How to find the partitioned tables and the number of sheets in each table

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  I wrote a table of number in 2 groups of columns in a file using LabWindows/CVI ArrayToFile... Now, if I want to read the file with the FileToArray function so how do I know the number of items in the file. during the time of writing, I know how many elements array to write. But assume that I want the file to be read at a later time, then how to find the number of items in the file, so that I can read the exact number and present it. Thank you all

  Hello

  I start with the second question:

  bytes_read = ReadLine (file_handle, line_buffer, maximum_bytes);

  the second argument is the buffer to store the characters read, so it's an array of characters; It must be large enough to hold maximum_bytes the value NULL, if char [maximum_butes + 1]

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• A torn my sticker with the serial number. How to find the number of the whole installation?

  Best regards, tore my sticker with the serial number. I don't see the numbers. How to find the number of the whole installation?

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• How to find the number of users connected to the database of the level operating system (Linux)

  Hi all
  
  Could someone knows how to find the number of users connected to the database without connection with sql * more
  
  y at - it a command to find?
  
  example, we have 10 databases in a server, how to find the number of users connected to the special data base without connecting to database(v$session)?
  
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  Thank you.
  
  Kind regards
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• How to count the number of nodes under each parent in any given xml

  How to count the number of nodes under each parent in any given xml. for example the xml below was
  books has 3 childern, library [1] has 4, [2] library has 6 and bookshop [3] has 2. is it possible to get the number of tags in a childnode duplicate IE library [1]
  Book1 Tagus repeated twice... vice versa. do we need to make plsql lie we can achieve through sql
  
  < book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  ACR < book1 > < / book1 >
  Lac < Book4 > < / Book4 >
  < / book >
  < library >
  ABC < book1 > < / book1 >
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  ACR < book3 > < / book3 >
  ACR < book3 > < / book3 >
  tray of < bookn_1 > < / bookn_1 >
  adjusted cost base < bookn > < / bookn >
  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
  < / books >
  
  
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  Select
  XMLQUERY ('count($doc/Books/Bookstore[1]/descendant::*)' in the way of xmltype ("< books >
  < library >
  ABC < book1 > < / book1 >
  ACR < book1 > < / book1 >
  Lac < Book4 > < / Book4 >
  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
  (< / books > ')
  as 'doc' of happy return) .getNumberVal () as node_count
  of the double
  
  Select
  XMLQUERY ('count($doc/Books/descendant::*)' in the way of xmltype ("< books >
  < library >
  ABC < book1 > < / book1 >
  ACR < book1 > < / book1 >
  Lac < Book4 > < / Book4 >
  < / book >
  < library >
  ABC < book1 > < / book1 >
  BCA < book2 > < / book2 >
  < / book >
  (< / books > ')
  as 'doc' of happy return) .getNumberVal () as node_count
  of the double
  
  How can I get the counts for each parent in a single query
  
  Published by: user7955917 on August 24, 2012 07:26

  Generic function how you want the query to be.

  If the structure is known in advance, as in your example a 'books' and then a 'library' root element, it's as simple as:

  SQL> select x1.parent_id, x2.child_name, count(*)
    2  from tmp_xml t
    3     , xmltable(
    4         '/books/bookstore'
    5         passing t.object_value
    6         columns parent_id   for ordinality
    7               , child_list  xmltype path '*'
    8       ) x1
    9     , xmltable(
   10         '/*'
   11         passing x1.child_list
   12         columns child_name varchar2(30) path 'name()'
   13       ) x2
   14  group by x1.parent_id, x2.child_name
   15  order by x1.parent_id, x2.child_name
   16  ;
  
   PARENT_ID CHILD_NAME                       COUNT(*)
  ---------- ------------------------------ ----------
           1 book1                                   2
           1 book2                                   1
           1 book4                                   1
           2 bookn                                   1
           2 bookn_1                                 1
           2 book1                                   1
           2 book2                                   1
           2 book3                                   2
           3 book1                                   1
           3 book2                                   1
  
  10 rows selected
   
  

  If you want a generic solution that works without knowledge of the structure, you will need a recursive approach, and most importantly, you should know which nodes in distinct, I suppose that the leafs?

  Also, please help if you can provide the link of reference on the function name() years what are the other expression, that I can use after the path

  You can start reading the documentation: http://docs.oracle.com/cd/E11882_01/appdev.112/e23094/xdb_xquery.htm#CBAGCBGJ

  The clause PATH expects a XQuery expression however before 11.2, we can put only simple XPath expressions.

• How to find the first max value for each item

  Hello
  
  I have the me_result of the table as below,
  
  SELECT * FROM me_result;
  
  ID     ||| ELITE     ||||||||||| FREQ_ITEM | COMBINED_STR | SUP
  1     ||; 1; 10; 2; 3; 4; 5; 7; 8. 1     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  2     ||; 1; 10; 2; 3; 4; 5; 7; 8. 2     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  3     ||; 1; 10; 2; 3; 4; 5; 7; 8. 3     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  4     ||; 1; 10; 2; 3; 4; 5; 7; 8. 4     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  5     ||; 1; 10; 2; 3; 4; 5; 7; 8. 5     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  6     ||; 10; 2; 3; 4; 5; 8; 9. 1     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9; 1 ||| 1
  7     ||; 10; 2; 3; 4; 5; 8; 9. 2     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  8     ||; 10; 2; 3; 4; 5; 8; 9. 3     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  9     ||; 10; 2; 3; 4; 5; 8; 9. 4     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  10     ||; 10; 2; 3; 4; 5; 8; 9. 5     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  
  
  I need to find the first COMBINED_STR max for each element of the ELITE,
  I mean, max value is the max REGEXP_COUNT (combined_str,' ;')))
  
  really, I try to write down, but I had a lot of values for each ELITE and I need only the first, that
  SELECT * from me_result
  WHERE (ELITE, REGEXP_COUNT (combined_str,' ;')))) IN
  (SELECT ELITE, MAX (REGEXP_COUNT (combined_str,' ;'))))) ME_RESULT ELITE GROUP);
  
  I need the result to be as below.
  
  1; 1; 10; 2; 3; 4; 5; 7; 8-1; 1; 10; 2; 3; 4; 5; 7; : p
  6; 10; 2; 3; 4; 5; 8; 9 1; 10; 2; 3; 4; 5; 8; 9; 1 1
  
  any help please,.
  
  Published by: user11309581 on July 10, 2011 22:03

  Can be

  with t as
  (select 1     ID, ';1;10;2;3;4;5;7;8'     ELITE, 1     FREQ_ITEM, ';1;10;2;3;4;5;7;8' COMBINED_STR, 2 SUP from dual union all
  select 2     ,';1;10;2;3;4;5;7;8'     ,2     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 3     ,';1;10;2;3;4;5;7;8'     ,3     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 4     ,';1;10;2;3;4;5;7;8'     ,4     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 5     ,';1;10;2;3;4;5;7;8'     ,5     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 6     ,';10;2;3;4;5;8;9'     ,1     ,';10;2;3;4;5;8;9;1'     ,1 from dual union all
  select 7     ,';10;2;3;4;5;8;9'     ,2     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 8     ,';10;2;3;4;5;8;9'     ,3     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 9     ,';10;2;3;4;5;8;9'      ,4     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 10     ,';10;2;3;4;5;8;9'     ,5     ,';10;2;3;4;5;8;9'     ,2 from dual
  )
  select ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP
  from (
    SELECT ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP, ROW_NUMBER() over (PARTITION BY ELITE order by id) RN
    FROM t
    WHERE (ELITE,REGEXP_COUNT(combined_str,';')) IN
      (SELECT ELITE,MAX(REGEXP_COUNT(combined_str,';')) FROM t GROUP BY ELITE)
  ) where RN=1
  order by id
  
  ID                     ELITE             FREQ_ITEM              COMBINED_STR      SUP
  ---------------------- ----------------- ---------------------- ----------------- ----------------------
  1                      ;1;10;2;3;4;5;7;8 1                      ;1;10;2;3;4;5;7;8 2
  6                      ;10;2;3;4;5;8;9   1                      ;10;2;3;4;5;8;9;1 1     
  

• HP PSC 2410-how to find the number of pages

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  Hi @jay2769,

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  Re: Get the Date difference between 2 values of date in days

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  It is considered good etiquette to the answerers rewards with points (as "useful" - 5 pts - or 'correct' - 10pts)
  https://forums.Oracle.com/forums/Ann.jspa?annID=893