How to get the full path of the af:inputFile component

Similar Questions

• How to get the full path of the image open in a filter plugin file?

  Hello

  How to get the full path of the current file, including the directory, the file name with the extension. I need information to download the file on a webserver for a plugin. I found an example that can get the name of the document (title property) but without extension and directory. How can they?

  James

  There is no way to get the full path of the active document in a plug-in filter. A plugin automation has access to this information and the file format plug-ins.

• How to get the default path of the data of a table space file

  I used below the sql statement to create a table space:

  CREATE A TABLESPACE DATAFILE AAA BBB SIZE 10 M AUTOEXTEND OFF...

  Notice, I do not give a full path instead of a file name, and then ask questions relevant to tables

  get the full path of the data file, assume that it's path below:

  d:\oracle\...\BBB

  So I don't think that there is a default path that oracle can use it to create the data file. My question

  is how to get this default path before creating a table space.

  Thank you very much.

  Hello

  I did similar simulations for you, then it could be seen easily:

  SQL > Show parameter db_create_file_dest

  VALUE OF TYPE NAME

  ------------------------------------ ----------- ------------------------------

  db_create_file_dest chain

  SQL > SELECT NAME, VALUE OF V$ PARAMETER

  2 where lower (name) = "db_create_file_dest;

  NAME

  --------------------------------------------------------------------------------

  VALUE

  --------------------------------------------------------------------------------

  db_create_file_dest

  It has the value NULL. Then where my datafile is going?

  SQL > create tablespace TEST datafile 'test01.dbf' size 10 M;

  Created tablespace.

  SQL > select file_name

  2 of dba_data_files

  3 where nom_tablespace = 'TEST ';

  FILE_NAME

  --------------------------------------------------------------------------------

  /U01/app/Oracle/product/12.1.0/Db_1/DBS/Test01.dbf

  When you check the alert logs, it will not show you the location of the data file. It will tell you what exactly you ran.

  ..

  ..

  Completed: drop tablespace test whose content and data files

  create tablespace datafile 'test01.dbf' size 10 M TEST

  Completed: create tablespace TEST datafile 'test01.dbf' size 10 M

  ..

  ..

  You can not SQL user * more? Well, I would say that, when you run the CREATE TABLESPACE command, is where you run the command:

  SQL > select file_name

  2 of dba_data_files

  3 where nom_tablespace = 'TEST ';

  FILE_NAME

  --------------------------------------------------------------------------------

  /U01/app/Oracle/product/12.1.0/Db_1/DBS/Test01.dbf

  
  

  So, you should get the location of your data file. Alternatively, you can run the query in the parameter $ v so that you know your default data file location.

  I hope this helps.

  Thank you.

  Kind regards

  Gaetan

• ADF: How to get the path of the file when you use component InputFile

  Hi all

  I use jdeveloper 11.1.1.5.0 version.

  in my case, I created program Mail Client mail where I used the ADF InputFile component for attach file mail.

  but problem is this return path only component InputFile from the file (only the filename get)

  and in my mailer class DataSource uses the full path name of file access.

  UploadedFile uploadfile=(UploadedFile) actionEvent.getNewValue();
       String fname= uploadfile.getFilename();//this line only get file name.
  

  so, how can I get the full path using adf InputFile component or any other way to respond to my request.

  Thank you

  Manish

  Try this (I did not, so I can't promise it will work):

  MimeBodyPart messageBodyPart = new MimeBodyPart(uploadFile.getInputStream());
  messageBodyPart .setFileName(uploadFile.getFilename());
  messageBodyPart.setContent(multipart);
  

  It does use the inputStream from the downloaded file as the content of the file attached. You shouldn't need a full path, since you're not going to use a file object to provide the content.  And it shouldn't be necessary to define the DataHandler.

  But if that doesn't work, I go back to my first answer.  Use uploadFile.getInputStream () to get the inputStream from the downloaded file, create an outputStream to write the file to the file system of the application server.  Then you have a file with a known path that you can subscribe to the DataHandler.  You can delete the file when you're done with him.

• How to get the Subvi (the virtual path is in .exe) reference in Run Time System

  Hello world

  The problem is how to get the reference of the Sub - VI in run time system, when the Subvi is in .exe after construction.

  More details:

  Top of page vi called the Subvi dynamically, so that the Subvi is always included, and the source object is the application.exe.

  After the above configuration, the Sub - VI will be the application.exe. For example, the path of Subvi est...\application.exe\SubVI.vi

  So, how to get the reference of the Subvi in Run Time System?

  I can't do it when you use 'open reference VI' with le...\application.exe\SubVI.vi path in the run time system.

  In fact, I can create a file to include the Subvi, rather than build the Subvi in application.exe, then I can get the convenintly reference. But this isn't my favourate average.

  Thank you

  chenyin

  That is the problem. Call a Subvi dynamic means users could change, but it is also very attractive.

  The dynamic call should be used in a user control, but some parade can avoid problems.

  It depends on why you use dynamic calls...-online 2 main ways:

  -Dynamic call are used to maintain a scalable framework for the code without acting on the executable file-online a single VI distribution managed by the administrator/developer

  -Dynamic call are used to provide a collection of "external" characteristic that could be enriched by the administrator/developer. For example, you provide your customers a set of selectable custom signal filters in the executable.

  In 2 cases, you are only able to assess the skills of the users to know if there is a risk of damage, if there is a change.

  So to stay only master a parade might be to provide dynamic VI without a schema, but with the problem of maintenance, since no in-place editing and more attention to manage distribution.

  Another way is to hide the actual distribution to user-online call dynamic VI but it without name as *.vi but others (a repellent name as system of OS name ) or simply without extension in order to attract not user... but that's debatable...

  Another more difficult but more secure method is to create a consistency check before your routine (version, user, modified date,...)

• How to get the path of the vmdk to a VM stop file?

  Hi guys,.

  How to get the path of the vmdk to a VM stop file in ESX Server via the VIX API?

  I try to get it via the VixVM_ReadVariable() function. but it seems that this function requires that the virtual machine is power on.

  I don't want to go the virtual machine started, I just want to know if I can get the path of the vmdk file when a virtual machine is power off.

  Thanks in advance.

  Sorry, I don't have any samples.

  However, if you look at the layoutEx of the managed object VirtualMachine field, you will see that the VirtualMachineFileLayoutEx data object has a field "files" which should contain the paths of affected files.

  I hope that it should be able to help get started.

• Forms 6i: how to get the UNC path? SOLVED

  Anyone know how to get the UNC path of in Oracle Forms 6i
  
  For example, if the user enters an output file:
  j:\Data.txt
  
  How I translated that UNC path:
  \\serv-123\cfs\data.txt
  
  Basically, I need to pass the UNC path to a regular DB procedure that later would be to copy an output file at the location specified by the user. "J:" being a network drive mapped, the database server would not be able to copy the file.
  
  Thank you
  Jim

  It's perhaps easier: read the registry using WIN_API_ENVIRONMENT. READ_REGISTRY. The key is HKEY_CURRENT_USER\NETWORK\\RemotePath.

• How to get the path of the directory component in custom filter

  How to get the path of the directory component in a custom filter?

  final String absoluteComponentPath = CompInstallUtils.computeAbsoluteComponentLocation( "yourComponentName" );
  

• How to get the path or the file name of getChild

  Hey everyone, good day!

  Is - anyone here know how to get the path or the file name of an object inserted into the scene?

  Here's the scenario:

  I am developing a flash application, which allows the user to insert background to the scene to help her browse and select using the FileReference in flash. I inserted some image the user successfully choose, but what I'm trying to make, is that if the user clicks on save, the background image it has chosen will be copied to a different folder on the web (file upload). So I need to know the path and the file name of the background image.

  Here is my AS3 code:

  for (var i: uint = 0; i < container.numChildren; i ++) {}
  trace ('\t|\t' + i +'. \t name:' + container.getChildAt (i) .name + "\t type:" + typeof (container.getChildAt (i)) + "\t" + container.getChildAt (i));
  }

  ------------------------------------------------------------------------------------------ -----

  Here is the message trace of the code above:

  |     0 name: instance120 type: object [object Loader]

  ------------------------------------------------------------------------------------------ --------

  Any help here? I thank in advance.

  The Loader class has a property contentLoaderInfo (an instance of the class LoaderInfo) that contains information, that you are probably after, including the url of the content that has been loaded...

  Loader.contentLoaderInfo.url

• How to get the path page dynamically

  Hello.
  
  How to get the path to the current page in the processRequest of the controller method? e.g. "/ oracle/apps/ak/sandbox sand/webui/SamplePG.
  
  -wheleph

  pageContext.getParameter ("page");

  This line will give you exactly what you want...
  Thank you
  Annapurneswar

• Re: How to get the Tempo to work properly?

  Hello

  I have problems with the service of Tempo.

  I don't get updates via this application (all the settings of this application are accurate, i.e. "full control"). I know this because there are updates available online to my laptop via the pilot site of toshiba.

  When I installed first Tempo, updates for about a month, I received, and then all of a sudden, no update came through. My firewall is blocking either of this application.

  I tried to reinstall the application, but no change in the situation.

  Does anyone know if ALL updates are available via the website of driver toshiba out tempo? Because, in the month that this service worked, I got an update of the bios, but I recently saw a bios update online and Tempo has not always reports that it is available.

  Any ideas on how to get the Tempo to work properly?

  Thank you.

  I saw in your other thread you have installed SP1 on your Vista laptop.
  There may be some compatibility problems between SP1 and Tempo

  And Yes, as far as I know Tempo bring all available updates!

• How to get the parameter values of a step type custom when I create file and adding a type of step seq

  I use lv 8.5 and teststand 4.0.

  I did a step type custom and recorded at the MyTypes.ini in pallets of type.

  I specified a default module by opening the properties of the custom step of *.ini type window, then I put some values of the parameters.

  T1) when I open teststand and I add the custom step type manaully in seq file, the labview module parameter values are represented.

  But, if to use file (create and add support prototype stage), the labview module parameter values has the default value.

  Using joint file, how to get the setting custom step type values I put in *.ini?

  Q2) each type of step are automatically by name through the use of LoadTypePaletteFilesEx. When I open teststand and I add the custom step type manaully in seq file, the module is loaded automatically. Inside the attachment, I use a prototype of charge and a fixed path where the module labview is to load the labview module.

  Can I load module automatically without using a prototype of charge or how can I get a dynamic path of type step?

  I solved Q1 for myself by using the mapping tab of the parameter within the configuration to the default module window.

  Everyone knows Q2?

  Thank you.

• I'm new to CC.  I discovered that I had to download first CS6 inorder to get it. (May not yet know how to get the title templates, etc. cannot understand instructions; but I spread) I see that it still says trial.  How can I get the

  I'm new to CC.  I discovered that I had to download first CS6 in@order to get it. (May not yet know how to get the title templates, etc. cannot understand instructions; but I spread) I see that it still says trial.  How can I get the full thing.  I am a Subscriber complete cc

  I don't know what you've done, but here are the instructions to install the PProCS6 and the callback with a cloud account

  Yet the instructions http://helpx.adobe.com/encore/kb/encore-cs6-installed-cc.html if you have a subscription

  - and the difference in the Cloud application manager 2015 https://forums.adobe.com/thread/1906752

  Still will not run as a trial, it is enabled when you install and activate PProCS6

• How to convert ManagedObjectReference specified object type (for example, Indexderecherche) and how to get the HostSystem object?

  Hello

  I met two problems when you use the SDK for JAVA,: (, so I come back here for help.)

  1. I use the method getSearchIndex() to get the object of the ServiceContent Indexderecherche , 'Indexderecherche' of ServiceContent property is set as 'com.vmware.vim25.ManagedObjectReference' and 'ManagedObjectReference' is not a subclass named "Indexderecherche", so how do I convert it to class "Indexderecherche" but I can't use the methods defined in the class "Indexderecherche".

  2. I want to retrieve information about my server ESX, and "Guide to programming Web Services SDK vShpere" tells me to do this work by accessing data objects defined for the HostSystem. But I don't know how to get the object "HostSystem.

  Can someone help me? Thanks in advance.

  Its part java java-sdk sample.

  path:

  vijava\src\com\vmware\sample\vi

  classpath:

  com.vmware.sample.vi.ViDiscovery

• How to get the changes during the process of replicat ABENDED

  Hello
  I'm working on Oracle GG two-way DML replication. I m stuck in one place.
  
  My target replicat process has been ADDED due to the error:-ORA-01403: no data found. I restarted my process replicat again by runing the below command
  
  GGSCI (db1) 30 > replicat rep2 alter now
  GGSCI (db1) 30 > start replicat rep2
  
  After the reboot, the process to replicate that I do not see the changes on the target server which I had applied on the source for replicat target server was ABENED.
  My doubt is.
  
  1. is my command is correct for start replicat ABENDEND process?
  2. how to get the changes to the target server that applied to source for replication targer ABNDED?
  3. how to avoid the process of ABENDED replicat on the production server?
  4. how to follow the process in the production server ADDED?
  
  Please HELP:)
  
  Published by: Sabrina on August 29, 2012 03:32

  info from the GGSCI prompt will tell you the current file path and RBA.

  With this information, you can go in logdump and follow these steps:

  open 
  detail data on
  pos 
  n (next)
  

  It will appear the RBA # the next transaction. Then you return to the GGSCI prompt and do:

  ALTER EXTRBA
  BEGINNING

  With that he will take this next RBA from until you reach the following 1403

  Greetings,
  NACEUR

  PD: in the case where your question is answered please remember to mark your answers questions in order to clean up the forum and help others when they are looking for solutions to their problems.

• How to get the content during execution classpath

  In production mode, I can't stop the weblogic server. In the command line window, shows that recent information. How to get the content of the classpath of weblogic domain?

  You can view the log file of the server under the location */servers//log / *. The log file contains the details about the CLASSPATH setting.

  A typical classpath is represented by the java.class.path attribute in the log file.

  See you soon,.
  Julien
  http://WebLogic-wonders.com