How to get the sum of "(qty*rate) as salesValue 'as TotalSalesValue cust_id agenda?"

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• How to get the sum of the first row in the previous row?

  Dear gurus... I need to get the sum of a column of the first row of my result set to the previous line based on a condition. I read analytical functions for this but they provide the sum of the first rank to Current Row through declaration "rows between Unbounded preceding and current line. Y at - it a statement that calculates the sum as "rows between Unbounded preceding and previous row?

  Hello

  kamranpathan wrote:
  Dear gurus... I need to get the sum of a column of the first row of my result set to the previous line based on a condition. I read analytical functions for this but they provide the sum of the first rank to Current Row through declaration "rows between Unbounded preceding and current line.

  If you do not explicitly give a windowing clause, then you get the default windowing clause you indicated.
  If you want another clause of windowing, ionclude in the analytic function call.

  Y at - it a statement that calculates the sum as "rows between Unbounded preceding and previous row?

  Yes. The correct syntax for "Previous rank" is «PREVIOUS 1»

  ...  ROWS BETWEEN  UNBOUNDED PRECEDING
              AND        1          PRECEDING
  

  For more information, search for "Analytic Functions" in the manual of the SQL language:
  http://download.Oracle.com/docs/CD/E11882_01/server.112/e17118/functions004.htm#sthref917

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all tables and also post the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.
  You will find the answers better faster if you always provide this information whenever you post a question.

  Published by: Frank Kulash, Sep 17, 2011 17:04
  I just saw Etbin responses.
  As usual, Etbin has a good point. If the column that you are basically cannot be NULL, then it is probably easier to subtract the total current line and use the default windowing clause.
  Even if it can be null, you find may be easier to use this approach.

• How to get the sum by customer?

  Hi, in this query below, I want all the s () basically summing up of each "INVESTOR_CODE", can anyone help please?
  

  select 
  b.INVESTOR_CODE ,
  a.INVESTOR_NAME , 
  b.DEPARTMENT_CODE , 
  b.INVOICE_NO , 
  b.INVOICE_TYPE , 
  trunc(b.INVOICE_date) INVOICE_date, 
  c.COMPANY_SHORT_NAME , 
  sum(INVOICE_COMMISSION)  INVOICE_COMMISSION, 
  sum(INVOICE_KEEPING)  INVOICE_KEEPING , 
  sum(INVOICE_STAMP)  INVOICE_STAMP, 
  sum(INVOICE_OTHER) INVOICE_OTHER,
  sum(INVOICE_MISR) INVOICE_MISR,
  sum(INVOICE_INSURANCE) INVOICE_INSURANCE,
  sum(INVOICE_HAIAH)INVOICE_HAIAH
  from investor a , invoice b , company c , DEPARTMENT d
  where a.INVESTOR_CODE = b.INVESTOR_CODE
  and b.COMPANY_CODE = c.COMPANY_CODE
  and b.DEPARTMENT_CODE  = d.DEPARTMENT_CODE
  and trunc(invoice_date) >= '14-AUG-07'
  exists(select 1 from OPERATION_LINE_SMAEDAY ols where ols.INVOICE_NO  = b.INVOICE_NO and ols.INVOICE_type  = b.INVOICE_type  )
  group by  b.INVESTOR_CODE , a.INVESTOR_NAME , b.DEPARTMENT_CODE , b.INVOICE_NO , b.INVOICE_TYPE , trunc(b.INVOICE_date) , b.INVOICE_TYPE,c.COMPANY_SHORT_NAME
  order by b.INVESTOR_CODE  , INVOICE_date;

  For this table, the following query will do the grouping and order it as you want. You will still combine it with the previous query using the original paintings.

  SQL> select investor_code
    2       , investor_name
    3       , department_code
    4       , invoice_no
    5       , invoice_type
    6       , invoice_date
    7       , company_short_name
    8       , sum(invoice_commission)
    9       , sum(invoice_keeping)
   10       , sum(invoice_stamp)
   11       , sum(invoice_other)
   12       , sum(invoice_misr)
   13       , sum(invoice_insurance)
   14       , sum(invoice_haiah)
   15    from samedaydata
   16   group by investor_code
   17       , investor_name
   18       , rollup
   19         ( ( department_code
   20           , invoice_no
   21           , invoice_type
   22           , invoice_date
   23           , company_short_name
   24           )
   25         )
   26   order by investor_code
   27       , department_code
   28       , invoice_no
   29  /
  
  INVESTOR_CODE INVESTOR_NAME   DEPARTMENT_CODE INVOICE_NO INVOIC INVOICE_DATE        COMPANY_SHORT_NAME   SUM(INVOICE_COMMISSION)
  ------------- --------------- --------------- ---------- ------ ------------------- -------------------- -----------------------
  SUM(INVOICE_KEEPING) SUM(INVOICE_STAMP) SUM(INVOICE_OTHER) SUM(INVOICE_MISR) SUM(INVOICE_INSURANCE) SUM(INVOICE_HAIAH)
  -------------------- ------------------ ------------------ ----------------- ---------------------- ------------------
         240007 john                          2        123 sell   23-04-2010 00:00:00 OTC                                     27.5
                   3.4                  6                  4                 0                      2                 10
  
         240007 john                          2        124 buy    22-04-2010 00:00:00 ORACLE                                  29.6
                   2.4                  6                  4                 0                      2                 10
  
         240007 john                          2        125 sell   01-01-2010 00:00:00 ORACLE                                  63.5
                   2.4                  6                  4                 7                      2                 10
  
         240007 john                                                                                                         120.6
                   8.2                 18                 12                 7                      6                 30
  
         240008 paul                          3        256 sell   19-12-2010 00:00:00 OTC                                     93.5
                   8.4                  6                  4                 0                      2                 10
  
         240008 paul                          3        266 buy    06-03-2010 00:00:00 CBANK                                   83.2
                   3.4                  6                  3                 0                      2                  9
  
         240008 paul                          3        322 buy    23-04-2010 00:00:00 CBANK                                   43.4
                   2.4                  3                  4                 0                      2                  3
  
         240008 paul                          3        423 sell   23-04-2010 00:00:00 OTT                                     24.5
                   2.4                  2                  4                 0                      8                 10
  
         240008 paul                                                                                                         244.6
                  16.6                 17                 15                 0                     14                 32
  
  9 rows selected.
  

  Kind regards
  Rob.

• I have a photography teacher program Adobe and must add Adobe Illustrator for the BSc SAID curriculum I am on at the Academy of digital skills in Dublin, Ireland how I get the student discount to add Illustrator to mentoring rate?

  I have a photography teacher program Adobe and must add Adobe Illustrator for the BSc SAID curriculum I am on at the Academy of digital skills in Dublin, Ireland how I get the student discount to add Illustrator to mentoring rate?

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  Hello

  I have to read 4 analog channels using DAQmx AI read in LabVIEW 2012. I am using screws DAQmx.

  Acquisition rate is 4000 samples per second, and the number of samples per channel is 200.

  I use only one task DAQmx to read the data. I get 4 data tables for 4 channels each table length is 200, every time, DAQmx Read happens.

  But I want to get the seal of these 200 samples per channel. How to get the seal of these samples, made me know.

  Thank you

  You have not indicated your code. If you choose to read the waveform data, the cluster includes t0 and dt. That's all the information you need.

• How to get the balance of an element value

  Hello

  I have a requirement to obtain related information with balance. I am able to read the information on the element except balance.how to get the value of the particular item balance.

  for the application-> transfer and process-> queries with trust-> value the month selected and chosen balances button and queries with the obtained item name break it down the value of the balance.

  These values I want in my query.i tried backend with calling package by passing parameters like the number of transfer, balance the id and date but iam getting value "0".

  IAM new to hrms, Please help me on how to get this balance of values

  Thank you

  Hello

  It is not very clear what you want to display in the form of balance for a given range of dates.

  It depends on how you have configured your balances and periods and balance which you are referring.

  The API allows for a given only date that matches the date earned.

  Say, for example, that you have a "basic salary" defined with a "Treatment period assignment to Date" dimension and feed of the element that corresponds to the base salary.

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  Another way is by querying the tables/views directly: you can use, for example - it's perhaps easier to your situation:

  Select sum (nvl (pbv.value, 0))

  of pay_balance_values_v the VB.

  where pbv.balance_name = 'base salary.

  and pbv.database_item_suffix = '_ASG_PTD. '

  and pbv.assignment_id =

  and pbv.effective_date between to_date (' 01/02/2015 ',' dd/mm/yyyy')

  and to_date (' 31/03/2015 ',' dd/mm/yyyy');

  Kind regards
  Rajen

• try to get the SUM of all of the charges with the having clause

  Hi Oracle users.

  I'm trying to accomplish to get a sum of a series of charges and it should be easy, but I can't get it.

  For example, I have the following.

  Select ACCTLOC,  count(ACCTLOC) AS TOTALP
  FROM BOX_ACCTS_TBL 
   WHERE TIME_REQ > SYSDATE-120
   Group By ACCTLOC
    having (count(ACCTLOC) > 1)
   
   the results are
   
  ACCTLOC   TOTALP
   
  Philly     15970
  NY          8623
  Tacoma        3
  SanFran     195
  Hartford    5
  Miami       4374
  
    
  

  How can I get the SUM of this group? Do I put this in PL SQL and do a procedure to carry out the selection? Is this the way to go on this?
  I appreciate all the comments you can give.

  Thank you!

  with

  query_result as

  (select 'Philly' acctloc, 15970 totalp Union double all the)

  Select "NY", 8623 Union double all the

  Select "Tacoma", 3 double Union all

  Select "SanFran", 195 double Union all

  Select "Hartford", 5 Union double all the

  Select 'Miami', double 4374

  )

  Select acctloc, totalp, sum (totalp) on the_sum, avg (totalp) (on the_avg), ratio_to_report (totalp) (percentages))

  of query_result

  ACCTLOC	TOTALP	THE_SUM	THE_AVG	PERCENTAGES
  Philly	15970	29170	4861.66666666666666666666666666666666667	.547480287967089475488515598217346588961
  NY	8623	29170	4861.66666666666666666666666666666666667	.295611930065135413095646211861501542681
  Tacoma	3	29170	4861.66666666666666666666666666666666667	.000102845389098388755570791909496057593
  SanFran	195	29170	4861.66666666666666666666666666666666667	.006684950291395269112101474117243743572
  Hartford	5	29170	4861.66666666666666666666666666666666667	.000171408981830647925951319849160095989
  Miami	4374	29170	4861.66666666666666666666666666666666667	.149948577305450805622214604045251971203

  Concerning

  Etbin

• How to calculate the sum of two digital form fields based on the selection of the checkbox.

  I have a form in Acrobat Pro who needs a custom calculation. How to calculate the sum of two digital form fields based on a selection of the checkbox. I have three number fields. Field-A and B are simple one or two digits. Field-C is the sum, or the total field. I want to field-C have a control box which, when turned on and off, just gives a. gives the sum of A + B

  _ Field - 2

  _ Field - A 4

  [check] _ _ field - 6 C

  [disabled] _ _ field - 2 C

  Thank you

  The custom field C calculation script could be:

  (function () {
  
      // Get the values of the text fields, as numbers
      var v1 = +getField("A").value;
      var v2 = +getField("B").value;
  
      // Set this field's value based on the state of the check box named "CB"
      if (getField("CB").value !== "Off") {
          event.value = v1 + v2;
      } else {
          event.value = v1;
      }
  
  })();
  

  Replace 'A', 'B', and 'CB' with the real names of the fields.

• How to get the value of PMT in oracle?

  Hi all
  
  I need to calculate the value of the PMT
  
  
  There is the Excel PMT function == > PMT (rate, nPer, PV, (FV), (TYPE))
  
  I have to calculate using pl/sql.
  
  Can any body help how to get the value of PMT in PL/SQL?
  
  Thanks for your help.
  
  Kind regards
  Iwanto

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• Get the sum of all Member of a hierarchy.

  Hello
  I want to get the sum of each Member in a hierarchy.
  The hierarchy is defined in the strdet table:

  create table strdet
  
  (costcenterms varchar2(20),     // parent
  
   costcenterdet varchar2(20),    // child
  
   lev varchar2(1))

  The values for each object/material by costcenter (child) is defined in the details_det table:

  create table details_det
  
  (costcenterms varchar2(20),
  
   eppid varchar2(30) ,
  
   purchcontyear0 number(4,1) )

  Some examples of data:

  insert into strdet values ('1' , '1.1','2')
  
  /
  
  insert into strdet values ('1' , '1.2','2')
  
  /
  
  insert into strdet values ('1.1' , '1.1.1','3')
  
  /
  
  insert into strdet values ('1.1' , '1.1.2','3')
  
  /
  
  insert into strdet values ('1.2' , '1.2.1','3')
  
  /
  
  insert into strdet values ('1.2' , '1.2.2','3')
  
  /
  
  insert into strdet values ('1.2' , '1.2.3','3')
  
  /
  
  insert into strdet values ('1.1.1' , '1.1.1.1','4')
  
  /
  
  insert into strdet values ('1.1.1' , '1.1.1.2','4')
  
  /
  
  insert into strdet values ('1.1.2' , '1.1.2.1','4')
  
  /
  
  insert into strdet values ('1.2.1' , '1.2.1.1','4')
  
  /
  
  insert into strdet values ('1.2.1' , '1.2.1.2','4')
  
  /
  
  COMMIT;

  insert into details_det values('1.1.1.1','epp1',10);
  
  insert into details_det values('1.1.1.1','epp2',20);
  
  insert into details_det values('1.1.1.1','epp3',0);
  
  insert into details_det values('1.1.1.2','epp1',0);
  
  insert into details_det values('1.1.2.1','epp2',5);
  
  insert into details_det values('1.1.2.1','epp4',15);
  
  insert into details_det values('1.2.1.1','epp1',65);
  
  insert into details_det values('1.2.1.1','epp2',95);
  
  insert into details_det values('1.2.1.2','epp1',5);
  
  commit;

  The desired sql stmt output should be like this:

  costcenter             val
  
  --------------             ------
  
  1                        220 
  
  1.1                       55
  
  1.2                     165
  
  1.1.1                    30
  
  1.1.2                    20
  
  1.2.1                  165

  I wrote the following, so far...

  SQL> select distinct s.costcenterms , sum(purchcontyear0) over(partition by s.costcenterms order by s.costcenterms)
  
    2        from details_det d , strdet s
  
    3        where s.costcenterdet=d.costcenterms(+)
  
    4        start with s.costcenterms='1'
  
    5             connect by  s.costcenterms = prior s.costcenterdet
  
    6        order by s.costcenterms
  
    7  /
  
   
  
  COSTCENTERMS                                                 SUM(PURCHCONTYEAR0)OVER(PARTIT
  
  ------------------------------------------------------------ ------------------------------
  
  1.2                                                          
  
  1.2.1                                                                                   165
  
  1.1.1                                                                                    30
  
  1.1.2                                                                                    20
  
  1                                                            
  
  1.1                                                          
  
   
  
  6 rows selected

  How should I modify the above sql stmt to get the result you want...?
  
  Note: I use OracleDB 10 g. v.2
  
  Thank you very much
  SIM

  sgalaxy wrote:
  Anyway, since I want to use the sql stmt to define a materialized view, all versions of data of hierarchical queries are not allowed... (oracle ora-30361 error...).

  No error on my:

  Connected to:
  Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Production
  With the Partitioning, OLAP and Data Mining options
  
  SQL> create materialized view x_mv
    2  as
    3  select  grp,
    4          sum(purchcontyear0)
    5    from  (
    6           select  connect_by_root s.costcenterms grp,
    7                   d.purchcontyear0
    8             from  strdet s,
    9                   details_det d
   10                   where s.costcenterdet=d.costcenterms(+)
   11                   connect by s.costcenterms = prior s.costcenterdet
   12          )
   13    group by grp
   14  /
  
  Materialized view created.
  
  SQL> select  *
    2    from  x_mv
    3    order by grp
    4  /
  
  GRP                  SUM(PURCHCONTYEAR0)
  -------------------- -------------------
  1                                    215
  1.1                                   50
  1.1.1                                 30
  1.1.2                                 20
  1.2                                  165
  1.2.1                                165
  
  6 rows selected.
  
  SQL> 
  

  SY.

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• Re: How to get the Tempo to work properly?

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  I have problems with the service of Tempo.

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  When I installed first Tempo, updates for about a month, I received, and then all of a sudden, no update came through. My firewall is blocking either of this application.

  I tried to reinstall the application, but no change in the situation.

  Does anyone know if ALL updates are available via the website of driver toshiba out tempo? Because, in the month that this service worked, I got an update of the bios, but I recently saw a bios update online and Tempo has not always reports that it is available.

  Any ideas on how to get the Tempo to work properly?

  Thank you.

  I saw in your other thread you have installed SP1 on your Vista laptop.
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