How do know us that now the user using the server component
Hi allSuppose a user loged in to the siebel application.and requested for an object manager/component.and as the user who got. But this particular component is active in a portion so how do we know that now the user using the component.means Server user is in what server to use this object manager component.
Concerning
Remy
Using Server Manager, to connect without specifying a server, then run a command to sessions list for your device and you will see the user and the server.
Best regards
EvtLoglvl
Tags: Oracle Applications
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Deal all,
How to identify columns that have the same data in a SQL query or function? I have the sample data as below
!DEPT_ID EMP_ID Come on CITY STATE COUNTRY 1 1 1 June 1983 DELHI HUMAN RESOURCES India 1 2 18 January 1987 DELHI HUMAN RESOURCES India 1 3 28 November 1985 DELHI HUMAN RESOURCES India 1 4 4 June 1985 DELHI HUMAN RESOURCES India 2 5 5 June 1983 MUMBAI HD India 2 6 6 June 1983 MUMBAI HD India 2 7 7 June 1983 MUMBAI HD India . 19832 8 8 Jun MUMBAI HD India . June 19833 9 9 GURGAON DL India 3 10 10 June 1983 GURGAON DL India Now, I want to Indify columns that have the same data for the same Department ID.
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Thanks in advance.
You can try this?
WITH T1)
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), ()
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SELECT 1, 4, TO_DATE('4.) June 1985', 'JJ. LUN. (YYYY'), 'DELHI', 'HR', 'INDIA' OF THE DUAL UNION ALL
SELECT 2.5, TO_DATE('5.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL
SELECT 2.6, TO_DATE('6.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL
SELECT 2.7, TO_DATE('7.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL
SELECT 2.8, TO_DATE('8.) June 1983', 'JJ. LUN. (YYYY'), 'BOMBAY', 'HD', 'INDIA' OF THE DUAL UNION ALL
SELECT 3, 9, TO_DATE('9.) June 1983', 'JJ. LUN. (YYYY'), 'GURGAON', 'DL', 'INDIA' OF THE DUAL UNION ALL
SELECT 3.10, TO_DATE('10.) June 1983', 'JJ. LUN. (YYYY'), 'GURGAON', 'DL', 'INDIA' OF THE DOUBLE)
SELECT DEPT_ID,
RTRIM (XMLAGG (XMLELEMENT(A,VALS||',')). Extract ('//Text ()'), ',') COLUMNS_WITH_DUPLICATE
DE)
SELECT * FROM)
SELECT DEPT_ID,
EMP_ID,
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CITY,
STATE,
COUNTRY
DE)
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EMP_ID,
Date of birth
CITY,
STATE,
COUNTRIES,
COUNT (*) OVER(PARTITION BY DEPT_ID ORDER BY EMP_ID DESC,DOB DESC,CITY DESC,STATE DESC, COUNTRY DESC) RN
DE)
SELECT DEPT_ID,
CASE WHEN(CEID>1) AND THEN 'YES' ELSE 'NO' END AS EMP_ID.
CASE WHEN(CDOB>1) THEN 'YES' ELSE 'NO' END AS DATE OF BIRTH,
CASE WHEN(CCITY>1) AND THEN 'YES' ELSE 'NO' END AS CITY.
CASE WHEN(CSTATE>1) AND THEN 'YES' ELSE 'NO' END AS STATE.
CASE WHEN(CCOUNTRY>1) THEN 'YES' ELSE 'NO' END AS A COUNTRY
DE)
SELECT DISTINCT
DEPT_ID,
CEID,
CDOB,
CITY,
CSTATE,
CCOUNTRY
DE)
SELECT DEPT_ID,
COUNT (*) TO THE CEID (DEPT_ID PARTITION, EMP_ID),.
COUNT (*) ON CDOB (DEPT_ID SCORE, DATE OF BIRTH),
COUNT (*) ON THE CITY (DEPT_ID PARTITION, CITY),
COUNT (*) ON CSTATE (DEPT_ID PARTITION, STATE).
COUNT (*) ON CCOUNTRY (DEPT_ID, COUNTRY PARTITION)
FROM T1)))
WHERE RN = 1)
UNPIVOT (CLO FOR (VALS) IN (EMP_ID, DATE OF BIRTH, CITY, STATE, COUNTRY)))
WHERE COLS = "YES".
DEPT_ID GROUP;
OUTPUT:
DEPT_ID COLUMNS_WITH_DUPLICATE
--------- ------------------------1 CITY, COUNTRY, STATE
2 CITY, COUNTRY, STATE
3 CITY, COUNTRY, STATEPost edited by: Parth272025
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