Group using the order of rows

Hi all

one of my friends asked me a question and I think it's possible but how?

without using PLSQL, can it be done by sql?

We have a table and its data like this:
X   Y
----------
A   S
B   S
C   S
D   T
E   T
F   S
G   S
H   R
I want to order these data be field X (which is already happening in this example) and aggregate that data by field Y but if in the order of the value of the field changes, it means that it will be a new group.

I mean, for this example, A, B and C Archives is a group, D, and E are another group and E and F are one group to another. as you see ABC records and EF has same value Y (which is S) but I would like to assume they are different groups because of the order.

If I give a number of groups, it looks like this:
X   Y
----------
A   S      1
B   S      1
C   S      1
D   T      2
E   T      2
F   S      3
G   S      3
H   R      4
I have 4 different group here. any idea?

PS: we do not want just sql, plsql

If you don't care about the group being sequential numbers:

with t as (
           select 'A' x,'S' y from dual union all
           select 'B','S' from dual union all
           select 'C','S' from dual union all
           select 'D','T' from dual union all
           select 'E','T' from dual union all
           select 'F','S' from dual union all
           select 'G','S' from dual union all
           select 'H','R' from dual
          )
select  x,
        y,
        row_number() over(order by x) - row_number() over(partition by y order by x) rn
  from  t
  order by x
/

X Y         RN
- - ----------
A S          0
B S          0
C S          0
D T          3
E T          3
F S          2
G S          2
H R          7

8 rows selected.

SQL> 

SY.

Tags: Database

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    COMMIT;
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    

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             WHERE Ci.Guest_Id = Cdr.Guest_Id) v,
           Guest_Address Ca
     WHERE v.Guest_Id = Ca.Guest_Id;
    and explain the Plan shows
    1     Plan hash value: 3785964411
    2      
    3     ---------------------------------------------------------------------------------------------------------
    4     | Id  | Operation                     | Name                    | Rows  | Bytes | Cost (%CPU)| Time     |
    5     ---------------------------------------------------------------------------------------------------------
    6     |   0 | SELECT STATEMENT              |                         |  1806 |   199K|     9  (23)| 00:00:01 |
    7     |*  1 |  HASH JOIN                    |                         |  1806 |   199K|     9  (23)| 00:00:01 |
    8     |   2 |   MERGE JOIN                  |                         |   482 | 48682 |     6  (17)| 00:00:01 |
    9     |   3 |    TABLE ACCESS BY INDEX ROWID| Guest_ADDRESS          |   919 | 87305 |     4   (0)| 00:00:01 |
    10     |   4 |     INDEX FULL SCAN           | XAK1Guest_ADDRESS      |   919 |       |     1   (0)| 00:00:01 |
    11     |*  5 |    SORT JOIN                  |                         |   482 |  2892 |     2  (50)| 00:00:01 |
    12     |   6 |     INDEX FULL SCAN           | XPKGuest_INFO          |   482 |  2892 |     1   (0)| 00:00:01 |
    13     |   7 |   VIEW                        | index$_join$_003        |  3493 | 41916 |     3   (0)| 00:00:01 |
    14     |*  8 |    HASH JOIN                  |                         |       |       |            |          |
    15     |   9 |     INDEX FAST FULL SCAN      | XAK1Guest_DOMAIN_Relation |  3493 | 41916 |     1   (0)| 00:00:01 |
    16     |  10 |     INDEX FAST FULL SCAN      | XPKGuest_DOMAIN_Relation  |  3493 | 41916 |     1   (0)| 00:00:01 |
    17     ---------------------------------------------------------------------------------------------------------
    18      
    19     Predicate Information (identified by operation id):
    20     ---------------------------------------------------
    21      
    Is there in any case, I have Guess_Domain_Relation table join firstly that the join to Guess_Address table of Guest_info?

    I tried a few ways to rewrite the query, but he's no luck

    Thank you

    Published by: Y.L on March 20, 2013 13:59

    Y.L wrote:
    And my another problem here... I don't know why my first clue didn't work...

    Probably the syntax. The main indicator uses parentheses, as

    /*+
    select /*+ leading(table1, table2) */ *
      from table1, table2
    */
    

    Remember that you must use the table alias name in tips for the identifier to be recognized

    You can also consider using the y indicator (if you must use a hint) for several tables - beware, it is MUCH easier to do worse performance with this suspicion using the order of the tables in the FROM clause in left to right

    /*+
    select /*+  ordered */ *
      from table1, table2, table3
    . . .
    */
    

    How I create index will affect how it works?

    How the index was created probably won't affect how it works. Indexes can be created using constraints and directly with the CREATE INDEX command. The creation of the index should not be as important as its defined characteristics: index type, columns, etc.

  • What's the point of having several columns in the ORDER BY clause?

    DB version: 10 gr 2

    When you use the ORDER BY clause, the lines are always sorted by the first column in the ORDER BY clause. So, what's the point of having several columns in the ORDER BY clause (I always see this in production codes)?

    For the below SQLs' schema SCOTT, result sets are always classified according to the first column ename. When I added use asc and desc of employment, does not change the result set.
    SQL> select * from emp order by ename;
    
         EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
          7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
          7499 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
          7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
          7782 CLARK      MANAGER         7839 09-JUN-81       2450                    20
          7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
          7900 JAMES      CLERK           7698 03-DEC-81        950                    30
          7566 JONES      MANAGER         7839 02-APR-81       2975                    20
          7839 KING       PRESIDENT            17-NOV-81       5000                    20
          7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
          7934 MILLER     CLERK           7782 23-JAN-82       1300                    20
          7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
          7369 SMITH      CLERK           7902 17-DEC-80        800                    20
          7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
          7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
    
    14 rows selected.
    
    SQL> select * from emp order by ename, job;
    
         EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
          7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
          7499 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
          7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
          7782 CLARK      MANAGER         7839 09-JUN-81       2450                    20
          7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
          7900 JAMES      CLERK           7698 03-DEC-81        950                    30
          7566 JONES      MANAGER         7839 02-APR-81       2975                    20
          7839 KING       PRESIDENT            17-NOV-81       5000                    20
          7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
          7934 MILLER     CLERK           7782 23-JAN-82       1300                    20
          7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
          7369 SMITH      CLERK           7902 17-DEC-80        800                    20
          7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
          7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
    
    14 rows selected.
    
    SQL>  select * from emp order by ename, job desc;
    
         EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
          7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
          7499 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
          7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
          7782 CLARK      MANAGER         7839 09-JUN-81       2450                    20
          7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
          7900 JAMES      CLERK           7698 03-DEC-81        950                    30
          7566 JONES      MANAGER         7839 02-APR-81       2975                    20
          7839 KING       PRESIDENT            17-NOV-81       5000                    20
          7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
          7934 MILLER     CLERK           7782 23-JAN-82       1300                    20
          7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
          7369 SMITH      CLERK           7902 17-DEC-80        800                    20
          7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
          7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
    
    14 rows selected.

    Search in this example, you will see the difference

    SQL> create table test_order (name varchar2(10), surname varchar2(10), age number);
    
    Table created.
    
    SQL> insert into test_order values('Kamran','Agayev',26);
    
    1 row created.
    
    SQL> insert into test_order values('Kamran','Taghiyev',26);
    
    1 row created.
    
    SQL> insert into test_order values('John','Kevin',23);
    
    1 row created.
    
    SQL> select * from test_order;
    
    NAME       SURNAME           AGE
    ---------- ---------- ----------
    Kamran     Agayev             26
    Kamran     Taghiyev           26
    John       Kevin              23
    
    SQL> select * from test_order
      2  order by age;
    
    NAME       SURNAME           AGE
    ---------- ---------- ----------
    John       Kevin              23
    Kamran     Agayev             26
    Kamran     Taghiyev           26
    
    SQL> select * from test_order
      2  order by age asc, surname desc;
    
    NAME       SURNAME           AGE
    ---------- ---------- ----------
    John       Kevin              23
    Kamran     Taghiyev           26
    Kamran     Agayev             26
    
    SQL>
    

    When in the second query, I sorted out only for age, you saw it there two 26 years old Keita, there was first Agayev, then Taghiyev. But if I want to get the family names in descending order when there are two very old person, then I will add the second column in the order by clause

    - - - - - - - - - - - - - - - - - - - - -
    Kamran Agayev a. (10g OCP)
    http://kamranagayev.WordPress.com

  • The value of the PropFlags using the API

    Hello

    I created a new group using the c# API calls. I need to ensure that the new group is not deleted. So I tried using the SetFlag method to set these property flags.

    The code snippet is as

    userGroup = eng. NewUser (null);

    userGroup.LoginName = "Test";

    userGroup.AsPropertyObject (). Flags ("PropFlags_NotDeletable", 0x1, 0x400000);
    userGroup.AsPropertyObject (). Flags ("PropFlags_NameNotEditable", 0x1, 0x400000);

    However, the newly created group doesn't have these flags set.

    How can I go on the definition of these indicators?

    Thank you

    Arun

    You pass incorrect arguments to the function flags. The first parameter is the string to search for the property you want to set flags on. In this case, pass an empty string to reference the user object. The second parameter specifies the options for the function. In this case you need anything. The third parameter specifies the desired flags set on the property. You must pass the combination of indicators (PropFlags_NotDeletable |) PropFlags_NameNotEditable). If you remember the flags feature, it will overwrite the flags that you set in previous calls.

    userGroup.AsPropertyObject (). Flags ("", 0 x 0, PropFlags_NotDeletable |) PropFlags_NameNotEditable);

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