How to integrate my name in the EXIF data for multiple image at the time Bridge CS3

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  select  2222,     '03-AUG-11',     '03-AUG-11'     ,'03-AUG-11'     ,'BBB', 2 as hours  from dual   union all /*Overlap with row 5 upto 6:00 AM*/
  select  2222,     '03-AUG-11',     '03-AUG-11'     ,'03-AUG-11'     ,'CCC', 0 as hours  from dual   /* complete overlaps with row 6 */

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  I really appreciate it if someone can help me.
  Thank you.

  with data as (
  select 1111 as person_id, '01-AUG-11' as event_date, to_date('01-AUG-11 18:00', 'DD-MON-YY Hh24:MI') as start_time, to_date('02-AUG-11 06:00', 'DD-MON-YY Hh24:MI') as end_time, 'AAA' project_id from dual union all
  select 1111 as person_id, '02-AUG-11' as event_date, to_date('02-AUG-11 03:00', 'DD-MON-YY Hh24:MI') as start_time, to_date('02-AUG-11 06:00', 'DD-MON-YY Hh24:MI') as end_time, 'BBB' project_id from dual union all
  select 1111 as person_id, '02-AUG-11' as event_date, to_date('02-AUG-11 05:00', 'DD-MON-YY Hh24:MI') as start_time, to_date('02-AUG-11 08:00', 'DD-MON-YY Hh24:MI') as end_time, 'CCC' project_id from dual union all
  select 1111 as person_id, '03-AUG-11' as event_date, to_date('03-AUG-11 11:00', 'DD-MON-YY Hh24:MI') as start_time, to_date('03-AUG-11 15:00', 'DD-MON-YY Hh24:MI') as end_time, 'AAA' project_id from dual union all
  select 2222 as person_id, '02-AUG-11' as event_date, to_date('02-AUG-11 18:00', 'DD-MON-YY Hh24:MI') as start_time, to_date('03-AUG-11 08:00', 'DD-MON-YY Hh24:MI') as end_time, 'AAA' project_id from dual union all
  select 2222 as person_id, '03-AUG-11' as event_date, to_date('03-AUG-11 01:00', 'DD-MON-YY Hh24:MI') as start_time, to_date('03-AUG-11 10:00', 'DD-MON-YY Hh24:MI') as end_time, 'BBB' project_id from dual  union all
  select 2222 as person_id, '03-AUG-11' as event_date, to_date('03-AUG-11 01:00', 'DD-MON-YY Hh24:MI') as start_time, to_date('03-AUG-11 10:00', 'DD-MON-YY Hh24:MI') as end_time, 'CCC' project_id from dual
  )
  --
  -- end of test data
  --
  select
  person_id, start_time, end_time, project_id,
  (end_time - start_time) * 24 hours,
  greatest((
    end_time - greatest(start_time, nvl(lag(end_time) over (partition by person_id order by start_time,end_time),start_time))
  ) * 24, 0) hours_no_overlap
  from data
  order by
  person_id, start_time, end_time
  ;
  

  With the [http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/functions082.htm#i1327527 url] analytical function GAL, you can get what was the time of the end of the previous row. Greatest() function then takes the value of a line start_time or end_time from previous row, whichever is the greater.

  It is a way to do that is fairly simple. If you have multiple overlaps, so it may not work completely in all cases. But maybe it can serve as a starting point for you ;-)

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