Insert data in mysql database

Hello world

I searched all over the internet for solutions to my problems, but it is not easy to find good explanations of how things work with databases.

So, here's the situation:

I had a (built with LC designer 8.0) form with a button of HTTPsubmit linked to a php script which would address all communications to my mySQL database. Everything works very well for that.

now, I have a second form and wanted to do the same. But on this new form, I have a few paintings repeated data with the same name (each row has the same nodes), and the HTTP POST method will give me only one of the data. I could change the name of each node to make it unique, but 1. It takes some time and 2. It is not a very clean solution

So, I tried to set up the famous "DataConnection" I've tried to avoid in the first instance. I've successfully installed mySQL ODBC connector and communication between the form and the database is perfectly fine. But I understand that, in the 'method' of DataConnection each field of the form corresponds to a field in the database. While I would like to insert a new section of mySQL for each line of my paintings.

This is where I am stuck. I thought of two methods:

1. I am a newbie with DataConnection so maybe there's a way to do what I want, but I don't know. Ideally, I guess something like this: "OK, there is good communication with the mySQL database. When I click on the "submit" button, move forward with javascript code that collects information from the form and gives a request for INSERTION in the mySQLdatabase; "and that for each row in the table. Collection of information is no problem, but how should I handle these multiple query "INSERT"?

2. perhaps, it is also a way to change the submit button, so that the data is sent to a php server side or a js script, but instead of having urlencoded method or the HTTP POST method, send the code over XML data and the script will deal with it. In fact, I know that this change is possible; but I have no idea on how to manage the data from the form, if this isn't HTTP POST (or GET). If I choose a shipment to a php script, and I send XML or XDP, what is sent to the script?

Well, thank you in advance if I finally find a solution!

tguiot.

OK nevermind, I found the solution with an appropriate method. Here is the link where I found what I needed: http://blogs.adobe.com/formbuilder/2006/12/databases_ins_upd_del.html

That's exactly what I planned to do, but it is indeed a more advanced manipulation of the database connection object. Here's the idea:

  • create a DataConnection to your database, using the standard method (in my case, using the mySQL ODBC connector)
  • create a copy of the DataConnection object and clean it (to remove all unnecessary nodes)
  • Change the value of the
  • Run the SQL with the method 'Open'

in the link provided, you will find the pdf file to open it with livecycle designer. There is a "Database" variable which contains the functions, and the code is commented pretty precisely.

All I now need to do is navigate in my table and execute an insert sql for each line.

So good to finally have a solution!

Thanks anyway for your help pguerett.

Tags: Adobe LiveCycle

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    $editFormAction = $_SERVER ['PHP_SELF'];

    If (isset {}

    $editFormAction. = « ? ». htmlentities($_SERVER['QUERY_STRING']);

    }

    If ((isset($_POST["MM_insert"])) & & ($_POST ["MM_insert"] == "Register_Form")) {}

    $insertSQL = sprintf ("INSERT INTO"user identity"(Ui_LastName, Ui_Email, Ui_FirstName, Ui_Password) VALUES (%s, %s, %s %s)", ")

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    $Result1 = mysql_query ($insertSQL, $MAMPPRO) or die (mysql_error ());

    $insertGoTo = "LoginSuccessful.php";

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    @mysql_select_db ($database_MAMPPRO, $MAMPPRO);

    $query_Recordset1 = "SELECT *"IDENTITY of the user;"

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    $row_Recordset1 = mysql_fetch_assoc ($Recordset1);

    $totalRows_Recordset1 = mysql_num_rows ($Recordset1);

    ? >

    <! doctype html >

    < html >

    < head >

    < meta charset = "UTF-8" >

    Registeration < title > < / title >

    "< link href="jquery-mobile/jquery.mobile-1.3.0.min.css "rel ="stylesheet"type =" text/css">

    "< script src="jquery-mobile/jquery-1.8.3.min.js "type =" text/javascript"> < / script >

    "< script src="jquery-mobile/jquery.mobile-1.3.0.min.js "type =" text/javascript"> < / script >

    < / head >

    < body >

    < div data-role = 'page' id = "registrationpage" >

    < div data-role = "header" >

    < h1 > welcome!    < / h1 >

    < h1 > register yourself! < / h1 >

    < / div >

    < data-role = 'content' div > < / div >

    < do action = "<?" PHP echo $editFormAction;? ">" method = "POST" id = "Register_Form" name = "Register_Form" >

    < p >

    < label > Email < / label >

    < input name = "Register_Email" type = "email" required id = form register_email = "Register_Form" title = "Register_Email" >

    < label > < br >

    Password < / label >

    < input name = "Register_Password" type = "password" required id = form register_password = "Register_Form" title = "Register_Password" value = "" >

    < /p >

    < p >

    < label > name < / label >

    < input name = "Register_Lastname" type = "text" required id = form register_lastname = "Register_Form" title = "Register_lastname" value = "" >

    < label > < br >

    First name < / label >

    < input name = "Register_Firstname" type = "text" required id = form register_firstname = "Register_Form" title = "Register_Firstname" value = "" >

    < /p >

    < name of entry = "MM_insert" type = 'submit' form 'Register_Form' value = 'Registration' = >

    < input type = "hidden" name = "MM_insert" value = "Register_Form" >

    < / make >

    < a href = "index.php" data-role = "button" > return to connection < /a > "

    < div data-role = "footer" >

    footer < h4 > < / h4 >

    < / div >

    < / div >

    < / body >

    < / html >

    <? PHP

    mysql_free_result ($Recordset1);

    ? >

    Finally I found the problem.

    It seems in my setting, MAIL does not work in live mode DW. But if moved to any explores, it works fine.

    Adobe really needs to improve its management of PHP.

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    Afaf,.

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  • Insert data into a database with foreign key...

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    HERE'S OUR TABLES.

    CREATE TABLE 'ASSESMENT_TYPE '.
    (VARCHAR2 (15) 'ASSESMENT_TYPE',)
    VARCHAR2 (70) "ASSESMENT_DESCRIPTION."
    ENABLE 'ASSESMENT_TYPE_PK' CONSTRAINT PRIMARY KEY ('ASSESMENT_TYPE')
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    CREATE TABLE 'COURSES '.
    (NUMBER OF 'COURSE_NO',
    VARCHAR2 (30) "COURSE_NAME."
    DATE OF THE "COURSE_START_DATE."
    DATE OF THE "COURSE_END_DATE."
    NUMBER OF "TOTAL_UNITS."
    NUMBER OF "COURSE_COORDINATOR_STAFF_NO."
    NUMBER OF "TOTAL_COURSE_COST."
    NUMBER OF "THIRD_PARTY_SUPPLIER_NO."
    ACTIVATE THE KEY PRIMARY CONSTRAINT 'COURSE_PK' ('COURSE_NO'),
    "COURSE_CON_FK' FOREIGN KEY ('COURSE_COORDINATOR_STAFF_NO') CONSTRAINT
    ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
    "THPARTY_SUPPLIER_FK' FOREIGN KEY ('THIRD_PARTY_SUPPLIER_NO') CONSTRAINT
    SELECT REFERENCES "THIRD_PARTY_SUPPLIER" ("THIRD_PARTY_SUPPLIER_NO")
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    CREATE TABLE 'COURSE_OUTCOME '.
    (VARCHAR2 (5) 'COURSE_OUTCOME',)
    VARCHAR2 (25) "COURSE_OUTCOME_DESCRIPTION."
    ENABLE 'COURSE_OUTCOME_PK' CONSTRAINT PRIMARY KEY ('COURSE_OUTCOME')
    )

    CREATE TABLE 'DEPARTMENT '.
    (NUMBER OF 'DEPARTMENT_NO',
    VARCHAR2 (50) "DEPARTMENT_NAME."
    VARCHAR2 (150) "DEPARTMENT_LOCATION."
    NUMBER OF "DEPT_MANAGER_NO."
    ACTIVATE THE KEY CONSTRAINT PRIMARY "DEPARTMENT_PK" ("DEPARTMENT_NO'),
    "DEPTMANNO_FK' FOREIGN KEY ('DEPT_MANAGER_NO') CONSTRAINT
    SELECT REFERENCES 'EMPLOYEE' ('EMPLOYEE_NO')
    )
    CREATE TABLE 'EDUCATIONAL_INSTITUTION '.
    (VARCHAR2 (100) 'SCHOOL_UNIVERSITY_NAME',)
    VARCHAR2 (200) "SCHOOL_UNIVERSITY_ADDRESS."
    ENABLE 'EDUCATIONAL_INSTITUTION_PK' CONSTRAINT PRIMARY KEY ('SCHOOL_UNIVERSITY_NAME')
    )
    CREATE TABLE 'EMPLOYEE '.
    (NUMBER OF 'EMPLOYEE_NO',
    VARCHAR2 (50) "EMPLOYEE_NAME"
    VARCHAR2 (150) "EMPLOYEE_ADDRESS."
    VARCHAR2 (50) "JOB_DESCRIPTION."
    'STATUS' VARCHAR2 (15).
    'START_DATE' DATE,
    NUMBER OF "SALARY_CODE."
    NUMBER OF "SUPERVISOR_EMPLOYEE_NO."
    NUMBER OF "DEPARTMENT_NO,"
    ACTIVATE THE KEY PRIMARY CONSTRAINT 'EMPLOYEE_PK' ('EMPLOYEE_NO'),
    "SALARYCODE_FK' FOREIGN KEY ('SALARY_CODE') CONSTRAINT
    ACTIVATE THE REFERENCE 'SALARY' ('SALARY_CODE'),
    "SUPEMNO_FK' FOREIGN KEY ('SUPERVISOR_EMPLOYEE_NO') CONSTRAINT
    ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
    "EMDEPNO_FK' FOREIGN KEY ('DEPARTMENT_NO") CONSTRAINT
    ACTIVATE THE 'DEPARTMENT' ('DEPARTMENT_NO") REFERENCES
    )
    CREATE TABLE 'EMPLOYEE_COURSE_OUTCOME '.
    (NUMBER OF 'EMPLOYEE_NO',
    NUMBER OF "COURSE_NO."
    VARCHAR2 (5) "COURSE_OUTCOME_CODE."
    NUMBER OF "COURSE_EMPLOYEE_MARK."
    ACTIVATE 'EMPLOYEE_COURSE_OUTCOME_PK' CONSTRAINT PRIMARY KEY ('EMPLOYEE_NO', 'COURSE_NO'),
    "EM_FK' FOREIGN KEY ('EMPLOYEE_NO') CONSTRAINT
    ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
    "EMPLOYEE_COURSE_FK' FOREIGN KEY ('COURSE_NO') CONSTRAINT
    ACTIVATE THE REFERENCE 'COURSES' ('COURSE_NO'),
    "EMPLOYEE_COURSE_OCODE_FK' FOREIGN KEY ('COURSE_OUTCOME_CODE') CONSTRAINT
    SELECT REFERENCES "COURSE_OUTCOME" ("COURSE_OUTCOME")
    )
    CREATE TABLE 'EMPLOYEE_COURSE_UNIT_OUTCOME '.
    (NUMBER OF 'EMPLOYEE_NO',
    NUMBER OF "COURSE_NO."
    NUMBER OF "UNIT_NO."
    VARCHAR2 (5) "UNIT_OUTCOME_CODE."
    NUMBER OF "EMPLOYEE_UNIT_MARK."
    ACTIVATE 'EMPLOYEE_CUO_PK' CONSTRAINT PRIMARY KEY ('EMPLOYEE_NO', 'COURSE_NO', 'UNIT_NO'),
    "EMPCU_FK' FOREIGN KEY ('EMPLOYEE_NO') CONSTRAINT
    ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
    CONSTRAINT 'EMCU-FK' FOREIGN KEY ('UNIT_NO')
    SELECT REFERENCES 'UNIT' ('UNIT_NO')
    )
    CREATE TABLE 'EMPLOYEE_CRS_UNIT_ASSESMENT '.
    (NUMBER OF 'EMPLOYEE_NO',
    NUMBER OF "COURSE_NO."
    NUMBER OF "UNIT_NO."
    VARCHAR2 (15) "ASSESMENT_TYPE."
    NUMBER OF "EMPLOYEE_ASSESMENT_MARK."
    ACTIVATE A KEY PRIMARY ('EMPLOYEE_NO', 'COURSE_NO', 'UNIT_NO') CONSTRAINT 'EMPLOYEE_CRS_PK '.
    )
    CREATE TABLE 'EMPLOYEE_QUALIFICATION '.
    (NUMBER OF 'EMPLOYEE_NO',
    VARCHAR2 (5) "QUALIFICATION_TYPE."
    'SUBJECT' VARCHAR2 (20).
    NUMBER OF "QUALITY."
    VARCHAR2 (100) "SCHOOL_UNIVERSITY_NAME."
    VARCHAR2 (50) "AWARDING_BODY."
    NUMBER OF "DATE_QUALIFICATION_OBTAINED."
    TURN ON THE PRIMARY CONSTRAINT "EMPLOYEE_QUALIFICATION_CON_PK" ("EMPLOYEE_NO", "QUALIFICATION_TYPE", "SUBJECT").
    "DEPTNO_FK' FOREIGN KEY ('EMPLOYEE_NO') CONSTRAINT
    ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
    "EMQUALREF_FK' FOREIGN KEY ('QUALIFICATION_TYPE') CONSTRAINT
    ACTIVATE THE REFERENCE 'QUALIFICATION_TYPE' ('QUALIFICATION_TYPE'),
    "SCHUNINAME_FK' FOREIGN KEY ('SCHOOL_UNIVERSITY_NAME') CONSTRAINT
    SELECT REFERENCES "EDUCATIONAL_INSTITUTION" ("SCHOOL_UNIVERSITY_NAME")
    )
    CREATE TABLE 'QUALIFICATION_TYPE '.
    (VARCHAR2 (5) 'QUALIFICATION_TYPE',)
    VARCHAR2 (25) "QUALIFICATION_DESCRIPTION."
    ENABLE 'QUALIFICATION_TYPE_PK' CONSTRAINT PRIMARY KEY ('QUALIFICATION_TYPE')
    )
    CREATE TABLE 'WAGES. "
    (NUMBER OF 'SALARY_CODE',
    NUMBER OF "SALARY_AMOUNT."
    ENABLE 'SALARY_PK' CONSTRAINT PRIMARY KEY ('SALARY_CODE')
    )
    CREATE TABLE 'THIRD_PARTY_SUPPLIER '.
    (NUMBER OF 'THIRD_PARTY_SUPPLIER_NO',
    VARCHAR2 (100) "THIRD_PARTY_NAME."
    VARCHAR2 (100) "THIRD_PARTY_CONTACT_NAME."
    ENABLE 'THIRD_PARTY_SUPPLIER_PK' CONSTRAINT PRIMARY KEY ('THIRD_PARTY_SUPPLIER_NO')
    )
    CREATE TABLE "UNIT".
    (NUMBER OF 'UNIT_NO',
    VARCHAR2 (30) "UNIT_NAME"
    NUMBER (7.2) "UNIT_COST"
    ENABLE 'UNIT_PK' CONSTRAINT PRIMARY KEY ('UNIT_NO')
    )
    CREATE TABLE 'UNIT_OUTCOME '.
    (VARCHAR2 (5) 'UNIT_OUTCOME_CODE',)
    VARCHAR2 (25) "UNIT_OUTCOME_DESCRIPTION."
    ENABLE 'UNIT_OUTCOME_PK' CONSTRAINT PRIMARY KEY ('UNIT_OUTCOME_CODE')
    )
    NOW, WE TRY TO ENTER DATA.

    insert into values used (0002, "Mitch Vaughan', '145 a Green Street', 'Administrator', 'Active', December 1, 2010", 1,1,1 ");

    insert into values used (0001, "Ollie Marriott", "12 the Ghetto Street', 'Administrator', 'Active', 2 December 2010", 2,2,1);

    insert into values employee (0003, "Tim Reynolds, '12 Shoebury Way', 'Cleaner', ' Inactive', December 2, 2000, 3,0002,3);

    insert into values used (0004, "Tom Watson", ' 90 Seymour Road","Data Analyst","Active", December 10, 2008", 4 000 104 ");

    insert into values used (0005, "Wajj is', 125 hamlet Court ', 'Clean', 'Active', September 15, 2007", 5 000 105 ");

    insert into values used (0006, "Nathan Mann', '33 a Bushey Hill Road', 'Receptionist', 'Active'", December 2, 2010 ", 6 000 406);

    insert into values used (0007, "Tim DeLong', ' 34 Buena Vista Drive", "Receptionist", "Active", December 21, 2010 ', 7, 1, 06);

    NOW WE'RE GETTING THESE ERROR MESSAGES.

    Connected.
    SQL > insert into values used (0002, "Mitch Vaughan', '145 a Green Street', ' has)
    dministrator ', 'Active»(, 1er décembre 2010', 1,1,1);
    insert into values used (0002, "Mitch Vaughan', '145 a Green Street', ' administrative)
    strator ', 'Active', 1 December 2010 "(, 1,1,1).
    *
    ERROR on line 1:
    ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
    found


    SQL >
    SQL > insert into values used (0001, 'Ollie Marriott', ' 12 Ghetto Road', ' SMA)
    made ', 'Active»(, 2 décembre 2010', 2,2,1);
    insert into values used (0001, 'Ollie Marriott', ' 12 Ghetto Road', ' Directors)
    Rator ', 'Active»(, 2 décembre 2010', 2,2,1)'.
    *
    ERROR on line 1:
    ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
    found


    SQL >
    SQL > insert into values used (0003, 'Tim Reynolds, 12 Shoebury way', ' Clea)
    NER ","inactive»(, 2 décembre 2000', 3,0002,3);
    insert into values used (0003, "Tim Reynolds', ' 12 Shoebury Way", "Cleaner")
    ("Inactive", 2 December 2000', 3,0002,3)
    *
    ERROR on line 1:
    ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
    found


    SQL >
    SQL > insert into values used (0004, 'Tom Watson", ' 90 Seymour Road', ' data one)
    nalyst ","Active»(, 10 décembre 2008', 4 000 104);
    insert into values used (0004, 'Tom Watson", ' 90 Seymour Road', ' data Analys)
    t ', 'Active', December 10, 2008 "(, 4 000 104).
    *
    ERROR on line 1:
    ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
    found


    SQL >
    SQL > insert into values used (0005, 'Wajj is', ' 125 hamlet Court', ' Clean)
    St ', 'Active»(, 15 septembre 2007', 5 000 105);
    insert into values used (0005, "Wajj is', 125 hamlet Court ', 'Clean',')
    Active ", September 15, 2007"(, 5 000 105).
    *
    ERROR on line 1:
    ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
    found


    SQL >
    SQL > insert into values used (0006, "Nathan Mann', '33 a Bushey Hill Road', ')
    Receptionist ', 'Active', December 2, 2010 "(, 6 000 406);
    insert into values used (0006, "Nathan Mann', '33 a Bushey Hill Road', ' Recep)
    tionist ', 'Active»(, 2 décembre 2010', 6 000 406)'.
    *
    ERROR on line 1:
    ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
    found


    SQL >
    SQL > insert into values used (0007, "Tim DeLong', ' 34 Buena Vista Drive," ' R)
    Eceptionist ', 'Active»(, 21 décembre 2010', 7, 1, 06);
    insert into values used (0007, "Tim DeLong', ' 34 Buena Vista Drive," ' Recept)
    ionist ', 'Active»(, 21 décembre 2010', 7, 1, 06)'.
    *
    ERROR on line 1:
    ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
    found


    SQL >


    PLEASE HELP ME UNDERSTAND THIS! / / /

    Sounds like you have a problem with your tables. It should not be necessary to insert a "preliminary" to the employee record, and then eventually complete.
    Should not be possible. In your case, it is, for all columns is NULL allowed, which is really bad.

    In your case, it is necessary because you have a circular reference;

    Department of references used, which refers to employee. If you really want it to be like that, one of them should be DEFERRABLE (search)

    You need to go through all your tables, you seem to have missed additional / more than one foreign key.
    I proposed (all) in NOT NULL columns. At least give some thoughts to each column;
    'Should I a value here'-> NOT NULL
    "Do I always have value here"-> NOT NULL
    If it is in each case, perhaps that this cvolumn is not at this table. This could be the case for DEPARTMENT_MANAGER, which would also solve your circular reference.

    Do not use the NUMBER with any precision. Many point for example, 'COURSE_NO' NUMBER will it means it's a flutter. For example, use Number (38), personally I use 'always' NUMBER (13) for identifiers - this will insert in a Java int.

    Also, give thoughts to CHECK constraints, probably, he does not give meaning have a negative salaray, and so on.

    A good practice is to first create all tables, then all primary keys and finally all foreign keys. That decouple the tables, so no specific order of creation is necessary.

    When these changes have been made, then start by inserting tables which do not reference other tables and then take it from there, one table at a time.

    Concerning
    Peter

    Edit: One last thing, I don't get the need for a TREATMENT table. Think you should get rid of it.

    Published by: Peter on April 26, 2011 14:53

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    I have a little doubt who would like to see clarified.

    I want / need to select several rows in a gridview and then insert the selected value of the line in the database.

    What should I do to take only the values and send them to the database to help, for example, a stored procedure?

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    Assuming that already find you a way to determine the selected line in the gridview, the next steps are as simple as,
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    [Nur Hidayat | http://nur-hidayat.net/]

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