ListField onFocus selection last element

Hello

ListField seems to be select the last item in the list by default when it gets focus for the first time on a screen. Subsequent navigations between other fields in the form and the listfield seem to function normally (first elmt is picked up first).  Does anyone have an idea why this is happening?

Thank you

Teja.

Sorry misunderstood.  I'm not sure. Never seen that before.  You're doing a setSelectedIndex?

Tags: BlackBerry Developers

Similar Questions

  • question of ListField remove the last element

    Hi all!

    Is there a known problem in ListField which explains the revival of an OutOfboundException when removing an element from a list with a single element?

    When you use listField.delete () I get this exception when the screen tries to set the focus.

    Thank you for your response. I finally solved the problem in my case using the substitution of "isFocusable" you describe here.

    While the default empty string is not the best solution for me display information when the list does not contain any element, I implemented the my own specific logic with a custom LabelField displayed instead of the ListField.

  • I've added two elements (accessibility and analyze) in the Tools menu of right hand.  How to remove or hide?  Or at least rearrange the elements of the toolbar. I want to Sign & certify be the last element/section.  Thank you.

    I've added two elements (accessibility and analyze) in the Tools menu of right hand.  How to remove or hide?  Or at least rearrange the elements of the toolbar. I want to Sign & certify be the last element/section.  Thank you.

    Hi Stacey Nathan,

    To remove the items from right toolbar, click Tools at the top.

    Then open the fall down to the accessibility or analyze and select 'delete the shortcut '.

    In a similar way, select "Add a shortcut" in the Tools drop-down menu to add to the tool on the right pane.

    Let us know if you need help.

    Kind regards

    Meenakshi

  • You will return the "Select an element in the page" button right in Inspector?

    The 'select an element on the page' is to the extreme left now. Since ver.32 FF. As seen in this image:
    https://MDN.mozillademos.org/files/8315/Inspector-select-element-fx32.PNG
    Change for the worse in my opinion. You will return it right into the next version? Thank you.

    N ° it is always on the far left in the current construction of 35.0a1 of Firefox.

    All Toolbox items are on the far right, including the gear button options to define what items to display.

  • How to view the last element in a dynamic table 1 d

    Hello..

    I want to display the value of the last element in a dynamic array 1 d... / I mean... If I stop the vi race, I need to display the last element of the array... How can I do this?

    and is it possible to use a button to start the vi... instead of using the Run button on the face before of the vi?

    An array of index!.  Size of table allows to determine the size of your array, subtract 1, that feed into the terminal array of Index index.

    You start the VI running somehow.  It can be assigned to run when opening.  Assuming that what you want is a way to type values in a front panel, press a GO button you created on the front panel, then have the real part of the VI to run.  You can use a structure of the event.  Or put a while loop at the beginning with a small wait next statement which basically just asks the GO button.  When you press this button, the Boolean value true stops the whole loop and allows the program to move on the main body of your program.

  • Stopping everything in a loop after the last element of a 2D array

    How to stop a while loop after the last element of a 2d array.  I tried an uninitialized matrix wiring constant and comparison with table 2d, which has been indexed to a 1 d table, but that did not work.

    Hahaha, Hey, it's true what they say, a picture is worth a thousand words

  • stop all loop after the last element of the array

    I want to stop a while loop after the last element of an array. I can't use table size because the size of the array can change within the program.  What should I do?

    Why not use the function empty array like this...?

  • Last element of the array

    Hello

    Running mod, when I add elements in the table, I want to see in the last element of the array automatically.

    How can I do that. (without using the vertical scroll bar).

    In a thousand words or less.  Nodes property allows you to programmatically access the properties of the objects.

    (Yes, you will need to run twice to see the result I have no default value)

  • Last element in the chain

    Hi all

    I have a string like this:

    55.000000; 10.000000; 0.100000; 1.000000; 1.000000; 0.100000; 0.000000; 0.000000; 1.000000; 1.000000; 22.000000; 0.100000; 6144.000000;

    The length of the string is not always the same. What I want is to have the last element. That is to say in this case 6144

    One way is to get the length of the string and using a subset of the string to get the last element. But to do this, the length must be always constant.

    Y at - it another way to get the last element independent of the length of the string

    Thank you

    Since you have the extra semicolon at the end, I actually caught the element from the second to the last of the table after the string of worksheet to the table.

  • Remove the last element

    Hello

    I'm removing the last element in a LL individually. But it's not entry (method deleteFromTail) and also a message delete2 which I have not written anywhere in my print program... I don't have the code running on any other computer.

    Javax.swing import. *;

    Class StudNode {}

    int id;

    The name of the string;

    Next StudNode;

    StudNode (int id1, String name1) {}

    ID = id1;

    name = name1;

    }

    }

    public class StudListDel2 {}

    StudNode head, tail;

    StudListDel2 () {}

    head = tail = null;

    }

    Sub create4ElementList () {}

    Add them to the queue

    int id = 1;

    int i = 0;

    String name = "THIS" + id;

    StudNode newNode;

    newNode = new StudNode (id, name);

    head = newNode;

    tail = newNode;

    for (i = 0; i < 4; ++ I) {}

    ID ++;

    name = "THIS" + id;

    newNode = new StudNode (id, name);

    tail. Next = newNode;

    tail = newNode;

    tail. Next.Next = null;

    }

    }

    Sub display4List () {}

    tail = head;

    {while(tail!=null)}

    JOptionPane.showMessageDialog (null, "name =" + tail.name + "id =" + tail.id);

    tail = tail.next;

    }

    }

    Sub deleteFromTail () {}

    If only a single node in the list

    JOptionPane.showMessageDialog(null,"delete***=1");

    / * If (head == tail)

    head = tail = null;

    else {}

    JOptionPane.showMessageDialog(null,"delete***=2");

    StudNode temp.

    Temp = head;

    While (temp.next! = tail) {}

    Temp = temp.next;

    JOptionPane.showMessageDialog (null, "led2 inside while" + tail.name + "id =" + tail.id);

    }

    tail = temp;

    tail. Next = null;

    JOptionPane.showMessageDialog (null, "delete3 =");

    }

    */

    }

    Public Shared Sub main (String [] args) {}

    StudList obj = new StudList ();

    obj.create4ElementList ();

    obj.display4List ();

    JOptionPane.showMessageDialog (null, "deleteOOO1 =");

    obj.deleteFromTail ();

    JOptionPane.showMessageDialog (null, "deleteFFF4 =");

    obj.display4List ();

    }

    }

    Someone please guide me.

    Zulfi.

    Hello

    His work. I can't believe. I just changed the name of the file from StudListDel2.java to StudListDel3.java & changed the name of class, he began to work.

    I don't know if the logic is correct. But the logic is correct because I follow the logic of deletion of a book that I used 'while' Loop instead of "for". If any body having time, please read the code of void deleteFromTail () { is correct or not so that I shouldn't be passing wrong information.}

    The complete code is:

    public class StudListDel3 {}

    StudNode1 head, tail, last;

    StudListDel3 () {}

    last = Chief = tail = null;

    }

    Sub create4ElementList () {}

    Add them to the queue

    int id = 1;

    int i = 0;

    String name = "THIS" + id;

    StudNode1 newNode;

    newNode = new StudNode1 (id, name);

    head = newNode;

    last is tail is newNode;

    for (i = 0; i<4; ++i)="">

    ID ++;

    name = "THIS" + id;

    newNode = new StudNode1 (id, name);

    Last.Next = tail. Next = newNode;

    last is tail is newNode;

    tail. Next.Next = null;

    }

    }

    Sub display4List () {}

    tail = head;

    {while(tail!=null)}

    JOptionPane.showMessageDialog (null, "name =" + tail.name + "id =" + tail.id);

    tail = tail.next;

    }

    }

    Sub deleteFromTail () {}

    If only a single node in the list

    JOptionPane.showMessageDialog(null,"delete***=1");

    If (head is tail)

    head = tail = null;

    else {}

    JOptionPane.showMessageDialog(null,"delete***=2");

    StudNode1 temp.

    Temp = head;

    JOptionPane.showMessageDialog (null, "first and foremost remove * = 3");

    While (temp.next! = last) {}

    JOptionPane.showMessageDialog (null, "Inside all-in-1");

    Temp = temp.next;

    JOptionPane.showMessageDialog (null, "inside led2 while name =" + temp.name + "id =" + temp.id);

    }

    last is tail is temp;

    Last.Next = tail. Next = null;

    JOptionPane.showMessageDialog (null, "delete3 =");

    }

    }

    Public Shared Sub main (String [] args) {}

    StudListDel3 obj = new StudListDel3 ();

    obj.create4ElementList ();

    obj.display4List ();

    JOptionPane.showMessageDialog (null, "deleteOOO1 =");

    obj.deleteFromTail ();

    JOptionPane.showMessageDialog (null, "deleteFFF4 =");

    obj.display4List ();

    }

    }

    Thanks for your reply. Its really beneficial when we see the flow back of great programmers like you. I'm not a programmer.

    Zulfi.

  • ListField onFocus() calling repeatedly

    Hello

    For OS 6.0, nobody knows what are the onFocus() method of a ListField causes several times if you hold your finger down on an empty area of the ListField (where there is no line) and move you your finger?  I don't see this behavior on 5.0.  I don't know why onFocus() is regularly invited as when I do this, one of my lines of list is selected and the ListField should have already developed.

    This affects a logic I use to dynamically add the MenuItems when the ListField is focused.  Therefore, I am trying to stop this behavior...

    Thank you!

    Found the problem:

    Once I overrided touchEvent() for the ListField, then the problem stopped.

  • How to select an element of a list with a separate button item

    This is a repost, I decided it would probably be better here than in the General discussion Forum. I will try to remove it.

    Hi all
    This is my first post here. I'm trying to find a way to select an item in a list with a button element. This button calls a function. I searched for the last 3 hours online and I can't find anything about it. I thought that maybe I could together the selectedItem parameter, but which is read-only and I think it returns an object rather than something like a number reference, so even if I could put it, it would be useless. I also found a button of update of get, thinking that can lead somewhere, but I think it's to define which element has the focus currently insofar as grasping and things like that. I'm lost.

    Basically, I'm looking for a way to type this myList.setSelected (5); where 5 is the 5th item in the list.

    Any help would be appreciated.

    Never mind found. It's called selectedIndex property and it is writable

  • How to change the sort order of the items sought for the last element of this research first. I DON'T want to say the order search engines, but the existing research by arrow down

    I want to be able to change the sort order of the items, I already looked in the search box. I want to be able to hit the arrow key down and see my previous searches in order of last search showing the first. For the moment, I don't know how it is sorting and it is very annoying to have to re - enter a query that I typed 5 minutes earlier, but because I typed in another 10 since it's lost somewhere in the list. Is it possible, I Googled, but did not find the topic anywhere. Just to clarify, I DON'T mean of the order of the search engines (which is what appears in google), I mean that the text typed into which has been registered in the drop-down list.

    Thank you

    'Form filling' uses a "frecency" algorithm, frequency + recency, similar to the list of AutoComplete address bar.

    I found an extension that seems relevant, but critics are old, so I'm not sure it's still working: Searchbar Autocomplete Order.

    But... is the AutoComplete does not? I expect that typing a few characters of the previous query would be to filter the list so that you can easily select? Or is the problem that the list does not remember quite who looking for?

  • Select last tab tab close

    Problem with addon, TabUtilities. After that closing a tab, the browser always focuses on the far right tab REGARDLESS of what I have select(or unselect) in the three boxes under catch on the tab in the settings. I even tried to change different values in 'extensions.tabutils.selectOnClose' in topic: config. Nothing seems to have an effect. I'm putting TabUtilities to focus on the last tab visited after closing a tab. In other words, focus to the tab containing the link that I opened a new window with. I tried all the settings including the last tab visited without success. Thank you very much. Using FF4b8 on WinXPProf

    There is a thread of user to Tab Utilities on the Mozillazine forum support. You should post your question here. It is listed in the "Developer comments" section on the page Add on.

  • Adding the n last elements of an array

    I collect data from an instrument once per minute and add each value in a table. After many days, there are a large number of values in the table. I want to be able to select a duration, that is 4 hours and the last 4 hours of values added together, so it can be displayed. Any ideas. Thanks in advance for the help.

    ssmith

    Use the subset of the array and add items to the table.

    Once per minute = 60 values per hour.

    Number of hours * 60 = number of items you want.

    So subtract number of items in the table size to get your index.

    Quick and easy!

    8-)

Maybe you are looking for