How many captures instant ESXi provides for each VM?

Similar Questions

• How can I make a cell formula will apply for the entire column? For example D2 appears B2 - C2. How can I copy this formula for each cell in the column?

  How can I make a cell formula will apply for the entire column? For example D2 appears B2 - C2. How can I copy this formula for each cell in the column?

  If you want the formula is the same (B2 - C2) in the cell of each column you must change it as ($B$ - 2$ C$ 2). Then copy it, select the whole column and paste.

• How to find the child level for each table in a relational model?

  Earthlings,
  
  I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
  
  So: How to find the child level for each table in a relational model?
  
  I have a database of relacional (9.2), all right?
  

  .
       O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */
      /↑\ Fks
     O"O O" <-- level 2 for first table (circle)
    /↑\ Fks
  "o"o"o" <-- level 1 for middle table (circle)
     ↑ Fk
    "º"

  Tips:
  -Each circle represents a table;
  -Red no tables have foreign key
  -the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
  
  I started to think about the following:
  
  First of all, I need to know how to take the kids:

  select distinct child.table_name child
    from all_cons_columns father
    join all_cons_columns child
   using (owner, position)
    join (select child.owner,
                 child.constraint_name fk,
                 child.table_name child,
                 child.r_constraint_name pk,
                 father.table_name father
            from all_constraints father, all_constraints child
           where child.r_owner = father.owner
             and child.r_constraint_name = father.constraint_name
             and father.constraint_type in ('P', 'U')
             and child.constraint_type = 'R'
             and child.owner = 'OWNER') aux
   using (owner)
   where child.constraint_name = aux.fk
     and child.table_name = aux.child
     and father.constraint_name = aux.pk
     and father.table_name = aux.father;

  Thought...
  We will share!
  
  Thanks in advance,
  Philips
  
  Published by: BluShadow on April 1st, 2011 15:08
  formatting of code and hierarchy for readbility

  Have you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?

  SQL> create table my_emp (
    2    emp_id number primary key,
    3    emp_name varchar2(10),
    4    manager_id number
    5  );
  
  Table created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  create table my_mgr (
    2    manager_id number primary key,
    3    employee_id number references my_emp( emp_id ),
    4    purchasing_authority number
    5* )
  SQL> /
  
  Table created.
  
  SQL> alter table my_emp
    2    add constraint fk_emp_mgr foreign key( manager_id )
    3         references my_mgr( manager_id );
  
  Table altered.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by prior child_table_name = parent_table_name
  SQL> /
  ERROR:
  ORA-01436: CONNECT BY loop in user data
  

  If you have a cycle, you have some problems.

  (1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on

  SQL> ed
  Wrote file afiedt.buf
  
    1   select level lvl,
    2          child_table_name,
    3          sys_connect_by_path( child_table_name, '/' ) path
    4     from (select parent.table_name      parent_table_name,
    5                  parent.constraint_name parent_constraint_name,
    6                  child.table_name        child_table_name,
    7                  child.constraint_name   child_constraint_name
    8             from user_constraints parent,
    9                  user_constraints child
   10            where child.constraint_type = 'R'
   11              and parent.constraint_type = 'P'
   12              and child.r_constraint_name = parent.constraint_name
   13           union all
   14           select null,
   15                  null,
   16                  table_name,
   17                  constraint_name
   18             from user_constraints
   19            where constraint_type = 'P')
   20    start with child_table_name = 'MY_EMP'
   21*  connect by nocycle prior child_table_name = parent_table_name
  SQL> /
  
         LVL CHILD_TABLE_NAME               PATH
  ---------- ------------------------------ --------------------
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
           1 MY_EMP                         /MY_EMP
           2 MY_MGR                         /MY_EMP/MY_MGR
  

  (2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.

  -Generate the DDL for all tables without constraint
  -Can generate the DDL for all primary key constraints
  -Can generate the DDL for all unique key constraints
  -Can generate the DDL for all foreign key constraints

  This is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.

  Justin

• How many times a product key for Vista can be used on other computers?

  any1 knows how many times you use the product key for Vista Edition home premium on another computer?

  any1 knows how many times you use the product key for Vista Edition home premium on another computer?

  Hey bman1990

  license product key a vista = an installation of vista on a computer

  but you can reinstall this dvd and product key of vista on the same computer as many times as necessary to make it work again properly on that computer

  If it is an oem product key, it is related to the original computer that it is installed on this computer life

  If a retail product key you can transfer it to another computer, but once more it can only be installed on a computer at any time

  Walter, the time zone traveller

• How many months will I pay for monthly plan and how many years will I pay for annual plan?

  I understand the notion of paying a certain amount monthly or yearly, but how MANY months or years I have to continue to pay? I want to be able to have the creative cloud forever without having to pay for the rest of my life! The plan I want to get Creative student Cloud.

  If you want to spend a time of payment and you can use the software 3 years and more, click the link buy CS6 via phone http://www.adobe.com/products/cs6.html

• Many storage spaces and data for each quarter of the year files

  Hello

  I am junior DBA and I have a question about tablespace partitioning or data file sharing.

  I have a database of 10g in many storage spaces, for example:

  KER_DATA_2009_Q1

  KER_DATA_2009_Q2

  KER_DATA_2009_Q3

  KER_DATA_2009_Q4

  KER_INDX_2009_Q1

  KER_INDX_2009_Q2

  KER_INDX_2009_Q3

  KER_INDX_2009_Q4

  There is also a data file for each tablespace that is mentioned.

  But for this year 2013, only two big storage space I can get one and data KER_DATA, KER_INDX files.

  All tables and indexes in the whole database are KER_DATA, KER_INDX, tablespaces.

  I don't know any cut in two storage spaces and means of data files. Is this something like tablespace partitioning? This can be done automatically or someone needed to do it manually on the end of each quarter?

  This should be done to improve performance, several small files data instead a large?

  Can some admin explain this to me?

  The reason for this separation of database/tablespace was partitioning. There are a lot of tables partitioned by date column, and there are partitions for each quarter of the year. There are tablespace with a data file for each quarter (partition).

• How to get all the records for each group - double

  Hi all
  
  I have developed customized reports, I have a three for each group, the first group is for PO number and the second is for line number Po and the third is for activity ID.
  
  
  Today the third group is based on the activity ID.
  
  Some time the activity id is unique and other data are different. If at this time its settlement only one record.
  
  For example
  
  Date of activity Id
  
  1 25 - Jan
  
  1 26 - Jan
  
  
  
  Its single record display.
  
  Can someone tell me how to avoid this separate for each group.
  
  Thanks and greetings
  Srikkanth.M

  As another user said, delete syntax regroup.
  Why do you bring here?

• How can I create legends customized for each image (large) target displayed with the widget to the Gallery?

  Greetings!

  I'm having any joy with the thumbnails Gallery - with the exception of a customization widget, I would like to make.

  I would like to have descriptive legends custom unique each 'target' (large image) image displayed. I can see the legend box personalized, move, modify, etc, but this is fixed for all images in the gallery.

  How do I change each caption for each image of the target?

  Thank you very much

  JL

  Assuming you are talking "Vignettes" under "Slide shows" widget in the widget library, simply drag the widget on a page to insert it. Once inserted, make sure you have legends in reverse by clicking the widget inserted on the page, and then on the small blue arrow top right of the widget that appears once the widget itself is selected, and check the box called "Legends", this will add captions [Lorem Ipsum] to each photo, you can then at this point click or double-click the text "Lorem" on each photo and that you want it to be. I hope this helps.

• How to find the rank lowest for each student using a Select query?

  Hey I'm having a little trouble here
  
  I have this table
  
  
  Student - Grade
  
  John - 8
  Richard - 9
  Louis - 9
  Francis - 5
  John - 13
  Richard - 10
  Peter - 12
  
  Shades may vary from 0 to 20.
  
  Name - varchar (50)
  Grade - wide
  
  I'm trying to generate a SQL search to search for each rank lowest for each student.
  
  So far, I did:
  
  Select s.name, s.grade
  s student
  where s.grade = (select min (grade) of student)
  
  The result of this search returns me only the rank lowest of all ranks posted above, which is Francis - 5.
  
  I want to find the lowest rank, but not only for Francis, but for all students in the table.
  
  How do I do that?
  
  Thank you in advance.

  Ok

  Now we head into analytical SQL:

  with student as (select 'John' name, 8 grade, 'fail' result from dual union all
                   select 'John' name, 13 grade, 'pass' result from dual union all
                   select 'Francis',     5 grade,  'fail' from dual union all
                   select 'Peter', 12, 'pass' from dual)
  -- End of your test data
  SELECT   name,
           MAX (result) KEEP (DENSE_RANK FIRST ORDER BY grade) result,
           MIN (grade) min_grade
  FROM     student
  GROUP BY name
  

  Please note that I passed ;)

  Concerning
  Peter

  To learn more:
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions056.htm#SQLRF00641

• How to capture the execution plan for a query

  Hi all
  
  Can someone help me please to find the command to capture the execution plan for a query.
  
  Execution plan for select * from EMP where < condition >
  
  Is getting executed successfully, but I need to get the appropriate for the same execution plan.
  
  Thank you

  Read the Doc

• Where to check how many licenses I've got for my CSI

  Hello
  Two questions:
  
  (1) is it possible to register support.oracle.com how many licenses is supported by my CSI number?
  I followed these steps and check my CSI number, but I do not see how many licenses I've got.
  
  1. connect to My Oracle Support (MOS)
  2. click the tab more, then settings, and then select the account & privileges
  3. click on the hyperlink to the relevant ICS
  4. This will open a window in the MOS and show the products supported
  
  (2) I have several numbers of CSI, but my e-mail account in support.oracle.com is associated only with a single CSI number. How would I know what e-mail accounts are associated with my other CSI numbers?
  
  Thank you very much.

  user521219 wrote:
  Hello
  Two questions:

  (1) is it possible to register support.oracle.com how many licenses is supported by my CSI number?

  N ° in your license agreement that you can not read in My Oracle Support.

• HP probook 4530 s - face recognition does not. How can I delete information provided for this

  How can I delete information of face recognition with which I have provided my HP Probook 4530 s when I started the unit? I do not use the software because it does not work when I try to use it and prefer the fingerprint reader.

  Hello

  Uninstall the system of "facial recognition for HP ProtectTools.

  This will remove the data (you may be asked to confirm this choice).

  Resources:
  Uninstall software in Windows 7

  Uninstall or change a program in Windows 7

  There may be second solution (I am not able to check it out).

  Open the HP ProtectTools Security Manager. Look there for the recognition of face on the list.
  Check all the options of this software. There also may be an option to remove this information.

  If you want to check the latest version of this software, then you can download it from here.

• How to add the action button for each column in the interactive report

  Hi all

  I'm new in APEX, so pls forgive my question, if it's simple, but I am struggling with this problem for days now. I have interactive report and you want to add button in each row. What I want to do with this button is the following:

  1. to execute some stored procedure in need of that particular line item values

  2. returns a (id)

  3. go in another page in the application by passing the value out of the procedure (id).

  and I'm not find the way to do it. I tried now means:

  1. If I add the link of the column, so I can refer to the value of the current row, I don't know how to call the stored procedure and perform actions of rest I need

  2. If I add the button to the region, I do not know how to reference the values in column of a particular line of the interactive report...

  and I'm stuck...

  I just forms and global report and probably still think the "wrong" way .

  Any help would be appreciated!

  Thank you!!!

  
  

  user3253917 wrote:

  Please update your forum profile with a real handle instead of 'user3253917 '.

  I request of the company: there is a customer who always orders the same standard product orders (always order the same products, fair amount is different). I want to make it simple for the user: instead of retyping the command (master and few records details every time yet) I want to copy selected command (copy of the master record and record details) so that the user will only change date order (in master record) and amount fields in record details).

  So, in order to give him:

  1. the user must be able to choose the order in which I would copy (at page 4), select it,

  2. I need to make PL/SQL procedure to insert the new master record (order) and a few record details (order_items) (copy of the order/order_items chosen in step 1)

  3. navigate the user to page 29, where the master account at stage 2 insterted appears, so that the user can change the date and quantities.

  Any solution will be highly appreciated! Thank you very much!!!

  In simple terms:

  1. Add a link to column "Command copies" in the report on page 4, which sets the COPY request and passes the order ID on page 29.
  2. On page 29, create a process before header, sequenced to be the first process executed and conditional on REQUEST be EXEMPLARY, which creates a new order as a copy of the order with the ID from page 4 and returns the ID of the new order in the PK command ID of 29 page element.

• How to remove the "subject" prefix for each message list in thunderbird

  Hello.
  It seems now that on the screenshot.
  In each row shows "object:" prefix. I have not found in thunderbird not google how to disable.
  Help, please.

  It is not a built-in feature, so I suspect an add-on, possibly from Conversations. Run Safe Mode (hold SHIFT when you start TB) and see if it persists.

• How many electrical outlets are needed for a Cisco 55 '' Profiler?

  Hi people!

  Power outlets how do I need to connect a Profiler 55 "?

  Guess of mi is that 4: 2 for two LCD screens, 1 for the CODEC and 1 for the touchscreen to control... but in the installation guide it only seems to be a power cord for the Profiler together 55 ".

  If you have installed previously and you saw the power outlets needed... can you help me please with this info?

  Thaks & best regards!

  The system has internal sale but points that one main power cable. Believe me, that I built it several time ;-)

  Sent by Cisco Support technique iPhone App