Limit the levels of the hierarchy

Similar Questions

• How to set a limit to the level of the hierarchy

  Hello

  I use a component of the hierarchy to show a family relationship between registers and I managed to make the Parent and the child of this profile, but I want to limit the level of the child to one, which means that I only want to show the direct Childs of this profile and not the child of a child of this profile.

  Is it possible to do?

  I use jdev 11.1.1.7.1

  Thank you

  You can add buttons/links in knots - and these buttons can manipulate the model that drives the HV and add/remove items.

  If you are looking for something that will allow you to 'paint' graphically relationships - take a look at the diagram component:

  http://jdevadf.Oracle.com/ADF-richclient-demo/faces/feature/diagram/index.JSPX

  https://docs.Oracle.com/CD/E50629_01/ADF/DVTTR/tagdoc/dvt_diagram.html

  https://pinboard.in/search/u:OracleADF? query = % 3Adiagram dvt

• OBIEE BI answers: measures bad aggregation at the top level of the hierarchy

  Hi all,
  I have the following problem. I hope to be clear in my English because it is somewhat complicated to explain.
  
  I did following:
  
  ID of drugs classified in quantity
  1 9
  2 4
  1 3
  2 2
  
  and drugs following table:
  
  Drug brand Id brand Description drug whose active ingredient Id drug whose active principle Description
  Aulin Nimesulide 1 1
  2 Asprina 2 Acetilsalicilico
  
  In AWM, I've defined a Dimension of drugs based on the following hierarchy: drug whose active ingredient (parent) - brand name of medication (sheet) mapped as Description:
  
  The active ingredient of drug = drug Active ingredient Id of my Table of drugs (pharmaceutical = Description of the active ingredient LONG DESCRIPTION attribute)
  Pharmaceutical brand Description = drug brand Id of my drugs Table (LONG DESCRIPTION = Description of drug brand attribute)
  
  Indeed, in my cube, I have traced pharmaceutical leaf-level brand Description = Id of the drug of my fact table. In AWM drugs Dimension is mapped as Sum aggregation operator
  
  If I select on answers drug whose active ingredient (parent of my hierarchy) and the quantity, in my view, after the result
  
  Description of the active ingredient drugs classified in quantity
  Acetilsalicilico 24
  Nimesulide 12
  
  indeed of the correct values
  
  Description of the active ingredient drugs classified in quantity
  Acetilsalicilico 12
  Nimesulide 6
  
  EXACTLY the double! But if I dig drug Description of the active ingredient Acetilsalicilico I can't see correctly:
  
  Drug whose active ingredient Description pharmaceutical brand classified in quantity Description
  Acetilsalicilico
  -12 Aspirina
  Total 12
  
  Aggregation of evil is only at the top level of the hierarchy. The aggregation on the lower level of the hierarchy is correct. Perhaps the answers also amount Total line? Why?
  
  I'm frustrated. I ask your help, please!
  
  Giancarlo

  OK your on 10G but the view of the cube and the obligation to limit the levels in the LTS in the RPD is valid in both.
  I think we found the problem,
  Go to each source logical table this logic table (x 2 in your case you have two levels) and on the content tab, window background ' use this "Clause Where" filter to limit the rows returned. »
  Open the expression builder, locate LEVEL_NAME according to your cube and limit accordingly, it is to say LEVEL_NAME = "BRAND_DESCRTIPION" for the aggregation BRAND_DESCRIPTION LTS and LEVEL_NAME = "XXXX" in detail, SFF, where XXXX is the name of level of hierarchy in your cube for details (leaves) records.

  Can you try that and let us know?
  Thank you
  Alastair

• Allowing entry of the value of a property at the level of the hierarchy and restricting to whole new level.

  Hi all

  I have two property definition Custom.Levelnumber and Custom.Allowattribute which are the goods as well as Local property node level.

  I want validation to restrict the user to allow any value for the Custom.Allowattribute property for any level of hierarchy other than level 6 i, e Custom.Levelnumber with the value 6.

  all other classes in the hierarchy must have an empty value for the Custom.Allowattribute property.

  Hi Madhu,

  Try this-

  If)

  Not (Equals (Integer, PropValue (Custom.LevelNumber), 6));

  Not (IsDefinedPropVal (Custom.Allowattribute, ABBREV (())).

  True)

• Is it possible to create the formula at the level of the hierarchy?

  Dear all,

  In case, I've dimension branch consist of region, sector, branch

  And I have 3 measures Region_target, Area_target, Branch_target

  I want to create new metrics and check if members at the level of the regions, would like to show Region_target measures

  And also for the region and the target.

  So I tried to write the case where the formula, but impossible to refer to the level of the hierarchy, Ho can I do?

  Something like

  Case when the level. Branch_Hierarchy = region then Region_target

  When the level of . Branch_Hierarchy = area, then zone_target

  of other Branch_target

  end

  Please advise, my problem is to only synchronize the targets for each level. Target of all the branch cannot amount to area and target of any region cannot amount to the region.

  Please notify.

  Thank you

  What you're looking for, it's 'level based on measures '. Basically, you'll logical columns called 'Target' that has 3 sources from 3 LTSS - one for each level.

  LTS 'Target area' level 'Région' is the physical column "Region_target."

  LTS 'Target area' level 'Space' is the physical column "Area_target."

  LTS 'Branch target' level 'Branch' is the physical column "Branch_target."

  You are faced with one of the main features and capabilities of OBI: the power of the LTSS and levels in the business model and of the mapping layer. It is crucial to understand these concepts. It's what separates OBI of all other solutions out there.

• Newbie question: Dimension of the hierarchy doesn't let me drag columns to levels

  Help.
  
  I am installing a new Dimension of the hierarchy in my repository OBIEE. It allows me to create a new dimension, and to set up the levels, but then it doesn't let me drag the columns above. I missed a step somewhere, but I don't know what.
  
  Steps to create a hierarchy of Dimension - >
  Create a dimension object.
  Add a parent level object.
  Add objects of child level.
  Determine the number of items.
  Specify level columns. -C' is where I'm stuck. I can drag columns from the fact, but not the size.
  Create level keys.
  
  B

  You can take the dimension columns from the dimesnion on which you created the hierarchy. You cannot extract columns of two dimensions in a hierarchy...

  Try to rebuild the hierarchy. Right-click on the dimension table and select Create dimension. All the columns in this dimension will be appera in the hierarchy. Then, you can create different levels and can drag columns of fall of hierarchy itself.

  Kind regards
  Sandeep

• How can I limit the number libraries which is to find Photos

  How can I limit the number libraries which is to find pictures?

  I have about 10 libraries I've migrated opening today.

  I followed the advice I got from leonie, (level 10) below.

  Photos will create a new library of Photos in your iPhoto library.  The new library will be named as the iPhoto, with the extension ".photoslibrary" library and your original library will have a new file name extension ".migratedphotolibrary".  Rename the resulting ".photolibrary", so you will always be able to open in Aperture. The icons of libraries will change also. New photo library will display an icon of 'fan photos' with the flower of the Rainbow.

  
  

  So, I have now two files in my folder "Images".   One is called "Photo library" (these are ALL of .photoslibrary) the other is 'BACKUP ONLY iPhoto libraries' (these are ALL of .photolibrary).

  When I hold down the option key and start the Photos is to find all the libraries of two files above. How can I say Photos don't not to look in the old folder "iPhoto library"?

  This isn't a feature of Photos

  You can request that Apple itself - http://www.apple.com/feedback/photos.html - but not, it is not an option

  LN

• Why don't I have a green exclamation point on one of my vi in the hierarchy of VI?

  

  Hi seafood

  Stay of execution

  
  

  Suspend execution of a Subvi to change the values of
  controls and indicators, to control the number of times that the Subvi is running
  before you return to the caller, or return to the beginning of the
  the Subvi execution. You can get all calls to a Subvi
  with the suspended, or you can suspend a specific call to a Subvi.

  To suspend all calls a slot - VI, open the Subvi and select Operate"
  Suspend when it is called.
  The Subvi suspends automatically when another VI calls it. If you
  Select this option when single-no, the Subvi does not suspend
  immediately. The Subvi suspended when it is called.

  To end a call specific Subvi, click the Subvi on the block schema node, and then select node Subvi
  The installation program in the context menu. Check the suspend when it is called to suspend enforcement only to this instance of the Subvi.

  "The window of the Hierarchy of VI , which view you by selecting view" VI hierarchy.
  indicates if a VI is interrupted or suspended. An arrow glyph, shown as
  as a result, indicates a VI runs regularly or not not unique.

  

  A glyph break, shown below, indicates a VI interrupted or suspended.

  

  A green break glyph, or a hollow glyph in black and
  White, shows a VI that stops when it is called. A glyph of Red break, or a
  Glyph of solid black and white, shows a VI that is currently
  pause. A glyph of exclamation point, shown below, indicates that
  the Subvi is suspended.

  

  A VI can be suspended and stopped at the same time.

  Determination of the current Instance of a Subvi

  
  

  When you hold a Subvi, calls list
  pull down menu in the toolbar list the chain of callers of the
  first level VI down to the Subvi. This list is not the same list you see
  "When you select go" callers to this VI, which lists asking them all screws regardless of whether they are running. Use call list
  menu to determine the current instance of the Subvi if block
  diagram contains multiple instances. When you select a VI in the menu calls list , its block diagram opens, and LabVIEW highlights the current instance of the Subvi.

  content above http://zone.ni.com/reference/en-XX/help/371361B-01/lvconcepts/debug_techniques/

• Question re: display globals in the hierarchy of the vi

  I am an older (LV2009) application debugging which was written by another developer and includes a large number of global variables (~ 100).   When I discovered the hierarchy VI for the (rather large) VI of high level and I have the option "Include Globals", I notice that the icons for the various globals generally - but not always - have a number superimposed on them.  It does not correlate with the number of callers, the number of institutions, or level in the hierarchy, so I'm curious to know what it is supposed to represent?  Seems like this should be a trivial matter that it is easy to find an answer to, but I checked the forums help and discussion of LV and found exactly so far nada.

  

  Can someone enlighten me?

  Bob_Schor wrote:

  When you create a Global Variable, you end up saving them as a VI, with the default name Global 1(vi).  As with every VI that creates LabVIEW, it creates a default icon, and as it does for all the default icons, he assigns a number, starting with 1.  If you create several Global screws in a single session of LabVIEW, the default icons will be numbered 1, 2, 3...  However, if you stop LabVIEW after you have created the global with global icon 1, and then restart LabVIEW and create another world, its VI (which must have a different name) will have the same global icon 1.

  Bottom line - do you a favor and change the default icon LabVIEW to create so that the icon means something to you.

  BS

  In fact, I think that the OP has already done this.  I think it's the reason for the confusion in the first place; the OP was not used to seeing a default icon.  In fact, I was momentarily confused until I created a world as an experience.  Then I got a good laugh.

• Add the hierarchy to the dash prompt

  Hello

  I have a question

  I created the analysis:

  

  And add filters:

  

  And I add the hierarchy of categories of purchases to prompt dashboard:

  

  But when I open a dashboard and choose an option in the command prompt, for example:

  

  Nothing happens:

  

  Do I need something additional set or If there is even an option use a hierarchy in command prompt ?

  Hello

  When to use a hierarchy as a guest you don't filter the analysis by setting "is invited" at all levels but you add the hierarchy in the analysis and using the stages of selection, you set it can be replace by the guest. "

  

• How to write this query in the hierarchy

  Hi gurus,

  Really need your help on this query.  Thank you very much in advance.

  SELECT
    t1.key as root_key ,
  (SELECT
        t2.unit_id AS unit_id 
        level-1 AS level ,
        t2.name,
        t2.creator
      FROM
        tab t2
        START WITH t2.unit_id       =   t1.unit_id            -----check each node as root
        CONNECT BY prior t2.unit_id = t2.parent_unit_id
  
    )
     t1.name as parent_unit_name
  FROM
    tab t1
  

  I'll write a query of the hierarchy as above, and that EACH line (node, totally more than 10200) is checked as root node to see how many sheets are accessible for her... It must be implemented in a single query.

  I know inline query should NOT return multiple rows or multiple columns, but the inline elements are necessary and can certainly be made in a correct solution.

  (env):

  Database Oracle 12 c Enterprise Edition Release 12.1.0.2.0 - 64 bit Production

  PL/SQL Release 12.1.0.2.0

  )

  Test data:

  select 1 as unit_id, null as parent_organization_unit_id, 'U1' as name from dual
  union all
  select 2, 1, 'U2' FROM DUAL
  UNION ALL
  SELECT 3, NULL, 'U3' FROM DUAL
  UNION ALL
  SELECT 4, 3, 'U4' FROM DUAL
  UNION ALL
  SELECT 5, 2, 'U5' FROM DUAL
  UNION ALL
  SELECT 6, 5, 'U6' FROM DUAL
  UNION ALL
  SELECT 7, 6, 'U7' FROM DUAL
  UNION ALL
  SELECT 8, 5, 'U8' FROM DUAL
  UNION ALL
  SELECT 9, 5, 'U9' FROM DUAL;
  

  Final result should be like this

  key unit_id,    level,   name, parent_name
  1    1    0    u1      u1
  1    2    1    u2       u1
  1    5    2     u5      u1
  1    6    3     u6      u1
  1    7    4    u7       u1
  1    8    3    u8       u1
  1    9    3     u9      u1
  2    2    0     u2       u2
  2    5    1      u5       u2
  2    6    2     u6       u2
  2    7    3      u7      u2
  2    8    2      u8       u2
  2    9    2      u9       u2
  
  

  Don't know how get you your output, it does not match your data...

  with tab as)

  Select 1 as unit_id, null as parent_organization_unit_id 'U1' as the name of double

  Union of all the

  Select 2, 1, 'U2' FROM DUAL

  UNION ALL

  SELECT 3, NULL, 'U3' FROM DUAL

  UNION ALL

  SELECT 4, 3, 'U4' FROM DUAL

  UNION ALL

  SELECT 5, 2, 'U5' OF THE DOUBLE

  UNION ALL

  SELECT 6, 5, 'U6' OF THE DOUBLE

  UNION ALL

  SELECT 7, 6, "U7" OF THE DOUBLE

  UNION ALL

  SELECT 8, 5, 'U8' FROM DUAL

  UNION ALL

  9. SELECT, 5, 'U9' FROM DUAL

  )

  Select dense_rank() key (order by connect_by_root unit_id), unit_id, level - 1 as 'LEVEL', connect_by_root name root_parent_name

  t tab

  Start with parent_organization_unit_id is null

  Connect prior unit_id = parent_organization_unit_id

  KEY	UNIT_ID	LEVEL	ROOT_PARENT_NAME
  1	1	0	"U1".
  1	2	1	"U1".
  1	5	2	"U1".
  1	6	3	"U1".
  1	7	4	"U1".
  1	8	3	"U1".
  1	9	3	"U1".
  2	3	0	"U3".
  2	4	1	"U3".

• Export only the hierarchy names & properties hierarchy

  Hi all

  Is there a way to export only the hierarchy properties associated with this hierarchy in a database table and the name of the hierarchy? For example, I have a group of hierarchies HG1 who has 10 hierarchies H1, H2... H10. Each hierarchy has 3 properties of hierarchy that are associated with, HP1, HP2, HP3. Each hierarchy has also its own set of branches and leaves. Is there a way I can export only H1, H2... H10, as well as the property of hierarchy associated with each hierarchy in a database table in a format something like below:

  Name of the hierarchy	Property1 (HP1)	Property2 (HP2)	Property3 (HP3)
  H1	some value	some value...	some value...
  H2
  H3	..
  H4
  ...
  ...			..
  H10			..

  Thanks in advance

  Create a hierarchy export, select the choice of the hierarchy as "Group of the hierarchy" and select the respective hierarchies group, put the filter as a level 1 is, that will give you only one record for each hierarchy and select the required properties columns, it should work for you.

• working with the hierarchy

  Hello

  I work with the hierarchy (using start with and plug by front) in order to built a 'tree' of jobs in the application.

  For each job, the hirarchy start with LEVEL 1 to the level "n".

  In the example below, I built the hirarchy for job number 34461, with 4 levels.

  Of curse, I have hundreds of jobs, but for simplicity I shows that the values of a job.

  I need your advice with the following problem:

  In the case wherever one of the lines return "bz" in mach_name column, I need to return ALL of the hirarchy work (in the example below - all 11 lines)

  where "bz" value didn't exists column mach_name - no lines related to the specific job should be returned.

  Please notify.

  < code >

  SQL > fixed line 300

  SQL > with all_data as (SELECT X.JOB_NAME, x.joid, LEVEL,

  x.box_joid,

  mach_name

  OF AEDBADMIN.ujo_job x, AEDBADMIN.ujo_job_tree j

  WHERE X.JOID = J.JOID

  START WITH J.PARENT_JOID = 34461

  CONNECT PRIOR X.JOID = J.PARENT_JOID)

  Select all_data.*

  of all_data;

  JOID'ART BOX_JOID LEVEL MACH_NAME JOB_NAME

  ------------------------------------ ---------- ---------- ---------- ----------

  Ys_Crm_Inv_Push_Load_Ctrl_tr_BOX 31596 1 34461

  Ys_Crm_Inv_Push_Load_Ctrl_tr 31605 2 31596

  Ys_Crm_Inv_BOX 31586 3 31605

  Ys_Crm_Inv 31587 4 31586 bz

  Auto Ys_Crm_Inv_OK 31588 4 31586

  E_Push_Trx_BOX 31594 3 31605

  E_Push_Trx 31595 4 31594 cr

  E_Push_Trx_OK 31597 4 31594 auto

  Ys_Crm_Load_Cntrl_tr_BOX 31599 3 31605

  Ys_Crm_Load_Cntrl_tr 31600 4 31599 bz

  Ys_Crm_Load_Cntrl_tr_OK 31602 4 31599 auto

  11 selected lines.

  < code >

  Thank you

  SELECT DISTINCT *.

  de)

  SELECT mytest.*

  , COUNTY (CASE

  WHEN mach_name = "bz".

  THEN 1

  END

  ) ON (SCORE OF CONNECT_BY_ROOT joid'art) AS good_cnt

  sys_connect_by_path(joid,'/')

  OF mytest

  START WITH lvl = 1

  CONNECT BY box_joid = PRIOR joid'art

  ) t

  ORDER BY road;

• Help of the hierarchy

  I have a table that stores users survey participation and another table that contains the hierarchy of the employee, I need to be able to say how many people have taken the survey for a data manager.  Here is my configuration

  {code}

  create table emp

  (number of person_id,

  person_name varchar2 (240).

  person_email_address varchar2 (240).

  number of employee,

  supervisor_email_address varchar2 (240).

  active_flag VARCHAR2 (3)

  );

  insert into emp values (1, 'owner', '[email protected]', null, null, 'Y');

  insert into emp values (2, 'VP', '[email protected]', 1, '[email protected]', 'Y');

  insert into emp values (3, 'Manager1', '[email protected]', 2, '[email protected]', 'Y');

  insert into emp values (4, 'Manager2', '[email protected]', 2, '[email protected]', 'Y');

  insert into emp values (5, 'Manager3', '[email protected]', 2, '[email protected]', 'Y');

  insert into emp values (6, 'Manager1_1', '[email protected]', 3, '[email protected]', 'Y');

  insert into emp values (7, 'User1', '[email protected]', 6, '[email protected]', 'Y');

  insert into emp values (8, 'User2', '[email protected]', 6, '[email protected]', 'Y');

  insert into emp values (9, 'User3', '[email protected]', 6, '[email protected]', 'Y');

  insert into emp values (10, 'User4', '[email protected]', 6, '[email protected]', 'Y');

  insert into emp values (11, 'Manager2_1', '[email protected]', 4, '[email protected]', 'Y');

  insert into emp values (12, 'Manager2_2', '[email protected]', 11, '[email protected]', 'Y');

  insert into emp values (13, 'Lettres5', '[email protected]', 12, '[email protected]', 'Y');

  insert into emp values (14, 'Manager2_3', '[email protected]', 12, '[email protected]', 'Y');

  insert into emp values (15, 'Manager2_4', '[email protected]', 14, '[email protected]', 'Y');

  insert into emp values (16, "Utilisateur6", "[email protected]", 15, '[email protected]', 'Y');

  insert into emp values (17, 'User7', '[email protected]', 15, '[email protected]', 'Y');

  insert into emp values (18, 'User8', '[email protected]', 5, '[email protected]');

  insert into emp values (19, 'User9', '[email protected]', 5, '[email protected]');

  create the table survey_users

  (email_address varchar2 (240))

  date of completed_date

  );

  insert into survey_users values ('[email protected]', sysdate);

  insert into survey_users values ('[email protected]', sysdate-1);

  insert into survey_users values ('[email protected]', sysdate-2);

  insert into survey_users values ('[email protected]', null);

  insert into survey_users values ('[email protected]', sysdate-1);

  insert into survey_users values ('[email protected]', sysdate-2);

  insert into survey_users values ('[email protected]', null);

  insert into survey_users values ('[email protected]', sysdate-1);

  insert into survey_users values ('[email protected]', sysdate-2);

  insert into survey_users values ('[email protected]', null);

  insert into survey_users values ('[email protected]', sysdate-3);

  {code}

  See logical configurations looks something like this;

  Owner

  VP

  Manager1 (5)

  Manager1_1 [survey]

  User1 [full]

  User2 [full]

  User3 [full]

  User4 [not complete]

  Manager2 (7)

  Manager2_1 [survey]

  Manager2_2 [not complete]

  User 5 [complete]

  Manager2_3 [full]

  Manager2_4 [survey]

  Utilisateur6 [full]

  User7 [not complete]

  Manager3 (2) [no survey]

  User8 [full]

  User9 [full]

  The final goal is to be able to see results for the direct reports to the VP for a given period of time.

  Manager1 3/5 60%

  Manager2 3/7 42.8%

  Manager3 2/2 100%

  Hello

  You want people to view the responses that work?  Then make sure that the code you post your question works, too.  The new INSERT instructions you posted don't work; they have values of 5, but the table has 6 columns.  This shows one of the reasons why you must always include an explicit list of columns in INSERT statements.

  Here's a way to do what you asked:

  WITH got_descendants AS

  (

  SELECT person_email_address

  CONNECT_BY_ROOT person_name AS ancestor_name

  WCP

  WHERE LEVEL 1 >

  START WITH (IN) Manager

  SELECT person_id

  WCP

  WHERE person_name = "VP".

  )

  CONNECT BY supervisor_id = person_id PRIOR

  )

  SELECT d.ancestor_name

  COUNTY (s.email_address) |

  ' / '                           ||

  (D.person_email_address) be ACCOUNT AS txt

  , TO_CHAR (100 * COUNT (s.email_address))

  / COUNT (d.person_email_address)

  , "999.9'."

  ) || '%'                       AS pct

  OF got_descendants d

  LEFT OUTER JOIN survey_users s ON s.email_address = d.person_email_address

  "AND s.completed_date > = DATE ' 02-04-2014"

  AND s.completed_date<  date="">

  GROUP BY d.ancestor_name

  ORDER BY d.ancestor_name

  ;

  Assuming that all the INSERTs work you posted were executed April 4 at noon, the results we get for this window of time (from April 2 to April 30) are:

  ANCESTOR_NAME TXT PCT

  -------------------- ------- -------

  Manager1 3 / 5 60.0%

  Manager2 2 / 7 28.6%

  Manager2 had 3 subordinates who responded to the survey, but 1 of them it completed April 1, outside the window.

• Getting the name of the top of the hierarchy of the inventory in a VC

  When you cross a VC inventory, what is the type of the object at a higher level? I think it's a folder - that's what I'm doing once the connection and I browse the hierarchy correctly.

  File fd (sc.rootFolder);

  Where sc is the ServiceContent instance I understand well after the connection to the server.

  The VC that I use is named STORAGE2 and the top-level object is also named STORAGE2 - but when I ask the name of the object "fd" he gave a name "data centers". When I ask the other folders in the hierarchy down, I make own name except for this one.

  Am I wrong in thinking that the top-level of the VC object is a folder? How can I name own derieve for this object?

  Thank you

  . / Siva.

  "Data centers" is the name of the rootFolder.  The next type of the object in the tree is defined entities of data center.  Take a look at the ServiceInstance object to see the tree in the API documentation.

  ServiceInstance

  In the user of the vSphere Client interface, the rootFolder is hidden, and they show rather the name of vCenter. If you want to emulate the appearance of the user interface of vSphere, you need to hide some of the items of base directory, but they are there in the real inventory tree in code.

• How to manage the hierarchy in the list of key words

  I have a few keywords that are nested two levels down, but when I click on and drag on the key word to move it to the top one or two levels in the hierarchy, it does not move. He's here. Of course, I know how to put a key word in a lower hierarchy but now I need to move some of them to a higher level, as you can do it in the Navigation pane on the left. Is there a place outside (LR) where I can go and manage the hierarchy?

  Suppose you have two keywords, A > B > X and has > X and you want to merge all the A > B > X pics has > X and delete > B > X.  To do this:

  1. in the keyword list Panel, hover over A > B > X and click the arrow that appears to the right of the keywodr.  This will exactly show photos that have A > B > X.

  2 Select all these photos by Edit > select all.

  3. in the Keywording Panel, in "Click here to add keywords", type "has > X»  Now all the photos that had a > B > X will also have A > X.

  4. in the keyword list Panel, right-click A > B > X and select Remove.