How the lack of dates online results of the query and convert the output

Hi Experts,

My inline query returns the data in this format

2-jan-2016    10
4-jan-2016    33
5-jan-2016    20
7-jan-2016    70
8-jan-2016    77

I want to display the output as

1-jan-2016 2-jan-2016 3-jan-2016 4-jan-2016 5-jan-2016 6-jan-2016 7-jan-2016 8-jan-2016 9-jan-2016 10-jan-2016 
0    10    0   33  20 0  70 77 0 0

Can you please help me with query how over the missing dates, is it tier, collar or pivot?

Thanks in advance.

Kind regards

IVW

Hello

Is that what you are looking for?

WITH
SampleSet
AS (SELECT TO_DATE (' 2 January 2016', 'DD-mon-yyyy') dt, val 10 FROM DUAL)
UNION ALL
SELECT TO_DATE (' 4 January 2016', 'DD-mon-yyyy'), 33 FROM DUAL
UNION ALL
SELECT TO_DATE (' 5 January 2016', 'DD-mon-yyyy'), 20 FROM DUAL
UNION ALL
SELECT TO_DATE (' 7 January 2016', 'DD-mon-yyyy'), 70 FROM DUAL
UNION ALL
SELECT TO_DATE (' 8 January 2016', 'DD-mon-yyyy'), 77 FROM DUAL
)
sample_rn as
(
Select
DT
val
, dt - min (dt) (order 1) + 1 rn
2 line_no
Of
SampleSet
order by
DT
)
mindate as
(select min (dt) dt sampleset)
dates in the FORM
(
SELECT
DT + level 1 - dt
null val
level rn
1 line_no
Of
MinDate
CONNECT BY ROWNUM<= 10 ="" --="" number="" of="">
)
a, as
(
Select
to_char Col (DT)
rn
line_no
Of
dates d
Union
Select
to_char Col (Val)
rn
line_no
Of
sample_rn
where
RN<= 10             ="" --="" number="" of="">
)
Select
*
Of
a pivot (pass the max (col) of rn (1,2,3,4,5,6,7,8,9,10))--liste of columns 1 to))

What makes a list with 2 rows. Line 1 has dates starting with the first data of sampleset. and line 2 has the values. The number of columns, you can determine yourself.

Kind regards

Peter

Tags: Database

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