How to get the ID of the layer name layer?

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• How to get the host name of the physical computer inside a virtual machine until the user logs in Windows?

  I don't know if this is the right place to post this question, I develop software to support VMWare PCoIP and need to know how to get the host name of the physical machine (which manages the virtual machine and View Client) within a virtual machine before the user logs in Windows of the virtual machine.

  I understand there are two ways to read the host name, via the HKEY_CURRENT_USER\Volatile Environment registry and environment variables, but they are available once the user is connected. I need info before the user connects.

  Is there a VMware API that can be called or asked the host name?

  Thank you.

  Not on the broker, but there are the startup scripts to log on to the computer virtual itself: http://pubs.vmware.com/view-52/topic/com.vmware.view.integration.doc/view_integration_startsession_script.9.2.html

  Note that these executed when a virtual desktop computer allocated connection, not to the point that the client connects - it is possible for the customer to not complete the connection (crash, cancel, network failure) and so any what solution you design must handle this.

  Mike

• How to get the Base name of the executable process

  Hi all
  I have a problem for the creation of SQL AnyWhere Plugin (Database Plugin). In this regard, ServerDetector class long pids [] = getPids ("State.Name.eq =?"). Instead of question mark that I place. And how to get the name of this executable process.
  
  Thanks and greetings
  Florent K Reddy

  Take a look at the doc following if you have not already:

  http://support.Hyperic.com/Confluence/display/Sigar/PTQL

  State.Name is the name of the base of the executable of the process, such as "dbsrv9.

  On 16 May 2007, at 23:24, fredo Reddy wrote:

  Hi all
  I have a problem for the creation of SQL AnyWhere Plugin (Database Plugin). In this regard, ServerDetector class long pids [] = getPids ("State.Name.eq =?"). Instead of question mark that I place. And how to get the name of this executable process.

  Thank you & best regards
  Florent K Reddy

• How to get the computer name - forms 10g

  Hello
  
  How to get the name of the server or some other identification forms 10g Application?
  We have several servers and host load balancing redirects user to the X Server and the forms application, I have to get information from the server to which the user was redirected? Is there a way how to do?
  
  It can be the name of the server, Ip or other identifying information...
  
  Thank you.

  As the client that connects to the database is the application server

  CHE_TEST@tcp_asterix_impl> select sys_context('userenv', 'host') from dual;
  
  SYS_CONTEXT('USERENV','HOST')
  ----------------------------------------------------------------------------
  LINZ\CHE-WS
  

  Should return you the host name of your application server.

  See http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions165.htm#SQLRF06117 for more information you can get with sys_context

  see you soon

• How to get the full name of the user to a sso.

  Hi all
  
  I am brand new with oracle application server.
  I use oracleAS 10g with SSO enabled. How can I get the full names of the users?
  I know that this information can be obtained with the command 'ldapseach' but I'm looking for information in a view or a package.
  Is it possible to get this information in a view or a package?
  
  Thank you.

  Look at the portal.wwse_api function person_info package
  Maybe it's something similar that you are looking for

• [MAF] How to get the user name and password after login?

  Hi Experts,

  I have a call to REST where it requires identification information of the user (uname and password) to identify the data that belongs to who.

  Authentication has been made with OAuth.

  I believe that there is an API to get the user name and password in the CRG

  See you soon,.

  Hendry

  Hello.

  You don't need to manipulate the credentials yourself in code. MAF will propagate the logon cookie or inject the identification information in the HTTP header if cookies are not supported.

  To do this, you must select the purchase option of cookie from the server connection Include in REST in the dialog box create a connection Login MAF , such as discussed here:

  http://docs.Oracle.com/middleware/maf210/mobile/develop/MAF-securing.htm#ADFMF23732

  In addition, you must attach the policy of security appropriate to the connection, as explained here:

  http://docs.Oracle.com/middleware/maf210/mobile/develop/MAF-Web-services.htm#ADFMF23697

  Best regards

  Frédéric Desbiens

  Senior Product Manager

  Mobility and Cloud oracle

  Twitter: @BlueberryCoder

  blog: http://blogs.oracle.com/blueberry

• How to get the full name of the user of the OPS?

  Hi Experts,

  I know we can get the login controller pageContext.getUserName () user name. Is there a simple way/API to get the full name of the user (name, first name) of the OPS?

  Thank you.

  Hello

  USER name and information of the PERSON are two different concepts. You can get the id of user with pageContext.getUserId () connection. In order to get the first name, last name, you must select it from table PER_ALL_PEOPLE_F.

  You can use the sql select and set pUserId of pageContext.getUserId ();

  SELECT FIRST_NAME, LAST_NAME TO PAP PER_ALL_PEOPLE_F, FND_USER FU

  WHEN TRUNC (SYSDATE) BETWEEN PAP. EFFECTIVE_START_DATE AND PAP. EFFECTIVE_END_DATE

  AND FU. EMPLOYEE_ID = PAP. PERSON_ID

  AND FU. User_id =: pUserId

  Anil

• How to get the user name during the execution of a workflow?

  Here's what I would do:

  Say that each user is allowed to have 4 instances QA, create a workflow when a user run from vCenter plugin, it must be able to get the user name of the SSO user jsmith, and then he questions if there is an existing virtual machine jsmith_qa1, jsmith_qa2,jsmith_qa4, etc., if there isn't one, then create one for him; If not, indicate to the user that there are already 4 cases.

  I found that I can use getCurrentLdapUser to get [email protected] , now I want to remove the domain.name (there are several areas):

  username = actionResult.userPrincipalName.replace ("@[a - z].") +","");

  This does not work. Anyone know where I can find the right document for the document script of vRealize Orchestrator?

  Thank you!

  Jack

  vRO uses javascript as its scripting engine.

  UPN var = actionResult.userPrincipalName;

  var username = upn.substring (0, upn.indexOf("@"));

  Something like this will give what you want. You could also do a replacement, but I think that you should remove the quotes around the regex and use "/" instead.

  username = actionResult.userPrincipalName.replace (/ @[a - z] "+ /," "");

  Paul

• How to get the role name of the OIM 11 g using the API

  Hello
  I have a scenario in which I create role/group of OIM 11 g & she gets supplied with AD [= works great] & other party it is when I remove role in OIM 11 g then it should
  removed from the AD. I wrote the postprocess event handler to achieve this goal.
  In the authoring part of role I get all the parameters by using "orchestration.getParameters ()"; but when I delete the role then "orchestration.getParameters ();" is empty, so I'm
  Unable to get the name of the role.
  Is there a way to get the role name when you remove roles by using the API?
  
  Thank you
  Rahul Shah

  Hello

  To implement using pre-wet the handler rather post-processing.

  Kind regards
  Ralu

• How to get the file name of the current active document in InDesign CS4?

  Hello

  If I open a document in the file-> open, I can get the file name of the document using IOpenedFileInfo-> GetOpenedFilePath().

  But, if I create a new document and run the file-> save as, GetOpenedFilePath is invalid back reference IdFichier.

  What is the right way to get the file name of the active document?

  Thank you

  VSP

  You can try this:

  IDatabse * db =: GetDatabase (theDoc);

  IdFichier * SYSIXCOL = db-> GetSysFile();

  PMString docName is SYSIXCOL-> GetFileName();.

  Good luck

• How to get the customer name, UUID, and cluster comments

  Hello

  I was wondering if somone could show me how to tie somethings together. I can get a VM UUID, I can get the names of the virtual machines and the cluster on which they sit, but I'm having a hard time getting all 3 into a single csv report. All the world is that who could share? Thank you!

  Try this

  Get - VM | Select Name,@{N="UUID; E={$_. ExtensionData.Config.Uuid}},@{N="Cluster '; E={($_ | Get - Cluster). Name}}

• How to get the user name in "atfer serverror" trigger?

  Hi people;
  
  How do I get the name of the user who simply lack connection to the database in a trigger "after serverror"?
  The code of the trigger:

  create or replace
  TRIGGER TRG_LOGGON_FAILURES 
  AFTER SERVERERROR ON DATABASE 
  BEGIN
    IF (IS_SERVERERROR(1017)) THEN
    UPDATE utilisateur_ora SET UTO_STA='BLOQUE', UTO_DATE_STATUT=sysdate WHERE UTO_USR_GPL=<var_user>;
    COMMIT;
    END IF;
    
  END;

  11.2 you can use

  sys_context('userenv', 'authenticated_identity')
  

• How to get the instance name of the Clip?

  Hello!

  Is there a way to get the name of the instance of an element of travel when he's on the stage?  In my dress up game, I need to know which elements are on the doll to keep them visible.  My drag and drop feature uses a table and currentTarget:

  var dragArray:Array = [Doll.Drawers.Dress1, Doll.Drawers.Dress2, Doll.Drawers.Dress3, Doll.Drawers.Dress4];
            
            for(var i:int = 0; i < dragArray.length; i++) 
              {
                      dragArray[i].buttonMode = true;
                      dragArray[i].addEventListener(MouseEvent.MOUSE_DOWN, item_onMouseDown);
                      dragArray[i].addEventListener(MouseEvent.MOUSE_UP, item_onMouseUp);
              }
  
  
  function item_onMouseDown(event:MouseEvent):void 
            {
                 var clip:MovieClip = MovieClip(event.currentTarget);
                 clip.startDrag();
            }
    
  function item_onMouseUp(event:MouseEvent):void 
            {
                 var clip:MovieClip = MovieClip(event.currentTarget);
                 clip.stopDrag();
                 if(clip.hitTestObject(Doll.Skins))
                      {
                               //Here's where the problem starts!   ----------------------------------------------  //
                                trace("It's on the doll!");
                      }
            }
  
  

  It can run this code.  However, instead of plotting "It's on the doll!", I would like to transform the currentTarget in its instance name, which should be "Doll.Drawers.Dress1" etc. and to register this name in a table.

  How can I do this?

  I looked into e.target.name, but I keep getting errors...

  Use the name property of the item (if it is the movieclip that you want the name):

  var dragArray:Array = [Doll.Drawers.Dress1, Doll.Drawers.Dress2, Doll.Drawers.Dress3, Doll.Drawers.Dress4];
  
            for(var i:int = 0; i < dragArray.length; i++)
              {
                      dragArray[i].buttonMode = true;
                      dragArray[i].addEventListener(MouseEvent.MOUSE_DOWN, item_onMouseDown);
                      dragArray[i].addEventListener(MouseEvent.MOUSE_UP, item_onMouseUp);
              }
  
  function item_onMouseDown(event:MouseEvent):void
            {
                 var clip:MovieClip = MovieClip(event.currentTarget);
                 clip.startDrag();
            }
  
  function item_onMouseUp(event:MouseEvent):void
            {
                 var clip:MovieClip = MovieClip(event.currentTarget);
                 clip.stopDrag();
                 if(clip.hitTestObject(Doll.Skins))
                      {
                               //Here's where the problem starts!   ----------------------------------------------  //
                                trace(clip.name);  // but that won't be Doll.Drawers.Dress1.  it might be Dress1.
                      }
            }
  
  
  

• How to get the user name in a workflow?

  I have a simple request of what appears to be a basic workflow step.
  
  I create a workflow that has the user approve/reject their own review as the first step of the workflow. My question is, how do I get the username of each document as it comes in the workflow?
  
  I read on wfAddUser. If that's what I use, how to use it and where I can add it to the Workflow screen?
  
  Thank you.

  I don't know exactly what you are after all in a row. You want to get the original author?

  The document is checked and the user name is registered. It is the only name available at the moment where the document to enter the workflow, which would be the only user attached to the content so far.

  have you tried looking at the dDocAuthor variable?

• How to get the database name/IP address of the server forms10g database

  Hello world
  How can I get the name of the database instance and the IP address of the database server?
  
  I use GEC 10 g and the database server is Oracle 10 g.
  
  Dobbelaere

  How can I get the name of the database instance and the IP address of the database server?

  To use the IP UTL_INADDR

  For example name you can use sys_context ('userenv', 'instance_name')
  or
  SQL > select instance_name from v$ instance;

• How to get the file names?

  Hello

  I have two questions,

  1. I have a set of xml files in a folder in a blackberry. I need to be able to read the contents of the folder that is read all the names of the xml files and be able to display them. How should I do for this?

  2. the samples of the fileconnection class containing all to access the .txt files. Is it not possible to read other files and .xml files?

  just give the path up to the last directory...

  try {}
  FileConnection fconn = (FileConnection)Connector.open("file:///SDCard/BlackBerry/documents",Connector.READ_WRITE);
                
  If (! fconn.exists ())
  {
                        
  Enumeration e = fconn.list ("*", true);

  }

  This will retrieve all the file name in the folder of document...

  See you soon!