Is there an easy way to get the previous record in the Apex?

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• is there an easy way to get the number of months in a year in a date range?

  Hi, experts, I am a newbie.
  
  are there any easy ways to get the number of months in a year in a date range?
  
  I would like to write a user-defined function.
  
  the input parameters are startdate, enddate, year
  
  the output is a number, not a month.
  
  for example, case 1
  
  StartDate = 01032009 (DDMMYYYY)
  end date = 28022010 (DDMMYYYY)
  If the year 2009, the output is 10
  If the year = 2010, the output is 2
  
  case 2:
  
  StartDate = 10032009 (DDMMYYYY)
  end date = 15032010 (DDMMYYYY)
  If the year 2009, the output is 10
  If the year = 2010, the output is 3
  
  Thank you very much!

  Hello

  You can (also) try this:

  SQL> with s as (
    2  ------------ Sample data -------------
    3  select to_date('01032009','ddmmyyyy') startdt, to_date('28022010','ddmmyyyy') enddt, 2009 yr from dual
    4  union all
    5  select to_date('01032009','ddmmyyyy') startdt, to_date('28022010','ddmmyyyy') enddt, 2010 yr from dual
    6  union all
    7  select to_date('10032009','ddmmyyyy') startdt, to_date('15032010','ddmmyyyy') enddt, 2009 yr from dual
    8  union all
    9  select to_date('10032009','ddmmyyyy') startdt, to_date('15032010','ddmmyyyy') enddt, 2010 yr from dual
   10  ------------ Sample data -------------
   11  )
   12  select startdt, enddt, yr,
   13  months_between(
   14          least(trunc(to_date(yr+1,'yyyy'),'year') , add_months(trunc(enddt,'month'),1))
   15          , greatest(trunc(to_date(yr,'yyyy'),'year') , trunc(startdt,'month'))
   16  ) nbmonths
   17  from s;
  
  STARTDT    ENDDT              YR   NBMONTHS
  ---------- ---------- ---------- ----------
  01/03/2009 28/02/2010       2009         10
  01/03/2009 28/02/2010       2010          2
  10/03/2009 15/03/2010       2009         10
  10/03/2009 15/03/2010       2010          3
  

  It's pretty simple. (no connection with, without functions SQL only integrated multicast, etc...)

• Y at - it an easy way to get the sql code that is sent in the query UPDATE

  I have a request to UPDATE abbreviated for readability. Is there an easy way to get the sql code that is sent? I use get this info for sql select in the display of debugging in cfeclipse but not for the UPDATE.

  < cfquery debug = "" name = "q" datasource = "#datasource #" > "

  
  
  UPDATE [BookingSystem]. [dbo]. [tbTrades]
  SET
  [Status] = #MATCHED_STATUS #.
  WHERE

  clientID = < cfqueryparam value = "" #arguments.clientID # "cfsqltype ="cf_sql_integer"> AND"
  
  < / cfquery >

  It might pay to read the docs for - http://livedocs.adobe.com/coldfusion/8/htmldocs/Tags_p-q_17.html#1102316 - focusing on the RESULT parameter.

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  --

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  TIA

  Welcome to the forums. Here's a thread fairly new all about this topic.

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• Is there an easy way to identify the type of disk required by the optical drive in my computer? How to identify DVD + compared to a DVD player?

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  http://Windows.Microsoft.com/en-us/Windows-Vista/which-CD-or-DVD-format-should-I-use

  Should which CD or DVD format I use

  The above should help you.

  http://Windows.Microsoft.com/en-us/Windows-Vista/burn-a-CD-or-DVD

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  See you soon.

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  I would like to start with a blank publication.

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• IIOMetadataNode is there an easy way to get all the items?

  Y at - it an easy way to get all elements with no recursion to a depth of level in the XML getAsTree IIOMetadataNode ("formatname") document and make the images of type jpeg with EXIF metadata (when its present on the image) who return to the IIOMetadataNode?

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  The EXIF data will be be summarised into a byte array [] under a sequence of 'unknown' marker with a value of 225 marker.

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  LabVIEW HelloWorld:

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  I tried the remodel, table vi, but could not get.

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  \\carlos

  

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  Thanks in advance

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• Is there an easy way to get a Date/time string seconds?

  I have 2 strings of the format depending on whether I would like to convert in seconds (since 1900). I need this value to set the t0 in a field.

  Date: ' 30/06/2014 '.

  "Time: '16:06 ' 08."

  Is there a CVI function that will do this conversion for me? If not, is there an easy way to do it?

  Thank you!

  This code should do what you want:

  
  
  
  static time_t  calt;
  
  struct Shared  tm tm;
  
  public static char    msg [64];
  
  public static int     AA, mm, DD, hh, mn ss;
  
  strcpy (msg, ' 2014/06/30 16:06:08 ');
  Extract the date/time string component
  
  Scan (msg, "%d [x] %d [x] %d [x] %d [x] [x] %d %d", & mm, dd, and yy, & hh, & mn, &ss);)
  Transfer to a struct tm components
  
  TM.tm_hour = hh;
  
  TM.tm_min  = mn;
  
  TM.tm_sec  = ss;
  
  TM.tm_year = yy - 1900;
  
  TM.tm_mon  = mm - 1;
  
  TM.tm_mday = dd;
  Obrtain calendar
  
  CALT = 0;
  
  CALT = mktime (&tm);)
  
  

• An easy way to get the IP address of a VMware Player running?

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  Hi Badboy,

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  VMware Player has no IP address, but the guest inside the VM systems have not one.

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• Is there an easy way to delete the original files replicated by iTunes game downloads?

  I have a library of great music stored on my Mac. When I subscribed to iTunes game, most of my songs appear in iTunes with the icon 'cloud' indicating that I was able to download the track, even if the files were stored locally in my iTunes music library.

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