Getting the Unix path in OFA

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• How to get the default path of the data of a table space file

  I used below the sql statement to create a table space:

  CREATE A TABLESPACE DATAFILE AAA BBB SIZE 10 M AUTOEXTEND OFF...

  Notice, I do not give a full path instead of a file name, and then ask questions relevant to tables

  get the full path of the data file, assume that it's path below:

  d:\oracle\...\BBB

  So I don't think that there is a default path that oracle can use it to create the data file. My question

  is how to get this default path before creating a table space.

  Thank you very much.

  Hello

  I did similar simulations for you, then it could be seen easily:

  SQL > Show parameter db_create_file_dest

  VALUE OF TYPE NAME

  ------------------------------------ ----------- ------------------------------

  db_create_file_dest chain

  SQL > SELECT NAME, VALUE OF V$ PARAMETER

  2 where lower (name) = "db_create_file_dest;

  NAME

  --------------------------------------------------------------------------------

  VALUE

  --------------------------------------------------------------------------------

  db_create_file_dest

  It has the value NULL. Then where my datafile is going?

  SQL > create tablespace TEST datafile 'test01.dbf' size 10 M;

  Created tablespace.

  SQL > select file_name

  2 of dba_data_files

  3 where nom_tablespace = 'TEST ';

  FILE_NAME

  --------------------------------------------------------------------------------

  /U01/app/Oracle/product/12.1.0/Db_1/DBS/Test01.dbf

  When you check the alert logs, it will not show you the location of the data file. It will tell you what exactly you ran.

  ..

  ..

  Completed: drop tablespace test whose content and data files

  create tablespace datafile 'test01.dbf' size 10 M TEST

  Completed: create tablespace TEST datafile 'test01.dbf' size 10 M

  ..

  ..

  You can not SQL user * more? Well, I would say that, when you run the CREATE TABLESPACE command, is where you run the command:

  SQL > select file_name

  2 of dba_data_files

  3 where nom_tablespace = 'TEST ';

  FILE_NAME

  --------------------------------------------------------------------------------

  /U01/app/Oracle/product/12.1.0/Db_1/DBS/Test01.dbf

  
  

  So, you should get the location of your data file. Alternatively, you can run the query in the parameter $ v so that you know your default data file location.

  I hope this helps.

  Thank you.

  Kind regards

  Gaetan

• How to get the full path of the af:inputFile component

  Hello

  I use af:inputFile component in my application to download an Excel file and get the data from the file.

  From the component, I could get only the file name.and not the full path to the file.

  So, I am unable to access the file to extract the data from it.

  Is it possible to get the full path of the file to access to retrieve the data from it?

  Data or data streams is only valid in the same request. Once you navigate, the stream is closed and you get nothing if you try to read it. You need to download the file on the first train in the temporary location (Tip: search ;) File.createTempFile ("temp-file-name", ".tmp") and put the file name and the path to your beans.)

  Timo

• How to get the absolute path to a file in photoshop extended?

  Hello

  I try to send a file via an entry inside an extension of Photoshop. But how can I get the absolute path to this file inside the computer?

  Thanks in advance

  I don't know what you mean by sending a file. Do you want to open a file in PS or do I have to declare the path for support for the extension file? With javascript, you must define a variable. In Win it should look like:

  var file = new File('/c/images/myfile.psd');
  

  or

  var myScript = new File(app.path + '/Presets/Scripts/myJavascript.jsx');
  

• Forms 6i: how to get the UNC path? SOLVED

  Anyone know how to get the UNC path of in Oracle Forms 6i
  
  For example, if the user enters an output file:
  j:\Data.txt
  
  How I translated that UNC path:
  \\serv-123\cfs\data.txt
  
  Basically, I need to pass the UNC path to a regular DB procedure that later would be to copy an output file at the location specified by the user. "J:" being a network drive mapped, the database server would not be able to copy the file.
  
  Thank you
  Jim

  It's perhaps easier: read the registry using WIN_API_ENVIRONMENT. READ_REGISTRY. The key is HKEY_CURRENT_USER\NETWORK\\RemotePath.

• How to get the full path of the image open in a filter plugin file?

  Hello

  How to get the full path of the current file, including the directory, the file name with the extension. I need information to download the file on a webserver for a plugin. I found an example that can get the name of the document (title property) but without extension and directory. How can they?

  James

  There is no way to get the full path of the active document in a plug-in filter. A plugin automation has access to this information and the file format plug-ins.

• How to get the Page Path in Webcenter at run time

  Hi all

  I want to get the path to the page of the current page which is consulted by the user at run time (rather, in the method of TF activity)... This path of the page will get the def page and do some operations above.

  We tried to get it from the context of Navigation, but node.path returns null.

  Guidance on how I can get the computer?

  Kind regards

  Siddharth

  SID,

  You can use the EL #{pageDocBean.pagePath} for the path of the page.

  K

• How to get the full path without a docs «~»

  My file is here:

  'C:\Users\first.last\Desktop\PS_Tester\SRC\Work.psd '.

  Note that doc is on the desktop (Windows).

  Copy the following code:

  var Vc_v7 = activeDocument.fullName;

  Alert (myTest);

  Returns:

  "~ / Desktop/PS_Tester/SRC/Work.psd".

  I would like to and wait until he returns the real path with the 'C:\Users\first.last' and not the «~»

  When I pass the ~ path to another app folly occurs.

  Or y at - it a way to get that represents the tilde?

  Just a slight correction, for the alert. using a forward slash is not now with what you're going to get back, that will be all the backslashes normal. You need a double backslash:

  alert(MyTest+"\\"+app.activeDocument.name);
  

• Get the full path of the file.

  Hi all!
  I work with ODI 11.1.1.3 and everything works well in my interfaces. Now, I need to add a new step on the package.
  My interface uses a flat file (.txt) as the source and load its data to an Oracle DB.
  The new step that I have to add should delete the source at the end of the process.
  I don't want to hard-code the full path of the file in the delete command, so I wanted to do the sam using the odiRef functions, but I did not work.
  I used the getObjectName function, but it does not work.
  
  Anyone has an idea on how to get the full name of the file?
  
  Thanks in advance!

  Hello

  Sorry for typo's fault.

  The command has been

  OdiFileDelete ""-FILE = < %="odiRef.getSchemaName" (""="" model_code_here"",="" ""d"")%=""> /YOUR_FILE_HERE ""-RECURSE = NO "" "-CASESENS = NO" "-NOFILE_ERROR = YES.

  Sorry for the distraction :(

• How can I get the current path of LUN?

  I want to know the active path for all my lun. How can I get this value?

  Tios thanks!

  Best regards

  Xavier

  VCP4 and professional VCP3 certified VMware.

  -

  ---

  If upon that esta o any other campaign respuesta ha sido utility, votalas. Gracias.

  If you find this or any other information useful or appropriate, please consider giving points. Thank you.

  You could do something like that

  $report = @()
  Get-VMHost  | %{
       $esx = $_
       $_ | Get-ScsiLun | %{
            $lun = $_
            $_ | Get-ScsiLunPath | %{
                 $row = "" | Select HostName, LUNname, Path, Active
                 $row.HostName = $esx.Name
                 $row.LUNname = $lun.CanonicalName
                 $row.Path = $_.Name
                 $row.Active = $_.State
                 $report += $row
            }
       }
  }
  $report
  

  ____________

  Blog: LucD notes

  Twitter: lucd22

• How to get the full path using HTP. PRINT ("&lt;" input type = "file")...

  Hello everyone,
  
  I'm working on downloading the page file to another using the package HTP, but whenever I submit the form, it takes only the file name without the full path.
  for example:
  If I sent 'c:\dir\a.txt', the other page receives the parameter file as 'a.txt ".
  
  
  the code is here
  
  
  Download of the PROCEDURE (appno in varchar2, wsct in varchar2) AS
  
  
  
  l_real_name VARCHAR2 (1000);
  
  
  
  
  BEGIN
  
  
  
  
  HTP.htmlopen;
  HTP.headopen;
  HTP.title ("Test Upload'");
  HTP.headclose;
  HTP.bodyopen;
  HTP.header (1, 'Test Upload');
  HTP.print ('< form action = "https://ssltrng.uaeu.ac.ae/trng/document_api.upload1" method = "get" >');
  HTP.print (' download file: < input type = "file" name = "file" >)
  ');
  HTP.print ('< input type = "submit" value = "Upload" >');
  HTP.print ('< activated >');
  HTP.bodyclose;
  HTP.htmlclose;
  
  
  Download END;
  
  the other page see so
  
  file is "water lilies.jpg".
  
  Thank you
  
  Published by: dtabed on March 30, 2011 01:02

  For Internet Explorer 8 and later versions, you must set a security setting to get the full qualified path: see http://msdn.microsoft.com/en-us/library/ms535128.aspx.

  For other browsers, there could be a similar setting.

• Get the name/path of current .cfm file...

  I'll make a script of "tracking" for a Web site.  My idea is to add a < CFINCLUDE > to each server the .cfm file (at the very end, it would be easier to remove when im done), and have the included script add a record to a database containing the path/file name of the .cfm file.  for example, index.cfm will include trackscript.cfm, and after the treatment the index.cfm a database will be a record in this container path/name of the file to index.cfm.

  I'm new to coldfusion, but I think that I got it, except on the way to get the name of the file that will be added to the database.  is there some kind of function or variable available that will give me the name of the file running .cfm?

  GetCurrentTemplatePath() will give you the absolute path of the current CFM file.
  

• How to get the full path of the appellant VI?

  LabVIEW 8.x broken my code.  I used to be able to refer to a VI by name, and it now wants the full path.  Unfortunately, "call chain.vi" returns only the name.  Does anyone know how to refer to the vi (its full path) that calls a particular sub - VI, of the Subvi?  It was the second element of the array string of "call chain.vi".

  I use LV8.6.

  Thank you

  Jeremy

  Hi Jeremy,.

  I'm not sure 8.6, but in 8.5.1 you can always use a string containing the name of VI to open a reference of a VI in memory.

  Does not allow a constant way with just the name of VI well.

  

  Daniel

• Get the multi path-

  I found this code. Is there a way I can get the results into an Excel instead of just the screen?

  Get-VMHost | %{$_.Name; $_ | Get-ScsiLun | Select CanonicalName, MultiPathPolicy}

  And even better, since I will connect to an instance of vCenter4, I really need information of two of our clusters.  Cluster names are ProductionCluster8 and ProductionCluster9

  Thank you!

  I fixed that in the script in my first post. Now he has to work and only to retrieve information about the two groups.

• Is there a way to get the full path to a folder on the network drive without a format "drive letter":?:

  When I need to send the path to a network drive to a colleague, I always type it in manually.   Is it possible that I can right click on the drive or see the path to the folder in the address bar, as it is in the format "\\server\share\folder' rather than 'Y:\. » ?

  Thank you

  Ben

  Hi Ben,

  The question you posted would be better suited for COMPUTING public Pro on TechNet. I would recommend posting your query in the TechNet Forums to get help:

  Windows 7 networking TechNet Forums