I think I need a LEAD/LAG function?
Hello
Oracle 10.2.0.4
I have a table that contains an atrribute used over time. Number of lines does not change the value and is there only to maintain integrity between the lines of other tables.
CREATE THE EMP_ATTR TABLE (EMPID VARCHAR2 (8) NOT NULL, ASOFDATE DATE NOT NULL, ATTR VARCHAR2 (13));
Values inserted INTO the EMP_ATTR ("'001', January 1, 2010 ', ' XX');
INSERT INTO EMP_ATTR VALUES ('001', FEBRUARY 2, 2011 "," YY");
INSERT INTO EMP_ATTR VALUES ('001', MARCH 4, 2011 "," YY");
INSERT INTO EMP_ATTR VALUES ('002', JANUARY 1, 2010 "," TT");
INSERT INTO EMP_ATTR VALUES (' '002', 1ST FEBRUARY 2010 TT ', ' ');
INSERT INTO EMP_ATTR VALUES (' '002', 1 DECEMBER 2013 ', ' TT');
INSERT INTO EMP_ATTR VALUES (' '003', JANUARY 1, 2010 ', ' EW');
INSERT INTO EMP_ATTR VALUES (' '003', MARCH 2, 2010 ', ' RT');
INSERT INTO EMP_ATTR VALUES (' '003', 1 NOVEMBER 2013 EW ', ' ');
INSERT INTO EMP_ATTR VALUES (' '003', 1 DECEMBER 2013 EW ', ' ');
What I have to do is to analyze the table, and for each return line when the person assigned this attribute, without going through another attribute assigned in the meantime
So I need something that will return
EMPID, ATTR, ASOFDATE, FIRST_ASOFDATE
001, XX, JANUARY 1, 2010, JANUARY 1, 2010
001, YY, FEBRUARY 2, 2011, FEBRUARY 2, 2011
001, YY, March 4, 2011, February 2, 2011 <-as this was awarded in February and the line of March has not changed the attribute
002, TT, JANUARY 1, 2010, JANUARY 1, 2010
002, TT, FEBRUARY 1, 2010, JANUARY 1, 2010
002, TT, DECEMBER 1, 2013, JANUARY 1, 2010
003, EW, JANUARY 1, 2010, JANUARY 1, 2010
003, RT, MARCH 2, 2010, MARCH 2, 2010
003, EW, November 1, 2013, November 1, 2013 <-EW was previously assigned in 2010, but they have a RT line between Mar-2010 so it's seen as a reboot
003, EW, December 1, 2013, November 1, 2013 <-there was no intermediate attribute inherit so assignment NOV forward
Can be
SQL > select empid, asofdate, attr, asofdate_first
25 years of emp_attr
model 26
27 partition by (empid)
size 28 per (row_number() over (partition by asofdate order empid) rno)
29 measures (asofdate, attr, sysdate asofdate_first, ' ' attr_prev)
30 rules
(31)
32 attr_prev [any] = attr [cv () - 1],
33 asofdate_first [any] = decode (attr_prev [cv ()], attr [cv ()], [cv () - 1] asofdate_first, asofdate [cv ()])
34)
35 order by empid, asofdate;
EMP ASOFDATE TO ASOFDATE_
--- --------- -- ---------
001-1 JANUARY 10 XX 1 JANUARY 10
001 2 FEBRUARY 11 AA 2 FEBRUARY 11
001 4 MARCH 11 AA 2 FEBRUARY 11
002 1 JANUARY 10 TT 1 JANUARY 10
002 1 FEBRUARY 10 TT 1 JANUARY 10
002 1 DECEMBER 13 TT 1 JANUARY 10
003 1 JANUARY 10 EW 1 JANUARY 10
003 2 MARCH 10 RT 2 MARCH 10
1ST NOVEMBER 13 003 EW 1 NOVEMBER 13
1ST DECEMBER 13 003 EW 1 NOVEMBER 13
10 selected lines.
Tags: Database
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Oracle version: 11.0.2.0.2.0
Dear all
I have a question where I am using tables Tab1 and Tab2
Struncture of tab1 is
Store_no NUMBER,
Sell_date DATE
Sell quantity number,
number of item_no
to tab2
Number of Item_no
date date1,
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I need know the total price of the article sold for 2 days (current as previous)
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Could you please suggest if we capture these sorts of queries where Lag/lead are used.
Your query does not much sense. Analytical functions are applied to already recovered lines, and since you have sell_date = date1, all you get is one day sales. All you need is:
Select the store
Max (sell_date),
tab1.item_no,
sum (case sell_date when date1 then sell_qty * end item_price) day_sales_amount,.
sum (case sell_date when date1 - sell_qty then 1 * item_price end) prev_day_sales_amount
of tab1.
tab2
where tab1.item_no = tab2.item_no
and sell_date in the fields (date1, date1 - 1).
Store group,
tab1.item_no;
SY.
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addition of {noformat}{noformat} tags. Please read {message:id=9360002} to learn to do this yourself in future.You would dump the subquery LAST_WEEK together. Then replace the calculation of your failure with
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Cheers, APC
Published by: APC on 6 January 2012 13:41
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-------------------------------------------------------------
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Need help with analytical function (LAG)
The requirement is as I have a table with described colums
col1 County flag Flag2
ABC 1 Y Y
XYZ 1 Y Y
XYZ 1 O NULL
xyz *2* N N
XYZ 2 Y NULL
DEF 1 Y Y
DEF 1 N NULL
To get the columns Flag2
1 assign falg2 as indicator for rownum = 1
2 check the colm1, count of current line with colm1, Earl of the previous line. The colm1 and the NTC are identical, should assign null...
Here's the query I used to get the values of Flag2
SELECT colm1, count, flag
BOX WHEN
LAG(Count, 1,null) OVER (PARTITION BY colm1 ORDER BY colm1 DESC NULLS LAST) IS NULL
and LAG(flag, 1, NULL) PLUS (SCORE FROM colm1 ORDER BY colm1, cycle DESC NULLS LAST) IS NULL
THEN the flag
END AS Flag2
FROM table1
but the query above returns the o/p below which is false
col1_ County flag Flag2
ABC 1 Y Y
XYZ 1 Y Y
XYZ 1 O NULL
xyz *2* N NULL
XYZ 2 Y NULL
DEF 1 Y Y
DEF 1 N NULL
Thank you
Published by: user9370033 on April 8, 2010 23:25Well, you have not enough explained your full requirement in this
1 assign falg2 as indicator for rownum = 1
2 check the colm1, count of current line with colm1, Earl of the previous line. The colm1 and the NTC are identical, should assign null...as you say not what Flag2 must be set on if com1 and cnt are not the same as the previous row.
But how about this as my first guess what you mean...
SQL> with t as (select 'abc' as col1, 1 as cnt, 'Y' as flag from dual union all 2 select 'xyz', 1, 'Y' from dual union all 3 select 'xyz', 1, 'Y' from dual union all 4 select 'xyz', 2, 'N' from dual union all 5 select 'xyz', 2, 'Y' from dual union all 6 select 'def', 1, 'Y' from dual union all 7 select 'def', 1, 'N' from dual) 8 -- END OF TEST DATA 9 select col1, cnt, flag 10 ,case when lag(col1) over (order by col1, cnt) is null then flag 11 when lag(col1) over (order by col1, cnt) = col1 and 12 lag(cnt) over (order by col1, cnt) = cnt then null 13 else flag 14 end as flag2 15 from t 16 / COL CNT F F --- ---------- - - abc 1 Y Y def 1 Y Y def 1 N xyz 1 Y Y xyz 1 Y xyz 2 Y Y xyz 2 N 7 rows selected. SQL>
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