row inserted
  
   
  
  SQL> insert into sample values(7839,'10/10/2009',null);
  
   
  
  1 row inserted
  
   
  
  SQL> insert into sample values(7844,NULL,'11/10/2010');
  
   
  
  1 row inserted

  After insertion of the sample of the table, the following query returns the required results:

  select empno,
  
         sal,
  
         case when empno not in (select empno from sample) 
  
           then 0
  
           when dates2 is null 
  
           then 1
  
           when dates2 is not null
  
           then 0
  
         end dates      
  
  from       
  
  (
  
  select e.empno,
  
         e.sal,
  
         s.dates2,
  
         s.dates1
  
     from emp e
  
     left outer join sample s
  
       on s.empno=e.empno
  
  )
  
  
  
  
  
  EMPNO       SAL      DATES
  
  ----- --------- ----------
  
   7788   3000,00          1
  
   7839   5000,00          1
  
   7844   1500,00          0
  
   5499   9000,00          0
  
   7782    250,00          0
  
   7521   1250,00          0
  
   7654   1250,00          0
  
   5498   3000,00          0
  
   5410   1150,00          0
  
   7698   2850,00          0
  
   7566   2975,00          0
  
   7499   1600,00          0
  
   7934   1300,00          0
  
   7902   3000,00          0
  
   7369    850,00          0
  
   5411    500,00          0
  
   7876   1100,00          0
  
   7900    950,00          0
  
   
  
  18 rows selected

  The logic underlying the result set is:
  for each empno on table emp that exists (if exists) also on the example table:
  (1) if dates1 and dates 2 are null, the flag {dates column} should be 1
  (2) if dates1 is not null, the flag should be 1
  (3) if dates2 is not null, the flag must be 0
  If empno does not exist on the sample of the table, the flag must be 0
  
  The problem is when I insert a new record in the empno existing on the sample table... such as:

  insert into sample values(7844,NULL,'11/10/2010');
  
  
  
  two records appear whereas only one is expected. The one expected is:
  
  7844,NULL,'11/10/2010'

  Notes: dates1 or dates2 cannot be simultaneously null (but can be simultaneously null),
  If dates2 exists then the flag is 0 (it replaces the other cases, for example if only empno gave or empno and both dates values)
  I use dev10g v.2
  
  How to write the query to get the result you want...?
  
  Thank you
  SIM

  Check the code below...

  I could not fully understand what conditions take priority... so change the conditions in this case, according to the order in which they must be evaluated.

    1  select e.empno,
    2         e.ename,
    3         e.sal,
    4         s.dates1,
    5         s.dates2,
    6         case when (s.empno is null) then 0
    7              when (s.dates1 is null and s.dates2 is null) then 0
    8              when (s.dates2 is not null) then 0
    9              when (s.dates1 is not null) then 1
   10              else 1
   11         end flag
   12    from emp e,
   13         sample s
   14*   where e.empno = s.empno (+)
  SQL> /
  
       EMPNO ENAME             SAL DATES1     DATES2           FLAG
  ---------- ---------- ---------- ---------- ---------- ----------
        1002 SMITH             800                                0
        7369 SMITH             800                                0
        7499 ALLEN            1600                                0
        7521 WARD             1250                                0
        7566 JONES            2975                                0
        7654 MARTIN           1250                                0
        7698 BLAKE            2850                                0
        7782 CLARK            2450                                0
        7788 SCOTT            3000                                0
        7839 KING             5000 10/10/2009                     1
        7844 TURNER           1500            11/10/2010          0
  
       EMPNO ENAME             SAL DATES1     DATES2           FLAG
  ---------- ---------- ---------- ---------- ---------- ----------
        7876 ADAMS            1100                                0
        7900 JAMES             950                                0
        7902 FORD             3000                                0
        7934 MILLER           1300                                0
  

  The outer join will ensure you get a null value for sample.empno, so you don't need to do a still exists...

  s.empno is null
  and
  e.empbno = s.empno(+)
  

  We will give you all the lines in the example table that do not have a line used for the emp table.

• bug of the pipette

  Hello world

  It seems Photoshop eyedropper or CMS has a problem. I've attached an example of .psd file so that anyone can reproduce the error.

  
  

  Simply open and switch layer1 to the linear density screen blending mode. You will notice that therefore gray pixels will get visually a bit brighter, but the pipette will show RGB = (38,38,38) in both cases! (you can measure anywhere in the center of the image, for example the pixel (X = 51, Y = 35), which is the point where I measured for the screenshots below).

  The point is: any pixel identified by Photoshop RGB = (38,38,38) should look the same, not sometimes brilliant and sometimes darker.

  
  

  If you don't trust your eyes (which can fall pray to an optical illusion), just open my screenshots in any application with a pipette (even Windows Paint will do I guess) and compare the values of the gray area (make sure that the eyedropper sample size is 1 x 1 (sample point)). The values will differ.
  

  Or if you want to not count on my screenshots, just make your own.

  
  

  To ensure that additional measures, I also used a pipette utility screen named "ColorCop" which displays the actual values of RGB pixel of the screen at the current position of the cursor in real-time. The recorded values are obviously the same as can be recovered in the screenshots below, either = (42,42,42) for the screenshot 1 RGB and RGB = (43,43,43) for the screenshot 2.

  NOTE 1: The question is unrelated to any resulting possible rounding of blend modes errors and multiple layers. To prove this, you can flatten the image (menu: layer > > flatten image). Still the same problem.

  
  

  NOTE 2: For those of you familiar with color management, the actual values comes from your screenshots depending on the color profile associated with your monitor. This explains the differences between the RGB = (38,38,38) and the values in the screenshots (in my case 42,42,42 and 43,43,43). Your values will be obviously different. I also noticed that if you choose sRGB as your monitor profile, the error can be reproduced.

  Parameters:

  the color picker sample size: 1 x 1
  

  document measured pixel: X = 51, Y = 35

  measure screen pixel: X = 602, Y = 510
  

  Adobe Photoshop: CS3

  the document color space: (irrelevant, sRGB)

  document .psd in question: Home

  screenshot 1 (RGB = 38, 38, 38 shown in dark gray):

  (click to enlarge!) :
  

  

  screenshot 2 (RGB = 38, 38, 38 shown in lighter gray):

  

  ¶

  always looks like a simple rounding error for me, when you look at to CMYK you get 71/65/64/70 for screen and 71/65/64/69 for linear density

• How to use Ajax get multiple values in an array?

  Hi All-

  I am using AJAX to get multiple values in a table using example of Denes Kubicek in the following link-

  http://apex.oracle.com/pls/otn/f?p=31517:239:9172467565606:NO:

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  http://apex.oracle.com/pls/apex/f?p=4550:1:0:

  Workspace: iConnect

  Login: demo

  password: demo

  I was able to reproduce his example on page 1 (homepage).

  However, I want to use system generate a table to complete this example and was not able to complete the data correctly.

  Page 2 (method 2) is that I'm struggling to fill the column values. When I checked the item application values in the Session, and values seems to be filled properly.

  That's what I did on this page:

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  DECLARE
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    v_price my_book_store.price%TYPE;
    v_author my_book_store.author%TYPE;
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    v_price := c.price;
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    HTP.prn ('<item id="f06_' || :t_rownum || '">' || v_author || '</item>');
    HTP.prn ('<item id="f07_' || :t_rownum || '">' || v_qty || '</item>');
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  2. create two objects application - TEMPORARY_APPLICATION_ITEM2, T_ROWNUM2

  3. put the following text in the Page header:

  <script language="JavaScript" type="text/javascript">
  function f_set_multi_items_tabular2(pValue, pRow){
      var get = new htmldb_Get(null,html_GetElement('pFlowId').value,
  'APPLICATION_PROCESS=Set_Multi_Items_Tabular2',0);
  if(pValue){
  get.add('TEMPORARY_APPLICATION_ITEM2',pValue)
  get.add('T_ROWNUM2',pRow)
  }else{
  get.add('TEMPORARY_APPLICATION_ITEM2','null')
  }
      gReturn = get.get('XML');
      if(gReturn){
          var l_Count = gReturn.getElementsByTagName("item").length;
          for(var i = 0;i<l_Count;i++){
              var l_Opt_Xml = gReturn.getElementsByTagName("item")[i];
              var l_ID = l_Opt_Xml.getAttribute('id');
              var l_El = html_GetElement(l_ID);    
              if(l_Opt_Xml.firstChild){
                  var l_Value = l_Opt_Xml.firstChild.nodeValue;
              }else{
                  var l_Value = '';
              }
              if(l_El){
                  if(l_El.tagName == 'INPUT'){
                      l_El.value = l_Value;
                  }else if(l_El.tagName == 'SPAN' && l_El.className == 'grabber'){
                      l_El.parentNode.innerHTML = l_Value;
                      l_El.parentNode.id = l_ID;
                  }else{
                      l_El.innerHTML = l_Value;
                  }
              }
          }
      }
      get = null;
  }
  </script>
  
  
  Add the follwing to the end of the above JavaScript:
  
  <script language="JavaScript" type="text/javascript">
  function setLOV(filter, list2)
  {
   var s = filter.id;
   var item = s.substring(3,8);
   var field2 = list2 + item;
   
   f_set_multi_items_tabular2(filter, field2);
  }
  
  
  
  
   
  
  
  

  4 query in the form:

  select
  "BOOK_ID",
  "BOOK",
  "SUBJECT",
  "PRICE",
  "AUTHOR",
  "QTY",
  "BOOK_ID" BOOK_ID_DISPLAY
  from "#OWNER#"."MY_BOOK_STORE"
  
  
  
  
  
  

  5. in the column of Book_ID_DISPLAY attribute:

  Add the following code to the attributes of the element: onchange = "javascript:f_set_multi_items_tabular2(this.value,'#ROWNUM#'); »

  Changed-> onchange = "javascript:setLOV(this,'f03'); »

  Now, T_ROWNUM2 returns the value as f03_0001. But TEMPORARY_APPLICATION_ITEM2 returns in the form [object HTMLSelectElement]...

  Please help me to see how I can fill the data in the tabular presentation format. Thank you in advance!

  Ling

  Updating code in red...

  Ling

  LC says:

  Application	Item Value	Item Name
  54522	3	TEMPORARY_APPLICATION_ITEM2
  54522	f03_0003	T_ROWNUM2

  No T_ROWNUM2 should be 0003.

  I made a copy of your page to make corrections.

  There are several problems.

  First you where submiting T_ROWNUM2 whereas you would use: t_rownum in the pl/sql code.

  I changed the name of the element in the f_set_multi_items_tabular2.

  Secondly you where now affecting the rownumber f03_0001 for the first line.

  Resulting XML returned as follows.

  this xml genericly sets multiple items
  CSS Mastery
  22
  Andy Budd
  1
  
  

  I changed the following text in the show_lov.

  var point = s.substring (4.8);

  var Field2 = item;

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  Hello

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  now, I wanted to get these value from view if last_updatetime change in the base table and wanted to store only the data in a temporary table.

  Please help me to solve the above problem

  Thanks in advance

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• How can I get a clear picture after the use of the pipette?

  I found how to use the pipette, but after you apply the effect, my background is grainy and snowy. How can I get it clear?

  Here's another good is a little more to the point.

  Thank you
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