[JS CS4] Order alphabetical problem dropdownlists

Hello

I built a script simple dialogue which looks up and displays data from a CSV file. There are three drop-down lists with the first two being connected together if the selection in the second changes if the selection in the first changes.

I am very happy with that, especially since I only need update the CSV file to be filled automatically drop-down list. Someone showed me this pointed out that the second dropdown is not sorted in alphabetical order.

My problem is that I can have just one or the other list aphabetically.

Here's the code to this day, many of which I got from the kind contributors of this forum. I added a link to the script and the CSV file.

var colWidthValue = "100mm".
firstLine var = getHeadings();
firstLine.shift)
firstLine.shift)
var colWidths = firstLine;
var myPubCodeList = getCodes (0)
var myTitlesList = getCodes (1)
var l is new window ('dialogue', "Publication of information Lookup");.
w.orientation = "row";
w.addList = new Array();

1 drop
w.textPubCode = w.add ("statictext', undefined, ' Pub Code :');")
w.pubCodes = w.add ('dropdownlist', undefined, myPubCodeList);
w.pubCodes.selection = w.pubCodes.items [0];

2nd drop
w.textTitle = w.add ("statictext', undefined, 'title :');
w.Titles = w.add ('dropdownlist', undefined, myTitlesList);
w.Titles.selection = w.Titles.items [0];

w.Titles.onChange = function() {}
w.pubCodes.selection = w.Titles.selection.index;
}

3rd dropdown
w.textCols = w.add ("statictext', undefined, ' Data :');")
w.colNum = w.add ('dropdownlist', undefined, colWidths);
w.colNum.selection = w.colNum.items [0];
w.Group = w.add ("group");

w.pubCodes.onChange = function() {}
code = w.pubCodes.selection.text
cols = w.colNum.selection.index
w.Titles.selection = w.pubCodes.selection.index;
If (this.window.addList.length > 0) {}
This.Window.Group.Remove (this.window.addList.pop ());
This.Window.Layout.Layout (true);
}
this.window.addList.push (w.group.add ('statictext', undefined, getWidth (code, passes + 2)));
This.Window.Layout.Layout (true);
}
w.colNum.onChange = function() {}
code = w.pubCodes.selection.text
cols = w.colNum.selection.index

If (this.window.addList.length > 0) {}
This.Window.Group.Remove (this.window.addList.pop ());
This.Window.Layout.Layout (true);
}
this.window.addList.push (w.group.add ('statictext', undefined, getWidth (code, passes + 2)));
This.Window.Layout.Layout (true);
}
w.Show ();

I know that my script is probably awkward and time consuming but it works.

It would be greatly appreciated if someone could point me in the right direction to get the two lists to display in alphabetical order, but still the other day with the correct value drop-down.

Thank you

http://webbanners.nepads.co.UK/scripts/LookupScript.zip

> Err, did you really use "index2" there? If so, I think that you ignored the part of the explanation...

You're right, that should have been index1. In any case, here is an example of work. The script displays a window with list boxes (these are virtually identical to dropdowns scripting-wise, but you can see much better what's happening). Click on the list on the left, and the script selects the corresponding item in the list on the right and vice versa. The indices could probably be implemented smarter.

Peter

#target indesign;

array1 = ['A', 'B', 'C', 'D', 'E'];array2 = ['dA', 'eB', 'aC', 'cD', 'bE'];

// Create indexes -- associative arrays// index12 is used to find which item in list 1 points to which item in list2

index12 = create_index (array1, array2);

// and index21 is used to find which item in list 2 points to which item in list1

index21 = create_index (array2, array1);

//~ At this point,//~ index12 ['A']  returns 'dA'//~ index12 ['B']  returns 'eB'//~ etc.

//~ index21 ['dA'] returns 'A'//~ index21 ['eB'] returns 'B'//~ etc.

w = new Window ("dialog");    w.orientation = "row";    // display list 1 and select first item    list1 = w.add ("listbox", undefined, array1);    list1.selection = 0;    // display list 2 sorted    list2 = w.add ("listbox", undefined, array2.sort ());    // when the window is drawn, select the correct item in list 2    list2.selection = list2.find (index12[array1[0]]);

    list1.onChange = function ()        {        // selection made in list 1:         var select_in_list2 = index12 [list1.selection.text];        list2.selection = list2.find (select_in_list2);        }

    list2.onChange = function ()        {        var select_in_list1 = index21 [list2.selection.text];        list1.selection = list1.find (select_in_list1);        }

w.show ();

function create_index (a, b)    {    var array = [];    for (var i = 0; i < a.length; i++)        array [a[i]] = b[i];    return array;    }

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[JS CS4] Order alphabetical problem dropdownlists

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