Multiple Table join result problem

Similar Questions

• CF8 cfquery multiple table join with the same names of columns - default

  This seems to be a defect in the CF8 cfquery object. I'm at a loss as to a solution or a good work around. With regard to the substance, this query is generated dynamically on the fly based on what is happening in it a user. This isn't the most elegent SQL but work and return all columns. The app itself is a data viewer to look at the logs. Here is an example of a query being generated.

  Select *.

  of web_trans, web_info_trans, web_res_trans

  where (web_info_trans.trans_dte > = '' 2008-12-1)

  and web_info_trans.trans_dte < '' 2008-12-2)

  and (web_info_trans.trans_dte = web_trans.trans_dte)

  and (web_info_trans.trans_num = 5060345)

  and (web_info_trans.trans_num = web_trans.trans_num)

  and (web_res_trans.trans_num = 5060345)

  and (web_res_trans.trans_num = web_trans.trans_num)

  and (web_trans.web_trans_cde = "NTUI")

  and (web_trans.web_status_cde = 'P')

  and (web_trans. TRANS_NUM < 5060347)

  order of web_trans. TRANS_NUM / / desc

  These three tables contain a similar column called ZIP_CDE. They contain different values, and when this query is executed in Microsoft Query Analyzer results are displayed correctly. Run this same query SQL with CFQUERY and the value of one of the other tables (web_trans) will eventually replace the value for the other columns called ZIP_CDE. The exact amount columns are retruned only values some how get corrupted.

  This is a defect of cf8 is a book autour or an update that resolves this problem that I may have missed?

  Thank you for the ideas.

  Thus it seems still as a default since CF is essentially where, except for the return value play. Other query tools return results correctly so for me, it turns out be CF bug at a certain level.

  Actually I'm swinging to agree with you here, but not for the same reason.  CF actually * is * get all the columns back (as you say), it just doesn't expose a way to tell the difference between a column called 'x' and an another column called 'x', because the way to access the data in columns is simple queryname [columnName] [rowNumber] (or a Variant fo this, but all the amount of variations to that or abbrev. it).  This code shows how he has all four columns of the original two queries (being a stand-in for tables, in this case):

  
  Q1 = queryNew("");
  Q2 = queryNew("");
     
  queryAddColumn (q1, 'id', [1,2,3,4]);
  queryAddColumn (q1, "data", ["one", "two", "three", "four"]);
  queryAddColumn (q2, 'id', [1,2,3,4]);
  queryAddColumn (q2, "data", ["tahi", "rua", "toru", "wha"]); It's Maori, in case you are interested
  

  
  SELECT *.
  Q1, q2
  WHERE q1.id = q2.id
  
  

  So CF knows there are four columns (a call getMetadata (q3) get also demonstrates this), but it does not expose a way to approach the second (or even greater) column of the same name.  This is the bug/shortfall.

  However, relying on an underlying coldfusion.sql.QueryTable method, you can rename the columns, so:

  Then you're OK.

  I would be normally reluctant to recommend doing this, because these methods change from version to version of CF, but it's your call whether this approach will help you.

  To be honest, I'm with Owain who, even in SQL one generally doesn't work with columns with the same name, an alias them qualified with a table name/alias. As the table columns from of is not returned by SQL with the result set, it must be evidence against this by folding the columns in the first place.

  Also, I wonder at the bottom of the extraction of data, you don't really know the structure, that is to say, do SELECT *.  How can you know not even that is ours as the first column, second column, etc.?  I don't think that SQL applies in fact a contract that, t - it?  (I don't know).

  What are you actually do here?

  --

  Adam

• Multiple Table join without loss of data - SQL help

  Hello
  I have the following tables 3 employee as indicated in the scripts below, please help in writing SQL that connects all these 3 tables and displays the output as shown below
  
  Required output
  EMP ID Loc Value 1 Value 2 Value 3                    
  1     A     3     1     6
  1 B 4 9 null
  Value null null 1 Wh 8
  2 Z 4 9 null
  3 R 0 null 1
  4 Y 1 null null
  5 O 7 7 null
  Value null null 5 Wh 5
  6 M 7 null 7
  6 B null null 8
  
  / * Create Tables * /.
  Create table Emp1 (Empid number, Loc Varchar2 (10), Value_1 number);
  Create the Emp2 Table (Empid number, Loc Varchar2 (10), Value_2 number);
  Create table emp3 (empid number, loc varchar2 (10), Value_3);
  
  / * Insert Scripts * /.
  Insert Into Emp1 Values (1, 'A', 3);
  Insert Into Emp1 Values (2, 'Z', 4);
  Insert Into Emp1 Values (3, 'R', 0);
  Insert Into Emp1 Values (4, 'Y', 1);
  Insert Into Emp1 Values (5, 'o', 7);
  Insert Into Emp1 Values (6, am', 7);
  
  Insert Into Emp2 Values (1, 'A', 1);
  Insert Into Emp2 Values (1, 'B', 4);
  Insert Into Emp2 Values (1, 'Wh', 8);
  Insert Into Emp2 Values (2, 'Z', 9);
  Insert Into Emp2 Values (5, 'o', 7);
  Insert Into Emp2 Values (5, 'Wh', 5);
  
  Insert Into Emp3 Values (1, 'A', 6);
  Insert Into Emp3 Values (1, 'B', 9);
  Insert Into Emp3 Values (3, 'R', 1);
  Insert Into Emp3 Values (6, am', 7);
  Insert Into Emp3 Values (6, 'B', 8);
  Commit;
  
  
  Thank you
  Varun

  Like this?

  SQL> select nvl(e.empid, e3.empid) empid
    2       , nvl(e.loc, e3.loc) loc
    3       , e.value_1
    4       , e.value_2
    5       , e3.value_3
    6    from (
    7            select nvl(e1.empid, e2.empid) empid
    8                 , nvl(e1.loc, e2.loc) loc
    9                 , e1.value_1
   10                 , e2.value_2
   11              from emp1 e1
   12              full join emp2 e2
   13                on e1.empid = e2.empid
   14               and e1.loc = e2.loc
   15         ) e
   16    full join emp3 e3
   17      on e.empid = e3.empid
   18     and e.loc = e3.loc
   19   order
   20      by empid
   21       , loc
   22  /
  
       EMPID LOC           VALUE_1    VALUE_2    VALUE_3
  ---------- ---------- ---------- ---------- ----------
           1 A                   3          1          6
           1 B                              4          9
           1 Wh                             8
           2 Z                   4          9
           3 R                   0                     1
           4 Y                   1
           5 O                   7          7
           5 Wh                             5
           6 B                                         8
           6 M                   7                     7
  
  10 rows selected.
  
  SQL> 
  

• Optimizer (?) excluded table join

  Hello

  I have a problem. We use 10.2.0.5.0 database. I discovered very weird behavior when running a very simple three-table join. I tried two forms of the same join. The first was:

  SELECT

  NVL(c.cen_za_ks,1) as a2,

  NVL(c.cen_za_kg,1) like a3

  Of

  vymenny_urad VIEW

  JOIN IN-HOUSE

  Krajina K ON vu.vymur_krj_id = K.KRJ_ID

  JOIN IN-HOUSE

  CENNIK_090 C ON C.CEN_KR_KOD = K.KRJ_KOD

  WHERE

  vu.vymur_id = AND c.cen_kategoria = 369 has '

  Execution plan for this selection is:

  -----------------------------------------------------------------------------------------

  | ID | Operation | Name               | Lines | Bytes | Cost (% CPU). Time |

  -----------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |                    |     4.    88.     5 (0) | 00:00:01 |

  |   1.  NESTED LOOPS |                    |     4.    88.     5 (0) | 00:00:01 |

  |*  2 |   INDEX UNIQUE SCAN | IX_PK_VYMENNY_URAD |     1.       |     1 (0) | 00:00:01 |

  |*  3 |   TABLE ACCESS FULL | CENNIK_090 |     4.    56.     3 (0) | 00:00:01 |

  -----------------------------------------------------------------------------------------

  Information descriptor (identified by the operation identity card):

  ---------------------------------------------------

  2 - access("VU".") VYMUR_ID "= 369)

  3 - filter("C".") CEN_KATEGORIA "(='D')"

  
  

  Thus, for specific settings, I had 8 rows

  
  

  If I added any column of krajina of table columns selected like this:

  
  

  SELECT

  krj_id,

  NVL(c.cen_za_ks,1) as a2,

  NVL(c.cen_za_kg,1) like a3

  Of

  vymenny_urad VIEW

  JOIN IN-HOUSE

  Krajina K ON vu.vymur_krj_id = K.KRJ_ID

  JOIN IN-HOUSE

  CENNIK_090 C ON C.CEN_KR_KOD = K.KRJ_KOD

  WHERE

  vu.vymur_id = AND c.cen_kategoria = 369 has '

  
  

  the execution plan has been changed to:

  
  

  ----------------------------------------------------------------------------------------------------

  | ID | Operation | Name               | Lines | Bytes | Cost (% CPU). Time |

  ----------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |                    |     1.    29.     6 (0). 00:00:01 |

  |   1.  NESTED LOOPS |                    |     1.    29.     6 (0). 00:00:01 |

  |   2.   NESTED LOOPS |                    |     1.    15.     3 (0) | 00:00:01 |

  |*  3 |    TABLE ACCESS BY INDEX ROWID | VYMENNY_URAD |     1.     8.     2 (0) | 00:00:01 |

  |*  4 |     INDEX UNIQUE SCAN | IX_PK_VYMENNY_URAD |     1.       |     1 (0) | 00:00:01 |

  |   5.    TABLE ACCESS BY INDEX ROWID | KRAJINA |   244.  1708.     1 (0) | 00:00:01 |

  |*  6 |     INDEX UNIQUE SCAN | PK_KRAJINA |     1.       |     0 (0) | 00:00:01 |

  |*  7 |   TABLE ACCESS FULL | CENNIK_090 |     1.    14.     3 (0) | 00:00:01 |

  ----------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter("VU".") VYMUR_KRJ_ID"< 2147483648)

  4 - access("VU".") VYMUR_ID "= 369)

  6 - access("VU".") VYMUR_KRJ_ID '=' K '. ("' KRJ_ID")

  7 - filter("C".") CEN_KATEGORIA "= A"AND "C". ". CEN_KR_KOD '=' K '. ("' KRJ_KOD")

  and result set had only 2 rows, because of the restriction imposed by the table "krajina", which was not in the first case considered by the optimizer.

  Y at - it a reasonable explanation for this behavior? Have someone at - he found a reliable solution?

  Thanks for help

  Miro

  I received your email

  I saw something strange in the, but then realize that the elimination was logically invalid and created a simple demo.

  If you look at the two surviving tables SEPARATELY it seems reasonable to eliminate the krajina - but when you look at the other two tables at the same time you realize that you have a line in krajina which corresponds to a line in vymenny_urad but not in cennik_090 and a line that does the opposite. In this case, the other two lines survive when you eliminate the krajina, but they disappear if krajina is located in the middle of the join.

  The problem is solved by 11.1.0.7

  Concerning

  Jonathan Lewis

• Left join with three-table join query

  I am trying to create a query that left me speechless. Most of the query is simple enough, but I have a problem I do not know how to solve.
  
  Background:
  We have stock stored in i_action.
  
  We have the attributes available for each type of action. The attributes available for each action are described in shared_action_attribute. Each type of action can have three attributes or none at all.
  
  We have the values stored for the attributes in i_attribute_value.
  
  An example says:
  We have a transfer action (action_code B4). The action of B4 entry into i_action records the fact that the transfer took place and the date at which he spoke. The attributes available for a transfer action are the function code receiver, the receiving unit number and the reason of transfer code. These types of attributes available and their order are stored in shared_action_attribute. The actual values of the attributes for a specific action of transfer are stored in i_attribute_value.
  
  Now i_action and i_attribute_value can be connected directly in action_seq in i_action and ia_action_seq in i_attribute_value. A left join on these two tables provides results for all actions (including actions that have no attributes) and assign values (see Query 1 below).
  
  There are two questions. First of all, I want only the first two attributes. To specify the attributes of the first two, I also i_attribute_value a link to shared_action_attribute (which is where the order is stored). I can build a simple query (without the left join) which connects the three tables, but then shares without attributes would be excluded from my result (see Query 2 below).
  
  The second problem is that I'd actually a row returned for each action with first_attribute and second_attribute in the form of columns instead of two lines.
  
  The final query will be used to create a materialized view.
  
  Here are the tables and examples of what is stored in the:
  
  TABLE i_action
  Name Type
  ----
  ACTION_SEQ NUMBER (10)
  DATE OF ACTION_DATE
  ACTION_CODE VARCHAR2 (3)
  VARCHAR2 (1) DELETED
  
  EXAMPLE OF LINES
  ACTION_SEQ ACTION_DATE DELETED ACTION_CODE
  ----
  45765668 9 OCTOBER 09 B2 HAS
  45765670 9 OCTOBER 09 BA HAS
  45765672 B6 9 OCTOBER 09A
  45765673 9 OCTOBER 09 B4 HAS
  45765674 9 OCTOBER 09 G1 HAS
  45765675 9 OCTOBER 09 M3 HAS
  
  TABLE i_attribute_value
  Name Type
  ---
  IA_ACTION_SEQ NUMBER (10)
  SACTATT_SACT_CODE VARCHAR2 (3)
  SACTATT_SAT_TYPE VARCHAR2 (3)
  VARCHAR2 VALUE (50)
  
  EXAMPLE OF LINES
  IA_ACTION_SEQ SACTATT_SACT_CODE SACTATT_SAT_TYPE VALUE
  ----
  45765668 B2 COA 37 B
  45765670 BA ROA D
  45765670 BA ROR P
  45765672 B6 CAT C
  B4 45765673 RFC E
  45765673 B4 TRC P
  B4 45765673 RUN 7
  45765674 G1 SS 23567
  G1 45765674 ASG W
  
  TABLE shared_action_attribute
  Name Type
  ---
  SACT_CODE VARCHAR2 (3)
  SAT_TYPE VARCHAR2 (3)
  ORDER NUMBER (2)
  TITLE VARCHAR2 (60)
  
  EXAMPLE OF LINES
  SACT_CODE SAT_TYPE UNDER THE ORDER
  ----
  B2 ACO 1 Office code
  BA ROR 1 reason to re-open
  Authority of BA ROA 2 reopen
  B6 CAT 1 category
  B4 RFC 1 reception function code
  B4 RUN 2 receives the unit code
  B4 TRC 3 transfer of reason code
  Sequence of G1 SS 1 personal
  Reason for G1 ASG 2 assignment
  
  QUERY 1:
  It's my current query as well as its results. Most are select simple but only one column is filled using the function analytic last_value (thank you guys). The last column in the view sub stores the value of the attribute. What I want is to replace this single column with two columns named first_attribute and second_attribute and eliminate all other attributes.
  SELECT ia.action_seq, ia.action_date, ia.action_code cod,
  NVL
  (LAST_VALUE (CASE
  WHEN ia.action_code = "G1".
  AND iav.sactatt_sat_type = 'SS '.
  THEN THE VALUE
  WHEN ia.action_code IN ('A0', 'A1')
  THEN '67089'
  END IGNORE NULLS
  ) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date,
  IA.serial_number, ia.action_seq),
  '67089'
  ) staff_seq,.
  value
  From i_action LEFT JOIN i_attribute_value iav AI
  ON iav.ia_action_seq = ia.action_seq
  WHERE ia.deleted = 'A ';
  
  ACTION_SEQ ACTION_DA COD STAFF_SEQ VALUE
  ----
  45765668 9 OCTOBER 09 B2 67089 37 B
  45765670 9 OCTOBER 09 BA D 67089
  45765670 9 OCTOBER 09 BA 67089 P
  45765672 9 OCTOBER 09 B6 67089 C
  45765673 9 OCTOBER 09 B4 67089 E
  45765673 9 OCTOBER 09 B4 67089 P
  45765673 9 OCTOBER 09 67089 7 B4
  45765674 9 OCTOBER 09 23567 23567 G1
  45765674 9 OCTOBER 09 G1 23567 W
  45765675 9 OCTOBER 09 M3 23567
  
  QUERY 2:
  This query is limited to the first two attributes but he also filed actions which have no attributes, and it creates still several lines for each action instead of a single line with two columns for attributes.
  SELECT ia.action_seq, ia.action_date, ia.action_code cod,
  NVL
  (LAST_VALUE (CASE
  WHEN ia.action_code = "G1".
  AND iav.sactatt_sat_type = 'SS '.
  THEN THE VALUE
  WHEN ia.action_code IN ('A0', 'A1')
  THEN '67089'
  END IGNORE NULLS
  ) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date,
  IA.serial_number, ia.action_seq),
  '67089'
  ) staff_seq,.
  value
  OF shared_action_attribute saa, ims_action AI, ims_attribute_value iav
  WHERE iav.ia_action_seq = ia.action_seq
  AND iav.sactatt_sact_code = saa.sact_code
  AND iav.sactatt_sat_type = saa.sat_type
  AND saa.display_order IN ('1 ', ' 2')
  AND ia.deleted = 'A ';
  
  ACTION_SEQ ACTION_DA VALUE OF COD
  ----
  45765668 9 OCTOBER 09 B2 67089 37 B
  45765670 9 OCTOBER 09 BA D 67089
  45765670 9 OCTOBER 09 BA 67089 P
  45765672 9 OCTOBER 09 B6 67089 C
  45765673 9 OCTOBER 09 B4 67089 E
  45765673 9 OCTOBER 09 67089 7 B4
  45765674 9 OCTOBER 09 23567 23567 G1
  45765674 9 OCTOBER 09 G1 23567 W
  
  I found it quite complex to try to write - I hope that I was clear.
  
  Thank you very much!

  Hello

  You can use an alias for column (such as staff_seq) in the ORDER BY. Unfortunately, it's the only place where you can use it in the same query, where it was defined.
  You can use it anywhere in the super-requetes, however, so you can still work around this problem in assigning the aliases in a subquery and GROUP BY (or other) in a Super query, like this:

  WITH   ungrouped_data      AS
  (
      SELECT ia.action_seq, ia.action_date, ia.action_code,
            NVL
                (LAST_VALUE (CASE
                                WHEN ia.action_code = 'G1'
                                 AND sactatt_sat_type = 'SS'
                                   THEN VALUE
                                WHEN ia.action_code IN ('A0', 'A1')
                                   THEN '67089'
                             END IGNORE NULLS
                            ) OVER (PARTITION BY ia.ici_charge_inquiry_seq ORDER BY ia.action_date, ia.action_seq),
                 '67089'
                )staff_seq,
             (CASE
                WHEN display_order = '1'
                THEN VALUE
             END) first_attribute,
             (CASE
                WHEN display_order = '2'
                THEN VALUE
             END) second_attribute
        FROM i_action ia
        LEFT JOIN i_attribute_value iav
             ON iav.ia_action_seq = ia.action_seq
        LEFT JOIN shared_action_attribute
             ON sactatt_sact_code = sact_code
           AND sactatt_sat_type = sat_type
       WHERE ia.deleted = 'A'
  )
  SELECT       action_seq
  ,       action_date
  ,       action_code
  ,       staff_seq
  ,       MIN (first_attribute)          AS first_attribute
  ,       MIN (second_attribute)     AS second_attribute
  FROM       ungrouped_data
  GROUP BY  action_seq
  ,       action_date
  ,       action_code
  ,       staff_seq
  ;
  

  There are other alternatives for special cases, but none of them work in this particular case.

• To create an interactive report in the apex by selecting from multiple tables

  Hi, I am creating an interactive report by selecting from multiple tables.

  SELECT w.FIRST_NAME as name, w.SURNAME as name, i.ROAD Road, i.DATE_OF_INC as DATE_OF_INC, S.STATEMENT as a STATEMENT OF Declaration

  JOIN THE

  WITNESS w

  ON w.witness_id = s.FK1_WITNESS_ID

  JOIN THE

  Incident I have

  WE

  i.incident_no = w.FK1_INCIDENT_NO

  JOIN THE

  user_station ps

  ON ps.station_id = i.nearest_station_id

  JOIN THE

  the user in.

  WE

  in. STATION_ID = ps.station_id

  WHERE po.officer_id = 1

  by I continue to encounter this error "the report query requires a unique key to identify each row. The supplied key cannot be used for this query. Please change the report attributes to define a unique key column. "ORA-01445: cannot select ROWID from where sample, a join without key preserved table view '

  So I googled around and found that in the attibutres tables report, I need to change the "LINK" COLUMN so first, I changed "Link to custom target", but the report is so I changed it to "Exclude link Clolumn" again, the report didn't report and I STILL got a blank page with only the tabs.

  I wonder you can not create a report by selecting from multiple tables?

  If you can please I need your help.

  Thank you

  You can, but in this case, it might be easier to build your report tables that are joined Oracle views and then build your report out of the newly built sight...

  Or wrap a selection around your selection with joins, and then make the where clause on the external selection...

  Thank you

  Tony Miller
  Software LuvMuffin
  Ruckersville, WILL

• Update multiple columns from multiple tables in a single UPDATE request

  Hello

  I'm trying to figure if I'm heading in the right direction.

  I want to update multiple columns from multiple tables in a single UPDATE request. Also, I would like to update multiple columns in a table from the tables.

  Scenario 1

  UPDATE Table2, Table 3
  SET T2.Column1 = T1.Column1 
  ,T2.Column2 = T1.Column2
  ,T3.Column2 = T1.Column2
  FROM Table1 T1, Table2 T2, Table3 T3
  WHERE T1.id = T2.id
  and T1.id = T3.id
  
  

  Scenario 2

  UPDATE Table3
  SET T3.Column1 = T1.Column1 
  T3.Column2 = T1.Column2
  ,T3.Column3 = T2.Column3
  ,T3.Column4 = T2.Column4
  FROM Table1 T1, Table2 T2, Table3 T3
  WHERE T3.id = T1.id
  and T3.id = T2.id
  
  

  Hello

  For scenario 1, you must write separate instructions UPDATE table2 and table3.

  To guard against someone else change one of these tables while you act so you can copy all relevant data in a global temporary table and update this global temporary table table3.

  ENGAGE only when two tables have been changed.

  You can write a procedure or an INSTEAD OF trigger to do all this.

  For scenario 2, you can reference many tables that you need when new table3.  It might be more efficient and simpler to use the MERGER rather than UPDATED.  For example:

  MERGE INTO table3 dst

  WITH THE HELP OF)

  SELECT t1.id

  t1.column1

  t1.column2

  t2.column3

  t2.column4

  FROM table1 t1

  JOIN table2 t2 ON t1.id = t2.id

  )             src

  WE (dst.id = src_id

  WHEN MATCHED THEN UPDATE

  SET dst.column1 = src.column1

  dst.column2 = src.column2,

  dst.column3 = src.column3,

  dst.column4 = src.column4,

  ;

• data in multiple tables and columns

  Hello
  
  How to find if multiple tables are containing the same data?
  Text of the 'Apple' is in three different tables and under three different column names.
  

  Expected result
   
  fruits_one
  fruits_two 
  fruits_three

  Select name, quantity from fruits_one;
  Apple   1
  Orange  1
  Pear    1
  
  
  select flavour, desc from fruits_two;
  Red,   Apple 
  Blue, Berry
  
  select order,date,details  from fruits_three;
  101  11/11/2011    Grapes
  102  12/01/2010    Apple

  Thank you
  Sandy

  SQL> create table fruits_one (name varchar2(100), quantity number);
  
  Table created.
  
  SQL> insert into fruits_one
    2  select 'Apple'  name, 1 quantity from dual union all
    3  select 'orange'  name, 1 quantity from dual; 
  
  2 rows created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> create table fruits_two (flavour varchar2(100), des varchar2(100));
  
  Table created.
  
  SQL> insert into fruits_two
    2  select 'Red' flavour,   'Apple' des  from dual union all
    3  select 'blue' , 'berry'  from dual ;
  
  2 rows created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> set serveroutput on
  SQL> declare
    2  l_search varchar2(10) := 'APPLE';
    3  l_cnt number := 0;
    4  begin
    5
    6  for x in (select column_name, data_type, table_name from user_tab_cols where data_type in ('VAR
  CHAR2'))
    7  loop
    8
    9    execute immediate  'select count(*) from "' || x.table_name ||'" where upper("' || x.column_n
  ame || '") like ''%' || l_search || '%''' into l_cnt;
   10
   11    if l_cnt > 0  then
   12    dbms_output.put_line('table = "' || x.table_name ||'", column = "' || x.column_name ||'"');
   13    end if;
   14
   15  end loop;
   16
   17  end;
   18  /
  table = "FRUITS_ONE", column = "NAME"
  table = "FRUITS_TWO", column = "DES"
  
  PL/SQL procedure successfully completed.
  
  SQL> 
  

• cannot find the table name of the multiple tables which has more columns.

  Hello
  
  I'm trying to find the NAME of the TABLE from multiple tables which has more columns. I can't count the number of columns in the table, but cannot find the name of the table that has larger columns in other tables.
  
  SELECT TABLE_NAME, COUNT (*) FROM THE USER_TAB_COLUMNS WHERE TABLE_NAME LIKE '% LOC' GROUP TABLE_NAME
  
  
  Thank you.

  in SQL, you can try this:

  var v_name varchar2(40)
  
  begin
     with
        subq1 as ( select table_name, count(*) as column_count from user_tab_columns where table_name like 'FIBER%'
                       group by table_name
                       order by count(*) desc )
     select table_name
       into :v_name
      from subq1
     where rownum = 1;
  end;
  

  To get the result:

  select :v_name from dual
  

  The clause "with" brings together all the tables and ordered them all first, by the greatest number of columns
  The final query uses the rownum restriction so that it takes the first name from the table of results of the subquery.

  The restriction of rownum also exactly guarantees a result each time so that it will work with the variable binding.

  RP

• Create record in the Table of results gives error

  Hi all
  
  Update page there is a table of results with the Add button to create a new line.
  
  Everything by creating a new record on the table of results gives an error
  
  The attributes defined for AccessId in the view object xxlcupdvariablesvo1 failed
  
  I checked the EO and VO attributes, everything seems to be good.
  Updatable also has the value "Always".
  
  
  Still don't know why this error is coming.
  
  Please help resolve this error.
  
  
  Thank you
  SK

  SK

  Don't forget that your AO made correctly and you do your from VO of the two OS after this AO. If possible, allow Jdev to create your AO. Try to create is not in manuallly

  Hope it solves your problem

  Thank you
  AJ

• Tree of SQL on multiple tables

  Hi gurus,
  
  I have a question about the trees of building sql on multiple tables.
  
  It's the exit, I hope:

  0
  - 10, 'Company Blue1', 0
  -- 101, 'Part Blue1', 10
  --- 1001, 'Accounting Blue', 101
  ---- 10001, 'Hans Mueller', 1001
  --- 1002, 'Special Problems Blue', 101 
  ---- 10002, 'Stephen Meyer', 1002
  ---- 10003, 'Carlos Anceto', 1002
  -- 102, 'Part Blue2', 10
  --- 1003, 'Information Technology Blue', 102
  ---- 10004, 'Tobias Tries', 1003
  - 20, 'Company Red1', 0
  -- 201, 'Part Red1', 20
  --- 2001, 'Accounting Red', 201
  ---- 20001, 'Carl Van Deser', 2001
  ---- 20002, 'Geromel Boats', 2002
  - 30, 'Company Green1', 0
  -- 301, 'Part Green1', 30
  --- 3001, 'Accounting Green', 301
  ---- 30002, 'Peter Finnighan', 3001
  --- 3003, 'Special Problems Green', 301
  ---- 30001, 'Loui Van Ecke', 3003

  This is the situation: I have 4 table which can be forced to key foreign and all build toghether in a tree.

  Table1:
  tbl_company (c_id, company_name)
  Values: 
  10, 'Company Blue1'
  20, 'Company Red1'
  30, 'Company Green1'
  
  Table2:
  tbl_company_parts (cp_id, part_name, company_id)
  Values: 
  101, 'Part Blue1', 10
  102, 'Part Blue2', 10
  201, 'Part Red1',20
  301, 'Part Green1',30
  
  Table3:
  tbl_departments (d_id, dept_name, part_id)
  Values: 
  1, 'Accounting Blue', 101
  2, 'Special Problems Blue', 101
  3, 'Information Technology Blue', 102
  4, 'Accounting Red',201
  5, 'Accounting Green',301
  6, 'Special Problems Green',301
  
  Tablemployees (e_id, dept_name, department_id)
  Values: 
  1, 'Hans Mueller', 1
  2, 'Stephen Meyer', 2
  3, 'Carlos AncetoÄ, 2
  4, 'Carl Van Deser',4
  5, 'Geromel Boats', 4
  6, 'Loui Van Ecke',5
  7, 'Peter Finnighan',6
  8, 'Tobias Tries',3

  The problem is that I do not know how in alle concate these values and using the connection by the clause that creates this tree

  Hi Tobias,.

  It was not exactly how id should be calculated, but this example you get:

  SQL> create table tbl_company (c_id, company_name)
    2  as
    3  select 10, 'Company Blue1' from dual union all
    4  select 20, 'Company Red1' from dual union all
    5  select 30, 'Company Green1' from dual
    6  /
  
  Table created.
  
  SQL> create table tbl_company_parts (cp_id, part_name, company_id)
    2  as
    3  select 101, 'Part Blue1', 10 from dual union all
    4  select 102, 'Part Blue2', 10 from dual union all
    5  select 201, 'Part Red1',20 from dual union all
    6  select 301, 'Part Green1',30 from dual
    7  /
  
  Table created.
  
  SQL> create table tbl_departments (d_id, dept_name, part_id)
    2  as
    3  select 1, 'Accounting Blue', 101 from dual union all
    4  select 2, 'Special Problems Blue', 101 from dual union all
    5  select 3, 'Information Technology Blue', 102 from dual union all
    6  select 4, 'Accounting Red',201 from dual union all
    7  select 5, 'Accounting Green',301 from dual union all
    8  select 6, 'Special Problems Green',301 from dual
    9  /
  
  Table created.
  
  SQL> create table tbl_employees (e_id, emp_name, department_id)
    2  as
    3  select 1, 'Hans Mueller', 1 from dual union all
    4  select 2, 'Stephen Meyer', 2 from dual union all
    5  select 3, 'Carlos Anceto', 2 from dual union all
    6  select 4, 'Carl Van Deser',4 from dual union all
    7  select 5, 'Geromel Boats', 4 from dual union all
    8  select 6, 'Loui Van Ecke',5 from dual union all
    9  select 7, 'Peter Finnighan',6 from dual union all
   10  select 8, 'Tobias Tries',3 from dual
   11  /
  
  Table created.
  
  SQL> select coalesce
    2         ( case when e.department_id is null then null else
    3             trunc(d.part_id,-2) * 100 + dense_rank() over (partition by d.part_id order by e.e_id)
    4           end
    5         , trunc(d.part_id,-2) * 10 + dense_rank() over (partition by d.part_id order by d.d_id)
    6         , p.cp_id
    7         , c.c_id
    8         , 0
    9         ) id
   10       , coalesce
   11         ( e.emp_name
   12         , d.dept_name
   13         , p.part_name
   14         , c.company_name
   15         ) name
   16       , coalesce
   17         ( trunc(d.part_id,-2) * 10 + dense_rank() over (partition by d.part_id order by d.d_id)
   18         , d.part_id
   19         , p.company_id
   20         , case grouping(c.c_id) when 0 then 0 end
   21         ) parent_id
   22    from tbl_company c
   23       , tbl_company_parts p
   24       , tbl_departments d
   25       , tbl_employees e
   26   where c.c_id = p.company_id
   27     and p.cp_id = d.part_id
   28     and d.d_id = e.department_id
   29   group by rollup
   30         ( ( c.c_id,c.company_name)
   31         , ( p.cp_id,p.part_name,p.company_id)
   32         , ( d.d_id,d.dept_name,d.part_id)
   33         , ( e.e_id,e.emp_name,e.department_id)
   34         )
   35   order by c.c_id nulls first
   36       , p.cp_id nulls first
   37       , d.d_id nulls first
   38       , e.e_id nulls first
   39  /
  
          ID NAME                                                                               PARENT_ID
  ---------- --------------------------------------------------------------------------------- ----------
           0
          10 Company Blue1                                                                              0
         101 Part Blue1                                                                                10
        1001 Accounting Blue                                                                         1001
       10001 Hans Mueller                                                                            1001
        1002 Special Problems Blue                                                                   1002
       10002 Stephen Meyer                                                                           1002
       10003 Carlos Anceto                                                                           1002
         102 Part Blue2                                                                                10
        1001 Information Technology Blue                                                             1001
       10001 Tobias Tries                                                                            1001
          20 Company Red1                                                                               0
         201 Part Red1                                                                                 20
        2001 Accounting Red                                                                          2001
       20001 Carl Van Deser                                                                          2001
       20002 Geromel Boats                                                                           2001
          30 Company Green1                                                                             0
         301 Part Green1                                                                               30
        3001 Accounting Green                                                                        3001
       30001 Loui Van Ecke                                                                           3001
        3002 Special Problems Green                                                                  3002
       30002 Peter Finnighan                                                                         3002
  
  22 rows selected.
  

  Kind regards
  Rob.

• Query with multiple Tables

  Hello

  I want to run the table several queries. I have 4 tables. Table 1 is to have relatively in table 2, but table 3 & 4 is not related with table 1. wherever I want to extract the data from table 1, table 4. My current query works well but it miss the Chronogram of table 1, which records do not exist in table 2, where, from table 2 of table 4 its working fine.

  SELECT z.productcode, fabqty z.productionadviceno, sum (z.fabricatedqty).

  Fabqtynoms Round (Sum(z.fabricatedqty*.015) + Sum (z.fabricatedqty)),

  w.workorderno, ons min (w.ons).

  ((SOMME (w.qtyinsheets) * min (ons))) PCS,

  (SELECT SUM (NVL (mrnqty, 0)))

  OF CANMRN

  WHERE workorderno = w.workorderno) mrnqty;

  (SELECT ROUND (SUM (NVL (ptnqty, 0))))

  OF CANPTN

  WHERE workorderno = w.workorderno

  ) ptnqty

  OF CANWORKORDER w, productionadvice z

  where w.productionadviceno = z.productionadviceno

  and w.productcode = 501001

  GROUP BY w.workorderno, z.productionadviceno, z.productcode

  PRODUCTCODE PRODUCTIONADVICENO FABQTY FABQTYNOMS WORKORDERNO ONS SCP MRNQTY PTNQTY

  ----------- ------------------ --------- ---------- ----------- --------- --------- --------- ------

  501001 20004182 250000 253750 20001805 15 253755 16917 253755

  501001 20004229 200000 203000 20001817 15 202995 13533 202995

  501001 20004251 130000 131950 20001829 15 131955 8797 131955

  501001 20004256 200000 203000 20001839 15 202995 13533 202995

  501001 20004277 500000 507500 20001844 15 507495 33833 507495

  501001 20004411 500000 507500 20001918 15 507495 31619 474285

  501001 20004904 230000 233450 20002150 15 233445

  I want to get this record also is missing after you run the query, as I had mentioned w.productionadviceno = z.productionadviceno due to which its does not, how, in a delicate way, we can use this relationship.

  501001 20004905 10000 10150

  Sandy

  use of EXTERNAL JOINS as follows

  where w.productionadviceno = z.productionadviceno (+)
  

  above is a left outer join. A LEFT OUTER JOIN is a JOIN operations that allow you to specify a join clause. He keeps the lines without correspondence of the first (left) table, join them with a NULL row in the form of the second table (right).

  More details: LEFT OUTER JOIN operation

• Use with need to collect in bulk to insert records from multiple tables

  Hello

  I plsql record type with several tables with multiple columns. so when I used bulk collect with education for ALL. I want to insert records in multiple tables.

  Please give me suggestions.

  ForAll is designed to be used with a single DML statement, which may include dynamic SQL statements. However, I do not know what advantage this will give you your list iteration save several times, one for each table - especially since there is an air show with SQL dynamic.

  Example 1 (dynamic SQL):

  begin

    ...

    forall i in vRecList.First..vRecList.Last
    execute immediate '
    begin
      insert into Table1 (Col1, Col2, Col3) values (:1, :2, :3);
      insert into Table2 (Col1, Col2, Col3) values (:1, :2, :3);
    end;' using vRecList(i).Col1, vRecList(i).Col2, vRecList(i).Col3;
end;

  Another approach that I should work (but not tested) is using to insert all the Scriptures and based record inserts, but you need to try on your version of Oracle forall has changed between the versions.  In this case vRecList must be compatible with the Table % ROWTYPE and Table2% ROWTYPE type.

  
  

  Example 2 (insert all):

  begin

    ...

    forall i in vRecList.First..vRecList.Last

      insert all

        into Table1 values vRecList(i)
      into Table2 values vRecList(i)
    select 1 from dual;
end;

• Images in the table of results

  

  Hello

  I use latitude short 2.2.2 studio and I have many results in the application.

  There is a table of results, where I have the image as the value of the cell (see as steep as above - second column with a small img)

  I want to resize the height and width for only this instance of the results table.

  How can I achieve this?

  Thanks in advance for the answers.

  Hello

  "You pass the value of the image as http://pathtoimage/name.png" width = "150" height = "150" > '?

  Short Studio 2.2 has no image support. But little CSS trick can work.

  Comment out the following line in tomcat-6.0.29\webapps\ROOT\html\extjs\endeca-extjs-overrides.css

  max height: 11px; / * same size as the text in the grid * /.

  Note: This may alter the alignment.

• Select Max (date) between multiple tables

  I need to retrieve a record from a Table in a set of similar tables with a common "date field". You can select the record where this "date field" value is greater between multiple tables.

  Here, any help is appreciated.  Thank you in advance.

  FOR EXAMPLE

  No. EMP is the primary key.

  Again, each table can have multiple records for EMP n ° 1

  TABLE1:

  FIRST NAME

  FAMILY NAME
  THE EMP NO.

  BASE SALARY

  DATE_FROM

  TABLE 2

  FIRST NAME

  FAMILY NAME
  THE EMP NO.

  SALARY GRADE

  DATE_FROM

  TABLE 3

  FIRST NAME

  FAMILY NAME
  THE EMP NO.

  COMPENSATION

  DATE_FROM

  Hello

  Said Knani, if you use the current design of the table, then here is a way to do what you want:

  WITH union_data AS

  (

  SELECT MAX (base_salary) AS sal FROM table1 UNION ALL

  SELECT MAX (grade_salary) table2 UNION ALL

  SELECT MAX (compensation) FROM table3

  )

  SELECT MAX (sal) AS max_sal

  Of union_data

  ;