Get the height of the strings

Hello..

can someone tell me how to get the height of the chain

My String is "Blackberyy developer \n".

I got it..

Tags: BlackBerry Developers

Similar Questions

How to get the string (specified by row and column) of txt file with labview

Hello world

How to get the string (specified by row and column) of txt file with labview

THX

As far as I know, a text file has no column. Be more specific. Do you mean something like the 5th word on line 4, where the words are separated by a space, and lines are separated by a newline character? You can read from the spreadsheet String function and set the delimiter to a space. This will produce a 2D channels table. Then use the table to index and give the line number and column number.

Get the string invalid Base64 of image of toDataURL() for the first time in 10 of blackberry webworks

Hello

I need to get the Contact image converted to string Base64 using BB 10 Webworks (blackberry.pim.contacts) I get only the contact.photos [0] .smallFilePath which returns the path to the phonebook file.

Now, I want to get the image of this path and convert it to a Base64 string.

Here's the javascript code :

var img = document.createElement ('Image');
var canvas = document.createElement ('Canvas');

function getBase64Image (p) {}
img.setAttribute ("src", p);

Img.width = Canvas.Width;

Canvas.height = img.height;

CTX var = canvas.getContext ("2d");
ctx.drawImage (img, 0, 0);
Return canvas.toDataURL("image/jpg");

}

This means bad Base64 string of image for the first time. When I convert this string to the image it displays white screen. But returns a string in the Mithraeum and after conversion, display a correct image.

I use Blackberry Z10 (OS 10) for the test.

I think that the canvas is not drawing image properly for the first time.

I have searched and tried many things, but not got success. What will be the solution.

Thanks in advance.

My guess is that the image did not load the source completely still. Setting the src / image loading is an asynchronous event, which means that your code will continue to the next line regardless of whether the image has loaded yet or not.

After calling setAttribute instead of execute the code of the Web, you will probably need define an event on img for the load event listener. Once the image is loaded, you can then use the img with canvas variable to retrieve its data.

Note that getBase64 will return immediately, so you may need to develop some sort of mechanism to wait before returning, or the asynchronous approach and integrate reminders for the success trigger the next piece of code.

How can I get the string value displayed on a digital control defined for the relative time.

I have a digital potentiometer to display relative time in increments of 30 minutes.

I want to record the value displayed on the control string. Unfortunately, when I use the "convert to decimal string.vi" number, the resulting string is just the value in seconds.

How can I get the value as a string? (for example 01:30 for an hour and thirty minutes)

Thank you

Sean

Hi Sean.C!

M_Peeker's suggestion is a good thing. A stage that could clarify things is that you must set the % t <%H:%M> format string entry.

< br / > Kristen:.

How to get the string contents of itemByRange?

Hi all
Here's what I'm trying to achieve:
I selected a Word and you want to get the content of the 1^st word in the string (the name of a person).
In fact, the selected text is the source * a hyperlink and my goal is to get the name of the person designated by him.
[0] is the same as hyperlink.source.sourceText
Since I can not get the paragraph or line where the selected word is (or simply do not know how to do this), I'm trying to get the full story: from the 1^st character of the selected word and moving backward character by comparing its content. When it hits '\r', I know it's the beginning of the line. This way I can get the part of the line, I'm interested with the itemByRange() method, which returns "Array of Character."
```
Main();

function Main() {
    var doc = app.activeDocument;
    var sel = app.selection[0];

    GetName(sel);
}

function GetName(txt) {
    var lastCharacter = txt.characters[0];
    var character = txt.characters[0];
    var story = txt.parentStory;
    var index = lastCharacter.index;

    while (character.contents != "\r") {
        character = story.characters[index];
        index--;
    }

    // Array of Character itemByRange (from: varies, to: varies)
    // Returns the Characters within the specified range. 
    var arr = story.characters.itemByRange(character, lastCharacter);

    var str1 = arr.contents[0];
    var str2 = str1.match(/^\S+/);

    return str2;
}
```
My problem is that I can't get the content- str1 - by script. However, I can see in the data browser that it is there. If I click on str1, it appears:
If I type str1 in the Console, I also get:
I also tried to use:
arr.getElements)
arr.getElements () [0]
.silence arr.getElements () [0]
…
etc.
but that didn't work either.
I must be missing something very obvious, but I'm stuck. Can someone help me, please?
Kind regards
Kasyan

Hello

I did something wrong or

App.Selection [0]. Lines [0]. Words [0] .silence

is a 1 Word, you are looking for?

I hope that...

get the strings '? ' instead of strings stored in the db
Hello

I migrate an application from Weblogic 8 to 10 and Oracle 9i and 10g

I question my database by calling a procedure stored that paintings of buildings of type which is defined like this:

CREATE OR REPLACE
TYPE 'XXXXX '. "' STRING_ARRAYTYP ' IS THE TABLE OF 40;

I run a CallableStatement and get the berries via cs.getArray (stored in a java.sql.array).

In the field of data debug mode, I get a byte []: [-120, 1, -2, 0, 0, 2, 93,-110, 1, 3, 0, 8, 50, 48, 48, 56, 48, 51, 49, 51, 8, 50, 48, 48, 56, 48, 51, 49, 51, 8, 50, 48, 48, 56, 48, 51, 49, 51, 8, 50, 48, 48, 56, 48, 51, 49, 51, 8, 50] 48-48, 56, 48, 51, 49, 51, 8, 50, 48, 48, 56, 48, 51, 49, 51,...]

When I convert it to a string in debug mode, I give myself: "[special characters] 200505252005052520050525200505252005052" who are my data.

but when I get the result set and I call rs.getString (2), I get a '? ' string (after rs.next () call of course)

The application worked before we migrate.

Any idea?
'?' is the replacement for a character unknown character (in an unknown character) so I suggest you add orai18n.jar in your classpath. Is the jar of Oracle that supports all charset conversions. The JDBC jar does support a few games of characters.

Get the string inside parentheses - to help scan from string

I have a very basic question here. I would like to extract a part of a chain that is inside the brackets (example: I work with [National Instruments]). In the string, I want to extract only of National Instruments, I know logical extraction in finding media and their extraction. But I am interested in the use of analysis of the chain or possibly any other primitive with a single blow. Please suggest if someone has an idea, I'm not use to the format specifiers. I got this link for reference, but I'm not able to find a solution.

get the string between {}

IN the string I want to take all values between {and}.
This is the string.
({Location1} # tie # 12-< and > {Item1} # top # (8) < and > {Item2} # # (40) < and > {DOCDATE} "# # 10 January 2015" AND 10 January 2017 ' < and > {amount} # tie # 1).
Vinodh

Here's a way to do what you asked (which may or may not be what you need), using REGEXP_REPLACE to remove everything that is not between two brands of {}:

with t as

(select ' ({Location1} # equal (12) < and=""> {Item1} # more than # (8) < and=""> {Item2} # # (40) < and=""> {DOCDATE} # between # "January 10, 2015" AND 'January 10, 2017' < and=""> {amount} # equal # 1)' txt)

the double)

-end of test data-

Select regexp_replace (regexp_replace (regexp_replace(txt,'}[^}]*{','',1,0),'^ [^ {}] * {', ", 1,0}) {,'}. * $',", 1.0)

t

Get the string variable name in PL/SQL
Hello
Strange question. Is there a way to have access to the object of a decision of the variable IN the name in a procedure?

for example.
```
procedure (var1    IN VARCHAR2(6),
                var2    IN VARCHAR2(6),
                var3    IN VARCHAR2(6))

IS....
```
You run this procedure and pass in parameters to:

var1 = > "abcdef"
var2 = > "defghi",.
var3 = > 'ghikjl ';

In the code, I want to access the number in the string of the + variable name: var1+.

In a naïve sense,.
```
num_of_in_var := substr(var1, 4,1) 
```
would I hoped to achieve, but

var1 is set to 'abcdef' if so,
```
num_of_in_var := substr(var1, 4,1) 
```
would return was '.

Any thoughts?

Thank you

Published by: chris001 on November 20, 2012 13:16
Hi Chris,

You can find the details of the $user_arguments data dictionary view settings.
```
select argument_name from user_arguments where object_name = 'PROCEDURE_NAME';
```

Splitting of a column and get the strings as different columns
I had a table with lets say 4 columns.

age sex nationality name

ABC - xyz 20 M IND
def - uvw F 30, US

Now I want 5 columns with 1 name, first name as 2nd, as 3rd age sex nationality as 4th, 5th.

nationality of first name last name age sex

ABC xyz 20 M IND
def uvw F 30, US

How to get results like that since the above mentioned table game.

TIA.

Published by: 986155 on March 12, 2013 05:35

Published by: 986155 on March 12, 2013 05:35
Use SUBSTR/INSTR:
```
with t as (
           select 'abc xyz' name,20 age,'M' gender,'IND' nationality from dual union all
           select 'def uvw',30,'F','US' from dual
          )
select  substr(name,1,instr(name,' ') - 1) name_part1,
        substr(name,instr(name,' ') + 1) name_part2,
        age,
        gender,
        nationality
  from  t
/

NAME_PA NAME_PA        AGE G NAT
------- ------- ---------- - ---
abc     xyz             20 M IND
def     uvw             30 F US

SQL> 
```
SY.

Get the string between two operators <>
Hello

I have a string that looks like this "text here < emplid > more text here '." Now, I want to choose the data between the < and >. These data is still a number. I tried the following query, but it does not give good results.
```
select SUBSTRING(NAME,CHARINDEX('<',NAME),CHARINDEX('>',[NAME])) as col01
from databasename
```
This will result in the number, including the < and > (which I'm not) and some characters more. I also need the rest of the chain to be available to insert in another field.

Published by: wijnandgritter on 23 January 2012 0:03
Hello

You should be able to
```
update tablename
set field = regexp_replace(fieldname,'^.*<(\d+)>.*$','\1 this is an employee')
where fieldname = '123'
```
or something similar...

HtH
Johan

How to get the part of string before and after a character

Hi all
How to get the string before and after the comma character)
Ex: The string contains the value John Kennedy
I need the output as first stirng - John
Second stirng - Kennedy
Create table names (fullname varchar2 (20));
insert into values of names ("John, Kennedy");
insert into values of names ("papa ibra, Shan");
insert into values of names ('Don Bosco'),
Select * from names;
Expected results
FullName firstname lastname
John, Kennedy John Kennedy
Nicolas, Nicolas Shan Shan
Don Bosco Don Bosco
Please let me know how to proceed
Thank you

Hello

This proves what I said before, on 0 and several commas commas.

If we add these 3 rows to the sample data you posted:

insert into names (fullname) values ("tou").

insert into names (fullname) values (' David, Lloyd, George ");

insert into names (fullname) values ('J, R, R, Tolkien");

then the query I posted earlier produced these results:

FULLNAME FIRSTNAME LASTNAME

-------------------- -------------------- --------------------

John, Kennedy John Kennedy

Nicolas, Nicolas Shan Shan

Don Bosco Don Bosco

TOU tou

David Lloyd, George David Lloyd, George

J, R, R, Tolkien J R, R, Tolkien

If you prefer to get these results:

FULLNAME FIRSTNAME LASTNAME

-------------------- -------------------- --------------------

John, Kennedy John Kennedy

Nicolas, Nicolas Shan Shan

Don Bosco Don Bosco

TOU tou

David Lloyd, George David, Lloyd George

J, R, R, J, R, R Tolkien Tolkien

then you just change line 1:

WITH got_commapos AS

(

SELECT FullName

, INSTR (fullname, ','-1) AS commapos-* CHANGED *.

Names

)

SELECT FullName

, SUBSTR (fullname, commapos 1, -1) AS a first name

SUBSTR (fullname, commapos + 1) in the FORM name

OF got_commapos

;

Cannot get the "< FEFF >" string in the selected text [indesign CS6]

Hello world!
I can't get the string to the selected text. The selected text contains several xml tags.
In adobe indesign cc version of 2014, the selected text is bring the string «< FEFF >» tags
In indesign adobe cs6 version cannot get the string "< FEFF >. they do ""-empty space.
Are the above-selected text contains several xml tags.
but I get content using script code can't get the string.
the script gives the result, xml tags are converted to "". "" I expect "< FEFF >.
I expect the output is: "< FEFF > Applescript < FEFF > < FEFF > selected text < FEFF > < FEFF > < FEFF >."
Please help me...
Thank you
John Peter.

the script gives the result, xml tags are converted to "". "" I expect to ''.

The xml tags are not converted to "" but "\uFEFF" (zero-width space non-bec), it is the character used to represent the tags in a text frame. Looks like the apple script converts a hexadecimal representation unicode values.

Get the value of an enum as a Variant text

I want to use a group of settings with which sent to another application via DDE link. The label of each control of the cluster is sent with the value as text. Using an array of references to the command I get the Label.Text property for each control in the cluster. The value is presented as a Variant, so I have to convert the data into a string according to the type of data. I got this connected to a business structure that could convert to a string data type and the data type of the ClassName property. It works very well for the (trivial) chain, Digital and the ring but I cannot work out how to get the string value of an Enum. I would have thought that it would be possible that the string value is a part of the data as shown but the picture indicator of variants.

I would appreciate help with this.

The attached vi show what I've got so far. The desired output array is a dummy control to show what I want to get this VI

Ken

Hi Ken,

See the vi changed please. If that's not enough, please also see the «OpenG» vi´s

Mike

How let labview to check the string is in Scientific Notation.

Hey all,.

I want to labview to convert a worksheet string in a table. It's easy using the tool 'chain of worksheet to the table '. The only problem I have is that I get the string from a RS232 device and the critical moment arrives.

Example:

If I read the data from the buffer it gives me:

1.50337800E + 00 + 1.70316300E + 00 for both channels, it is converted and accepted

If there is a slight delay, I get:

+ 1.50337800E + 00 + 1.70316

It is also accepted because + 1.70316 is also recognized as a number.

How can program labview to check each number he reads is according to Scientific Notation?

Thank you

This regex seems to work for me, for all cases, I've tried:

[+/-]\d+\.\d+[Ee][+/-]\d+

Note that it is very restrictive and only follows the shape of ±n.nnnE±mm

How to convert numbers to the string with an optimal number of numbers?

Hello.

I'm doing something that seems just, and I wonder how much trouble I have with this. I'm sure there is a way to get LabVIEW for this.

I have a table of numbers (double), and I use the 'Worksheet picture String' function to generate a string that I can write to a file.

The problem I have is I want to make the chain to omit useless zeros after the decimal point, but I don't want to limit the accuracy of the numbers that requires it.

For example, if my data is as follows:

0.02

0.4476

-0.0244570001

I would like for the string I can be exactly like what I wrote above. However, depeding on the format string that I use, that's what I get:

format string: %.10f

0.0200000000

0.4476000000

-0.0244570001

format string: %f (it seems that by default 6 figures)

0.020000

0.447600

-0.024457

format string: %.4f

0,0200

0.4476

-0.0244<= all="" trailing="" digits="" for="" this="" number="" have="" been="">

Anyone know what the format string should be to get the string I want to (what is this

0.02

0.4476

-0.0244570001

Thanks in advance,

Alejandro

Hello Alejandro:

Try %#f

Get the height of the strings

Similar Questions

Maybe you are looking for