missing closing parenthesis when creating foreign key

Similar Questions

• Online syntax to create Foreign key with Alter Table statement

  I am a pretty meticulous reader. That being said, from the 4 texts that I read to start to learn SQL, I do not remember and do more that probably not, find a syntax online for the creation of a CF with the statement alter table.

  Just something I thought while I was reading.

  Is there a such syntax?

  And if so someone can give me direction on my code?

  ALTER table emp4 change employee_id key foreign employees of references (employe_id);

  It gives me the option error invalid alter table.

  Any idea would be appreciated.

  Thank you.

  rp0428 wrote:

  A foreign key is a constraint, you must use ADD CONSTRAINT.

  Thare is more than one way to skin a cat:

  SQL > create table tbl (id number, name varchar2 (10))
  2.

  Table created.

  SQL > alter table tbl adds (foreign key references emp (empno))
  2.

  Modified table.

  SQL > select constraint_name,.
  2 constraint_type
  3 from user_constraints
  4 where table_name = 'TBL '.
  5.

  CONSTRAINT_NAME C
  ------------------------------ -
  SYS_C0021920 R

  SQL > drop table tbl purge
  2.

  Deleted table.

  SQL > create table tbl (id number, name varchar2 (10))
  2.

  Table created.

  SQL > alter table tbl change (foreign key references emp (empno))
  2.

  Modified table.

  SQL > select constraint_name,.
  2 constraint_type
  3 from user_constraints
  4 where table_name = 'TBL '.
  5.

  CONSTRAINT_NAME C
  ------------------------------ -
  SYS_C0021921 R

  SQL >

  SY.

• Create Foreign Key forced in Warehouse Builder

  Hello world
  
  Yet once I need your help, please.
  My question is: Warehouse Builder is a way to create relationships between the Dimension Tables and one fact Table?
  I give you a simple example:
  We have produced paintings, customer, sales. So product and customer become a dimension table and sales become a fact table. In this fact table, we store the product_table_key, the customer_table_key and the messure of sale itself.
  If we think of datamodeling aspects our relationship 1: n between product_dimension_table and fact_table and also a relationship 1: n between customer_dimension_table and fact_table.
  How can we create these reports in the Warehouse Builder?
  If we design the objects of SQL database, we could create the need forced like that:
  Fact_table ALTER TABLE ADD (REFERENCES of KEY FOREIGN (customer_dim_fk) customer (customer_table_key));
  
  Please let me know how we can treat them in Warehouse Builder. I don't want to create which restricts manually in SQL Developer later.
  Thank you very much!
  
  Kind regards
  David

  Hi David,

  You can create the foreign key in OWB.
  An example of comprime1 that is created or imported in OWB.
  Open the T1 table in the data editor.
  Click constraints
  Type a name for the constraint
  Set the foreign key type
  Choose the local column on which you want to create the FK
  Now goto reference tab and choose the table and column (PK) whereby the CF should have a reference.

  She's.
  Save and generate the table T1 script you will have something similar to the following

  ALTER TABLE '' ADD CONSTRAINT '' FOREIGN KEY ('')
  REFERENCES "" ("");

  You can do a lot of settings on this FK in Table T1---> configure---> foreign keys

  Thank you
  Fati

• Missing right parenthesis when you use the CONTAINS function

  Hello
  
  The following sql causes the error "missing right parenthesis. Its a search engine simple execution of PHP that dynamically adds each keyword to a connection variable. This works fine if I use only 1 keyword, but as soon as others are added, I get the error.
  
  Here's the SQL echo:
  

  SELECT SCORE(1), TITLE FROM MYTABLE WHERE CONTAINS(TITLE, :1 AND :2, 1) > 0 ORDER BY SCORE(1), TITLE ASC

  My 1st thought was contains it seeks single quote so I tried the following combinations:
  

   CONTAINS(TITLE, ':1' AND ':2', 1) > 0
   CONTAINS(TITLE, ':1 AND :2', 1) > 0

  Both through the crossover so maybe its nothing to do with citations. I also tried to use single quotes when concatinating the sql in PHP. No joy :(

  CONTAINS the second parameter is a string, so you should concatenate your variables of two link with the chain AND:

  CONTAINS (TITLE,: 1 |) ' AND ' | (: 2, 1) > 0

• is missing a closing parenthesis in create materialized view statement

  Hi, I am using oracle 10g R2 and try to create a view of materalized with the following statement:

  CREATE MATERIALIZED VIEW MVT_DEC_TAB USING INDEX REFRESH FAST ON COMMIT AS 
  select i.rowid as ind_rowid,c.rowid as indc_rowid,r.rowid as r_rowid,b.rowid as b_rowid,brk.rowid as brk_rowid,
  i.name,i.sname,i.address,i.tel,i.fax,i.email,
  DECODE(c.BRKNO,null,0,1) AS DEC_BRK,
  TO_TIMESTAMP(NVL(VEKDOV,'2001/01/01')||' 12:00:00','YYYY/MM/DD HH:MI:SS'),
  DECODE(c.brkno,null,DECODE(c.ncmpcode,null,c.vekdov,b.bcarddov),brk.validitydov)
  from indiv i,indivcoding c
  LEFT OUTER JOIN BROKER brk ON brk.brkno = c.brkno
  LEFT OUTER JOIN CORPORAT r
  ON c.ncmpcode=r.cmpcode INNER JOIN BCARD b ON b.bcardno=r.bcardno
  where c.typeact=2  
  and c.natcode=i.natcode
  and c.brkno is not null or c.ncmpcode is not null or c.nnatcode is not null

  but I get an error message:
  where c.typeact = 2
  ERROR on line 11:
  ORA-00907: lack of right parenthesis
  
  which makes no sense because if I run the sql code of the materialized view, it runs normally.
  I need to know what the causing this can someone help?

  Do not use the "LEFT OUTER JOIN" ANSI syntax in your CREATE MATERIALIZED VIEW definition.
  Specify

  FROM indiv i,indivcoding c, broker brk, corporat r
  WHERE brk.brkno(+) = c.brkno
  AND c.ncmpcode(+) = r.cmpcode
  

  OR

  FROM indiv i,indivcoding c, broker brk, corporat r
  WHERE c.brkno = brk.brkno(+)
  AND r.ncmpcode = c.cmpcode(+)
  

  (I find it more readable).

  Hemant K Collette

• Missing page layouts when creating new file

  Hi all

  I use the current version of the DreamWeaver CC. When I go to File > New > blank Page > HTML, I see only two layouts in the layout box:

  • 2 fixed columns, sidebar, header and footer right
  • 3 fixed columns, header and footer

  Help of DreamWeaver (http://helpx.adobe.com/dreamweaver/using/css-layouts.html) says "you can choose from 16 different layouts."

  Does anyone have an idea on what has happened to the other page layouts?

  Thank you

  Douglas

  CC is HTML5-centric now if only 2 page layouts are available.  Previous versions of DW had more options but these page content layouts code which is considered by many to be obsolete by today's standards.

  If you need more options, check out FluidGrid Layouts. Or simply change the pixels to % CSS widths in 2 layouts provided.

  In addition to creating your own layouts, customized with CSS Designer, you might jumpt start your projects with one of these popular frameworks:

  Zurb Foundation

  http://Foundation.ZURB.com/templates.php

  Reusable skeleton

  http://www.getskeleton.com/

  Initializr (HTML5 Boilerplate, sensitive or "bootstrap")

  http://www.Initializr.com/

  Bootstrap DMX area * free extension for DW *.

  http://www.DMXzone.com/go/21759/DMXzone-bootstrap/

  Project of seven Page Packs * commercial CSS Templates *.

  http://www.Projectseven.com/products/templates/index.htm

  Nancy O.

• logical foreign key

  Hi all
  
  I'm sorry to bring the similar question. .
  I am able to create the logical foreign key for table logic with A new (A.2 = B.2) (2 is calculated logical column).
  However there are still some physical join foreign key with the old constitution (A1 = B. 1). When I deploy this RPD, it generates sql with (A1 = B. 1) join condition.
  
  Then, I removed this RPD physical foreign key join and received a warning "logical dimension B has a source which don't happen with any fact table" in the consistency check.
  
  Always after the deployment of the Dre, I get the error message [nQSError: 14025] indeed no table exists at the level of detail requested: in the report.
  
  I'm missing something. The logical foreign key has join condition correct that he is still not on the physical join of riding.
  
  Thank you for going through this question,
  
  http://Tinypic.com/r/2qiwmrr/6

  Based on your comments, I am looking at the documentation:
  I found a Note: a logical key to a fact table should consist of key columns that join the tables of attribute. Logical foreign key joins may be necessary if the Oracle's BI server should be used as an ODBC data source for some queries and third party reporting tools.

  I need to see why ODBC, and unlike the foreign logic key join is not the substitution of the physical layer to join.

  BTW: Since you want to go with a join defined using logical column, you can use the same expression in physical join using the expression builder?

  It should work.

  EX: T43770. Department_id = case when T43764. Department_id > 10 then T43764. Department_id 0 otherwise end

  Published by: Srini VIEREN on 18 January 2013 16:52

• Insert data into a database with foreign key...

  So I recently learned how to use oracle and am doing my first DB, I created the tables and added constraints, now I am trying to add data in my takes but I'm getting errors, below I listed all my tables, then the data im trying to insert followed by error messages. Please can somebody translate my error messages in plain English and tell me how to fix... Thank you
  
  Ollie!
  
  
  HERE'S OUR TABLES.
  
  CREATE TABLE 'ASSESMENT_TYPE '.
  (VARCHAR2 (15) 'ASSESMENT_TYPE',)
  VARCHAR2 (70) "ASSESMENT_DESCRIPTION."
  ENABLE 'ASSESMENT_TYPE_PK' CONSTRAINT PRIMARY KEY ('ASSESMENT_TYPE')
  )
  
  CREATE TABLE 'COURSES '.
  (NUMBER OF 'COURSE_NO',
  VARCHAR2 (30) "COURSE_NAME."
  DATE OF THE "COURSE_START_DATE."
  DATE OF THE "COURSE_END_DATE."
  NUMBER OF "TOTAL_UNITS."
  NUMBER OF "COURSE_COORDINATOR_STAFF_NO."
  NUMBER OF "TOTAL_COURSE_COST."
  NUMBER OF "THIRD_PARTY_SUPPLIER_NO."
  ACTIVATE THE KEY PRIMARY CONSTRAINT 'COURSE_PK' ('COURSE_NO'),
  "COURSE_CON_FK' FOREIGN KEY ('COURSE_COORDINATOR_STAFF_NO') CONSTRAINT
  ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
  "THPARTY_SUPPLIER_FK' FOREIGN KEY ('THIRD_PARTY_SUPPLIER_NO') CONSTRAINT
  SELECT REFERENCES "THIRD_PARTY_SUPPLIER" ("THIRD_PARTY_SUPPLIER_NO")
  )
  
  CREATE TABLE 'COURSE_OUTCOME '.
  (VARCHAR2 (5) 'COURSE_OUTCOME',)
  VARCHAR2 (25) "COURSE_OUTCOME_DESCRIPTION."
  ENABLE 'COURSE_OUTCOME_PK' CONSTRAINT PRIMARY KEY ('COURSE_OUTCOME')
  )
  
  CREATE TABLE 'DEPARTMENT '.
  (NUMBER OF 'DEPARTMENT_NO',
  VARCHAR2 (50) "DEPARTMENT_NAME."
  VARCHAR2 (150) "DEPARTMENT_LOCATION."
  NUMBER OF "DEPT_MANAGER_NO."
  ACTIVATE THE KEY CONSTRAINT PRIMARY "DEPARTMENT_PK" ("DEPARTMENT_NO'),
  "DEPTMANNO_FK' FOREIGN KEY ('DEPT_MANAGER_NO') CONSTRAINT
  SELECT REFERENCES 'EMPLOYEE' ('EMPLOYEE_NO')
  )
  CREATE TABLE 'EDUCATIONAL_INSTITUTION '.
  (VARCHAR2 (100) 'SCHOOL_UNIVERSITY_NAME',)
  VARCHAR2 (200) "SCHOOL_UNIVERSITY_ADDRESS."
  ENABLE 'EDUCATIONAL_INSTITUTION_PK' CONSTRAINT PRIMARY KEY ('SCHOOL_UNIVERSITY_NAME')
  )
  CREATE TABLE 'EMPLOYEE '.
  (NUMBER OF 'EMPLOYEE_NO',
  VARCHAR2 (50) "EMPLOYEE_NAME"
  VARCHAR2 (150) "EMPLOYEE_ADDRESS."
  VARCHAR2 (50) "JOB_DESCRIPTION."
  'STATUS' VARCHAR2 (15).
  'START_DATE' DATE,
  NUMBER OF "SALARY_CODE."
  NUMBER OF "SUPERVISOR_EMPLOYEE_NO."
  NUMBER OF "DEPARTMENT_NO,"
  ACTIVATE THE KEY PRIMARY CONSTRAINT 'EMPLOYEE_PK' ('EMPLOYEE_NO'),
  "SALARYCODE_FK' FOREIGN KEY ('SALARY_CODE') CONSTRAINT
  ACTIVATE THE REFERENCE 'SALARY' ('SALARY_CODE'),
  "SUPEMNO_FK' FOREIGN KEY ('SUPERVISOR_EMPLOYEE_NO') CONSTRAINT
  ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
  "EMDEPNO_FK' FOREIGN KEY ('DEPARTMENT_NO") CONSTRAINT
  ACTIVATE THE 'DEPARTMENT' ('DEPARTMENT_NO") REFERENCES
  )
  CREATE TABLE 'EMPLOYEE_COURSE_OUTCOME '.
  (NUMBER OF 'EMPLOYEE_NO',
  NUMBER OF "COURSE_NO."
  VARCHAR2 (5) "COURSE_OUTCOME_CODE."
  NUMBER OF "COURSE_EMPLOYEE_MARK."
  ACTIVATE 'EMPLOYEE_COURSE_OUTCOME_PK' CONSTRAINT PRIMARY KEY ('EMPLOYEE_NO', 'COURSE_NO'),
  "EM_FK' FOREIGN KEY ('EMPLOYEE_NO') CONSTRAINT
  ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
  "EMPLOYEE_COURSE_FK' FOREIGN KEY ('COURSE_NO') CONSTRAINT
  ACTIVATE THE REFERENCE 'COURSES' ('COURSE_NO'),
  "EMPLOYEE_COURSE_OCODE_FK' FOREIGN KEY ('COURSE_OUTCOME_CODE') CONSTRAINT
  SELECT REFERENCES "COURSE_OUTCOME" ("COURSE_OUTCOME")
  )
  CREATE TABLE 'EMPLOYEE_COURSE_UNIT_OUTCOME '.
  (NUMBER OF 'EMPLOYEE_NO',
  NUMBER OF "COURSE_NO."
  NUMBER OF "UNIT_NO."
  VARCHAR2 (5) "UNIT_OUTCOME_CODE."
  NUMBER OF "EMPLOYEE_UNIT_MARK."
  ACTIVATE 'EMPLOYEE_CUO_PK' CONSTRAINT PRIMARY KEY ('EMPLOYEE_NO', 'COURSE_NO', 'UNIT_NO'),
  "EMPCU_FK' FOREIGN KEY ('EMPLOYEE_NO') CONSTRAINT
  ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
  CONSTRAINT 'EMCU-FK' FOREIGN KEY ('UNIT_NO')
  SELECT REFERENCES 'UNIT' ('UNIT_NO')
  )
  CREATE TABLE 'EMPLOYEE_CRS_UNIT_ASSESMENT '.
  (NUMBER OF 'EMPLOYEE_NO',
  NUMBER OF "COURSE_NO."
  NUMBER OF "UNIT_NO."
  VARCHAR2 (15) "ASSESMENT_TYPE."
  NUMBER OF "EMPLOYEE_ASSESMENT_MARK."
  ACTIVATE A KEY PRIMARY ('EMPLOYEE_NO', 'COURSE_NO', 'UNIT_NO') CONSTRAINT 'EMPLOYEE_CRS_PK '.
  )
  CREATE TABLE 'EMPLOYEE_QUALIFICATION '.
  (NUMBER OF 'EMPLOYEE_NO',
  VARCHAR2 (5) "QUALIFICATION_TYPE."
  'SUBJECT' VARCHAR2 (20).
  NUMBER OF "QUALITY."
  VARCHAR2 (100) "SCHOOL_UNIVERSITY_NAME."
  VARCHAR2 (50) "AWARDING_BODY."
  NUMBER OF "DATE_QUALIFICATION_OBTAINED."
  TURN ON THE PRIMARY CONSTRAINT "EMPLOYEE_QUALIFICATION_CON_PK" ("EMPLOYEE_NO", "QUALIFICATION_TYPE", "SUBJECT").
  "DEPTNO_FK' FOREIGN KEY ('EMPLOYEE_NO') CONSTRAINT
  ACTIVATE THE REFERENCE 'EMPLOYEE' ('EMPLOYEE_NO'),
  "EMQUALREF_FK' FOREIGN KEY ('QUALIFICATION_TYPE') CONSTRAINT
  ACTIVATE THE REFERENCE 'QUALIFICATION_TYPE' ('QUALIFICATION_TYPE'),
  "SCHUNINAME_FK' FOREIGN KEY ('SCHOOL_UNIVERSITY_NAME') CONSTRAINT
  SELECT REFERENCES "EDUCATIONAL_INSTITUTION" ("SCHOOL_UNIVERSITY_NAME")
  )
  CREATE TABLE 'QUALIFICATION_TYPE '.
  (VARCHAR2 (5) 'QUALIFICATION_TYPE',)
  VARCHAR2 (25) "QUALIFICATION_DESCRIPTION."
  ENABLE 'QUALIFICATION_TYPE_PK' CONSTRAINT PRIMARY KEY ('QUALIFICATION_TYPE')
  )
  CREATE TABLE 'WAGES. "
  (NUMBER OF 'SALARY_CODE',
  NUMBER OF "SALARY_AMOUNT."
  ENABLE 'SALARY_PK' CONSTRAINT PRIMARY KEY ('SALARY_CODE')
  )
  CREATE TABLE 'THIRD_PARTY_SUPPLIER '.
  (NUMBER OF 'THIRD_PARTY_SUPPLIER_NO',
  VARCHAR2 (100) "THIRD_PARTY_NAME."
  VARCHAR2 (100) "THIRD_PARTY_CONTACT_NAME."
  ENABLE 'THIRD_PARTY_SUPPLIER_PK' CONSTRAINT PRIMARY KEY ('THIRD_PARTY_SUPPLIER_NO')
  )
  CREATE TABLE "UNIT".
  (NUMBER OF 'UNIT_NO',
  VARCHAR2 (30) "UNIT_NAME"
  NUMBER (7.2) "UNIT_COST"
  ENABLE 'UNIT_PK' CONSTRAINT PRIMARY KEY ('UNIT_NO')
  )
  CREATE TABLE 'UNIT_OUTCOME '.
  (VARCHAR2 (5) 'UNIT_OUTCOME_CODE',)
  VARCHAR2 (25) "UNIT_OUTCOME_DESCRIPTION."
  ENABLE 'UNIT_OUTCOME_PK' CONSTRAINT PRIMARY KEY ('UNIT_OUTCOME_CODE')
  )
  NOW, WE TRY TO ENTER DATA.
  
  insert into values used (0002, "Mitch Vaughan', '145 a Green Street', 'Administrator', 'Active', December 1, 2010", 1,1,1 ");
  
  insert into values used (0001, "Ollie Marriott", "12 the Ghetto Street', 'Administrator', 'Active', 2 December 2010", 2,2,1);
  
  insert into values employee (0003, "Tim Reynolds, '12 Shoebury Way', 'Cleaner', ' Inactive', December 2, 2000, 3,0002,3);
  
  insert into values used (0004, "Tom Watson", ' 90 Seymour Road","Data Analyst","Active", December 10, 2008", 4 000 104 ");
  
  insert into values used (0005, "Wajj is', 125 hamlet Court ', 'Clean', 'Active', September 15, 2007", 5 000 105 ");
  
  insert into values used (0006, "Nathan Mann', '33 a Bushey Hill Road', 'Receptionist', 'Active'", December 2, 2010 ", 6 000 406);
  
  insert into values used (0007, "Tim DeLong', ' 34 Buena Vista Drive", "Receptionist", "Active", December 21, 2010 ', 7, 1, 06);
  
  NOW WE'RE GETTING THESE ERROR MESSAGES.
  
  Connected.
  SQL > insert into values used (0002, "Mitch Vaughan', '145 a Green Street', ' has)
  dministrator ', 'Active»(, 1er décembre 2010', 1,1,1);
  insert into values used (0002, "Mitch Vaughan', '145 a Green Street', ' administrative)
  strator ', 'Active', 1 December 2010 "(, 1,1,1).
  *
  ERROR on line 1:
  ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
  found
  
  
  SQL >
  SQL > insert into values used (0001, 'Ollie Marriott', ' 12 Ghetto Road', ' SMA)
  made ', 'Active»(, 2 décembre 2010', 2,2,1);
  insert into values used (0001, 'Ollie Marriott', ' 12 Ghetto Road', ' Directors)
  Rator ', 'Active»(, 2 décembre 2010', 2,2,1)'.
  *
  ERROR on line 1:
  ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
  found
  
  
  SQL >
  SQL > insert into values used (0003, 'Tim Reynolds, 12 Shoebury way', ' Clea)
  NER ","inactive»(, 2 décembre 2000', 3,0002,3);
  insert into values used (0003, "Tim Reynolds', ' 12 Shoebury Way", "Cleaner")
  ("Inactive", 2 December 2000', 3,0002,3)
  *
  ERROR on line 1:
  ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
  found
  
  
  SQL >
  SQL > insert into values used (0004, 'Tom Watson", ' 90 Seymour Road', ' data one)
  nalyst ","Active»(, 10 décembre 2008', 4 000 104);
  insert into values used (0004, 'Tom Watson", ' 90 Seymour Road', ' data Analys)
  t ', 'Active', December 10, 2008 "(, 4 000 104).
  *
  ERROR on line 1:
  ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
  found
  
  
  SQL >
  SQL > insert into values used (0005, 'Wajj is', ' 125 hamlet Court', ' Clean)
  St ', 'Active»(, 15 septembre 2007', 5 000 105);
  insert into values used (0005, "Wajj is', 125 hamlet Court ', 'Clean',')
  Active ", September 15, 2007"(, 5 000 105).
  *
  ERROR on line 1:
  ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
  found
  
  
  SQL >
  SQL > insert into values used (0006, "Nathan Mann', '33 a Bushey Hill Road', ')
  Receptionist ', 'Active', December 2, 2010 "(, 6 000 406);
  insert into values used (0006, "Nathan Mann', '33 a Bushey Hill Road', ' Recep)
  tionist ', 'Active»(, 2 décembre 2010', 6 000 406)'.
  *
  ERROR on line 1:
  ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
  found
  
  
  SQL >
  SQL > insert into values used (0007, "Tim DeLong', ' 34 Buena Vista Drive," ' R)
  Eceptionist ', 'Active»(, 21 décembre 2010', 7, 1, 06);
  insert into values used (0007, "Tim DeLong', ' 34 Buena Vista Drive," ' Recept)
  ionist ', 'Active»(, 21 décembre 2010', 7, 1, 06)'.
  *
  ERROR on line 1:
  ORA-02291: integrity constraint (ISAD2. SALARYCODE_FK) violated - parent key not
  found
  
  
  SQL >
  
  
  PLEASE HELP ME UNDERSTAND THIS! / / /

  Sounds like you have a problem with your tables. It should not be necessary to insert a "preliminary" to the employee record, and then eventually complete.
  Should not be possible. In your case, it is, for all columns is NULL allowed, which is really bad.

  In your case, it is necessary because you have a circular reference;

  Department of references used, which refers to employee. If you really want it to be like that, one of them should be DEFERRABLE (search)

  You need to go through all your tables, you seem to have missed additional / more than one foreign key.
  I proposed (all) in NOT NULL columns. At least give some thoughts to each column;
  'Should I a value here'-> NOT NULL
  "Do I always have value here"-> NOT NULL
  If it is in each case, perhaps that this cvolumn is not at this table. This could be the case for DEPARTMENT_MANAGER, which would also solve your circular reference.

  Do not use the NUMBER with any precision. Many point for example, 'COURSE_NO' NUMBER will it means it's a flutter. For example, use Number (38), personally I use 'always' NUMBER (13) for identifiers - this will insert in a Java int.

  Also, give thoughts to CHECK constraints, probably, he does not give meaning have a negative salaray, and so on.

  A good practice is to first create all tables, then all primary keys and finally all foreign keys. That decouple the tables, so no specific order of creation is necessary.

  When these changes have been made, then start by inserting tables which do not reference other tables and then take it from there, one table at a time.

  Concerning
  Peter

  Edit: One last thing, I don't get the need for a TREATMENT table. Think you should get rid of it.

  Published by: Peter on April 26, 2011 14:53

• ORA-02449: unique/primary keys in table referenced by foreign keys

  SQL > create table empinformation
  () 2
  primary key pk_empinformation number (6) 3 forced mobileno
  4 address varchar (100),
  5 salary number (10),
  6 personalid varchar (10) constraints fk_employees_section references employee (emp_id));
  
  Table created.
  
  
  SQL > drop table empinformation;
  
  ORA-02449: unique/primary keys in table referenced by foreign keys

  solution

  This error happens when the foreign key of a table is referenced by the primary key of the other table.

  If you want to remove the table had refernce key then, you must
  need to remove this table with the foreign key is referenced.

  or

  SQL > drop table EMPLOYEE CASCADE CONSTRAINTS;
  Deleted table.

  This will remove the table parent without droping the child table.

  Published by: Ritesh Singh October 3, 2011 14:04

• Foreign key between 2 application system.

  Hello
  I work with the Oracle 10 g designer and so far there is no need for what I would like to explain.
  
  Well, we have a shared Workarea Global, 2 Application (AS1, AS2) systems and 2 (C1, C2) - containers for each container Application System (-> C1-> C2 AS2 AS1).
  
  I created a single entity (E1) in C1 and another entity (E2) in C2.
  Now I want to make the relationship between E1 and E2, E1 for example refer to the E2.
  
  Could someone explain what are the right steps to get there?
  To achieve that, when I run the transformer design of database it creates Foreign Key in the server for E1 model.
  
  I have tried different "methods", but obviously I do a few mistakes in the steps...
  
  Thank you!
  Zlatko

  Instructions step by step are in the online help. So, what exactly is not clear? What is:

  I tried and nothing

  I do like this in the RON:
  -Right-click on the node of the System Application child node.
  -Choose Create reference
  -Select the parent Application System
  -Select the table (or any object type) you want to reference

• Foreign key constraint, not recognized during the synchronization of data with the model dictionary

  Hello

  Data Modeler is a foreign key constraints do not recognize when synchronizing data with the model dictionary, although the foreign key is there (in the database that a data dictionary is read). I can't find any criterion when a foreign key is not recognized by the Data Modeler. Are there limits to the length of the attribute, or the number of columns in a foreign key, or other limitations which may lead to this behavior not to recognize a fk by Data Modeler? I have columns more than 32 characters. I compared with the fk is recognized by DM, but I can't find anything that indicates why it is not recognized.

  I wonder if someone also has constraints of foreign keys that are not recognized in the comparison of data bases and model?

  Thank you

  Robert

  Hi Robert,.

  Thanks for the comments, I logged a bug.

  Philippe

• Missing right parenthesis

  Hi all

  Im trying to insert these results to my table of facts (fact_apartments) with the following:

  INSERT INTO fact_apartments (avg_price, segmentid, projectid)

  SELECT (AVG (Price), segmentid, projectid)

  OF projetou

  WHERE projectid = '1';

  but the return with the missing closing parenthesis, it could not know what the problem

  I don't know why you get this error, probably because you have other errors.

  you will need a group on your query. FOR EXAMPLE

  INSERT INTO fact_apartments (avg_price, segmentid, projectid)

  SELECT AVG (Price), segmentid, projectid

  OF projetou

  WHERE projectid = '1'

  GROUP BY segmentid, projectid;

  Concerning

  André

• actually logical foreign keys

  Hello
  
  Can I define foreign keys in the logical fact table? I need to use '= count distinct aggregation rule' column of the foreign key in my reports.
  
  Thank you.
  
  Andy

  Hi Andy,.

  You can add foreign keys to your fact table as a measure column (aggregate distinct count).

  Do not use these foreign keys to create foreign key joins in the logic layer. Always use complex joins (http://obibb.wordpress.com/2010/08/06/joins-in-oracle-bi-ee/)

  Good luck

  Daan Bakboord
  http://obibb.WordPress.com

• Foreign keys without ON DELETE CASCADE; Database design question

  It's the 3rd company, while I work, where I see that created foreign keys

  ON DELETE CASCADE

  clause.
  My colleague said that it is created without the ON DELETE CASCADE clause in order to complicate the deletion of data (records of children). Thus, for codes of the Purge and archive, before we delete the parent table we must remove from the child table first.
  
  Occasinaly, something is wrong and we will end up disabling FKs make them all and then purging, archiving, etc...
  
  So, is it not better to create foreign keys with the clause ON DELETE CASCADE, rather than having all these hassles?
  
  Experience, no matter what you think?

  Personally, I am firmly in the removal of the brand of hard data camp. In the vast majority of cases, trying to remove an active parent is an error if the user must be informed of what they are trying to do and must make a conscious effort to do so (in other words, remove first the children).

  John

• Another syntax for creating primary key

  
  Hello
  
  
  I have a question about the right way to create primary keys.
  Earlier, we were on Oracle 9i and we have upgraded to Oracle 10 g. The question is when creating primary key is allowed to create the unique index and then to create the primary key constraint? or directly create the first key is better? or are there ways to both the same?
  
  
  for example:
  one way:
  
  
  SQL & gt; CONN u2/u2@db1
  Connected.
  SQL & gt; create table a (a1, b1 varchar2 number (2), the date c1);
  
  
  Table created.
  
  
  SQL & gt; create an index on a (a1) tablespace unique pk_a t1;
  
  
  The index is created.
  
  
  
  SQL & gt; ALTER table a Add (constraint primary key (a1) using index pk_a);
  
  
  Modified table.
  Another way:
  SQL & gt; CONN u1/u1@db1
  Connected.
  SQL & gt; create table a (a1, b1 varchar2 number (2), the date c1)
  2.
  
  
  Table created.
  
  
  SQL & gt;
  SQL & gt; ALTER table a Add (constraint primary key (a1) using index tablespace t1 pk_a)
  2.
  
  
  Modified table.
  Which of the two approach is better? or are they the same?
  
  
  Thank you
  Cedric
  
  

  Oracle will attempt to create the index to apply the constraint. Of course, it is certainly possible that the creation of the index will fail, but you would be just to move the point of failure of the CREATE INDEX statement to the ALTER TABLE statement, assuming that everything else is equal (that is, you create the index in the same tablespace, quotas and tablespace sizes are the same, permissions are not changed, etc.)

  It may be preferable in some contexts to create a non-unique index before the creation of the constraint and instruct Oracle to use the non-unique index to apply the constraint. If you decide in the future to make the primary key constraint can be delayed, for example, have a non-unique index allows you to make this change without having to (implicitly), drop and re-create the index. A separate CREATE INDEX statement also influences when you go to remove a constraint / index. If the index was created before the constraint, you can remove the constraint without affecting the index. If the index was created after the constraint, deleting the constraint implicitly removes the index. Normally, particularly with OLTP applications, this doesn't buy you much. Sometimes, however, there are ETL process benefiting from such things.

  Justin