Jdev 11 g, adf table to obtain the current data line

Similar Questions

• I need to create a table that has each increment of 15 minutes between the current date and time in the past.

  I can around the current datetime object to the the last quarter of an hour and show all dates for last year, but I'm looking for all the 15 minutes for each day of '1 October 13' to the current date.

  Here's what I have so far:

  SELECT

  trunc (sysdate, 'mi')-

  NUMTODSINTERVAL (mod (to_char (sysdate, 'mi'), 15), 'minute') as Quarter_Hr,

  (sysdate-365 (LEVEL-1)) AS DATES

  FROM DUAL connect by level < = (sysdate-(sysdate-365))

  Any help would be appreciated. I use that as a dimension table to evaluate performance on a base quarter of an hour.

  ALTER session set nls_date_format = "hh24:mi:ss dd/mm/yyyy '.

  /

  Select date "'2013-10-1 + (level - 1) / 96 dt"
  of the double
  connect by level<= trunc((sysdate="" -="" date="" '2013-10-1')="" *="" 96)="" +="">
  /

  DT
  -------------------
  01/10/2013 00:00:00
  01/10/2013 00:15:00
  01/10/2013 00:30:00
  01/10/2013 00:45:00
  01/10/2013-01:00
  01/10/2013-01:15
  01/10/2013-01:30
  01/10/2013-01:45
  01/10/2013-02:00
  01/10/2013-02:15
  01/10/2013-02:30

  DT
  -------------------
  01/10/2013-02:45
  01/10/2013-03:00
  01/10/2013-03:15
  01/10/2013-03:30
  01/10/2013 03:45
  01/10/2013 04:00
  01/10/2013-04:15
  01/10/2013-04:30
  01/10/2013-04:45
  01/10/2013-05:00
  01/10/2013-05:15

  .

  .

  .

  DT
  -------------------
  06/08/2014-11:45
  06/08/2014-12:00
  06/08/2014-12:15
  06/08/2014-12:30
  06/08/2014-12:45

  29716 selected lines.

  SQL >

  SY.

• divide the table based on the number of lines

  Hello
  
  I am trying to split a table based on the number of lines and then treat.
  Say I have a TEST_XXX table that contains 50 lines, what I would do is.
  to access multiple lines of 10. How can we achieve this?
  
  What I thought is, once the table is created and the line are filled.
  Add a new column to the table and perform a procedure that inserts of 1 to 10 first lines
  and 2 to 10 lines and 3 to 10 next ranks... etc. Based on this, that we can treat
  the first set of lines then play next or etc...
  
  is there a better way to do it?
  
  Code to create the table:
  

  CREATE TABLE TEST_XXX
  (
    A_ID   VARCHAR2(10),
    B_ID   NUMBER,
    c_ID   VARCHAR2(10),
    D_ID   NUMBER
  )

  Code to add lines:
  
  

  DECLARE
  BEGIN
    FOR I IN 1..50
    LOOP
        INSERT INTO TEST_XXX VALUES('ABCDE',123,'ZYXWV',321);
    END LOOP;
    COMMIT;
  END;

  The original problem is, I have a huge table, and I write a sql query to process,
  When I treat him by selecting all the values in the table, it is very slow.
  But when I have treat small Coulon (say 100 rows), it works very well.
  That's how I got the approach described above in mind.

  You can use NTILE.

  See:
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions101.htm#SQLRF00680
  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:47910227585839

• Insert the current date in the column of a table advanced

  Hello
  
  I created a ViewObject this query for the current date. Now please help me extract this date value and place in an advanced table column. The column comes after clicking on the button Add another line tha. After you click the date button value would automatically come in the column.

  Hello

  If (tableBean.getName () .equals (pageContext.getParameter (SOURCE_PARAM)))
  (& ADD_ROWS_EVENT.equals (pageContext.getParameter (EVENT_PARAM)))
  {
  ...
  }

  where tableBean is the handle to your table.

  Kind regards
  Out Sharma

• How to add two lines when the second row is not visible, but also gets the first data line too?

  Mr President

  Jdev worm is 12.2.1

  How to add two lines when the second row is not visible, but also gets the first data line too?

  I want to add two lines like below picture, but want the second to remain invisible.

  

  I asked this question but my way of asking was wrong, that's why for me once again.

  Concerning

  Try to follow these steps:

  1. in the database table to add the new column "JOIN_COLUMN" and add the new sequence "JOIN_SEQ".

  2. Add this new column in the entity object. (You can add this in entity object by right clicking on the entity object and then select "Synchronize with database" then the new column and press on sync)

  3. in your bookmark create button to create only one line NOT 2 rows.

  4 - Open the object entity--> java--> java class--> on the entity object class generate and Tick tick on the accessors and methods of data manipulation

  5 - Open the generated class to EntityImpl and go to the doDML method and write this code

    protected void doDML(int operation, TransactionEvent e)
    {
      if(operation == DML_INSERT)
      {
        SequenceImpl seq = new SequenceImpl("JOIN_SEQ", getDBTransaction());
        oracle.jbo.domain.Number seqValue = seq.getSequenceNumber();
        setJoinColumn(seqValue);
        insertSecondRowInDatabase(getAttribute1(), getAttribute2(), getAttribute3(), getJoinColumn());
      }
  
      if(operation == DML_UPDATE)
      {
        updateSecondRowInDatabase(getAttribute1(), getAttribute2(), getAttribute3(), getJoinColumn());
      }
  
      super.doDML(operation, e);
    }
  

    private void insertSecondRowInDatabase(Object value1, Object value2, Object value3, Object joinColumn)
    {
      PreparedStatement stat = null;
      try
      {
        String sql = "Insert into table_name (COLUMN_1,COLUMN_2,COLUMN_3,JOIN_COLUMN, HIDDEN_COLUMN) values ('" + value1 + "','" + value2 + "','" + value3 + "','" + joinColumn + "', 1)";
        stat = getDBTransaction().createPreparedStatement(sql, 1);
        stat.executeUpdate();
      }
      catch (Exception e)
      {
        e.printStackTrace();
      }
      finally
      {
        try
        {
          stat.close();
        }
        catch (Exception e)
        {
          e.printStackTrace();
        }
      }
    }
  
    private void updateSecondRowInDatabase(Object value1, Object value2, Object value3, Object joinColumn)
    {
      PreparedStatement stat = null;
      try
      {
        String sql = "update table_name set column_1='" + value1 + "', column_2='" + value2 + "', column_3='" + value3 + "' where JOIN_COLUMN='" + joinColumn + "'";
        stat = getDBTransaction().createPreparedStatement(sql, 1);
        stat.executeUpdate();
      }
      catch (Exception e)
      {
        e.printStackTrace();
      }
      finally
      {
        try
        {
          stat.close();
        }
        catch (Exception e)
        {
          e.printStackTrace();
        }
      }
    }
  

• BI Layout Editor - how to display the current date?

  Hello

  Recently used BI Layout Editor (previously using MS Word to create the presentation of the State).

  He seems really nice and easy to use.

  However quick Q - How to display the current date in the layout editor (to show the report run date).

  Any quick suggestions is appreciated.

  Thank you

  Vivek

  Tab displays your selection available.

  It's like how when you insert the table in the Word document and when you select the table, you would see 2 additional tabs such as the design and the tool.

  Can you please insert "Text Element" and select the text element and see if you go to the tab 'text '?

• change the color of the current date af:inputDate

  Dear experts,

  I have demands to change the color of a specific date in af:inputDate, but I can't find a way to change the date of the day color (04/09/205-JJ/MM/AAAA). Do you have any suggestions?

  I want the 09/04/2015 also green.

  

  Thank you

  Ricky

  Hello

  AF | chooseDate::today The styles of the appearance of the cell of the table for the current date (today). For example, you can add a background color or a border to the cell. Pseudo classes Description selected

  JSPX page

  Below the code in skin file works for me, when we choose a date

  AF | {chooseDate::today}

  background-color: black;

  }

  

  Thank you

  Amey

• give meaning to cases where minimum effective_start_date is greater than the current date

  Hi guys, I'm not a developer oracle as such, but I'm trying to get some information from oracle to send to other systems of the company, since we are dealing with oracle HRMS as the master system for employee information.

  In particular, we would like to create people in our training and the security system when they are created in oracle.

  I was told that the oracle per_all_people_f object acts as a slowly changing dimension of type 2, where a person can have several versions, which only is always the current version and the current version can be retrieved using the standard parttern of "date of current between the effective start date and actual end date. So far so good.
  
  However, I can see there are cases where the minimum 'effective_start_date' is greater than the current date. It is, indeed, equal to their start_date. I guess start_date represents "the first day of work" of the person.

  But this means then there is no "current" information known to people who have not yet really started working for the company again. This seems odd. How can I have someone for whom we have no information "currently correct? I was told that the effective_start_date of the line is automatically set to their "first day of work" date on which the information is entered into the system, IE, the user to enter information doesn't have the ability to say 'this is the current version of the data for that person, who starts at a date in the future. "

  For this reason, I cannot know these new people (who have been entered in oracle, but did not have actually to their first day of work still) training system. But we would obviously get people established in related systems so that they can use all of these systems on their first day of work.

  Have I misunderstood something here? How can there be no correct version for a person at the date and time?

  Hello

  How normally "inform you" the training system on a new person record? If it's a kind of report or an interface, it may be useful changed to examine a number of days in the future, for example + 7

  It is important to understand when you look at an Oracle HRMS instance through enforcement (i.e. the ' front end'), you look at the data on a date date (of the session) - by default, the date is the system date, but it is possible for a user to change this date to be in the future or the past as they see fit. The ability to implement the records in person in the future is a great feature to have, of course, but it must be understood that in this situation, at the date of the day the person's file logically does not exist yet from the point of view of the MFC features. Behind the scenes, however, in the per_all_people_f of the table, the line exist. Similarly, future update of changes to a person (e.g. marital status from Single to married) could be implemented, and the change in status would be visible if the session has been scheduled on a date or after the date of the marriage. As correctly observe you, behind the scenes, the table will hold all historic entries for this person_id with contiguous effective_start_date and effective_end_date beaches.

  Either way, date_start value is not related to as such hiring date; It is actually the value of effective_start_date earlier for the person_id. All changes, regardless of how many or what the effective_start_date is in each case, will always carry this same start_date value. It * may * be identical to the hiring date (certainly the fact that you configure their hire date person records would cause that), but if the person has been created as a postulant effective from 1 September and was then hired has effect from 21 September, column start_date value would be still 1 September. The record of the person would be visible when the current date is on or after this date - the only difference is that they show that an employee until the 21st.

  I hope this helps, but it is possible, that I just confused you more!

  Clive

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  For example.

  If I run the select query on July 7, 2013, then the query must ignore the current month being July 2013 and last month, which is June 2013 and it shoud select only may 2013 and April 2013.

  Can someone help me how to make this request.

  SELECT *.

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• How to get the old data 6 months from the current date?

  Hi friends,
  
  I have a table which includes historical data, which are having more than 1 years old data. The historical table gets updated once a week. My requirement is that I should get the latest data from the week of each month for 6 months according to the current data. I use oracle 10g.
  
  Can you please someone help in this.
  
  Thanks in advance

  SELECT last_day (ADD_MONTHS (TRUNC (SYSDATE, 'mm'),-LEVEL))-7 start_dt.
  LAST_DAY (ADD_MONTHS (TRUNC (SYSDATE, 'mm'),-LEVEL)) end_dt
  OF THE DOUBLE
  CONNECT BY LEVEL<=>

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• How to insert the current date in a hidden field?

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  No idea how I can configure the hiddden in the current date field?

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• PowerShell script to delete files based on the current Date

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  This issue is beyond the scope of this site and must be placed on Technet or MSDN

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  I don't check June or July.  What can / would be the cause for it?

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  Hello

  ·         The time and date is set correctly on your computer?

  Method 1:

  I suggest you refer to the article below and check if it helps:

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  Method 2:

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  Hope this helps,

• Little VB program that can delete a folder using the current date

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  I try to write a rudimentary program that will delete a file.  I'll post some pseudocode to demonstrate what I intend to achieve:

  If FileFolder is < 8=""> as CurrentDate

  then delete

  I looked at a few other Web sites and ran across something that seems possible to use.  I will credit the site: http://www.vbforums.com/showthread.php?684680-RESOLVED-Delete-files-in-folder-that-are-older-than-a-certain-date

  Private Sub Command1_Click()
  Const FromFolder = "D:\seenu\from\" ' change the path
  Const FilePattern = "* .log" "change the model
  Dim file As String

  File = Dir$ (FromFolder & FilePattern, vbNormal)
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  Loop
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  Once this program is completed and updated, I intend to have Task Scheduler running on a daily basis.

  Sincere greetings,

  TI banker

  Hello

  You can try asking the question in MSDN to support forums:

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  I hope this helps.