Get the participant of the current call
I want to get the participant, specifically the name from an incoming call (if the number is stored in the local address book).
The only way I see to get the name is to look at the call log. It seems that the current call is added only after he's finished well.
It seems not possible to search for a number using BlackberryContactList, because need names for the entry.
Any ideas?
Probably not the cleanest because I didn't spend too much time on this, but I think that's what you're looking for:
Place in the earpiece of your phone callConnected method
//incomingcall: static boolean variable set to true during a callIncoming event if(incomingcall) { PhoneCall pc = Phone.getActiveCall(); String number = pc.getDisplayPhoneNumber(); //getDisplayPhoneNumber() method returns a label as well as the number //if caller is a contact, these lines will parse it. number = number.substring(number.indexOf(' ')); number = number.trim(); try{ BlackBerryContactList bbcl = (BlackBerryContactList)PIM.getInstance().openPIMList(PIM.CONTACT_LIST,PIM.READ_ONLY); Enumeration enumerate = bbcl.items(); //iterate through contacts while(enumerate.hasMoreElements()) { Contact c = (Contact)enumerate.nextElement(); PIMList pimlist = c.getPIMList(); int[] intarray = c.getFields(); for(int x = 0; x < intarray.length; x++) { if (pimlist.getFieldDataType(intarray[x]) == PIMItem.STRING) { if(intarray[x] == c.TEL) { for(int y=0; y < c.countValues(Contact.TEL); y++) { //see if opened contact matches the number if(c.getString(Contact.TEL, y).equals(number)) { //Caller's name stored in namearray String[] namearray = c.getStringArray(Contact.NAME,0); } } } } } } } catch(PIMException e) {} incomingcall = false;
EDIT: Keep in mind that this is probably not very effective, since it will iterate through EACH issue of EACH contact.
Another thing to note is that some fields (work2, home2) were not supported and are not accessible until 4.5 so if the number is stored in these areas, you cannot get the name of the contact with this method.
Tags: BlackBerry Developers
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