Calculate the days of salary

Similar Questions

• Function to calculate the days of work

  Hi all

  I accidentally develop an application in which I had to follow the thread below and it works perfectly for the weekend (Saturday and Sunday)

  PL/SQL function to calculate the non-working days

  Now, my specific question is: how to implement the same function , but weekends (Fri & sat).

  I tried to recognize the logic behind the calendar to change the days of the weekend, but I suspect.

  I need your recommendation around this function specifically.

  !-[CodeBlockStart:3cad70b5 - 81 a 0-4f6b-909 a-cacb29e25953]--> BOX WHEN IN l_case (-"Mon6", "Tue5", "Wed4", "Thu3", "Fri2" - exclude Saturday & Sunday, workday begins from Monday 'Sun6', 'Mon5', 'Tue4', 'Wed3', 'Thu2' - remove begins day 2 business days (Fri & sat) on Sunday and maintaining the order of the sequences,-"Sat1", "Sun1", "Sun2', 'Sun3', 'Sun4' - Include weekend can be for the rest of the week) , "Sat1", "Sat2", 'Fri1', "Sat3", "Sat4" - includes my week ends replace (with FRI Sat) & (Sun to SAT) & law enforcement-sequence, "Sun5', 'Sun6',"Sat5","Sat6"- replace (Sun with Sam).                                                                   ) 1 THEN WHEN IN l_case (-'Tue6', 'Wed5', 'Wed6', 'Thu4', "Thu5" - Old (Saturday and Sunday) end over the next week - I guess - sequence of days - since the week days sequence Changed (number 1 or 1 step backward) when numbers also changed accordingly "Tue5", "Wed4", "Wed5", "Thu3", "Thu4" - ok-, 'Thu6', 'Fri3', "Fri4", "Fri5", "Fri6", "Thu5", "Sun1", "Sun2", 'Sun3', 'Sun4' - contiue to Thu sequence number & then replace my current (Friday) holiday with start of work dat (Sun) "Fri1") (, 'Fri2', 'Fri3', 'Fri4', "Fri5") THEN 2 0 OTHERWISE END;

  Thanks in advance.

  Amatu Allah

  with

  calendar as

  (select dat_val,

  cases where to_char(dat_val,'mm-dd') in (12-25', 12-26', ' 01-01')-in fact select the host table to_char(holiday_date,'mm-dd')

  then "vacation."

  When to_char (dat_val, 'Dy') in ('Friday', 'Saturday')

  then 'weekend '.

  else 'work '.

  end dat_type

  sum (case when to_char(dat_val,'mm-dd') in (12-25', 12-26', ' 01-01'))

  then 0

  When to_char (dat_val, 'Dy') in ('Friday', 'Saturday')

  then 0

  1 other

  end

  ) on working_count (dat_val control)

  from (select date "' 2015-12-01 + level - 1 dat_val)

  of the double

  connect by level<=>

  )

  )

  Select dat_val,

  dat_type,

  working_count

  calendar

  where dat_val between to_date(:lo_date,'yyyymmdd') and to_date(:hi_date,'yyyymmdd')

  and dat_type! = work «»

  DAT_VAL	DAT_TYPE	WORKING_COUNT
  11/12/2015	end of week	8
  12/12/2015	end of week	8
  18/12/2015	end of week	13
  19/12/2015	end of week	13
  25/12/2015	holiday	18
  26/12/2015	holiday	18
  01/01/2016	holiday	23
  02/01/2016	end of week	23
  08/01/2016	end of week	28
  09/01/2016	end of week	28

  Select to_date(:lo_date,'yyyymmdd') lo_date,

  to_date(:hi_date,'yyyymmdd') hi_date,

  dat_val,

  dat_type,

  working_count,

  Lead (working_count) more (order of dat_val) - working_count + 1 working_days,

  to_date(:hi_date,'yyyymmdd') - to_date(:lo_date,'yyyymmdd') - lead (working_count) (order dat_val) + working_count non_working_days

  calendar

  where dat_val in (to_date (:hi_date,'yyyymmdd'),to_date(:lo_date,'yyyymmdd'))

  LO_DATE	HI_DATE	DAT_VAL	DAT_TYPE	WORKING_COUNT	WORKING_DAYS	NON_WORKING_DAYS
  10/12/2015	10/01/2016	10/12/2015	work	8	22	10
  10/12/2015	10/01/2016	10/01/2016	work	29	-	-

  Concerning

  Etbin

• calculate the day of the year using the date.

  Hi all
  Can calculate us the day of the year using the date form? Is this possible? Please help me thanks in advance
  Like this
  30/08/2009-30/08/2010 after calculation - 365
  
  
  Sarah
  
  Published by: SarahSarahSarah on August 30, 2009 12:49 AM

  Sarah.

  : ins1.noday must be a part of number!

  Create a function in forms like this:

  function get_nodays ( f_dtm_start in date,
                        f_dtm_end   in date ) return number is
  begin
  if
    f_dtm_start is null OR
    f_dtm_end is null
  then
    return ( null );
  end if;
  return ( trunc ( f_dtm_start ) - trunc ( f_dtm_end ) );
  exception when others
  then message ( sqlerrm || ' in function get_nodays occured.' );
  return ( null );
  end;
  

  Call this function in the when-validate-point triggers on ins1. INSPERIOD and: ins1.end love

  :ins1.noday := get_nodays ( :ins1.INSPERIOD, :ins1.end );
  

  It is redundant to have the: noday as a cause of part of database
  the value may by calculated every time using the values INSPERIOD and: end.

• to calculate the days of sheets each month

  Hi all

  I need a query which can get leaves from an employee of days each month.

  Example:

  1.

  If an employee has leave of date_start = 15 January 2014 ', date_end = 30 January 2014 "which is in the same month, then it will be"

  Duration = 15-30 + 1 = 16 days

  Total_days_in_jan = 31 days

  Calculation of salary leave will be amount = (: base +: housing) * (: duration) / (Total_days_in_jan)

  = (1000 + 2000) * 16/31

  ' 2. If his two month date_start = 15 January 2014 ', date_end = 10 February 2014.

  I wrote code that works perfect below

  If to_char(:date_start,'mm') = to_char(:date_end,'mm') then

  v_mon_days: = TO_CHAR (last_day (TO_DATE(:date_start,'DD-MON-YYYY')), 'DD');

  v_tot: = (nvl(:BASIC1,0) + nvl (:FUJ_LIVING,0)) *(:Duration_)/v_mon_days;

  elsif to_char(:date_start,'mm') <>to_char(:date_end,'mm') then

  v_mon_days_st_dt: = TO_CHAR (last_day(:date_start), 'DD');

  v_mon_days_en_dt: = TO_CHAR (last_day(:date_end), 'DD');

  v_lv_days_st_dt: = last_day(:date_start) -: date_start + 1;

  v_lv_days_en_dt: =: date_end - trunc(:date_end,'mm') + 1;

  v_tot_st_dt: = (nvl(:BASIC1,0) + nvl(:FUJ_LIVING,0)) * (v_lv_days_st_dt) / v_mon_days_st_dt;

  v_tot_en_dt: = (nvl(:BASIC1,0) + nvl(:FUJ_LIVING,0)) * (v_lv_days_en_dt) / v_mon_days_en_dt; 

  v_tot: = nvl(v_tot_st_dt,0) + nvl(v_tot_en_dt,0);

  end if;

  Return round (v_tot);

  3. If the 3 months off, say date_start = 24-may-2014 date_end = July 2, 2014.

  I need some help here... what happens if the 4 month also leave...

  Please suggest.

  Kind regards

  Afzal.

  Hi Roger, Etbin

  Thanks for your replies.

  I found the solution on the month to display between two dates.

  To calculate that I used the loop as below

  declare

  ST DATE: =: date_start;--TO_DATE('24-MAY-2014','DD-MON-YYYY');

  ED DATE: =: date_end;--TO_DATE('02-JUL-2014','DD-MON-YYYY');

  number of v_t_amount;

  CURSOR C1 IS

  SELECT more GRAND (ST, ADD_MONTHS (TRUNC (st, 'MONTH'), (LEVEL - 1))) dt.

  LESS (ed,

  LAST_DAY (ADD_MONTHS (TRUNC (st, 'MONTH'), (LEVEL - 1)))

  ) ld

  OF THE DOUBLE

  CONNECT BY LEVEL<>

  MONTHS_BETWEEN (TRUNC (ed, 'MONTH'), TRUNC (st, 'MONTH'))

  + 1

  ORDER BY 1;

  V_AMOUNT NUMBER: = 0;

  V_T_AMOUNT NUMBER: = 0;

  NUMBER OF V_DAYS;

  BEGIN

  FOR I IN C1 LOOP

  V_AMOUNT: = (nvl(:SALARY_DIFF,0) + nvl(:SPECIAL_ALLOWANCE,0) + nvl(:CF_OTHERS,0)

  + NVL(:Computer,0) + nvl(:PHONE_ALLOW,0) + nvl(:WORK_NATURAL,0)

  (+ nvl(:TRANSPORTATION,0) * (i.1d - i.dt + 1) / TO_CHAR (LAST_DAY (i.1d), 'dd'));

  V_T_AMOUNT: = V_AMOUNT;

  end loop;

  end if;

  dbms_output.put_line (v_t_amount);

  end;

• calculate the days remaining until a given date

  Hello

  I am facing a problem and can not find a good solution.

  I want to calculate how many days there are still up to a certain date.

  It is because I want to build in a callback to the re-kalibrate hardware which is used every year.

  So if it's today 05/11/2012, and the constant is 21/05/2012 labview must calculate there are still 10 days left before the re-kalibration must be finished.

  Someone has any idea how to do this?

  Thanks in advantage!

  of course, don't forget that time stamps are DBL in seconds.

  

  Hope this helps

• How to calculate the days with 2 Date/time fields

  Hello
  I tried to create a workflow to update a numeric field with the following formula, however, I get an error message "value too long for the field 'ZNum_0' (maximum size 16) (SBL-DAT-00235). Can I know what is the problem with my calculation?
  
  dtCloseDate - dtAssignDate
  
  Thank you

  Hi, your formula is correct.

  You could be facing this problem because it will assess the value in decimal and result has no set limit for the decimal point. As digital field accept only 16 characters, the problem is occure.

  You must truncate the result with a defined decimal.

  Hope this will help you
  Dinesh

• How to calculate the n prorations retained earnings

  When I am trying to enter code allocation House fast proration formula it gives me error. This same code works very well with the base salary only FF but with room allowance and other allowances n deducitons its gives me the following error: -.
  -------------------------------------------------------------------------------------------------------------
  APP-FF-33065: line 68: only the data base of points or input variables can be missed.
  
  Cause: You specified an item to be in default, which is not an element of database or an input variable.
  
  Action: Use an input variable or database in the default statement. If you want to change the value of a local variable, simply assign a value to it. You can change the global variable values using the form to handle Globals.
  ------------------------------------------------------------------------------------------------------------
  Now, the line 68 refers to the next line that I gave to my quick formula:
  
  IF (prorate_start did not fail) then
  (
  l_days = days_between (prorate_end, prorate_start) + 1
  day_in_Month = days_between (PAY_PROC_PERIOD_END_DATE, PAY_PROC_PERIOD_START_DATE) + 1
  House_allowance = (House_allowance * l_days) / day_in_Month
  House_allowance = (House_allowance)
  House_allowance2 = (House_allowance)
  House_allowance_tzs =(House_allowance*EXCHANGE_RATE1)
  )
  
  Please note that the folloing was referred to as a default value in the FF:
  
  the default for prorate_end is January 1, 1900 "(date)
  the default for prorate_start is January 1, 1900 "(date)
  default value for PAY_PROC_PERIOD_END_DATE IS 1 January 1950 ' (date)
  default value for PAY_PROC_PERIOD_START_DATE IS 1 January 1950 ' (date)
  
  I am trying to calculate the employee's salary n deductions based on the number of days the employee has worked.
  
  Please help/help me!

  I guess you need to add 'prorate_start' to the part "entries are" your quick formula. Same of course for the prorate_end (date).

• Calculation of the days of working in a function

  I have a function that will count the total number of days between two weeks. That is, May 19, 2010 to June 18, 2010 is 30 total days in my cycle. We do not work on weekend so that 30 days is not correct. The formula below is how I calculate the days between cycles. Is it possible to not counting the weekend in my cycle? Please see the formula below:
  
  TIMESTAMPDIFF (SQL_TSI_DAY, "Free Dim". "Release cycle Start Date ', 'Release Sun'." Output cycle end Date")

  You should subtract the start end date date, divide by 7 and multiply by 5.

  Try with it.

  Concerning

• calculate the time in seconds, the day of the year and year

  I have a data file where they record three columns, the seconds elapsed since midnight, day of the year and the year.  I am creating a timestamp of LabVIEW from these three numbers.  Of seconds elapsed since midnight, I can create seconds, minutes and hours.  If I feed in a cluster of time with the day of the year and the year, the timestamp of output is 0.  Does not work.  Although an input of the day of the year element, the Date and time with seconds function apparently requires day for months and months to work.

  The only solution I can imagine at this stage is to calculate the month and the day of the day of the year, which would imply a choice of the month table and a check of the leap year.

  Smart solutions, I'm missing?

  DaveT

  Dave,

  I found a Julian Georgian so far.

• Calculate the number of days remaining until the next anniversary. Help, please!

  Hi guys,.

  I'm new to the forum and to the development of BB. So please do not judge harshly if the answer to my question seems obvious.

  I need to calculate the number of days until the next birthday (taking into account any valid birth date)

  After looking at the API and the forum search, I realized that I could

  calculate the difference between two dates in milliseconds and then divide the delta of the value of a day in milliseconds. That is to say:

  birthdayCalendar.set (Calendar.YEAR, those);

  Date1 = birthdayCalendar.getTime () .getTime ();

  date2 = System.currentTimeMillis ();

  Delta = date1 - date2

  numOfDays = delta\DateTimeUtilities.ONEDAY

  Here's my question. How do I create a valid date1 what about leap years?

  Maybe there's a better way to solve this problem?

  Any help is greatly appreciated.

  I agree that the determination of the number of days between today and Feb. 29 could be a little difficult, if it is not a leap year.  I suspect that the calendar has a certain built-in mechanism to compensate for this, but your solution to choose a date is better.

  DST has a role to play, and Yes, the calendar makes up for it.  Let us take two dates, for example (before DST) March 1 and June 1 (after the DST).  If you take a calendar and set the same hour, minute, etc., they are all the same except for dates, then subtract one from the other, and then divide by the number of milliseconds in 1 hour, you calculate the number of hours between the same time on two different days.  You will find that it is not a multiple of 24 hours - because there is actually an hour less than the number of days since the clocks move forward (in the northern hemisphere anyway...),

  In your case, you are not calculating the number of hours, you calculate the number of days.  But you will be dividing by [24 * (time in an hour)].  If you take [23 * (time in an hour)] and divide it by [24 * (time in an hour)], using arithmetic on integers, you will end up 0.  The easiest to get around this, who also works for the end of the DST too, is to simply add one hour to the date before the division.

  Hope that makes sense...

• How to calculate the first day of the month following in BI Publisher

  I need to be able to calculate the first day of the month of a date field in a BI Publisher model. The field name is COL_CLM_180 and contains a date in the format "YYYY-MM-DD". I have found so far any documentation that still gives me an idea of what to do.

  Any help or advice would be appreciated

  Hi - thank you very much for your help. Your last answer got me going in the right direction and I indeed was dense. I don't know why I don't think to the calculation in the original query. I put the statement: TRUNC (ADD_MONTHS(A.COL_CLM_180,1), 'MM') in a column in the query of conduct and it has worked flawlessly. Thank you - thank you - thank you.

• Calculate the hours between 2 business days

  Hi all

  Do a complex calculation on the days I do not know how to achieve this.

  Here is my case:

  I have a week of work with hours of work.

  

  Then there's this delivery time sheet for how long should be set an order ready to be delivered:

  Order1: max 5 hours of work

  Order2: max 8 working hours

  Order3: max 16 hours of work

  When an order is placed, the time of the order is recorded, and when an order has been set in ready to be delivered, this time is also registered.

  How to calculate the time difference between the time where an order has been placed and the time where the order has been on loan. Thereby also taking into account the working days and hours of work.

  Example: type order1 order was placed Tuesday at 15:00.

  Order has been fixed loan Wednesday at 14:00

  This means that to fix this ready order lasts 7 hours, which means that it is 2 hours time.

  CREATE TABLE REF_WORKDAYS
    (
      
      "WERKDAG"       VARCHAR2(15 ) NOT NULL ENABLE,
      "SOORT_WERKDAG" VARCHAR2(15 ) NOT NULL ENABLE,
      "BEGIN_TIJD"    VARCHAR2(10 ) NOT NULL ENABLE,
      "EIND_TIJD"     VARCHAR2(10 B) NOT NULL ENABLE,
      
    )
  

  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Monday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Tuesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Wednesday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Thursday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Friday','WORKINGDAY','08:00','16:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Satrurday','WORKINGDAY','08:00','14:00');
  Insert into REF_WORKDAYS (WERKDAG,SOORT_WERKDAG,BEGIN_TIJD,EIND_TIJD) values ('Sunday','NOT-WORKINGDAY','08:00','16:00');
  
  COMMIT;
  

  create table glas_order
  
  (order_id number
  , order_desc varchar2(100) not null
  , order_type varchar2(10) not null
  , order_date date not null
  , order_ready date
  
  );
  

  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (1,'order bla','Order1',to_date('07-APR-15 09:00','DD-MON-RR HH24:MI'),to_date('08-APR-15 12:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (2,'order nice','Order1',to_date('14-APR-15 10:00','DD-MON-RR HH24:MI'),to_date('16-APR-15 16:00','DD-MON-RR HH24:MI'));
  Insert into GLAS_ORDER (ORDER_ID,ORDER_DESC,ORDER_TYPE,ORDER_DATE,ORDER_READY) values (3,'order ugly','Order2',to_date('18-APR-15 13:00','DD-MON-RR HH24:MI'),to_date('21-APR-15 09:00','DD-MON-RR HH24:MI'));
  
  COMMIT;
  

  Thank you

  Diana

  Select

  I like order_id

  such as length d

  order_type

  d decode(order_type,'Order1',5,'Order2',8)

  overtime

  of glas_order o

  model

  Reference r on

  (select

  WERKDAG w

  begin_tijd b

  e eind_tijd

  , (to_date (eind_tijd, 'HH24') - to_date (begin_tijd, 'HH24')) * 24 hard

  of ref_workdays

  where soort_werkdag = "WORKINGDAY")

  dimension (w)

  measures (b, e, hard)

  main m

  partition of (order_id I)

  size of (0 n)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as wday, order_type)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')), to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -bigger (to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI'), least (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  TO_DATE (to_char (order_date [0], 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  -bigger (order_date [0], to_date (to_char (order_date [0], 'YYYYMMDD') | r.b [WDAY [0]],'YYYYMMDDHH24:mi'))))

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  less (order_ready [0], to_date (to_char (order_ready [0], 'YYYYMMDD') | r.e [WDAY [0]],'YYYYMMDDHH24:mi'))))

  -to_date (to_char (order_ready [0], 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  ORDER_ID	DURATION	ORDER_TYPE	OVERTIME
  1	11	Order1	6
  2	22	Order1	17
  3	10	Order2	2

  Rewrittten party rules for readability purposes (more resources)

  measures (0d, order_date, order_ready, cast (null as varchar2 (10)) as to_date (null), (null) to_date, bd, order_type, wday ed)

  iterate (1e6) rules until (iteration_number > = trunc(order_ready[0]) - trunc(order_date[0])))

  WDAY [0] = to_char (order_date [0] + iteration_number, 'FMDay', 'NLS_DATE_LANGUAGE = ENGLISH')

  , comics [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.b [WDAY [0]], 'YYYYMMDDHH24:MI')

  , ed [0] = to_date (to_char (order_date [0] + iteration_number, 'YYYYMMDD') | r.e [WDAY [0]], 'YYYYMMDDHH24:MI')

  , d [0] = d [0] +.

  case

  When trunc(order_date[0]) = trunc(order_ready[0]) - beginning and ready same day

  then presentv (r.b [wday [0]],)

  less (largest (order_ready [0], [0] bd), ed [0])

  -Greatest (BD [0], least(ORDER_DATE[0],ED[0]))

  0) * 24

  When order_date [0] + iteration_number = order_date [0] - first day

  then presentv (r.b [wday [0]],)

  ED [0]

  -Greatest(ORDER_DATE[0],BD[0])

  0) * 24

  When trunc(order_date[0]) + iteration_number = trunc(order_ready[0]) - last day

  then presentv (r.b [wday [0]],)

  least(order_ready[0],ED[0])

  -bd [0]

  0) * 24

  of another nvl (r.dur [wday [0]], 0)

  end

  )

  Jubilee should be Saturday I guessed.

• PL/SQL function to calculate the non-working days

  Hello

  I have the following pl/sql function which generates a number of days between two selected dates (i.e. excluding weekends). However, I also need to exclude specific holidays - day of Christmas etc. These holiday dates are stored in a table in our database (11 GR 2) called "HOLIDAY".

  How can I integrate the holidays which is held in the table of holidays in the following query to exclude these dates as well? I know how to write a separate funtion pl/sql for a number of days between two dates using SELECT... BUT I can't work out how to bring together them in a single query.

  Could someone show me how with the pl/sql / dates below please?

  Example of HOLIDAY table below.

  Thank you!

  TP

  create or replace
  function WORKING_DAYS (pi_start_date in date, pi_end_date in date) return integer
  
  is
  
  v_start_date date :=pi_start_date;
  v_end_date date:=pi_end_date;
  v_count integer:=0;
  
  begin
  
  while v_start_date <= v_end_date
        loop
                          if to_char(v_start_date,'D') not in ('6','7')                    
                          then
                          v_count := v_count+1;                       
                          end if;
                         
                  v_start_date:=v_start_date+1;
                 
        end loop;
       
  return v_count;
  
  end;
  
  

  (select '10-Apr-2013' as NWD from dual union all
  select '06-May-2013' from dual union all
  select '27-May-2013' from dual union all
  select '26-Aug-2013' from dual union all
  select '26-Dec-2013' from dual union all
  select '25-Dec-2013' from dual union all
  select '01-Jan-2014' from dual union all
  select '18-Apr-2014' from dual union all
  select '21-Apr-2014' from dual union all
  select '05-May-2014' from dual union all
  select '26-May-2014' from dual union all
  select '25-Aug-2014' from dual union all
  select '25-Dec-2014' from dual union all
  select '26-Dec-2014' from dual) HOLIDAYS
  

  Hello

  the link is on MOSC, not OTN... Here's a copy:

  This function calculates the number of days between two dates, ignoring weekends and holidays (if requested and if the holidays are stored in a table)

  I give an example of table 'public_holiday' with sample data, but users must ensure that their table contains the relevant data (all holidays within the maximum range of use of the service)

  CREATE TABLE public_holiday (calendar_day, DATE, text VARCHAR2 (30));

  FUNCTION to CREATE or REPLACE nb_days (p_date_from IN DATE

  p_date_to DATE by DEFAULT TRUNC (sysdate)

  , p_public_holidays in CHAR DEFAULT 'Y '.

  ) RETURN NUMBER

  DEFINE AUTHID

  AS

  /*********************************************************************/

  / * Author: Bruno Vroman * /.

  / * Created: 23-AUG-2012 * /.

  / * Last updated: 23-AUG-2012 * /.

  / * Object: to calculate the number of days between 2 dates, to the exclusion of * /.

  / * Saturday and Sunday, but also "holidays" If the * /.

  / * argument 'p_public_holidays' = 'Y ' * /.

  / * Support: p_date_from<= p_date_to                             ="">

  / * component ' hour min dry "ignored (just counting days) * /.

  /* First step:                                                       */

  / * the calendar days between 2 days * /.

  / Remove 2 days for each "week" and 0 or 1 extra day * /.

  / * function to a condition "complex" mix day of first week * /.

  / * and the number of days when full remaining weeks are removed * /.

  / * (set up once for all, for example if there is 3 days and the * /)

  (/ * first day is a Thursday, there is 1 "Sat/Sun" to subtract) * /.

  / * Second step: If 'p_public_holidays' = 'Y': other * /.

  / * days, do not count holidays.                         */

  / Holiday everyday are defined in a table "public_holiday" * /.

  / * Note: there may be holidays defined on Saturday/Sunday.       */

  /*********************************************************************/

  l_result NUMBER;

  l_from DATE;

  l_to DATE;

  l_case tank (4);

  BEGIN

  l_from: = TRUNC (p_date_from);

  l_to: = TRUNC (p_date_to);

  l_case: = TO_CHAR (l_from, 'Dy', 'NLS_DATE_LANGUAGE = English').

  To_char (MOD (l_to - l_from + 1, 7));

  l_result: = l_to - l_from + 1

  -TRUNC ((l_to-l_from + 1) / 7) * 2

  -CASE

  WHEN l_case IN ('Mon6', 'Tue5', 'Wed4', 'Thu3', 'Fri2'

  , "Sat1", "Sun1", "Sun2', 'Sun3", "Sun4".

  , "Sun5', 'Sun6.

  )

  THEN 1

  WHEN l_case IN ('Tue6', 'Wed5', 'Wed6', 'Thu4', "Thu5"

  , 'Thu6', 'Fri3', 'Fri4', 'Fri5', 'Fri6 '.

  , "Sat2", "Sat3', 'Sat4', 'Sat5", "Sat6.

  )

  THEN 2

  0 OTHERWISE

  END

  ;

  IF SUPERIOR (p_public_holidays) = "Y".

  THEN

  SELECT l_result - COUNT (*)

  IN l_result

  OF public_holiday p

  WHERE p.calendar_day > = l_from

  AND p.calendar_day<=>

  AND SUBSTR (TO_CHAR (p.calendar_day

  , "Dy".

  'NLS_DATE_LANGUAGE = English'

  )

  , 1, 1 ) != 'S'

  ;

  END IF;

  RETURN l_result;

  EXCEPTION

  WHILE OTHERS

  THEN

  DBMS_OUTPUT. Put_line (' CTF nb_days (' |))

  To_char (p_date_from, "MON-DD-YYYY"). ', ' ||

  To_char (p_date_to, "MON-DD-YYYY"). ', ' ||

  p_public_holidays | ' ) : ' || SQLERRM

  );

  LIFT;

  END nb_days;

  /

  REM

  REM example:

  REM A) fill out the 'public_holidays '.

  REM

  TRUNCATE TABLE public_holiday;

  INSERT INTO public_holiday VALUES (DATE ' 2012-01-01', ' new year (a Sunday)');

  INSERT INTO public_holiday VALUES (DATE '' 2012-01-03, "for example");

  REM (insert other days...)

  COMMIT;

  Call the function for some pairs of dates of REM B)

  REM nb1: remove only Sat/Sun

  REM nb2: also remove holidays

  REM

  ALTER SESSION SET nls_date_format ='Dy DD-MON-YY';

  WITH some_dates AS

  (SELECT DATE ' 2011-12-29'd dual FROM

  UNION ALL SELECT DATE ' 2012-01-08' FROM dual

  UNION ALL SELECT DATE ' 2012-01-10' FROM dual

  )

  SELECT d1.d 'FROM '.

  , d2.d ' to THE '.

  , nb_days (d1.d, d2.d, ' don't) nb1

  , nb_days (d1.d, d2.d, 'Y') nb2

  OF some_dates d1

  some_dates d2

  WHERE d1.d<=>

  ORDER BY nb1, nb2, d1.d

  ;

  GO TO NB1 NB2

  ------------- ------------- ---- ----

  Monday, January 8, 12 Monday, January 8, 12 0 0

  Friday, December 29, 11 Friday, December 29, 11 1 1

  Wednesday, January 10, 12 Wednesday, January 10, 12 1 1

  Monday, January 8, 12 Wednesday, January 10, 12 2 2

  Friday, December 29, 11 Monday, January 8, 12 7 6

  Friday, December 29, 11 Wednesday, January 10, 12 9 8

  Hope that this could be useful, but note that this code has not been completely tested, so check and test before you trust it (in the case of any questions, please post a comment)

  Bruno Vroman.

  Best regards

  Bruno

• Calculate the number of days off weekends

  
  Hi all

  I have a requirement where I have to calculate the difference between two dates, excluding weekends and holidays. Is there a way I can do it in OBIEE analysis.

  Any help would be appreciated.

  Thanks in advance!

  Check it for weekends cool - bi.com

  For the holidays, you will need to customize you the size of the day

  check if help

• How to calculate the number of days/weeks/months between 2 dates?

  Hello
  
  I would like to know how to calculate the number of days/weeks/months between 2 dates in OBIEE 11 g, for example, I have 26/05/2013 and 19/05/2013, then I want to get 7 days.
  
  Thank you!
  Jamie

  Hi Jamie,

  Through this links...

  http://www.bravesoft.com/blog/?p=682
  http://twobiee.blogspot.in/2012/01/working-with-date-differences.html

  Mark as correct it allows u...
  Thank you...