Hyperic and SQL

Hello

After I installed agent Hyperic on SQl Sever and it went well, but after that I couldn't reach to the SQL database. In the following screen shot will I need sql admin password password hqadmin?

Are there additional configuration I need to do?

Thanks for the help

Password SQL DBO

Tags: VMware

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Please find test data and results as XML and SQL output.

Version : Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

create table emp_xml (empno number, emp_name varchar2 (100), by e-mail to varchar2 (100));

insert into emp_xml values (100, 'DAVID',' [email protected]');

insert into emp_xml values (101, 'ROBERT',' [email protected]');

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insert into emp_dept_xml values (' 101,'40, 20, 10, 30, 50, ");

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-----------------------

EMPNO EMP_NAME EMAIL DEPTNO

DAVID 100 [email protected] 10

DAVID 100 [email protected] 20

DAVID 100 [email protected] 30

ROBERT 101 [email protected] 10

ROBERT 101 [email protected] 20

ROBERT 101 [email protected] 30

ROBERT 101 [email protected] 40

ROBERT 101 [email protected] 50

DANIEL 102 [email protected] 10

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-----------------------

< USERS_DETAILS >

< USER >

< EMPNO > 100 < / EMPNO >

DAVID < NAME > < / NAME >

< EMAIL > [email protected] < / EMAIL >

< ASSIGNED_DEPT >

< DEPT > 10 < / DEPT >

< DEPT > 20 < / DEPT >

< DEPT > 30 < / DEPT >

< / ASSIGNED_DEPT >

< / USER >

< USER >

101/EMPNO < EMPNO > >

ROBERT < NAME > < / NAME >

< EMAIL > [email protected] < / EMAIL >

< ASSIGNED_DEPT >

< DEPT > 10 < / DEPT >

< DEPT > 20 < / DEPT >

< DEPT > 30 < / DEPT >

< DEPT > 40 < / DEPT >

< DEPT > 50 < / DEPT >

< / ASSIGNED_DEPT >

< / USER >

< USER >

< > 102 EMPNO < / EMPNO >

DANIEL < NAME > < / NAME >

< EMAIL > [email protected] < / EMAIL >

< ASSIGNED_DEPT >

< DEPT > 10 < / DEPT >

< / ASSIGNED_DEPT >

< / USER >

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  2         , e.emp_name
  3         , e.email
  4         , regexp_substr(d.dept_list, '[^,]+', 1, level) deptno
  5      from emp_xml e
  6      join emp_dept_xml d
  7        on e.empno = d.empno
  8   connect
  9        by level <= length(d.dept_list) - length(replace(dept_list, ','))
 10       and prior e.empno = e.empno
 11       and prior dbms_random.value() is not null;

     EMPNO EMP_NAME             EMAIL                DEPTNO
---------- -------------------- -------------------- --------------------
       100 DAVID                [email protected]      10
       100 DAVID                [email protected]      20
       100 DAVID                [email protected]      30
       101 ROBERT               [email protected]     40
       101 ROBERT               [email protected]     20
       101 ROBERT               [email protected]     10
       101 ROBERT               [email protected]     30
       101 ROBERT               [email protected]     50
       102 DANIEL               [email protected]     10

9 rows selected.

SQL> select xmlelement
  2         (
  3              "USERS_DETAILS"
  4            , xmlagg(xmlelement
  5              (
  6                  "USER"
  7                , xmlelement("EMPNO", empno)
  8                , xmlelement("NAME", emp_name)
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 17              from emp_xml e
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 22               and prior e.empno = e.empno
 23               and prior dbms_random.value() is not null
 24         )
 25   group
 26      by empno
 27       , emp_name;

XML_OUTPUT
--------------------------------------------------------------------------------

  
    100
    DAVID
    
      10
      20
      30
    
  
  
    101
    ROBERT
    
      40
      50
      30
      20
      10
    
  
  
    102
    DANIEL
    
      10
    
  


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