I need to display tomorrow's date in the format ' yyyy/mm/dd' in Captivate 8.

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  I have a Date column in the table and the respective VO.
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  in your VO, select the attribute Date--> UI select tips--> replace it Type of Format of Date Simple, and and the Format of the value of MMM - AA

• DateChooser display the current date in the format YYYY/MM/DD on init

  I have two date fields. I would like a date picker to display the current date on the complete creation and the other must show 30 days after the date of the day.
  
  The format must be YYYY/MM/DD.
  
  I get currently has the date of the day in a called var currentDate, but she returned to 11 December 2008.
  
  Thanks in advance.
  
  I have

  You can use the property formatString, like this:

• How can I use a date in the format YYYYMMDD "" to calculate an age?

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  Replace these two lines:

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• Storage of the data in the format of the FED

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• How to get the date in the format dd/mm/yyyy?

  Hello
  for this query:
  > select to_date (to_char (sysdate), ' dd/mm/yyyy') of double;
  I wanted to get a date in the format dd/mm/yyyy, but this query is not in the right format to date.
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  Why you are converting a date (it's a date in your table, right) tank and back to a date. When you want to display a date a certain way, you use to_char and specify the mask format to display the date as to_char (sysdate, 'dd-mm-yyyy'). Internally, dates are stored as bytes 7, you use to_char only for display purposes.

• SQL * Loader: load data in the format MM/DD/YYYY HH: mi: SS PM

  Please advice how to load data in the format MM/DD/YYYY HH: mi: SS PM in an Oracle Table using SQL * Loader.
  
  -Should what format I give in the control file?
  -What would be the type of column to create the table to load data.
  
  Examples of data below;
  
  MM/DD/YYYY HH: MI: SS PM
  
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  Thanks in advance
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  Astr0 wrote:
  Hello Srini,

  I tried with the date of creation as DATE data type, but I had an error like

  ORA-01830: date format picture ends before converting entire input string
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  Try

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  REDA

• What is the best way to obtain a string that represents a date in the format mm/dd/yyyy

  What is the best way to obtain a string that represents a date in the format mm/dd/yyyy
  
  It would be good if I could generate this string using the static methods of a class.
  
  
  
  
  
  
  

  You can use date formatter:

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  ...

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• JavaScript to display the field date in the format below

  I'm a customer form who need the date to display in the format below

  As if he puts day 13/05/2015 then it should show that may 13, 2016 (Please note that there should be "th" after 13)

  19/07/2016 should show that July 19, 2016 (an' th' after only 19 should be here)

  Thanking you

  This way of listing of numbers is known as "Ordinal". There are many was to this script. What works for the web that JavaScript can easily work with few changes in Acrobat Forms. This type of date format is generally used in legal forms.

  You should be able to search the forums for "legal date" or "ordinal" and find the post.

  I found a JavaScript function that can take a number of entry and returns the number with the ordinal suffix. This allows you to create any number of date formats.

  This function is not limited to a few dates bat can be used to add the ordinal suffix to a number any.

  The function:

  function ordinal_suffix_of (I) I have

  {

  var j = i % 10, / / tens of rest

  k = i % 100, //100's remains

  cSuffix = "e"; results of default suffix

  If (j == 1 & k! = 11) {}

  No 11;

  cSuffix = "m";

  }

  If (j == 2 & k! = 12) {}

  No 12;

  cSuffix = "nd";

  }

  If (j == 3 & k! = 13) {}

  No 13;

  cSuffix = "rd";

  }

  return i + cSuffix;

  } / / end of function ordial_suffix;

  I put this code in the location of the script to document level and then call it as necessary in the various areas.

  I enter the date in a different area that would not print and then have the date formatting in another area. You know how to divide the date entered in the month, string date and year, parts and then rearrange them as needed.

  You can test the code using the Acrobat JavaScript console:

  function ordinal_suffix_of (i)
  {
  var j = i % 10, / / tens of rest
  k = i % 100, //100's remains
  cSuffix = "e"; results of default suffix
  If (j == 1 & k! = 11) {}
  No 11;
  cSuffix = "m";
  }
  If (j == 2 & k! = 12) {}
  No 12;
  cSuffix = "nd";
  }
  If (j == 3 & k! = 13) {}
  No 13;
  cSuffix = "rd";
  }
  return i + cSuffix;
  } / / end of function ordial_suffix;

  function MyDateFormat (cFormat, cDate)
  {
  Kai var = util.scand (cFormat, cDate);
  if(oDate == null)
  {app.alert ("invalid date provided", 1, 0);}
  }
  on the other
  {
  "Return util.printd ("mmmm", letter) +" "+ ordinal_suffix_of (oDate.getDate ()) + ', ' + util.printd ("yyyy", anyway);"
  }
  }

  var dateInput = "13/05/2015; value of date entered;
  var cFormattedDate = MyDateFormat ("d/mm/yyyy", dateInput); formatted string for the date;
  Console.println (cFormattedDate);
  dateInput = ' 23/05/2015;
  Console.println (MyDateFormat ("d/mm/yyyy", dateInput));
  dateInput = "19/07/2015;
  Console.println (MyDateFormat ("d/mm/yyyy", dateInput));
  dateInput = "09/07/2015;
  Console.println (MyDateFormat ("d/mm/yyyy", dateInput));

• Display the current Date in the Format year (and now - 1, etc.)

  Our form has columns headers that need to change each year, positions are the current year (2010) + 3 previous years.  Trying to programmatically add the titles to eliminate changing the shape just to change the year, but not finding not how and was check some samples date found, but no success yet.  My question is the 2 part - how/where can I put code, I don't need the user to enter something, I want just a column header.  This example below is where I copied the idea from a sample and tried to compensate, calculate for a date/time field event, and I get an error message that says: "the view model 'date-{MM/YYYY]' is not compatible with the data format of the object.  Define a display compatible model.  This view model error is the 2nd part of the question.  How can I show only the 4 digit year?

  Year1.RawValue

  = num2date (date (), 'YYYY')

  How to achieve this - am newbie on this!  Thank you very much!

  I'd be happy to take a look at the form. stwalker. [email protected]

  Steve

• Need to display color on top of the region of the table.

  Hi all
  
  In my page, there are 3 table, just on the side of the region of table need to display green space (header) for each table.
  is it possible to display colors in the OPS?
  
  Please help me on this.
  
  Robet

  Code:

  OARowLayoutBean RowLayoutRN1 = (OARowLayoutBean) webBean.findChildRecursive ("RowLayoutRN1") ;---Id

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  -Use the same code and let me know... :))

  Concerning
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• How to display the date in the format "DD-MON-AA HH:MIPM '?

  Hello
  
  I have a form in which P9_SUBMIT_TIME element is created with the display of text type.
  In the source, I entered SUBMIT_TIME as value to call the ID passed to the form-based data in the SUBMIT_TIME column. Type of source for this article is defined as the source of the database column.
  Currently the option displays 'DD-MON-YY HH.
  I don't understand why "HH" is also displayed.
  How can I display the item with the format 'DD-MON-YY HH:MIPM?
  
  Thank you
  Guy

  Hi GUY3!

  To change the format of a textfield that textfield edit and search for the attribute "Format Mask" in the region of the "Source". Here, you can enter a format or a list, choose a given format. The type of format you are looking for is in the list.

  Yours sincerely

  Florian W.

• How to format a short date in the form YYYY

  Hello
  
  I would like to be able to show the form of YYYY year when I use DateFormat (int, locale aLocale style) and the locale of the user, and without hard-coding style in the source code.
  
  Here is my code:

  import java.text.DateFormat;
  import java.util.Calendar;
  import java.util.Locale;
  
  public class TestDates {
  
       public static void main(String[] args) {
            Calendar calDate = Calendar.getInstance();
            DateFormat fd = DateFormat.getDateInstance(DateFormat.SHORT, Locale.getDefault());
            System.out.println(fd.format(calDate.getTime()));
       }
  }

  The output on my machine is: 25/02/11
  But I'd like to see: 25/02/2011
  
  Is this possible? and how?
  
  Thank you for your help.

  839922 wrote:
  But then I have to hardcode the style in the source code as "MM/DD/YYYY" or ' dd/MM/YYYY', which is not desirable.

  No, you do not have to encode it. You can read from a file or user input, or whatever during execution. It is just a string. Not all channels are determined at compile time.

  I need the date of formatting to track the preferences of users that they enter in their BONES to their taste DD/MM/YYYY or MM/DD/YYYY or what they prefer.

  Then read this preference when running and create a SimpleDateFormat him.

  Currently, if I change my preferences in my operating system and set the "Format of short Date" as DD/MM/YYYY, I get 25/02/2011 in all applications except my java application, there are 25/02/11. If I go back and change the preferences of OS to MM.dd.YYYY, I see 02.25.2011 in all applications except my java application that shows 02.25.11

  So it seems that the question is now, "How to read this OS" preference "of Java? That, I don't know, and you may not be able to in the general case.

• We had to find the date in the format "DD-MM-YYYY" and "DD/MM/YYYY '.

  Hello world
  
  I need to find the hire_date in the format "dd-mm-yyyy" and "dd/mm/yyyy '. This shows also some errors, I can't found. pls help to solve this problem...

  Hello

  Christine Schnittker says:
  ... It works as well:

  SQL> select to_date('22-02-2012','dd/mm/yyyy') dt from dual;
  
  DT
  ----------
  22-02-2012
  

  (Does anyone know anything that actually says?)

  The Manual of the SQL language , after listing the format items allowed in TO_DATE, says the following:

  Any nonalphanumeric character is allowed to match punctuation characters in the format model. For example, the following statement returns no error:
  SELECT TO_CHAR (TO_DATE('02#07','MM/YY'), ' MM/YY') FROM DUAL;

  TO_CH
  -----
  02/07

• How to get the data in the format specified for this table?

  Table:

  ID     NAME     DESC1     COUNTRY_ID     PERFORMANCE
  
  001     abc1     description 1     CON0000006       .67
  001     abc2     descr2            CON0000004       1232.87
  001     abc3     dsc3                     CON0000003        76798
  002     abc4     descr4               CON0000005        8787
  002     abc5     descr5              CON0000001        989.9989
  003     abc6     dfrer                     CON0000001        676.90
  003     abc7     ioioi                    CON0000001        6.8778
  004     abc8     lilli                   CON0000001         334344

  performance column is of type varchar2.
  
  I want data like this:

  ID     NAME     DESC1     COUNTRY_ID     PERFORMANCE
  001     abc1     description 1     CON0000006       00.67
  001     abc2     descr2            CON0000004       1232.87
  001     abc3     dsc3                     CON0000003        76798.00
  002     abc4     descr4               CON0000005        8787.00
  002     abc5     descr5              CON0000001        989.99
  003     abc6     dfrer                     CON0000001        676.90
  003     abc7     ioioi                    CON0000001        6.87
  004     abc8     lilli                   CON0000001         334344.00

  I use oracle 10g on windows 7.
  can you please how do I get the performance data in this format?

  Try something like:

  SQL> alter session set nls_numeric_characters='.,';
  
  Session altered.
  
  SQL> -- generating sample performance column
  SQL> with t as (
    2  select '.67' perf from dual union
    3  select '1232.87' from dual union
    4  select '76798' from dual union
    5  select '8787' from dual union
    6  select '989.9989' from dual union
    7  select '676.90' from dual union
    8  select '6.8778' from dual union
    9  select '334344' from dual
   10  )
   11  --
   12  -- actual query:
   13  --
   14  select perf
   15  ,      to_char(trunc(to_number(perf), 2), 'fm999900.00') perf2
   16  from   t;
  
  PERF     PERF2
  -------- ----------
  .67      00.67
  1232.87  1232.87
  334344   334344.00
  6.8778   06.87
  676.90   676.90
  76798    76798.00
  8787     8787.00
  989.9989 989.99
  
  8 rows selected.