How to reference the layout object in the program unit?

Hello world

I'm changing the outcome of the result of a F_Test_Result1 field, so I create a trigger of format for it, the code is showed in below:

function boolean return F_Test_Result1FormatTrigger is
Start
If F_TEST_Result1 = "0" then
F_Test_Result1: = "Pass";
end if;
return (TRUE);
end;

but the Report Builder returns error saying F_TEST_Result1 is not yet defined. so, how can I do to direct these layout object and the object of data (from the data model) in triggering?

Thank you
Bryan

Published by: Bryanevil on April 22, 2009 20:50

Hello

I suggest to create a column formula in the group that contains the column PASS_FAIL_SUMMARY

and use a PL/SQL code like this for the column in the formula:

function CF_1Formula returns the Char type is
Start
If: PASS_FAIL_SUMMARY = '0' then
return ("pass");
on the other
Return('--');
end if;
end;

Then, set the column formula as a Source for the field in the layout.

Concerning

Tags: Oracle Development

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