How to calculate the days with 2 Date/time fields

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• How to calculate the sum of two digital form fields based on the selection of the checkbox.

  I have a form in Acrobat Pro who needs a custom calculation. How to calculate the sum of two digital form fields based on a selection of the checkbox. I have three number fields. Field-A and B are simple one or two digits. Field-C is the sum, or the total field. I want to field-C have a control box which, when turned on and off, just gives a. gives the sum of A + B

  _ Field - 2

  _ Field - A 4

  [check] _ _ field - 6 C

  [disabled] _ _ field - 2 C

  Thank you

  The custom field C calculation script could be:

  (function () {
  
      // Get the values of the text fields, as numbers
      var v1 = +getField("A").value;
      var v2 = +getField("B").value;
  
      // Set this field's value based on the state of the check box named "CB"
      if (getField("CB").value !== "Off") {
          event.value = v1 + v2;
      } else {
          event.value = v1;
      }
  
  })();
  

  Replace 'A', 'B', and 'CB' with the real names of the fields.

• How to calculate the difference between a Date column and the Date yesterday in the analysis (in the formula in the column)

  . For example, I need to calculate the difference between a date column, 'Table_Name '. "' Column_Name ' and (Current_Date-1). I tried different ways to do this. But nothing seems to work.

  Try the below formula.

  Replace "Time". "" Date "with your column.

  TIMESTAMPDIFF (SQL_TSI_DAY, "Time". "Date", TIMESTAMPADD (SQL_TSI_DAY-1, CURRENT_DATE))

  Thank you!

• frustrating problem with a dat/time field

  I'm pretty new to this tool (LiveCycle) - once more to try to modify/create a pdf form on very simple writing

  I inserted 2 fields of date time. I have a correctly configured automatically insert the current time, when the form is opened so the user does not have to do... ;

  The following field must be a time field so that the user does not enter anyone.

  I have the date field load properly, but for the life of me cannot get the time to display at all.  I tried:

  1 Add a new date/time field

  2 duplicate one that works and just change the format of 'Time '.

  3 tried to remove them both and then create again.

  I discovered by removing both and starting, as I can get the date to appear in these two areas, but I can't do anything else to appear.  I can not get the time to appear in each area. !!

  Frustrated: Somebody can tell me what I'm doing wrong here...

  Because I don't see a place for me to download the form here, I posted on the following Web site

  I think you just download it and take a peek - if someone would be so kind - could explain things better to see for yourself.  It seems buggy to me, but I do not know!

  Thanks in advance,

  Dan has.

  See: http://provsnusa.com/test.html

  Hi Dan,.

  The time field was still date in script functions, although you use a time model (in the object > field > models).

  Just changed the script for:

  Current time in short-style date format.

  $ = num2time (Time (), TimeFmt (1))

  Here is the form: https://acrobat.com/#d=63FQyQ3bVTlj8ERIjvUGJw

  Good luck

  Niall

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.

• How update just the day of a date value?

  Example:

  Table: FC_GQ_SOURCE_ANALYSIS

  Sample_type = C

  Effective_date = null

  Sample_date = 20/13/07/14 09:00

  Should that happen, it's for any analysis of the sample which has a 'C' sample_type we need for the entry into force the first day of the month for some months of the date of the sample is and keep the time that it is...

  so in the example data, the entry into force should be 2013/07/01 09:00.

  How to update only the part of the day of this string of date?

  Hello

  You don't need to convert it to a string and back to do.  TRUNC allows to get the right day and date arithmetic to get the right time, like this:

  UPDATE fc_gq_source_analysis

  SET effective_date = TRUNC (sample_date, 'MONTH')

  + (sample_date - TRUNC (sample_date))

  WHERE sample_type = 'C '.

  ;

  TRUNC (sample_date, 'MONTH') is midnight the 1st of the month you want.

  sample_date - TRUNC (sample_date) is the time you want, expressed in number of days (for example, 9/24 a day).

• How to calculate the half-year to date?

  Hello
  I have the dimension of time like that
  
  Time
  -T1
  -Jan
  -Feb
  -Mar
  -Qtr2
  -Apr
  -May
  -Jun
  -Qtr3
  -Jul
  -Aug
  -Sep
  -Qtr4
  -Oct
  -Nov
  -Dec
  
  I would like to add the half of the year as
  
  Time
  H-1
  -T1
  -Jan
  -Feb
  -Mar
  -Qtr2
  -Apr
  -May
  -Jun
  H-2
  -Qtr3
  -Jul
  -Aug
  -Sep
  -Qtr4
  -Oct
  -Nov
  -Dec
  so, how can I implement half year to date with such hierarchy.
  
  Published by: Manisha-user8955359 April 29, 2010 12:29

  Try this to get half of the year

  SELECT        FLOOR
                         (  TO_CHAR (ADD_MONTHS (TRUNC (SYSDATE, 'RRRR'),
                                                 LEVEL - 1
                                                ),
                                     'MM'
                                    )
                          / 7
                         )
                   +  1
                   || 'H-'
                   || TO_CHAR (ADD_MONTHS (TRUNC (SYSDATE, 'RRRR'), LEVEL - 1),
                               'YYYY'
                              ) AS calender_halfyear_year
              FROM DUAL
        CONNECT BY LEVEL <=
                      MONTHS_BETWEEN (ADD_MONTHS (TRUNC (SYSDATE, 'RRRR'), 12),
                                      TRUNC (SYSDATE, 'RRRR')
                                     )
  

• How to calculate the hours between two dates by the numbers

  If I update 09:00 start time 17:00 end time of shift in C3 and B3, how to use a D3 formula to calculate the number of hours between the two?  Then I can just copy down the lines for nth years...

  It is a spreadsheet of the part-time staff payroll.

  I'm sure that a lot of people out there have done that.

  Help, please.

  Thank you.

  Eddie

  What program of worksheet that you are using? Since you have a newer iMac running El Capitan, I can safely assume that you use NOT AppleWorks, which is a Power PC application that can run on any OS newer than the snow leopard, OS X 10.6.8.

  If you use numbers, try to repost your question in numbers for Mac forum. If you use Microsoft Excel, try posting in the Microsoft forums. LibreOffice also has community support.

• How to calculate the mask with joker to ACL

  Dear,

  I know it may seem a question very bacis, but frankly I've searched the net, books & asked many friends and no one could help you.

  I want to create one or two access list to hit the following ip prefix.

  192.168.2.0

  192.168.6.0

  192.168.11.0

  192.168.15.0

  192.168.18.0

  may well want to explain to me in binary computing.

  concerning

  I think your question is asking questions about the means to have a single line in the list ACL correspond to more than one address, so that with one or two lines of ACL you could match to these 5 addresses. The way to start is to understand what these addresses have in common. they all 192.168 in the first two bytes and 0 in the last byte. So the third byte is the place where there is no variation. We must therefore start with the value of the third byte in binary:

  2 is 00000010

  6 is 00000110

  11 is 00001011

  15 is 00001111

  18 is 00010010

  If you examine the binary and see what numbers have many BITS in common that we see that 2 and 6 have in common the 7 of the 8 bits and could be grouped. We see that the 11 and 15 have in common the 7 of the 8 bits and could be combined.

  Then the Group 2 and six that we want a mask which says that bit positions 1, 2, 3, 4, 5, 7 and 8 must match and bit position 6 does not. The mask with 0 to 1, 2, 3, 4, 5, 7 and 8 is 00000100 (4 in decimal). The Group 11 and 15, we also have bits 1, 2, 3, 4, 5, 7 and 8 to match while we would use this mask still 00000100.

  There is not a way to combine 18 very well with the other addresses. So an ACL have 3 statements to match these 5 addresses.

  permit 192.168.2.0 0.0.4.0

  permit 192.168.11.0 0.0.4.0

  Allow 192.168.18.0 0.0.0.0

  HTH

  Rick

• HP12C Platinum: How to calculate the EMI with a grace period?

  I'm figuring the tranche of loan compared to a loan with a grace period.  This can be done easily using MS Excel, but I need to do the calculation using my HP12CP.

  Details of the loan:

  Main: 1 million

  Interest rates. : 12% p.a.

  Tenor: 36 months

  Period: 3 months

  Payment frequency: monthly

  Loan annuity calculated with Excel: Q1 - zero; 4th in the 36th month: 36 810 /-per month

  Hello MilanH

  Perhaps this allows, if you train in two steps:

  1)

  n = 3 grace period

  IR/a=12%

  PV = 1 million

  FMT = 0.00

  FV =-1030301.00 (-because you have to pay it back)

  2)

  n = 33

  IR/a = 12%

  PV = 1030301.00

  VF = 0.00

  FMT = 36810.01 (-because you have to pay)

  I have no 12 c, but if this kind of loan is not built in, you can manage this way.

• How to calculate the number of days/weeks/months between 2 dates?

  Hello
  
  I would like to know how to calculate the number of days/weeks/months between 2 dates in OBIEE 11 g, for example, I have 26/05/2013 and 19/05/2013, then I want to get 7 days.
  
  Thank you!
  Jamie

  Hi Jamie,

  Through this links...

  http://www.bravesoft.com/blog/?p=682
  http://twobiee.blogspot.in/2012/01/working-with-date-differences.html

  Mark as correct it allows u...
  Thank you...

• How to calculate the periods that overlap between two or more given the date range?

  Hi all

  If there are several durations then how we can calculate the period of time that overlap between these times.

  For example: for 3 time periods. 03/12/2015-16/08/2015, 05/01/2015 to 31/07/2015 and the 06/09/2015 to 30/11/2015, how the overlap period can be calculated?

  There are many potential unknowns in your question.  For example, you want to count any overlap at all?  If two dates overlap, what matters?  Overlap - each of them?

  In any case, here is a solution that counts how many periods are overlapping in any point in time...  She, of course, using temporal logic.  You can then use ValueAt(), WhenLast(), WhenNext(), etc. as appropriate.

  Assume that your model has a child entity called 'the period' with name 'all time periods' relationship and basic attributes 'start date of the period of time' and 'date of end of period of time'.

  In your example:

  an entity should have the time period start date = 03/12/2015 and the date of end of period of time = 16/08/2015

  another entity might have the time period start date = 01/05/2015 and the date of end of period of time = 31/07/2015

  another entity might have the time period start date = 06/09/2015 and the date of end of period of time = 30/11/2015

  To find the number of overlapping over time, we want to count or entities that have an active period, so the rule is perhaps the sum:

  the number of overlapping = the number of all the periods for which it is true that the time period is active

  How do we know a time is active?  This is the time logic comes in.  He is active on or after the start date or no later than the end date:

  the time period is active if

  TemporalOnOrAfter (the date of beginning of period of time) and

  TemporalOnOrBefore (date of end of period of time)

  That's all.  Now, you can perform a temporal visualization of the 'number of overlapping' and you'll see it rise and fall over time.  As a reference, he said that the number of overlapping = 3.0 from 06/09/2015 across 31/07/2015.

  I hope this helps.  You can use the same model to count periods of time functions, but you end up having to use the most logical date.  You of course can count the total number of entities and compare this number of overlap over time to see if they overlap, but I digress...

• How to calculate the date interval

  Hi Experts,
  
  I'm looking for a way to calculate the interval between two dates. And get the result to the format "dd.mm.yyyy hh24:mi:ss.
  

  select  sysdate - to_date('1.1.2000 12:00:00','dd.mm.yyyy hh24:mi:ss') from dual

  Best practices for a problem like this?
  
  Best regards
  Igor

  select trunc( months_between( day2, day1 ) / 12 ) years
       , mod( trunc( months_between( day2, day1 ) ), 12 ) months
       , numtodsinterval( day2 - add_months( day1, trunc( months_between( day2, day1 ) ) ), 'DAY' ) rest
  from ( select to_date( '19-01-1979', 'dd-mm-yyyy' ) day1, sysdate day2 from dual )
  

• How to get the day as a numeric value without the date in shape?

  Hello
  to reduce the costs of a sql statement, I need to get the day of a date under the number (to compare to a numerical value) value without formatting. Each formatting causes a complete table of the table scan and the date field. Is there a function for this problem?
  
  Version of Oracle's 11g.
  
  Thank you Carsten

  You can use EXTRACT...

  SQL> select extract(day from sysdate) from dual;
  
  EXTRACT(DAYFROMSYSDATE)
  -----------------------
                        7
  
  SQL>
  

• Calculate the days of salary

  Dear friend
  
  
  I want to calculate the days of salary. We pay the salaries of the 21st of the month last to the 20th of the current month.
  
  I want to create a view where it will show of the the Scriptures based on this month wise condition
  
  Select empno, name, daytype, count (empno) days, MAX (TO_CHAR (ADATE, 'MONTH')) in dailyattendence
  When al > =('20-OCT-2010') AND ADATE < =('20-NOV-2010')
  Group by empno, daytype
  order by empno
  
  
  for ex
  
  562 SEUN BÉLANGER AFTERNOON OCTOBER 1
  562 SEUN BÉLANGER MORNING OCTOBER 2
  562 SEUN BÉLANGER NIGHT OCTOBER 2
  562 SEUN OFF BÉLANGER 1 OCTOBER
  
  562 SEUN BÉLANGER AFTERNOON NOVEMBER 1
  562 SEUN BÉLANGER MORNING 2 NOVEMBER
  562 SEUN BÉLANGER NIGHT NOVEMBER 2
  562 SEUN OFF BÉLANGER 1 NOVEMBER
  
  Suggest me how to set the dates so that I can get the report as shown above,
  
  Sandy

  It doesn't really have anything to do with the forms, but here's a solution.
  To get the 21st of the month before you use:

  select to_date('21'||to_char(add_months(sysdate,-1),'mmyyyy'),'ddmmyyyy')
  from dual;
  
  TO_DATE('
  ---------
  21-OCT-10
  

  The same for the 20th of this month. So you get:

  where adate between to_date('21'||to_char(add_months(sysdate,-1),'mmyyyy'),'ddmmyyyy')
     and to_date('20'||to_char(sysdate,'mmyyyy'),'ddmmyyyy')
  

  An addition: If your date includes a time, you must use the use trunc (date).

  Published by: InoL on November 11, 2010 12:10